+ All Categories
Home > Documents > Cones & Spheres AS 12.3.1 12.3.2

Cones & Spheres AS 12.3.1 12.3.2

Date post: 07-Apr-2018
Category:
Upload: wmathematics
View: 224 times
Download: 0 times
Share this document with a friend

of 14

Transcript
  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    1/14

    Cones&

    Spheres

    A S 12.3.1, 12.3.2

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    2/14

    Shape of objectsShape of objectsMost objects are combinations of

    shapes or approximations of shapese.g. Fibroblast cells like this

    one are cultured on

    circular coverslips 10 mmin diameter.

    Calculatethe area of

    the coverslip.

    A = (5)2

    78,54mm2

    Calculatethe area of

    a single

    A (45)

    (15)= 337 5 m2

    How many cellswill cover thecover slip?

    5,3371054,78

    6x

    No =

    2,33x105cells

    1mm2 = 106 m2

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    3/14

    The ConeA Cone is a three dimensional solid with a

    circular base and a curved surface thatgradually narrows to a vertex.

    Volume of Cone = 1/3 volume of

    cylinder

    V = 1/3 r2 h

    Find the volume of a

    cone with a diameterof5m and a height of

    V = (1/3) r2 h

    =(1/3)()

    (5/2

    )2(9)

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    4/14

    Find the area of a closed cone with aradius,

    r = 3 m and height, h = 4 m.

    l 2 = r2 + h2

    l 2 =(3)2 + (4)2

    Surface Area of a Cone = r2 +rl

    where r = radius ; h = heightl = the slant height

    Surface Area of aCone

    = r2 + rl

    = (3)

    2

    +

    (3)(5) 2

    Surf

    ace area of an open cone = rl

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    5/14

    TheSphere

    Volume of sphere = 4/3

    r3

    A sphere is a three dimensional circularsolid that is perfectly symmetrical. It hasno edges or vertices. A hemisphere is a sphere.

    Calculate the volume ofa

    sphere with a radius of6cm.

    V = 4/3 r3

    = 4/3 (6)3

    904,78 cm3

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    6/14

    If the diameter of abubble

    is 0,2 inches, what isthe

    surface area of thebubble

    in mm2?

    Area of sphere = 4 r2

    A = 4 r2

    = 4 (5,08 /2)2

    81,07 mm2

    1 inch 2,54 cm

    0,2 in = 2,54 x 0,2= 0,508cm= 5,08 mm

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    7/14

    A marble paperweight consists

    of a hemisphere with a radiusof 4 cm and a cuboid, withdimensions 10 cm x 10 cm x5 cm, as shown.

    1.

    V = (10 x 10 x 5) + (4/3. . 43)

    634,04 cm3

    Calculate the volume of the paperweight.

    What is the height of the paperweight ?

    h = 4 + 5 = 9 cm

    ConsolidationConsolidation

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    8/14

    e on o ay n eUSA you see a LCD HD

    TV. The dimensions withthe stand are 49.73 x34.22 x 12.17. Showwhether this TV will fitonto your tabletop with

    dimensions 130cm x30cm.

    metric dimensions= (49,73x2,54) x (34,22x2,54) x (12,17x2,54)

    126,31 cm x 86,92 cm x 30,91 cm

    2.

    Will not fit as the depth of TV is 30,91 cmand the table is only 30 cm deep.1 inch 2,54 cm

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    9/14

    A shop sign is created with semi-circularends. The shop manager wants the signto have a border made from flexible

    plastic.

    80cm250cm

    150

    cm

    What length of plastic,

    in m, will be needed togo

    round the sign?

    Length = 2 x x 0,82 + 2 x 2,5 7,01 m

    If the border costsR19,99 per metre,

    howmuch will the total

    border cost?

    Cost = R19,99 x 7,01 R140,13

    3.

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    10/14

    A container is made of sheet metal in theform of an open cone joined to an open-

    ended cylinder. The radius of the cylinderand of the base of the cone is 8,6 cm.

    Calculate the sheet metal area.4cm

    10

    ,9cmS A open cone = rl

    = (8,6)(10,9)= 294,49.. cm2

    S A cylinder = 2rh= 2(8,6)(4)= 216,14.. cm2

    Area of sheet metal= 294,49.. + 216,14.. 510,63 cm2

    4.

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    11/14

    The underneath of a viaduct arch is sold astorage space. Each end of the arch mustbe boarded up before the arch is sold. The

    top of the arch forms a semi-circle with thdiameter wider than the base.

    Calculate the boarding

    area?Area = 2 x (10x8 + 52)

    238,54 m2

    Calculate the total volume of the archspace.Volume = area base x height

    = 238,54 /2 x 16

    = 1907,32 m3

    5.

    r = 15cm - 10cm

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    12/14

    The diagram shows a small hot watercylinder, which is made up from a cylinderwhich is capped with a hemisphere.

    Calculate the maximum volume of water, in, that the cylinder can hold.

    Vol cylinder = .0,252 x 1

    = 0,19634 m3

    Vol sphere = x (4/3 0,253)

    = 0,032724 m3

    1 k = 1 m3

    Total volume = 0,196.. + 0,032..= 0,2290649 k

    229

    6.

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    13/14

    7. A wine glass is in a shape of a cone on astem. A cylindrical tumbler is used to fill

    the wine glass. Find the diameter of thetumbler so that it has the same volumeas the wine glass.

    12

    cm

    6cm

    10c

    mVolume wine glass= 1/3 r

    2 h

    = 1/3 (6/2)

    2 (10)

    94,25 cm2 Tumbler:94,25 = r2 (12)

    r2 = 94,25 /(.12)

    r 1,58 cm

  • 8/4/2019 Cones & Spheres AS 12.3.1 12.3.2

    14/14

    The diagram shows a section of a rocketfirework. If it is completely filled withgunpowder, what volume of gunpowder

    was used?

    V powder = r2h + 1/3r2h

    = (32) (20) + 1/3 (32)(5,12)

    613,74cm3

    Find radius: Sin 30o = r/6r = 6 sin30o

    = 3cm

    Find cone h: h2 = 62 32

    h 5,12cm

    8.


Recommended