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CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

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CONFIDENTIAL 1 Geometry Geometry Angles formed by Angles formed by Parallel Lines Parallel Lines and Transversals and Transversals
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Page 1: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 1

GeometryGeometry

Angles formed by Angles formed by Parallel Lines and Parallel Lines and

TransversalsTransversals

Page 2: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 2

Warm UpWarm Up

Give an example of each angle pair.

1) Alternate interior angles 2) Alternate exterior angles

3)Same side interior angles

Page 3: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 3

Parallel, perpendicular and skew linesParallel, perpendicular and skew lines

When a transversal cuts (or intersects) parallel lines several pairs of congruent and supplementary angles are formed.

1 23 4

5 67 8

There are several special pairs of angles formed from this figure.

Vertical pairs: Angles 1 and 4  Angles 2 and 3  Angles 5 and 8  Angles 6 and 7

Page 4: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 4

Supplementary pairs:

Angles 1 and 2 Angles 2 and 4 Angles 3 and 4 Angles 1 and 3 Angles 5 and 6 Angles 6 and 8 Angles 7 and 8 Angles 5 and 7

1 23 4

5 67 8

Recall that supplementary angles are angles whose angle measure adds up to 180°. All of these supplementary pairs are linear pairs.

There are three other special pairs of angles. These pairs are congruent pairs.

Page 5: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 5

If two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.

Corresponding angle postulateCorresponding angle postulate

1 2 3 45 6 7 8

p q

t

1 3 2 4 5 7 6 8

Page 6: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 6

Using the Corresponding angle postulateUsing the Corresponding angle postulate

Find each angle measure.

800 x0

B

C

A

A) m( ABC)

x = 80 corresponding angles

m( ABC) = 800

Page 7: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 7

B) m( DEF)

(2x-45)0 = (x+30)0 corresponding angles

m( DEF) = (x+30)0

(2x-45)0

EF

D

(x+30)0

x – 45 = 30 subtract x from both sides

x = 75 add 45 to both sides

= (75+30)0

= 1050

Page 8: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 8

Now you try!

1) m( DEF)

RSx0

1180

Q

Page 9: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 9

Remember that postulates are statements that are accepted without proof. Since the

Corresponding Angles postulate is given as a postulate, it can be used to prove the next

three theorems.

Page 10: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 10

Alternate interior angles theoremAlternate interior angles theorem

If two parallel lines are cut by a transversal, then the two pairs of Alternate interior angles are congruent.

1 3 2 4

1 2

4 3

Theorem

Hypothesis Conclusion

Page 11: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 11

Alternate exterior angles theoremAlternate exterior angles theorem

If two parallel lines are cut by a transversal, then the two pairs of Alternate exterior angles are congruent.

5 7 6 8

5 6

8 7

Theorem

Hypothesis Conclusion

Page 12: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 12

Same-side interior angles theoremSame-side interior angles theorem

If two parallel lines are cut by a transversal, then the two pairs of Same-side interior angles are supplementary.

m 1 + m 4 =1800 m 2 + m 3 =1800

Theorem

Hypothesis Conclusion

1 2

4 3

Page 13: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 13

Alternate interior angles theoremAlternate interior angles theorem

1 2

3m

lGiven: l || m

Prove: 2 3

Proof:

1 3l || m

Given Corresponding angles

2 3

2 1

Vertically opposite angles

Page 14: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 14

A) m( EDF)

Finding Angle measuresFinding Angle measures

1250

B

C

A

x0

D

E F

m( DEF) = 1250

x = 1250

Alternate exterior angles theorem

Find each angle measure.

Page 15: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 15

B) m( TUS)

13x0 + 23x0 = 1800 Same-side interior angles theorem

m( TUS) = 23(5)0

36x = 180 Combine like terms

x = 5 divide both sides by 36

= 1150

13x0 23x0

U

T

S

R

Substitute 5 for x

Page 16: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 16

2) Find each angle measure.

Now you try!

B C

ED

(2x+10)0A

(3x-5)0

Page 17: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 17

A treble string of grand piano are parallel. Viewed from above, the bass strings form transversals to the treble

string. Find x and y in the diagram.

(25x+5y)0

(25x+4y)0

1200

1250

By the Alternative Exterior Angles Theorem, (25x+5y)0 = 1250

By the Corresponding Angles Postulates, (25x+4y)0 = 1200

(25x+5y)0 = 1250

- (25x+4y)0 = 1200

y = 5

25x+5(5) = 125

x = 4, y = 5

Subtract the second equation from the first equation

Substitute 5 for y in 25x +5y = 125. Simplify and solve for x.

Page 18: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 18

3) Find the measure of the acute angles in the diagram.

Now you try!

(25x+5y)0

(25x+4y)0

1200

1250

Page 19: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 19

Assessment

Find each angle measure:

1270

x0

KJ

L

2) m( BEF)

(7x-14)0

(4x+19)0

G

AABC

FD

H

E

1) m( JKL)

Page 20: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 20

Find each angle measure:

1

3) m( 1)

(3x+9)0

6x0

A

B

C

D

Y

X

E

Z

4) m( CBY)

Page 21: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 21

Find each angle measure:

1150

Y0K

M

L

5) m( KLM)

6) m( VYX)

Y

X

W Z

(2a+50)0

V 4a0

Page 22: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 22

State the theorem or postulate that is related to the measures of the angles in each pair. Then find the angle measures:

12

34

5

7) m 1 = (7x+15)0 , m 2 = (10x-9)0

8) m 3 = (23x+15)0 , m 4 = (14x+21)0

Page 23: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 23

Parallel, perpendicular and skew linesParallel, perpendicular and skew lines

When a transversal cuts (or intersects) parallel lines several pairs of congruent and supplementary angles are formed.

1 23 4

5 67 8

There are several special pairs of angles formed from this figure.

Vertical pairs: Angles 1 and 4  Angles 2 and 3  Angles 5 and 8  Angles 6 and 7

Let’s review

Page 24: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 24

Supplementary pairs:

Angles 1 and 2 Angles 2 and 4 Angles 3 and 4 Angles 1 and 3 Angles 5 and 6 Angles 6 and 8 Angles 7 and 8 Angles 5 and 7

1 23 4

5 67 8

Recall that supplementary angles are angles whose angle measure adds up to 180°. All of these supplementary pairs are linear pairs.

There are three other special pairs of angles. These pairs are congruent pairs.

Page 25: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 25

If two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.

Corresponding angle postulateCorresponding angle postulate

1 2 3 45 6 7 8

p q

t

1 3 2 4 5 7 6 8

Page 26: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 26

Using the Corresponding angle postulateUsing the Corresponding angle postulate

Find each angle measure.

800 x0

B

C

A

A) m( ABC)

x = 80 corresponding angles

m( ABC) = 800

Page 27: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 27

B) m( DEF)

(2x-45)0 = (x+30)0 corresponding angles

m( DEF) = (x+30)0

(2x-45)0

EF

D

(x+30)0

x – 45 = 30 subtract x from both sides

x = 75 add 45 to both sides

= (75+30)0

= 1050

Page 28: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 28

Alternate interior angles theoremAlternate interior angles theorem

If two parallel lines are cut by a transversal, then the two pairs of Alternate interior angles are congruent.

1 3 2 4

1 2

4 3

Theorem

Hypothesis Conclusion

Page 29: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 29

Alternate exterior angles theoremAlternate exterior angles theorem

If two parallel lines are cut by a transversal, then the two pairs of Alternate exterior angles are congruent.

5 7 6 8

5 6

8 7

Theorem

Hypothesis Conclusion

Page 30: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 30

Same-side interior angles theoremSame-side interior angles theorem

If two parallel lines are cut by a transversal, then the two pairs of Same-side interior angles are supplementary.

m 1 + m 4 =1800 m 2 + m 3 =1800

Theorem

Hypothesis Conclusion

1 2

4 3

Page 31: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 31

Alternate interior angles theoremAlternate interior angles theorem

1 2

3m

lGiven: l || m

Prove: 2 3

Proof:

1 3l || m

Given Corresponding angles

2 3

2 1

Vertically opposite angles

Page 32: CONFIDENTIAL 1 Geometry Angles formed by Parallel Lines and Transversals.

CONFIDENTIAL 32

You did a great job You did a great job today!today!


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