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Constraint Satisfaction Problems Chapter 6 TB Artificial Intelligence Slides from AIMA — http://aima.cs.berkeley.edu 1 / 31
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Page 1: Constraint Satisfaction Problems - Chapter 6

Constraint Satisfaction ProblemsChapter 6

TB Artificial Intelligence

Slides from AIMA — http://aima.cs.berkeley.edu

1 / 31

Page 2: Constraint Satisfaction Problems - Chapter 6

Outline

I CSP examplesI Backtracking search for CSPsI Problem structure and problem decompositionI Local search for CSPs

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Page 3: Constraint Satisfaction Problems - Chapter 6

Constraint satisfaction problems (CSPs)

I Standard search problem: state is a “black box”—any old data structure that supports goaltest, eval, successor

I CSP:I state is defined by variables XiI with values from domain DiI goal test is a set of constraints specifying allowable combinations of values for subsets of

variables

I Simple example of a formal representation languageI Allows useful general-purpose algorithms with more power

than standard search algorithms

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Page 4: Constraint Satisfaction Problems - Chapter 6

Example: Map-Coloring

WesternAustralia

NorthernTerritory

SouthAustralia

Queensland

New South Wales

Victoria

TasmaniaI Variables WA, NT , Q, NSW , V , SA, TI Domains Di = {red , green, blue}I Constraints: adjacent regions must have different colors, e.g., WA 6= NT (if the language

allows this), or (WA,NT ) ∈ {(red , green), (red , blue), (green, red), (green, blue), . . .}

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Page 5: Constraint Satisfaction Problems - Chapter 6

Example: Map-Coloring contd.

WesternAustralia

NorthernTerritory

SouthAustralia

Queensland

New South Wales

Victoria

Tasmania

I Solutions are assignments satisfying all constraints, e.g.,{WA= red ,NT = green,Q = red ,NSW = green,V = red ,SA= blue,T = green}

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Page 6: Constraint Satisfaction Problems - Chapter 6

Constraint graph

I Binary CSP: each constraint relates at most two variablesI Constraint graph: nodes are variables, arcs show constraints

Victoria

WA

NT

SA

Q

NSW

V

T

General-purpose CSP algorithms use the graph structure to speed up search. E.g., Tasmania isan independent subproblem!

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Page 7: Constraint Satisfaction Problems - Chapter 6

Varieties of CSPs

I Discrete variablesI finite domains; size d =⇒ O(dn) complete assignments

I e.g., Boolean CSPs, incl. Boolean satisfiability (NP-complete)I infinite domains (integers, strings, etc.)

I e.g., job scheduling, variables are start/end days for each jobI need a constraint language, e.g., StartJob1 + 5 ≤ StartJob3I linear constraints solvable, nonlinear undecidable

I Continuous variablesI e.g., start/end times for Hubble Telescope observationsI linear constraints solvable in poly time by LP methods

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Page 8: Constraint Satisfaction Problems - Chapter 6

Varieties of constraints

I Unary constraints involve a single variablee.g., SA 6= green

I Binary constraints involve pairs of variablese.g., SA 6= WA

I Higher-order constraints involve 3 or more variablese.g., cryptarithmetic column constraints

I Preferences (soft constraints)e.g., red is better than greenoften representable by a cost for each variable assignment→ constrained optimization problems

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Page 9: Constraint Satisfaction Problems - Chapter 6

Example: Cryptarithmetic

OWTF U R

+OWTOWT

F O U R

X2 X1X3

I Variables: F T U W R O X1 X2 X3

I Domains: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}I Constraints

alldiff(F ,T ,U,W ,R,O)O +O = R + 10 · X1

. . .9 / 31

Page 10: Constraint Satisfaction Problems - Chapter 6

Real-world CSPs

I Assignment problemse.g., who teaches what class

I Timetabling problemse.g., which class is offered when and where?

I Hardware configurationI SpreadsheetsI Transportation schedulingI Factory schedulingI FloorplanningI . . .

Notice that many real-world problems involve real-valued variables

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Page 11: Constraint Satisfaction Problems - Chapter 6

Standard search formulation (incremental)

Let’s start with the straightforward, dumb approach, then fix it

States are defined by the values assigned so far

I Initial state: the empty assignment, { }I Successor function: assign a value to an unassigned variable that does not conflict with

current assignment =⇒ fail if no legal assignments (not fixable!)I Goal test: the current assignment is complete

1. This is the same for all CSPs!

2. Every solution appears at depth n with n variables =⇒ use depth-first search

3. Path is irrelevant, so can also use complete-state formulation

4. b=(n − `)d at depth `, hence n!dn leaves!!!!

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Page 12: Constraint Satisfaction Problems - Chapter 6

Backtracking search

I Variable assignments are commutative, i.e.,[WA= red then NT = green] same as [NT = green then WA= red ]

I Only need to consider assignments to a single variable at each node=⇒ b= d and there are dn leaves

I Depth-first search for CSPs with single-variable assignments is called backtracking searchI Backtracking search is the basic uninformed algorithm for CSPsI Can solve n-queens for n ≈ 25

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Page 13: Constraint Satisfaction Problems - Chapter 6

Backtracking search

function Backtracking-Search(csp) returns solution/failurereturn Recursive-Backtracking({ }, csp)

function Recursive-Backtracking(assignment, csp) returns soln/failureif assignment is complete then return assignmentvar←Select-Unassigned-Variable(Variables[csp], assignment, csp)for each value in Order-Domain-Values(var, assignment, csp) do

if value is consistent with assignment given Constraints[csp] thenadd {var = value} to assignmentresult←Recursive-Backtracking(assignment, csp)if result 6= failure then return resultremove {var = value} from assignment

return failure

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Page 14: Constraint Satisfaction Problems - Chapter 6

Backtracking example

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Page 15: Constraint Satisfaction Problems - Chapter 6

Backtracking example

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Page 16: Constraint Satisfaction Problems - Chapter 6

Backtracking example

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Page 17: Constraint Satisfaction Problems - Chapter 6

Backtracking example

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Page 18: Constraint Satisfaction Problems - Chapter 6

Improving backtracking efficiency

General-purpose methods can give huge gains in speed:

1. Which variable should be assigned next?

2. In what order should its values be tried?

3. Can we detect inevitable failure early?

4. Can we take advantage of problem structure?

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Page 19: Constraint Satisfaction Problems - Chapter 6

Minimum remaining values

Minimum remaining values (MRV):choose the variable with the fewest legal values

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Page 20: Constraint Satisfaction Problems - Chapter 6

Degree heuristic

Tie-breaker among MRV variables

Degree heuristic:choose the variable with the most constraints on remaining variables

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Page 21: Constraint Satisfaction Problems - Chapter 6

Least constraining value

Given a variable, choose the least constraining value:the one that rules out the fewest values in the remaining variables

Allows 1 value for SA

Allows 0 values for SA

Combining these heuristics makes 1000 queens feasible

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Page 22: Constraint Satisfaction Problems - Chapter 6

Forward checking

Idea: Keep track of remaining legal values for unassigned variables

Terminate search when any variable has no legal values

WA NT Q NSW V SA T

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Page 23: Constraint Satisfaction Problems - Chapter 6

Forward checking

Idea: Keep track of remaining legal values for unassigned variables

Terminate search when any variable has no legal values

WA NT Q NSW V SA T

19 / 31

Page 24: Constraint Satisfaction Problems - Chapter 6

Forward checking

Idea: Keep track of remaining legal values for unassigned variables

Terminate search when any variable has no legal values

WA NT Q NSW V SA T

19 / 31

Page 25: Constraint Satisfaction Problems - Chapter 6

Forward checking

Idea: Keep track of remaining legal values for unassigned variables

Terminate search when any variable has no legal values

WA NT Q NSW V SA T

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Page 26: Constraint Satisfaction Problems - Chapter 6

Constraint propagation

Forward checking propagates information from assigned to unassigned variables, but doesn’tprovide early detection for all failures:

WA NT Q NSW V SA T

NT and SA cannot both be blue!

Constraint propagation repeatedly enforces constraints locally

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Page 27: Constraint Satisfaction Problems - Chapter 6

Arc consistency

Simplest form of propagation makes each arc consistent

X → Y is consistent iff for every value x of X there is some allowed y

WA NT Q NSW V SA T

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Page 28: Constraint Satisfaction Problems - Chapter 6

Arc consistency

Simplest form of propagation makes each arc consistent

X → Y is consistent iff for every value x of X there is some allowed y

WA NT Q NSW V SA T

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Page 29: Constraint Satisfaction Problems - Chapter 6

Arc consistency

Simplest form of propagation makes each arc consistent

X → Y is consistent iff for every value x of X there is some allowed y

WA NT Q NSW V SA T

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Page 30: Constraint Satisfaction Problems - Chapter 6

Arc consistency

Simplest form of propagation makes each arc consistent

X → Y is consistent iff for every value x of X there is some allowed y

WA NT Q NSW V SA T

I If X loses a value, neighbors of X need to be rechecked

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Page 31: Constraint Satisfaction Problems - Chapter 6

Arc consistency

Simplest form of propagation makes each arc consistent

X → Y is consistent iff for every value x of X there is some allowed y

WA NT Q NSW V SA T

I If X loses a value, neighbors of X need to be rechecked

I Arc consistency detects failure earlier than forward checkingI Can be run as a preprocessor or after each assignment

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Page 32: Constraint Satisfaction Problems - Chapter 6

Arc consistency algorithm

function AC-3( csp) returns the CSP, possibly with reduced domainsinputs: csp, a binary CSP with variables {X1, X2, . . . , Xn}local variables: queue, a queue of arcs, initially all the arcs in csp

while queue is not empty do(Xi , Xj )←Remove-First(queue)if Remove-Inconsistent-Values(Xi , Xj ) then

for each Xk in Neighbors[Xi ] doadd (Xk , Xi ) to queue

function Remove-Inconsistent-Values(Xi , Xj ) returns true iff succeedsremoved← falsefor each x in Domain[Xi ] do

if no value y in Domain[Xj ] allows (x,y) to satisfy the constraint Xi ↔ Xjthen delete x from Domain[Xi ]; removed← true

return removed

O(n2d3), can be reduced to O(n2d2) (but detecting all is NP-hard)

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Page 33: Constraint Satisfaction Problems - Chapter 6

Problem structure

Victoria

WA

NT

SA

Q

NSW

V

T

I Tasmania and mainland are independent subproblemsI Identifiable as connected components of constraint graph

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Page 34: Constraint Satisfaction Problems - Chapter 6

Problem structure contd.

I Suppose each subproblem has c variables out of n totalI Worst-case solution cost is n/c · dc , linear in nI E.g., n= 80, d = 2, c = 20

I 280 = 4 billion years at 10 million nodes/secI 4 · 220 = 0.4 seconds at 10 million nodes/sec

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Page 35: Constraint Satisfaction Problems - Chapter 6

Tree-structured CSPs

A

B

C

D

E

FTheoremIf the constraint graph has no loops, the CSP can be solved in O(n d2) time

I Compare to general CSPs, where worst-case time is O(dn)

I This property also applies to logical and probabilistic reasoning: an important example of therelation between syntactic restrictions and the complexity of reasoning.

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Page 36: Constraint Satisfaction Problems - Chapter 6

Algorithm for tree-structured CSPs

1. Choose a variable as root, order variables from root to leaves such that every node’s parentprecedes it in the ordering

A

B

C

D

E

F

A B C D E F

2. For j from n down to 2, apply RemoveInconsistent(Parent(Xj ),Xj)

3. For j from 1 to n, assign Xj consistently with Parent(Xj)

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Page 37: Constraint Satisfaction Problems - Chapter 6

Nearly tree-structured CSPs

Conditioning: instantiate a variable, prune its neighbors’ domains

Victoria

WA

NTQ

NSW

V

TT

Victoria

WA

NT

SA

Q

NSW

V

Cutset conditioning: instantiate (in all ways) a set of variablessuch that the remaining constraint graph is a tree

Cutset size c =⇒ runtime O(dc · (n − c)d2), very fast for small c

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Page 38: Constraint Satisfaction Problems - Chapter 6

Iterative algorithms for CSPs

Hill-climbing, simulated annealing typically work with“complete” states, i.e., all variables assigned

To apply to CSPs:

I Allow states with unsatisfied constraintsI Operators reassign variable valuesI Variable selection: randomly select any conflicted variableI Value selection by min-conflicts heuristic: choose value that violates the fewest constraints

I i.e., hillclimb with h(n) = total number of violated constraints

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Page 39: Constraint Satisfaction Problems - Chapter 6

Example: 4-Queens

I States: 4 queens in 4 columns (44 = 256 states)I Operators: move queen in columnI Goal test: no attacksI Evaluation: h(n) = number of attacks

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Page 40: Constraint Satisfaction Problems - Chapter 6

Performance of min-conflictsGiven random initial state, can solve n-queens in almost constant time for arbitrary n with highprobability (e.g., n = 10,000,000)

The same appears to be true for any randomly-generated CSPexcept in a narrow range of the ratio

R =number of constraintsnumber of variables

R

CPUtime

critical ratio

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Page 41: Constraint Satisfaction Problems - Chapter 6

Summary

I CSPs are a special kind of problem: states defined by values of a fixed set of variables goaltest defined by constraints on variable values

I Backtracking = depth-first search with one variable assigned per nodeI Variable ordering and value selection heuristics help significantlyI Forward checking prevents assignments that guarantee later failureI Constraint propagation (e.g., arc consistency) does additional work to constrain values and

detect inconsistenciesI The CSP representation allows analysis of problem structureI Tree-structured CSPs can be solved in linear timeI Iterative min-conflicts is usually effective in practice

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