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8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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Cones&
Spheres
A S 12.3.1, 12.3.2
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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Shape of objectsShape of objectsMost objects are combinations of
shapes or approximations of shapese.g. Fibroblast cells like this
one are cultured on
circular coverslips 10 mmin diameter.
Calculatethe area of
the coverslip.
A = (5)2
78,54mm2
Calculatethe area of
a single
A (45)
(15)= 337 5 m2
How many cellswill cover thecover slip?
5,3371054,78
6x
No =
2,33x105cells
1mm2 = 106 m2
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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The ConeA Cone is a three dimensional solid with a
circular base and a curved surface thatgradually narrows to a vertex.
Volume of Cone = 1/3 volume of
cylinder
V = 1/3 r2 h
Find the volume of a
cone with a diameterof5m and a height of
V = (1/3) r2 h
=(1/3)()
(5/2
)2(9)
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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Find the area of a closed cone with aradius,
r = 3 m and height, h = 4 m.
l 2 = r2 + h2
l 2 =(3)2 + (4)2
Surface Area of a Cone = r2 +rl
where r = radius ; h = heightl = the slant height
Surface Area of aCone
= r2 + rl
= (3)
2
+
(3)(5) 2
Surf
ace area of an open cone = rl
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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TheSphere
Volume of sphere = 4/3
r3
A sphere is a three dimensional circularsolid that is perfectly symmetrical. It hasno edges or vertices. A hemisphere is a sphere.
Calculate the volume ofa
sphere with a radius of6cm.
V = 4/3 r3
= 4/3 (6)3
904,78 cm3
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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If the diameter of abubble
is 0,2 inches, what isthe
surface area of thebubble
in mm2?
Area of sphere = 4 r2
A = 4 r2
= 4 (5,08 /2)2
81,07 mm2
1 inch 2,54 cm
0,2 in = 2,54 x 0,2= 0,508cm= 5,08 mm
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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A marble paperweight consists
of a hemisphere with a radiusof 4 cm and a cuboid, withdimensions 10 cm x 10 cm x5 cm, as shown.
1.
V = (10 x 10 x 5) + (4/3. . 43)
634,04 cm3
Calculate the volume of the paperweight.
What is the height of the paperweight ?
h = 4 + 5 = 9 cm
ConsolidationConsolidation
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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e on o ay n eUSA you see a LCD HD
TV. The dimensions withthe stand are 49.73 x34.22 x 12.17. Showwhether this TV will fitonto your tabletop with
dimensions 130cm x30cm.
metric dimensions= (49,73x2,54) x (34,22x2,54) x (12,17x2,54)
126,31 cm x 86,92 cm x 30,91 cm
2.
Will not fit as the depth of TV is 30,91 cmand the table is only 30 cm deep.1 inch 2,54 cm
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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A shop sign is created with semi-circularends. The shop manager wants the signto have a border made from flexible
plastic.
80cm250cm
150
cm
What length of plastic,
in m, will be needed togo
round the sign?
Length = 2 x x 0,82 + 2 x 2,5 7,01 m
If the border costsR19,99 per metre,
howmuch will the total
border cost?
Cost = R19,99 x 7,01 R140,13
3.
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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A container is made of sheet metal in theform of an open cone joined to an open-
ended cylinder. The radius of the cylinderand of the base of the cone is 8,6 cm.
Calculate the sheet metal area.4cm
10
,9cmS A open cone = rl
= (8,6)(10,9)= 294,49.. cm2
S A cylinder = 2rh= 2(8,6)(4)= 216,14.. cm2
Area of sheet metal= 294,49.. + 216,14.. 510,63 cm2
4.
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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The underneath of a viaduct arch is sold astorage space. Each end of the arch mustbe boarded up before the arch is sold. The
top of the arch forms a semi-circle with thdiameter wider than the base.
Calculate the boarding
area?Area = 2 x (10x8 + 52)
238,54 m2
Calculate the total volume of the archspace.Volume = area base x height
= 238,54 /2 x 16
= 1907,32 m3
5.
r = 15cm - 10cm
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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The diagram shows a small hot watercylinder, which is made up from a cylinderwhich is capped with a hemisphere.
Calculate the maximum volume of water, in, that the cylinder can hold.
Vol cylinder = .0,252 x 1
= 0,19634 m3
Vol sphere = x (4/3 0,253)
= 0,032724 m3
1 k = 1 m3
Total volume = 0,196.. + 0,032..= 0,2290649 k
229
6.
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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7. A wine glass is in a shape of a cone on astem. A cylindrical tumbler is used to fill
the wine glass. Find the diameter of thetumbler so that it has the same volumeas the wine glass.
12
cm
6cm
10c
mVolume wine glass= 1/3 r
2 h
= 1/3 (6/2)
2 (10)
94,25 cm2 Tumbler:94,25 = r2 (12)
r2 = 94,25 /(.12)
r 1,58 cm
8/4/2019 Cones & Spheres AS 12.3.1 12.3.2
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The diagram shows a section of a rocketfirework. If it is completely filled withgunpowder, what volume of gunpowder
was used?
V powder = r2h + 1/3r2h
= (32) (20) + 1/3 (32)(5,12)
613,74cm3
Find radius: Sin 30o = r/6r = 6 sin30o
= 3cm
Find cone h: h2 = 62 32
h 5,12cm
8.