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CONCEPT OF STRESS

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STRESS IN THE MEMBERS OF A STRUCTURE

The force per unit area, or intensity of the forces

distributed over a given section, is called the stress

on that section.

Denoted by Greek letter (Sigma)A

P

299

266

233

2

2

/10101

/10101

/10101

)(11

:.

mNPaGPa

mNPaMPa

mNPakPa

PascalPa

m

N

m

NUnitsSI

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AXIAL LOADING : NORMAL STRESS

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AXIAL LOADING: NORMAL STRESS

The normal stress at a particular point may not be

equal to the average stress but the resultant of the

stress distribution must satisfy

A

ave dAdFAP

The resultant of the internal forces for an axially

loaded member is normalto a section cut

perpendicular to the member axis.

A

P

A

Fave

A

0lim

The force intensity on that section is defined asthe normal stress.

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A uniform distribution of stress is only possible

if the concentrated loads on the end sections of

two-force members are applied at the section

centroids. This is referred to as centric loading.

If a two-force member is eccentrically loaded,

then the resultant of the stress distribution in asection must yield an axial force and a moment.

A uniform distribution of stress in a section infers

that the line of action for the resultant of the

internal forces passes through the centroid of the

section.

The stress distributions in eccentrically loaded

members cannot be uniform or symmetric.

Centric & Eccentric Loading

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The resultant of the internal shear force

distribution is defined as theshearof the section

and is equal to the loadP.

ForcesPand Pare applied transversely to the

memberAB. Corresponding internal forces act in the plane

of section Cand are calledshearingforces.

A

Pave

The corresponding average shear stress is,

Shear stress distribution varies from zero at themember surfaces to maximum values that may be

much larger than the average value.

The shear stress distribution cannot be assumed to

be uniform.

Shearing Stress

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A

F

A

Pave

Single Shear

A

F

A

P

2ave

Double Shear

Shearing Stress Examples

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Bolts, rivets, and pins create

stresses on the points of contactorbearing surfaces of the

members they connect.

dt

P

A

Pb

Corresponding average force

intensity is called the bearing

stress,

The resultant of the force

distribution on the surface isequal and opposite to the force

exerted on the pin.

Bearing Stress in Connections

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STRESS IN TWO FORCE MEMBERS

Axial forces on a two force

member result in only normal

stresses on a plane cut

perpendicular to the member axis. The forces acting on each end of

member must have the same

magnitude, same line of action,

and opposite sense.

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STRESS ON AN OBLIQUE PLANE

Pass a section through the member forming

an angle q with the normal plane.

qq

q

q

q

q

q

q

q

cossin

cos

sin

cos

cos

cos

00

2

00

A

P

A

P

A

V

A

P

A

P

A

F

The average normal and shear stresses onthe oblique plane are

qq sincos PVPF

ResolvePinto components normal and

tangential to the oblique section,

From equilibrium conditions, the

distributed forces (stresses) on the plane

must be equivalent to the forceP.

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MAXIMUM STRESSES

The maximum normal stress occurs when the

reference plane is perpendicular to the member

axis,

0

0

m A

P

The maximum shear stress occurs for a plane at

+ 45o with respect to the axis,

00

245cos45sin

A

P

A

P

m

qqq cossincos

0

2

0 A

P

A

P

Normal and shearing stresses on an oblique

plane

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Stress Under General Loadings

A member subjected to a general

combination of loads is cut into two

segments by a plane passing through

Q

For equilibrium, an equal and

opposite internal force and stress

distribution must be exerted on the

other segment of the member.

A

V

A

V

A

F

x

zA

xz

x

yA

xy

x

Ax

limlim

lim

00

0

The distribution of internal stress

components may be defined as,

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State of Stress Stress components are defined for the planes

cut parallel to thex,y andzaxes. Forequilibrium, equal and opposite stresses are

exerted on the hidden planes.

It follows that only 6 components of stress are

required to define the complete state of stress

The combination of forces generated by the

stresses must satisfy the conditions for

equilibrium:

0

0

zyx

zyx

MMM

FFF

yxxy

yxxyz aAaAM

0

zyyzzyyz andsimilarly,

Consider the moments about thezaxis:

i f b f

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Stress matrix in 3D=

Quantity Onedimension

Two dimension Threedimension

Scalar

Vector

Tensor

011

111

211

1

33

239

224

122

0310

21

zzzyzx

yzyyyx

xzxyxx

omparison of number ofcomponents

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FACTOR OF SAFETY

stressallowable

stressultimate

safetyofFactor

all

u

FS

FS

Structural members or

machines must be designed

such that the working stresses

are less than the ultimate

strength of the material.

Factor of safety considerations:

uncertainty in material properties

uncertainty of loadings

uncertainty of analyses

number of loading cycles types of failure

maintenance requirements and

deterioration effects

importance of member to structures

integrity risk to life and property

influence on machine function

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PROBLEM NO: 1

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PROBLEM NO: 2

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PROBLEM NO: 3

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PROBLEM NO: 4