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Arthur CHARPENTIER - Analyse des donnees
Analyse des donnees (1)
L’Analyse en Composantes Principales
Arthur Charpentier
http ://perso.univ-rennes1.fr/arthur.charpentier/
blog.univ-rennes1.fr/arthur.charpentier/
Master 2, Universite Rennes 1
1
Arthur CHARPENTIER - Analyse des donnees
Introduction a l’analyse des donnees
Dans ce cours, nous verrrons essentiellement deux types de methodes• les methodes factorielles, ou on cherchera a reduire le nombre de variables en
les resumant en un petit nombre de composantes synthetiques◦ en particulier l’ACP, Analyse en Composantes Principales si les variables
sont quantitatives◦ en particulier l’AC, Analyse des Correspondances si les variables sont
qualitatives, ou on cherchera les liens entre les modalites, avec l’ACFAnalyse des Correspondances Factorielles (simples) dans le cas ou on disposede 2 variables, et l’ACM Analyse des Correspondances Multiples dans le casou on dispose de plus de 2 variables
2
Arthur CHARPENTIER - Analyse des donnees
Introduction a l’analyse des donnees
• les methodes de classification, ou on cherchera a reduire la taille de l’ensembledes individus en les regroupant en un petit nombre de groupes homogenes
◦ en particulier la CAH, Classification Ascendante Hierarchique ...◦ en particulier l’Analyse Discriminante ...
Remarque Ce cours est davantage un cours d’algebre lineaire qu’un cours deprobabilite ou de statistique. Mais une interpretation sera parfois possible enterme de moyenne ou de variance (voire de covariance).
3
Arthur CHARPENTIER - Analyse des donnees
Exemple, ville et (in)securite
“Le palmares des departements : ou vit-on en securite ?, dans L’Express (no2589, 15 fevrier 2001)
• infra Nombre d’infractions totale pour 1000 habitants (2000)• vvi Nombre de vols avec violance pour 1000 habitants (2000)• auto Nombre de vols d’automobiles pour 1000 habitants (2000)
> add=read.table("http://perso.univ-rennes1.fr/arthur.charpentier/securite.txt",header=TRUE)
> base=add[,2:ncol(add)]
> rownames(base)=add$dep
> base=base[,c(1,6,9)]
> head(base)
infra vvi auto
D1 44.11 0.27 4.47
D2 45.97 0.55 4.39
D3 38.83 0.41 2.39
D4 49.68 0.21 4.17
D5 47.67 0.33 2.35
D6 109.21 4.10 8.83
4
Arthur CHARPENTIER - Analyse des donnees
Exemple, ville et (in)securite
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20 40 60 80 100 120 140
02
46
810
infractions
vols
ave
c vi
olen
ce
20 40 60 80 100 120 140
0 2
4 6
810
1214
0 2
4 6
810
infractions
vols
ave
c vi
olen
ce
vols
aut
omob
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5
Arthur CHARPENTIER - Analyse des donnees
Exemple, ville et (in)securite
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20 40 60 80 100 120 140
02
46
810
1214
infractions
vols
aut
omob
ile
20 40 60 80 100 120 140
0 2
4 6
810
1214
0 2
4 6
810
infractions
vols
ave
c vi
olen
ce
vols
aut
omob
ile
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6
Arthur CHARPENTIER - Analyse des donnees
Exemple, ville et (in)securite
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0 2 4 6 8 10
02
46
810
1214
vols avec violence
vols
aut
omob
ile
20 40 60 80 100 120 140
0 2
4 6
810
1214
0 2
4 6
810
infractions
vols
ave
c vi
olen
ce
vols
aut
omob
ile
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7
Arthur CHARPENTIER - Analyse des donnees
Exemple, ville et (in)securite
Les variables semblent plutot correlees positivement,
> cor(base)
infra vvi auto
infra 1.0000000 0.8583172 0.7808855
vvi 0.8583172 1.0000000 0.5032206
auto 0.7808855 0.5032206 1.0000000
Supposons que l’on cherche a regrouper les villes “proches”.
=⇒ Comme on a du mal a voir dans R3, on va essayer de projeter le nuage.
• projection sur un axe (droite)• projection sur un plan
8
Arthur CHARPENTIER - Analyse des donnees
Exemple, ville et (in)securite
20 40 60 80 100 120 140
0 2
4 6
810
1214
0 2
4 6
810
infractions
vols
ave
c vi
olen
ce
vols
aut
omob
ile
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9
Arthur CHARPENTIER - Analyse des donnees
Exemple, ville et (in)securite
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10
Arthur CHARPENTIER - Analyse des donnees
Exemple, ville et (in)securite
20 40 60 80 100 120 140
0 2
4 6
810
1214
0 2
4 6
810
infractions
vols
ave
c vi
olen
ce
vols
aut
omob
ile
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=⇒ recherche de la projection “la plus representative”, cf. idee des moindrescarres, qui minimise l’erreur de projection comise
11
Arthur CHARPENTIER - Analyse des donnees
Exemple, ville et (in)securite
Pourquoi pas projecter sur un plan ?
20 40 60 80 100 120 140
0 2
4 6
810
1214
0 2
4 6
810
infractions
vols
ave
c vi
olen
ce
vols
aut
omob
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12
Arthur CHARPENTIER - Analyse des donnees
Exemple, ville et (in)securite
Peut-etre faut-il normer les axes pour les rendre comparable ?
−2 −1 0 1 2 3 4 5
−2−1
0 1
2 3
−1 0
1 2
3 4
5 6
7
infractions
vols
ave
c vi
olen
ce
vols
aut
omob
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−2 −1 0 1 2 3 4 5
−2−1
0 1
2 3
−1 0
1 2
3 4
5 6
7
infractions
vols
ave
c vi
olen
ce
vols
aut
omob
ile
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13
Arthur CHARPENTIER - Analyse des donnees
Analyse de la “meilleur” projection d = 2
D1 D2
D3
D4
D5
D6
D7 D8 D9
D10
D11
D12
D13
D14 D15
D16
D17
D18 D19 D21
D22 D23
D24 D25
D26
D27
D28 D29
D30
D31
D32
D33
D34
D35
D36 D37
D38
D39 D40
D41
D42
D43
D44
D45
D46 D47
D48
D49
D50
D51
D52 D53 D54
D55 D56 D57 D58
D59
D60
D61
D62 D63 D64 D65
D66
D67 D68
D69
D70 D71
D72
D73 D74
D75
D76
D77
D78 D79 D80 D81
D82 D83
D84
D85 D86 D87
D88
D89
D90
D91
D92
D93
D94
D95
14
Arthur CHARPENTIER - Analyse des donnees
Analyse de la “meilleur” projection d = 2
40] 60] 80] 100] 120]
D1D2
D3
D4
D5
D6
D7D8D9
D10
D11
D12
D13
D14D15
D16
D17
D18D19 D21
D22D23
D24D25
D26
D27
D28D29
D30
D31
D32
D33
D34
D35
D36 D37
D38
D39 D40
D41
D42
D43
D44
D45
D46
D47
D48
D49
D50
D51
D52D53 D54
D55D56
D57D58D59
D60
D61
D62D63 D64D65
D66
D67D68
D69
D70D71
D72
D73D74
D75
D76
D77
D78D79 D80
D81
D82 D83
D84
D85D86
D87D88
D89
D90
D91
D92
D93
D94
D95
Infractions (total)
d = 2
40] 60] 80] 100] 120]
D1D2
D3
D4
D5
D6
D7D8D9
D10
D11
D12
D13
D14D15
D16
D17
D18D19 D21
D22D23
D24D25
D26
D27
D28D29
D30
D31
D32
D33
D34
D35
D36 D37
D38
D39 D40
D41
D42
D43
D44
D45
D46
D47
D48
D49
D50
D51
D52D53 D54
D55D56
D57D58D59
D60
D61
D62D63 D64D65
D66
D67D68
D69
D70D71
D72
D73D74
D75
D76
D77
D78D79 D80
D81
D82 D83
D84
D85D86
D87D88
D89
D90
D91
D92
D93
D94
D95●
Infractions (total)
15
Arthur CHARPENTIER - Analyse des donnees
Analyse de la “meilleur” projection d = 2
2] 4] 6] 8]
D1D2
D3
D4
D5
D6
D7D8D9
D10
D11
D12
D13
D14D15
D16
D17
D18D19 D21
D22D23
D24D25
D26
D27
D28D29
D30
D31
D32
D33
D34
D35
D36 D37
D38
D39 D40
D41
D42
D43
D44
D45
D46
D47
D48
D49
D50
D51
D52D53 D54
D55D56
D57D58D59
D60
D61
D62D63 D64D65
D66
D67D68
D69
D70D71
D72
D73D74
D75
D76
D77
D78D79 D80
D81
D82 D83
D84
D85D86
D87D88
D89
D90
D91
D92
D93
D94
D95
Vols avec violence
d = 2
2] 4] 6] 8]
D1D2
D3
D4
D5
D6
D7D8D9
D10
D11
D12
D13
D14D15
D16
D17
D18D19 D21
D22D23
D24D25
D26
D27
D28D29
D30
D31
D32
D33
D34
D35
D36 D37
D38
D39 D40
D41
D42
D43
D44
D45
D46
D47
D48
D49
D50
D51
D52D53 D54
D55D56
D57D58D59
D60
D61
D62D63 D64D65
D66
D67D68
D69
D70D71
D72
D73D74
D75
D76
D77
D78D79 D80
D81
D82 D83
D84
D85D86
D87D88
D89
D90
D91
D92
D93
D94
D95
●
Vols avec violence
16
Arthur CHARPENTIER - Analyse des donnees
Analyse de la “meilleur” projection d = 2
2] 4] 6] 8] 10] 12]
D1D2
D3
D4
D5
D6
D7D8D9
D10
D11
D12
D13
D14D15
D16
D17
D18D19 D21
D22D23
D24D25
D26
D27
D28D29
D30
D31
D32
D33
D34
D35
D36 D37
D38
D39 D40
D41
D42
D43
D44
D45
D46
D47
D48
D49
D50
D51
D52D53 D54
D55D56
D57D58D59
D60
D61
D62D63 D64D65
D66
D67D68
D69
D70D71
D72
D73D74
D75
D76
D77
D78D79 D80
D81
D82 D83
D84
D85D86
D87D88
D89
D90
D91
D92
D93
D94
D95
Vols d'automobiles
d = 2
2] 4] 6] 8] 10] 12]
D1D2
D3
D4
D5
D6
D7D8D9
D10
D11
D12
D13
D14D15
D16
D17
D18D19 D21
D22D23
D24D25
D26
D27
D28D29
D30
D31
D32
D33
D34
D35
D36 D37
D38
D39 D40
D41
D42
D43
D44
D45
D46
D47
D48
D49
D50
D51
D52D53 D54
D55D56
D57D58D59
D60
D61
D62D63 D64D65
D66
D67D68
D69
D70D71
D72
D73D74
D75
D76
D77
D78D79 D80
D81
D82 D83
D84
D85D86
D87D88
D89
D90
D91
D92
D93
D94
D95
●
Vols d'automobiles
17
Arthur CHARPENTIER - Analyse des donnees
Un peu de geometrie euclidienne
On observe n individus, et q variables (quantitatives, sur R).
Les nuages de points peuvent se decomposer de deux manieres,– l’espace des individus, i.e. Rq
– l’espace des variables, i.e. Rn
On note xij l’observation de la jeme variable sur le ieme individu.
variables
1 · · · j · · · q
individus 1 x11 · · · x1j · · · x1q
......
......
i xi1 · · · xij · · · xiq
......
......
n xn1 · · · xnj · · · xnq
18
Arthur CHARPENTIER - Analyse des donnees
Un peu de geometrie euclidienne
Chaque individu est characterise par Li = (xi1, · · · , xiq)t, appartenant a Rq,exprime dans la base canonique {e1, · · · , eq}.Definition 1. Les points individus dans l’espace vectoriel Rq, munie de{e1, · · · , eq} est appele espace des individus.
=⇒ comment mesurer la distance entre deux individus ?
19
Arthur CHARPENTIER - Analyse des donnees
Distance entre individusDefinition 2. Soit D une matrice diagonale q × q, dont les elements diagonauxsont strictement positifs (dii > 0 pour i = 1, · · · , q). Alors la fonctionϕ : Rq × Rq 7→ R definie par
(u,v)→ utDv =q∑
j=1
djjujvj
est un produit scalaire, note < ·, · >D.Definition 3. Soit D une telle matrice diagonale q × q, et < ·, · >D le produitscalaire associe. On note alors ‖ · ‖D la norme associee,
‖u‖D =√< u,u >D =
q∑j=1
djjujuj
et dD(·, ·) la distance associee,
dD(u,v) = ‖u− v‖D.
20
Arthur CHARPENTIER - Analyse des donnees
Exemples de produits scalaires
• D = Id correspond au produit scalaire canonique, < u,v >Id=q∑
j=1
ujvj
• Considerons le produit scalaire associe a D =
3/4 0
0 1/4
Les points a egale distance de l’origine 0 sont les points M = (x, y) ∈ R2 tels que
‖0M‖D = α > 0, i.e.34x2 +
14y2 = α,
c’est a dire une ellipse dans R2.
21
Arthur CHARPENTIER - Analyse des donnees
Deformation de l’espace
−2 −1 0 1 2
−2
−1
01
2
Produit scalaire canonique, Id
●
−2 −1 0 1 2−
2−
10
12
Produit scalaire associé à la matrice D
●
22
Arthur CHARPENTIER - Analyse des donnees
Les metriques usuelles
Il y a fondamentalement trois types de metriques a retenir,
• la metrique usuelle i.e. M = I, la matrice identie
Dans ce cas, la distance depend de l’unite de mesure, et de la dispersion desvariables.
• la metrique reduite i.e. M = diag(s−21 , · · · , s−2
q ), la matrice diagonale desinverses des variances empiriques
Rappelons que pour une serie d’observations {x1, · · · , xq}, la moyenne(empirique) est
mx = x =1n
n∑i=1
xi
et que la variance (empirique) est
s2x =1n
n∑i=1
(xi − x)2 =1n
n∑i=1
x2i − x2.
23
Arthur CHARPENTIER - Analyse des donnees
Enfin, rappelons que la covariance entre x et y est
sxy =1n
n∑i=1
(xi − x)(yi − y) =1n
n∑i=1
xiyi − xy.
On appele correlation (au sens de Pearson) la grandeur
rxy =sxy
sxsy=
∑ni=1(xi − x)(yi − y)√∑n
i=1(xi − x)2 ·∑n
i=1(yi − y)2.
• la metrique transformee i.e. M = T ′T ,
Cela est equivalent a travailler avec la metrique classique I sur le tableautransformee XT ′.
Notons que pour toute matrice symmetrique positive M , il existe une tellematrice T , appele racine carree de M
24
Arthur CHARPENTIER - Analyse des donnees
Deformation de l’espace
Proposition 4. Munir l’espace de la metrique issue de D q × q, diagonale, estequivalent a attribuer des poids {
√d11, · · · ,
√dqq} aux q variables et d’utiliser la
metrique canonique.
Demonstration. Pour tout u,v ∈ Rq,
< u,v >D= utDv =q∑
j=1
djjujvj =q∑
j=1
(√djjuj
)(√djjvj
)soit < u,v >D=< u, v >Id ou u = (u1, · · · , uq), uj =
√djjuj .
25
Arthur CHARPENTIER - Analyse des donnees
Les variables, cas de la dimension 2
On cherche ici a mesurer une distance, ou une proximite, entre des variables.Intuitivement, cette notion doit etre proche de la notion de correlation.
Soient deux variables X1 et X2 continues.
Remarque La regression propose d’etudier le lien entre deux variables, dansl’optique d’en utiliser une pour prevoir l’autre.
26
Arthur CHARPENTIER - Analyse des donnees
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Ici, on s’interesse davantage a des projections (orthogonales). On parlera alors dedirection principal du nuage.
27
Arthur CHARPENTIER - Analyse des donnees
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On peut montrer que cet axe passe par le centre de gravite du nuage (comme lesdeux autres regressions).
Changeons les coordonnees pour simplifier, Y1 = X1 −X1 et Y2 = X2 −X2. Onnotera O ce barycentre, X les points d’origine et P les projections
28
Arthur CHARPENTIER - Analyse des donnees
orthongonales. On cherche a minimiser
I =n∑
i=1
‖XiPi‖2 =n∑
i=1
‖OiXi‖2 − ‖OiPi‖2 (qu’on appelera inertie),
par des proprietes d’orthogonalite. Les points O et X etant fixer, si u est levecteur directeur de l’axe, u = (a, b), suppose unitaire, minimiser I devient amaximiser
I2 =n∑
i=1
‖OiPi‖2 = (Y u)′Y Y uu′(Y ′Y )uu′(nΣ)u
ou Σ correspond a la matrice de variance-covariance de Y (et donc de X).
Σ est symmetrique, elle possede toujours deux valeurs propres, et deux vecteurspropres, et
Σ = UΛU ′ =
u1,1 u1,2
u2,1 u2,2
λ1 0
0 λ2
u1,1 u1,2
u2,1 u2,2
′
29
Arthur CHARPENTIER - Analyse des donnees
ou U est une matrice othonormee. Aussi,
I2 = λ1α2 + λ2β
2 ≤ max{λ1, λ2} [α2 + β2]︸ ︷︷ ︸=1
,
ou (α, β) sont les nouvelles coordonees de u.
L’inertie ne peut donc depasser la plus grande valeur propre (on supposera quec’est λ1), et elle atteint cette valeur lorsque u est le premier vecteur propre.
=⇒ l’axe principal d’un nuage de points bivarie est le vecteur propre associe a laplus grande valeur propre de la matrice de variance-covariance des deux variables.
Ce resultat va se generaliser en plus grande dimension.
30
Arthur CHARPENTIER - Analyse des donnees
L’espace des variables
De la meme maniere, chaque variable est characterise par Cj = (x1j , · · · , xnj)t,appartenant a Rn, exprime dans la base canonique {f1, · · · , fn}.
Generalement, dans l’espace des variables, un poids identique sera donne achaque individu.
31
Arthur CHARPENTIER - Analyse des donnees
Projeter un nuage de points
32
Arthur CHARPENTIER - Analyse des donnees
Sous R, on peut utiliser le code suivant
> library(mnormt);library(rgl)
> mu <- c(0,0,0)
> Sigma <- matrix(c(1,0.5,0.4,0.5,1,-0.5,0.4,-0.5,1), 3, 3)
> Z <- rmnorm(80, mu, Sigma)
> plot3d(Z,type="s",col="blue")
> plot3d(ellipse3d(cor(Z)),col="light green",alpha=0.5,add=TRUE)
=⇒ la recherche d’axes principaux est lie a la recherche des axes de l’ellipse.
33
Arthur CHARPENTIER - Analyse des donnees
Projeter un nuage de points
Attention des points proches dans Rk ont des projections proches, mais deuxpoints dont les projections sont proches ne sont pas necessairement proches.
34
Arthur CHARPENTIER - Analyse des donnees
Projeter des points, la notion d’inertie
Considerons le tableau de donnees X = (xij)1≤i≤n,1≤j≤q = {L1, · · · , Ln}.
L’espace individus (de Rq) est muni de la metrique issue D.
Definition 5. On appelle inertie du nuage des points {L1, · · · , Ln} la quantite
I(X, D) =n∑
i=1
di‖Li‖2D =n∑
i=1
q∑j=1
diDjjx2ij
=⇒ on cherche des axes ou des plans de projections telle que l’intertie soitmaximale.
35
Arthur CHARPENTIER - Analyse des donnees
Projection sur un plan
Plan de projection, en dimension 3
0 1 2 3 4 5 6
01
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45
6
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12
34
56
Projection sur le plan
●
36
Arthur CHARPENTIER - Analyse des donnees
Projection sur un plan
Plan de projection, en dimension 3
0 1 2 3 4 5 6
01
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56
Projection sur le plan
●
37
Arthur CHARPENTIER - Analyse des donnees
Projection sur un plan
Plan de projection, en dimension 3
0 1 2 3 4 5 6
01
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12
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56
Projection sur le plan
●
38
Arthur CHARPENTIER - Analyse des donnees
Projection sur un plan
Plan de projection, en dimension 3
0 1 2 3 4 5 6
01
23
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12
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56
Projection sur le plan
●
39
Arthur CHARPENTIER - Analyse des donnees
Projection sur un plan
Plan de projection, en dimension 3
0 1 2 3 4 5 6
01
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6
01
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6
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12
34
56
Projection sur le plan
●
40
Arthur CHARPENTIER - Analyse des donnees
Projection sur un plan
Plan de projection, en dimension 3
0 1 2 3 4 5 6
01
23
45
6
01
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45
6
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34
56
Projection sur le plan
●
41
Arthur CHARPENTIER - Analyse des donnees
Projection sur un plan
Plan de projection, en dimension 3
0 1 2 3 4 5 6
01
23
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6
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12
34
56
Projection sur le plan
●
42
Arthur CHARPENTIER - Analyse des donnees
L’inertie expliquee par un axe
Considerons le tableau de donnees X = (xij)1≤i≤n,1≤j≤q = {L1, · · · , Ln}.
L’espace individus (de Rq) est muni de la metrique issue D.
Definition 6. Soit u ∈ Rq. On appelle inertie du nuage des points {L1, · · · , Ln}expliquee par l’axe u la quantite I(X,u, D) correspondant a l’intertie du nuageprojecte orthogonalement sur u (pour < ·, · >D).
D’apres le theoreme de Pytaghore
inertie totale ≥ inertie expliquee par l’axe u.
Considerons le cas de la projection de R2 sur un axe u.
43
Arthur CHARPENTIER - Analyse des donnees
Le (premier) axe principal
Considerons le tableau de donnees X = (xij)1≤i≤n,1≤j≤q = {L1, · · · , Ln}.
L’espace individus (de Rq) est muni de la metrique issue D.Definition 7. L’axe principal, ou premier axe principal, pour un nuaged’individus {L1, · · · , Ln} est un vecteur unitaire u? ∈ Rq qui maximise l’inertieI(X,u, D) (pour < ·, · >D).
On cherche alors
u? = argmax{u′DX ′XDu}, avec ‖u‖D = 1.
Ce probleme est equivalent a chercher v? = D1/2u qui maximize
v? = argmax{v′D1/2X ′XD1/2v}, avec ‖v‖ = 1. (1)
la derniere norme etant la norme euclidienne.Proposition 8. Le vecteur unitaire v? ∈ Rq solution de ?? est le vecteur propreassocie a la plus grande valeur propre de la matrice (XD1/2)′(XD1/2).
44
Arthur CHARPENTIER - Analyse des donnees
Demonstration. v? est necessaire un vecteur propre car (utilisation duLagrangien pour determiner l’optimum)
(XD1/2)′(XD1/2)v? − λv? = 0.
Rappelons que (XD1/2)′(XD1/2) est diagonalisable dans une base orthonomee(car symmetrique reelle). Soient λ1 > · · · > λk toutes les valeurs propres, i.e.(XD1/2)′(XD1/2)vk = λkvk. Comme on cherche a maximiserv′D1/2X ′XD1/2v, c’est que v? = v1.
Corollaire 9. Le vecteur D-unitaire u? = u1 ∈ Rq maximisant I(X,u, D) estdefini de mani‘ere unique (au signe pres) par u? = D−1/2v1 ou v1 est le vecteurpropre associe a la plus grande valeur propre de la matrice (XD1/2)′(XD1/2). Etl’inertie expliquee par cet axe vaut alors λ1.
45
Arthur CHARPENTIER - Analyse des donnees
Un resultat d’algebre lineaire
Proposition 10. On a equivalence entre les resultats suivants• Si Ek est le sous-espace de dimension k portant l’inertie principale, alors
Ek+1 = Ek ⊕ uk+1
ou uk+1 est l’axe (espace de dimension 1) D-orthogonal a Ek portant l’inertiemaximale.
• Ek est engendre par les k vecteurs propres de (XD1/2)′(XD1/2) associes aux kplus grandes valeurs propres.
Aussi, l’ACP sur k+ 1 variables est obtenue par ajout d’une composante d’inertiemaximale a l’ACP sur k variable. C’est un mechanisme iteratif, il est inutile derefaire tourner des algorithmes.
46
Arthur CHARPENTIER - Analyse des donnees
Les autres axes principaux
Le 2eme axe principal est• un axe orthogonal a u1 pour < ·, · >D
• maximisant l’inertieEn fait, u2 = D−1/2v2 ou v2 est le vecteur propre associe a la plus secondegrande valeur propre de la matrice (XD1/2)′(XD1/2). Et l’inertie expliquee parcet axe vaut alors λ2.
Rappelons que < u1,u2 >D=< v1,v2 >D= 0.
47
Arthur CHARPENTIER - Analyse des donnees
Les autres axes principaux
De maniere plus generale, le keme axe principal est• un axe orthogonal a u1, · · · ,uk−1 pour < ·, · >D
• maximisant l’inertieEn fait, uk = D−1/2vk ou vk est le vecteur propre associe a la plus keme grandevaleur propre de la matrice (XD1/2)′(XD1/2). Et l’inertie expliquee par cet axevaut alors λk.
Rappelons que < uj ,uk >D=< vj ,vk >D= 0 pour j = 1, 2, · · · , k − 1.
48
Arthur CHARPENTIER - Analyse des donnees
Le (premier) axe principal
Considerons le tableau de donnees X = (xij)1≤i≤n,1≤j≤q = {L1, · · · , Ln}.
L’espace individus (de Rq) est muni de la metrique issue D.
Definition 11. Le plan principal, ou premier plan principal, pour un nuaged’individus {L1, · · · , Ln} est le plan engendre par u1,u2.
49
Arthur CHARPENTIER - Analyse des donnees
Rappel de la methodologie
Considerons le tableau de donnees X = (xij)1≤i≤n,1≤j≤q = {L1, · · · , Ln}.L’espace des individus (de Rq) est muni de la metrique issue D.
• on diagonalise (XD1/2)′(XD1/2).• soient λ1 ≥ λ2 ≥ λ3 ≥ · · · ≥ λq les valeurs propres, et vj les vecteurs propres• les axes principaux sont les uj = D−1/2vj .
Considerons le tableau de donnees X = (xij)1≤i≤n,1≤j≤q = {L1, · · · , Ln}.L’espace des variables (de Rn) est muni de la metrique issue ∆.
• on diagonalise (∆1/2X)′(∆1/2X).• soient λ1 ≥ λ2 ≥ λ3 ≥ · · · ≥ λq les valeurs propres, et νi les vecteurs propres• les axes principaux sont les µi = ∆−1/2νi.
50
Arthur CHARPENTIER - Analyse des donnees
Combien d’axes principaux doit-on retenir ?
Rappelons que l’on cherche a resumer l’information apportee par les variables parun “petit” nombre de facteurs, en tenant compte des correlation existant entreles variables.
=⇒ on veut garder peu d’axes principaux, avec• un soucis d’interpretation : on ne garde que des axes que l’on puisse interpreter,• des axes qui expliquent suffisement d’inertie. Pour cela, on a deux methodes◦ la methode du coude, correspondant a un decrochage au niveau des valeurs
propres◦ la regle de Kaiser, pour les variables centrees reduites : on ne garde que les
valeurs propres superieures a 1.(ce seuil de 1 correspond a la moyenne des valeurs propres).
51
Arthur CHARPENTIER - Analyse des donnees
Les composantes principales
prendre x pour les individus, y pour les individu centres, et z pour lesindividus centres reduits
Les coordonnees d’un individu centre yi sur un axe principal ∆k sont obtenuespar D-projection
ci,j =< yi, uk >D= y′iDuk
Definition 12. On appelera composantes principales les variables ck, dans RI ,definies par
ck = Y Duk
Il s’agit des coordonnees des projections D-orthongales sur les axes principaux.
52
Arthur CHARPENTIER - Analyse des donnees
Les composantes principales
Definition 13. La representation graphique du nuage des individus dans le planprincipal est alors le nuage des points c1, c2.
On notera que, par construction,ck = 0
car les colonnes de y sont centrees. De plus, V ar(ck) = λk et Cov(ck1 , ck2) = 0,i.e. les composantes principales sont orthogonales
53
Arthur CHARPENTIER - Analyse des donnees
Les donnees centrees reduites
Il peut parfois etre pertinant de travailler avec la metrique D1/s2 , car lesdistances entre variables sont tres sensibles aux unitees (et donc a la dispersion).
Rappelons que travailler avec la matrice D1/s2 sur le nuage y est equivalent atravailler avecla metrique usuelle I sur le nuage de points centres reduits.
Definition 14. On appelera nuage centre reduit le tableau Z contenant les
zi,j =xi,j − xj
sj
i.e. z = (x− x)D1/s = yD1/s.
54
Arthur CHARPENTIER - Analyse des donnees
Le “cercle des correlations”
On suppose que l’espace des variables est muni d’une metrique D. On prendra lametrique des poids. Alors
s2x = V ar(x) = ‖x‖2D et sxy = cov(x, y) =< x, y >D .
De plus, r(x, y) =< x, y >D
‖x‖D‖y‖D.
Si les variables sont supposees centrees et reduite, la correlation entre unecomposante principale ck et une variable zj , ou z = (x− x)D1/s est
r(zj , ck) =cov(zj , ck)√ck
=xj ′Dck√
λk
,
donc le vecteur des correlations du facteur ck avec toutes les variables z est
r(z, ck) =z′Dck√λk
,
55
Arthur CHARPENTIER - Analyse des donnees
or comme z′Dck = z′Dck = λkuk, on en dduit simplement que
r(z, ck) =√λkuk.
De cette expression, notons quep∑
k=1
r(zj , ck)2 = ‖zj‖2D = 1
et donc, en particulier, r(zj , c1)2 + r(zj , c2)2 ≤ 1.
Definition 15. On appelera cercle des correlations (e.g. dans le plan principal)le nuage de points (r(zj , c1), r(zj , c2)) pour k = 1, · · · , ????, ou sont projetees lesvariables.
La notion de “cercle” vient de la premiere propriete. Mais l’interpretation de laproximite des points n’est possible qu’au bord du cercle.
56
Arthur CHARPENTIER - Analyse des donnees
57
Arthur CHARPENTIER - Analyse des donnees
Ls contributions des individus
Nous avions note que λk =1n
n∑i=1
c2i,k.
Definition 16. On appelera contribution d’un individu i a un axe k la quantitec2i,knλk
.
La contribution sera importante si elle excede le poids de l’individu 1/n, i.e.|ci,k| >
√λk.
58
Arthur CHARPENTIER - Analyse des donnees
Enlever/rajouter des variables/individus
Il est possible de faire une analyse en enlevant certaines variables et/ou individus,quite a les rajouter par la suite,• certains individus vont etre sur-representes, et risqueront de tirer le nuage dans
une direction. On peut les exclure de la regression, quite a les rajouter par lasuite
• certains individus vont etre sur-representes, et risqueront de tirer le nuage desindividus dans une direction. On peut les exclure de la regression, quite a lesrajouter par la suite
• certaines variables peuvent, par un comportement assez different, deformer lenuage des variables.
Considerons ici la base ACPsup.csv) telechargeables sur ma page internet, dontl’ACP brute donne
59
Arthur CHARPENTIER - Analyse des donnees
Enlever/rajouter des variables/individus
−80 −60 −40 −20
−5
05
Les individus
cl1
cl2
1
2
3
4
5
6
7
8
9
10
11
121314
15
16
1718
19
20
2122
23
24
25
26
2728
29
30
31
323334
3536
37
38
3940
4142
43
44
4546
47
48
49
50
51
52
53
54
55
56
57
58
59
6061
62
63
64
65
66
67
68
69
70
71
72
7374
75 76
7778
79
80
81
82
83
84
8586
87
88
89
90
91
92
9394
95
96
97
9899
100
−14 −12 −10 −8 −6 −4 −2
−4
−2
02
46
Les variables
Comp1C
omp2
AB CD
E
60
Arthur CHARPENTIER - Analyse des donnees
Enlever/rajouter des variables/individus
−15 −10 −5 0
−4
−3
−2
−1
01
2
Les individus
cl1
cl2
123
4
5
6
7
8
9
10
11
12
1314
15
16171819
20
21
22
23
2425
26
2728
29
30
31
32
3334
3536
37
38
3940
4142
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
7778
79
80
81
82
83
84
85
86
87
88
89
90
91
92
9394
95
96
97
98
99
100
−1 0 1 2
−3
−2
−1
01
2
Les individus
cl1[1:99]
cl2[
1:99
]
1 23
4
5
6
7
8
9
10
11
12
1314
15
16 171819
20
2122
23
24 25
26
2728
29
30
31
32
3334
3536
37
38
3940
4142
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
6162
63
64
65
6667
68
6970
71
72
73
74
75
76
7778
79
80
81
82
83
84
8586
87
88
89
90
91
92
9394
95
96
97
98
99
−1.4 −1.2 −1.0 −0.8 −0.6 −0.4 −0.2 0.0
−0.
8−
0.6
−0.
4−
0.2
0.0
0.2
Les variables
Comp1
Com
p2
A
B
CD
E
61
Arthur CHARPENTIER - Analyse des donnees
Les variables supplementaires
Pour les individus supplementaires, on peut calculer la correlation entr lavariable et les composantes principales, plus placer ce point dans le cercle descorrelations. Si z est la variable centree reduite supplementaire, on calcule
r(z, ck) =z′Dck√λk
=1
n√λk
n∑i=1
zici,k.
Notons qu’il est possible de tester la significativite de la correlation.
z<- dudi.pca(don, center = T, scale = T, scannf = F)
ligsup<-suprow(z,donsup)
62
Arthur CHARPENTIER - Analyse des donnees
Les individus supplementaires
De meme ici, si Si z est l’individu centree reduite supplementaire, on calcule pourchaque axe principal k
ck =< z,uk) =p∑
j=1
zjuk,j .
63
Arthur CHARPENTIER - Analyse des donnees
Exemple sur donnees simulees
0.6 0.8 1.0 1.2
−0.
2−
0.1
0.0
0.1
0.2
0.3
0.4
Les variables
Comp1
Com
p2
A
B
C
D
0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4−
0.6
−0.
4−
0.2
0.0
0.2
0.4
Les variables
Comp1
Com
p2
A
BC
D
E
64
Arthur CHARPENTIER - Analyse des donnees
−4 −2 0 2 4 6
−2
−1
01
Les individus
cl1
cl2
1
2
3
45
6
7
8
9
10
11
12
1314
15
16
17
18
19
20
21 22
2324
25
26 27
28
29
30 31
32
3334
35
36
37
38
39
40 41
42
43
44
45
46
4748
49
50
51
52
53
54
55
5657
58
59
60
61
62
63
64
65
66
67
68
69
707172
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
9394
95
96
97
98
99
−25 −20 −15 −10 −5 0 5
05
10
Les individus
cl1
cl2
1
2
345
6
7
8
910 1112
131415
16
171819
20
21222324
2526 27
2829
30 31323334
35
36
3738
39404142
43
444546
4748
49
50 5152
53
54
55
565758
59
6061
6263
64
6566
6768
69
70 71727374
75
767778
79
80
81
82
838485
8687 88
89
9091929394
95
96
979899
100
65
Arthur CHARPENTIER - Analyse des donnees
Un cas d’ecole
Considerons les resultats de l’election presidentielle de 1995, au premier tour(base election95.csv). Notons que la personne pour laquelle on vote peut etre vuecomme une variable qualitative (cf cours 3 sur l’ACM).
Les variables principales sont les variables suivantes• VOY95 Pourcentage de vote de Mme Voynet• HUE95 Pourcentage de vote de M. Hue• JOS95 Pourcentage de vote de M. Jospin• LAG95 Pourcentage de vote de Mme Laguiller• VIL95 Pourcentage de vote de M. de Villiers• CHEM95 Pourcentage de vote de M. Cheminade• CHI95 Pourcentage de vote de M. Chirac• BAL95 Pourcentage de vote de M. Balladur• LEP95 Pourcentage de vote de M. Le Pen• inscrits 95 Nombre d’inscrits sur les listes electorales en mai 1995• exprimes 95 Nombre de suffrages exprimes au premier tour de l’election
66
Arthur CHARPENTIER - Analyse des donnees
presidentielle de 1995On obtient les graphiques suivants
●
−0.5 0.0 0.5 1.0
−0.
50.
00.
51.
0
CA factor map
Dim 1 (71.57%)
Dim
2 (
12.4
%)
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EspagnolItalienPortugais
AutresUE
Algerien
Marocain
Tunisien
Turc
Autres
−1.5 −1.0 −0.5 0.0 0.5 1.0
−0.
50.
00.
51.
0Axe 1
Axe
2
Agriculteurs
Artisans
CommercantsChefsEntreprise
ProfLiberalesCadresPublic
CadresEntreprProfIntPublicProfIntEntrepr
Techniciens
Contremaitres
EmployesPublicEmployesEntreprEmployesCommerc
PersonnelsServ
OuvriersQualifOuvriersNonQual
OuvriersAgricol
EspagnolItalien Portugais
AutresUE
Algerien
Marocain
Tunisien
Turc
Autres
• il y a plusieurs variables supplementaire, lies a la repartition par CSP dans undepartement, le niveau de diplome, la nationalite.
67
Arthur CHARPENTIER - Analyse des donnees
• on notera que des departements ont un comportement “singulier”, il seraitpeut-etre judicieux de les traiter comme individus supplementaires
Le diplome est traite comme variable “normale” a gauche, mais comme variablesupplmentaire a droite. Les modalites sont les suivantes DIPL0 Personne gee demoins de 15 ans, DIPL1 Aucun diplme, DIPL2 Certificat d’etudes primaires,DIPL3 BEPC, brevet elementaire, brevet des colleges, DIPL4 CAP, DIPL5 BEP,DIPL6 Baccalaureat general, DIPL7 Baccalaureat technologique ou professionnel,DIPL8 Diplme universitaire de 1er cycle, DIPL9 Diplme universitaire de 2e ou 3ecycle.
68
Arthur CHARPENTIER - Analyse des donnees
−1.0 −0.5 0.0 0.5 1.0
−1.
0−
0.5
0.0
0.5
1.0
Les variables
Comp1
Com
p2
VOY95
HUE95
JOS95
LAG95
VIL95CHEM95
CHI95
BAL95LEP95
DIPLOME0
DIPLOME1
DIPLOME2
DIPLOME3
DIPLOME4
DIPLOME5
DIPLOME6
DIPLOME7
DIPLOME8
DIPLOME9
−0.5 0.0 0.5
−0.
6−
0.4
−0.
20.
00.
20.
40.
60.
8
Les variables
Comp1
Com
p2
VOY95
HUE95
JOS95
LAG95
VIL95CHEM95
CHI95
BAL95
LEP95
DIPLOME0DIPLOME1DIPLOME2DIPLOME3DIPLOME4DIPLOME5DIPLOME6DIPLOME7DIPLOME8DIPLOME9
69
Arthur CHARPENTIER - Analyse des donnees
−1.0 −0.5 0.0 0.5 1.0
−1.
0−
0.5
0.0
0.5
1.0
Les variables
Comp1
Com
p2
VOY95
HUE95JOS95
LAG95
VIL95
CHEM95
CHI95
BAL95
LEP95CHOMEURS
ETUDIANTS
MILITAIRES
−1.0 −0.5 0.0 0.5
−0.
50.
00.
51.
0
Les variables
Comp1
Com
p2 VOY95
HUE95
JOS95
LAG95
VIL95CHEM95
CHI95
BAL95
LEP95
CHOMEURS
ETUDIANTSMILITAIRES
Pour les CSP, on notera CS1· Agriculteurs exploitants, CS2· Artisans,commerants et chefs d’entreprises, CS3· Cadres et professions intellectuellessuperieures, CS4· Professions intermediaires (dont CS44 pour le clerge), CS5·Employes, CS6· Ouvriers, CS7· Retraites (dont CS72 Anciens artisans,
70
Arthur CHARPENTIER - Analyse des donnees
commerants, chefs d’entreprise), CS8· Autres personnes inactives (dont CS81
Chmeurs n’ayant jamais travaille).
−1.0 −0.5 0.0 0.5 1.0
−1.
0−
0.5
0.0
0.5
1.0
Les variables
Comp1
Com
p2
VOY95
HUE95JOS95
LAG95
VIL95CHEM95
CHI95
BAL95
LEP95
CS11
CS12
CS13
CS21
CS22
CS23
CS31CS33
CS34
CS35
CS37
CS38
CS42
CS43
CS44
CS45
CS46
CS47
CS48
CS52CS53
CS54CS55
CS56
CS62
CS63
CS64CS65
CS67
CS68
CS69CS71
CS72
CS74CS75
CS77
CS78
CS81
CS83
CS84
CS85
CS86
−0.5 0.0 0.5−
0.6
−0.
4−
0.2
0.0
0.2
0.4
0.6
0.8
Les variables
Comp1
Com
p2
VOY95
HUE95
JOS95
LAG95
VIL95CHEM95
CHI95
BAL95
LEP95
CS11CS12CS13CS21
CS22 CS23
CS31CS33
CS34
CS35CS37
CS38CS42
CS43
CS44
CS45
CS46
CS47CS48
CS52
CS53CS54CS55
CS56
CS62
CS63
CS64
CS65
CS67
CS68CS69
CS71
CS72
CS74CS75CS77
CS78CS81
CS83
CS84
CS85
CS86
Pour les departements, on peut commencer par ecarter la correze
71
Arthur CHARPENTIER - Analyse des donnees
−1.0 −0.5 0.0 0.5 1.0
−1.
0−
0.5
0.0
0.5
1.0
Les variables
Comp1
Com
p2 VOY95
HUE95
JOS95
LAG95
VIL95CHEM95
CHI95
BAL95
LEP95
−6 −4 −2 0 2 4
−5
−4
−3
−2
−1
01
2
Les individus
cl1cl
2
AIN
AISNE
ALLIER
ALPES−DE−HAUTE−PROVENCE
HAUTES−ALPESALPES−MARITIMES
ARDECHE
ARDENNES
ARIEGE
AUBE
AUDE
AVEYRON
BOUCHES−DU−RHONE
CALVADOS
CANTAL
CHARENTE
CHARENTE−MARITIME
CHER
CORSE−DU−SUDHAUTE−CORSE
COTE−D−OR
COTES−D−ARMOR
CREUSE
DORDOGNE
DOUBSDROMEEURE
EURE−ET−LOIRFINISTERE
GARD
HAUTE−GARONNE
GERS
GIRONDE
HERAULT
ILLE−ET−VILAINE
INDREINDRE−ET−LOIRE
ISERE
JURA
LANDES
LOIR−ET−CHER
LOIRE
HAUTE−LOIRE
LOIRE−ATLANTIQUE
LOIRET
LOT
LOT−ET−GARONNE
LOZERE
MAINE−ET−LOIREMANCHE
MARNEHAUTE−MARNE
MAYENNE
MEURTHE−ET−MOSELLE
MEUSEMORBIHAN
MOSELLE
NIEVRE
NORD
OISE
ORNE
PAS−DE−CALAIS
PUY−DE−DOME
PYRENEES−ATLANTIQUES
HAUTES−PYRENEES
PYRENEES−ORIENTALES
BAS−RHINHAUT−RHIN
RHONE
HAUTE−SAONE
SAONE−ET−LOIRESARTHE
SAVOIE
HAUTE−SAVOIE
PARIS
SEINE−MARITIME
SEINE−ET−MARNE
YVELINES
DEUX−SEVRES
SOMME
TARNTARN−ET−GARONNE
VAR
VAUCLUSE
VENDEE
VIENNEHAUTE−VIENNE
VOSGES
YONNE
TERRITOIRE−DE−BELFORT
ESSONNE
HAUTS−DE−SEINE
SEINE−SAINT−DENIS
CORREZE
On peut aussi etudier l’impact de la Vendee
72
Arthur CHARPENTIER - Analyse des donnees
−1.0 −0.5 0.0 0.5 1.0
−1.
0−
0.5
0.0
0.5
1.0
Les variables
Comp1
Com
p2
VOY95HUE95
JOS95
LAG95
VIL95CHEM95
CHI95
BAL95
LEP95
−8 −6 −4 −2 0 2 4 6
−3
−2
−1
01
23
4
Les individus
cl1cl
2
AIN
AISNE
ALLIER
ALPES−DE−HAUTE−PROVENCEHAUTES−ALPES
ALPES−MARITIMES
ARDECHE
ARDENNES
ARIEGE
AUBE
AUDE
AVEYRON
BOUCHES−DU−RHONE
CALVADOS
CANTAL
CHARENTE
CHARENTE−MARITIME
CHER
CORREZE
CORSE−DU−SUD
HAUTE−CORSE
COTE−D−OR
COTES−D−ARMOR
CREUSE
DORDOGNEDOUBSDROME
EURE
EURE−ET−LOIR
FINISTERE
GARD
HAUTE−GARONNE
GERS
GIRONDE
HERAULT
ILLE−ET−VILAINE
INDREINDRE−ET−LOIRE
ISERE
JURALANDES
LOIR−ET−CHER
LOIRE
HAUTE−LOIRE
LOIRE−ATLANTIQUE
LOIRET
LOT
LOT−ET−GARONNE
LOZERE
MAINE−ET−LOIRE
MANCHEMARNEHAUTE−MARNEMAYENNE
MEURTHE−ET−MOSELLE
MEUSEMORBIHANMOSELLE
NIEVRE
NORDOISE
ORNE
PAS−DE−CALAIS
PUY−DE−DOME
PYRENEES−ATLANTIQUES
HAUTES−PYRENEES
PYRENEES−ORIENTALES
BAS−RHIN
HAUT−RHIN
RHONE
HAUTE−SAONESAONE−ET−LOIRE
SARTHE
SAVOIE
HAUTE−SAVOIEPARIS
SEINE−MARITIME
SEINE−ET−MARNE
YVELINES
DEUX−SEVRES
SOMME
TARN
TARN−ET−GARONNE
VAR
VAUCLUSE
VIENNEHAUTE−VIENNE
VOSGESYONNE
TERRITOIRE−DE−BELFORTESSONNE
HAUTS−DE−SEINE
SEINE−SAINT−DENIS
VENDEE
Et enfin l’impact de l’Alsace (Bas et Haut Rhin)
73
Arthur CHARPENTIER - Analyse des donnees
−1.0 −0.5 0.0 0.5 1.0
−1.
0−
0.5
0.0
0.5
1.0
Les variables
Comp1
Com
p2 VOY95
HUE95JOS95
LAG95
VIL95CHEM95
CHI95
BAL95
LEP95
−8 −6 −4 −2 0 2 4
−4
−3
−2
−1
01
2
Les individus
cl1
cl2
AIN
AISNE
ALLIERALPES−DE−HAUTE−PROVENCE
HAUTES−ALPESALPES−MARITIMES
ARDECHE
ARDENNESARIEGE
AUBE
AUDE
AVEYRON
BOUCHES−DU−RHONE
CALVADOS
CANTAL
CHARENTE
CHARENTE−MARITIME
CHER
CORREZE CORSE−DU−SUD
HAUTE−CORSE
COTE−D−OR
COTES−D−ARMOR
CREUSE
DORDOGNE
DOUBSDROMEEURE
EURE−ET−LOIR
FINISTERE
GARDHAUTE−GARONNE
GERS
GIRONDE
HERAULT
ILLE−ET−VILAINE
INDREINDRE−ET−LOIRE
ISERE
JURA
LANDES LOIR−ET−CHER
LOIRE
HAUTE−LOIRE
LOIRE−ATLANTIQUE
LOIRET
LOTLOT−ET−GARONNE
LOZERE
MAINE−ET−LOIREMANCHE
MARNEHAUTE−MARNE
MAYENNE
MEURTHE−ET−MOSELLE
MEUSEMORBIHAN
MOSELLE
NIEVRE
NORD
OISE
ORNE
PAS−DE−CALAIS
PUY−DE−DOME
PYRENEES−ATLANTIQUES
HAUTES−PYRENEES
PYRENEES−ORIENTALES
RHONEHAUTE−SAONE
SAONE−ET−LOIRESARTHE
SAVOIE
HAUTE−SAVOIE
PARIS
SEINE−MARITIME
SEINE−ET−MARNE
YVELINES
DEUX−SEVRES
SOMME
TARN
TARN−ET−GARONNEVAR
VAUCLUSE
VENDEE
VIENNE
HAUTE−VIENNEVOSGES
YONNE
TERRITOIRE−DE−BELFORT
ESSONNE
HAUTS−DE−SEINE
SEINE−SAINT−DENIS
BAS−RHINHAUT−RHIN
74
Arthur CHARPENTIER - Analyse des donnees
Mise en oeuvre pratique
75
Arthur CHARPENTIER - Analyse des donnees
Les donnees, en ACP
“Le palmares des departements. Ou vit-on en securite ?, dans L’Express (no 2589, 15
fevrier 2001).
• infra Nombre d’infractions totale pour 1000 habitants (2000)
• vols Nombre total de vols pour 1000 habitants (2000)
• eco Nombre d’infractions economiques et finacieres pour 1000 habitants (2000)
• crim Nombre de crimes et delits contre les personnes pour 1000 habitants (2000)
• vma Nombre de vols a main armee pour 1000 habitants (2000)
• vvi Nombre de vols avec violance pour 1000 habitants (2000)
• camb Nombre de cambriolages pour 1000 habitants (2000)
• roul Nombre de vols a la roulotte pour 1000 habitants (2000)
• auto Nombre de vols d’automobiles pour 1000 habitants (2000)
76
Arthur CHARPENTIER - Analyse des donnees
Les donnees, en ACP robuste
Dans les ACP robuste, on ne s’interesse plus aux niveaux mais aux rangs
77
Arthur CHARPENTIER - Analyse des donnees
Base de donnees pour les 25 villes compareesAngers 14 19 12 12 11 19 19 7 6 14 21
Bordeaux 20 7 18 18 9 3 7 19 19 23 13
Caen 8 17 16 6 24 13 15 12 5 13 18
Clermont-Ferrand 14 25 8 16 7 20 5 5 9 1 24
Dijon 17 20 18 14 13 24 16 11 11 10 16
Douai-Lens 1 23 3 5 23 17 21 3 2 5 19
Grenoble 22 11 16 21 7 4 8 23 14 7 6
Lille 10 6 8 5 20 6 24 21 16 3 8
Lyon 10 8 23 17 5 2 13 22 23 24 4
Marseille-Aix-en-Provence 24 3 24 25 3 5 6 5 24 19 3
Metz 4 12 3 2 13 14 19 9 10 12 22
Montpellier 25 2 14 22 4 12 4 18 20 9 10
Nancy 24 16 12 10 16 18 19 24 5 21 17
Nantes 6 10 12 12 17 9 12 17 18 22 11
Nice 20 1 23 23 2 8 1 6 22 16 2
Orl ?ns 4 13 8 13 15 15 24 17 3 11 14
Paris 12 4 25 8 19 1 25 25 25 25 1
Rennes 12 14 8 7 21 11 11 15 12 15 7
Rouen 6 22 20 1 22 25 22 13 7 8 20
Saint-Etienne 15 24 12 19 8 21 9 1 13 2 25
Strasbourg 20 9 21 9 14 16 10 15 17 20 15
Toulon 8 18 4 24 1 10 3 2 15 4 5
Toulouse 22 5 20 20 10 7 2 20 21 17 12
Tours 17 15 14 15 18 22 20 8 8 6 9
Valenciennes 2 21 3 5 25 23 14 10 1 18 23
78
Arthur CHARPENTIER - Analyse des donnees
Nombre de medecins (pour 1000 habitants)Angers 14 19 12 12 11 19 19 7 6 14 21
Bordeaux 20 7 18 18 9 3 7 19 19 23 13
Caen 8 17 16 6 24 13 15 12 5 13 18
Clermont-Ferrand 14 25 8 16 7 20 5 5 9 1 24
Dijon 17 20 18 14 13 24 16 11 11 10 16
Douai-Lens 1 23 3 5 23 17 21 3 2 5 19
Grenoble 22 11 16 21 7 4 8 23 14 7 6
Lille 10 6 8 5 20 6 24 21 16 3 8
Lyon 10 8 23 17 5 2 13 22 23 24 4
Marseille-Aix-en-Provence 24 3 24 25 3 5 6 5 24 19 3
Metz 4 12 3 2 13 14 19 9 10 12 22
Montpellier 25 2 14 22 4 12 4 18 20 9 10
Nancy 24 16 12 10 16 18 19 24 5 21 17
Nantes 6 10 12 12 17 9 12 17 18 22 11
Nice 20 1 23 23 2 8 1 6 22 16 2
Orl ?ns 4 13 8 13 15 15 24 17 3 11 14
Paris 12 4 25 8 19 1 25 25 25 25 1
Rennes 12 14 8 7 21 11 11 15 12 15 7
Rouen 6 22 20 1 22 25 22 13 7 8 20
Saint-Etienne 15 24 12 19 8 21 9 1 13 2 25
Strasbourg 20 9 21 9 14 16 10 15 17 20 15
Toulon 8 18 4 24 1 10 3 2 15 4 5
Toulouse 22 5 20 20 10 7 2 20 21 17 12
Tours 17 15 14 15 18 22 20 8 8 6 9
Valenciennes 2 21 3 5 25 23 14 10 1 18 23
79
Arthur CHARPENTIER - Analyse des donnees
Nombre de crimes et delits (pour 1000 habitants)Angers 14 19 12 12 11 19 19 7 6 14 21
Bordeaux 20 7 18 18 9 3 7 19 19 23 13
Caen 8 17 16 6 24 13 15 12 5 13 18
Clermont-Ferrand 14 25 8 16 7 20 5 5 9 1 24
Dijon 17 20 18 14 13 24 16 11 11 10 16
Douai-Lens 1 23 3 5 23 17 21 3 2 5 19
Grenoble 22 11 16 21 7 4 8 23 14 7 6
Lille 10 6 8 5 20 6 24 21 16 3 8
Lyon 10 8 23 17 5 2 13 22 23 24 4
Marseille-Aix-en-Provence 24 3 24 25 3 5 6 5 24 19 3
Metz 4 12 3 2 13 14 19 9 10 12 22
Montpellier 25 2 14 22 4 12 4 18 20 9 10
Nancy 24 16 12 10 16 18 19 24 5 21 17
Nantes 6 10 12 12 17 9 12 17 18 22 11
Nice 20 1 23 23 2 8 1 6 22 16 2
Orl ?ns 4 13 8 13 15 15 24 17 3 11 14
Paris 12 4 25 8 19 1 25 25 25 25 1
Rennes 12 14 8 7 21 11 11 15 12 15 7
Rouen 6 22 20 1 22 25 22 13 7 8 20
Saint-Etienne 15 24 12 19 8 21 9 1 13 2 25
Strasbourg 20 9 21 9 14 16 10 15 17 20 15
Toulon 8 18 4 24 1 10 3 2 15 4 5
Toulouse 22 5 20 20 10 7 2 20 21 17 12
Tours 17 15 14 15 18 22 20 8 8 6 9
Valenciennes 2 21 3 5 25 23 14 10 1 18 23
80
Arthur CHARPENTIER - Analyse des donnees
Ensoleillement moyen, entre 1991 et 2000Angers 14 19 12 12 11 19 19 7 6 14 21
Bordeaux 20 7 18 18 9 3 7 19 19 23 13
Caen 8 17 16 6 24 13 15 12 5 13 18
Clermont-Ferrand 14 25 8 16 7 20 5 5 9 1 24
Dijon 17 20 18 14 13 24 16 11 11 10 16
Douai-Lens 1 23 3 5 23 17 21 3 2 5 19
Grenoble 22 11 16 21 7 4 8 23 14 7 6
Lille 10 6 8 5 20 6 24 21 16 3 8
Lyon 10 8 23 17 5 2 13 22 23 24 4
Marseille-Aix-en-Provence 24 3 24 25 3 5 6 5 24 19 3
Metz 4 12 3 2 13 14 19 9 10 12 22
Montpellier 25 2 14 22 4 12 4 18 20 9 10
Nancy 24 16 12 10 16 18 19 24 5 21 17
Nantes 6 10 12 12 17 9 12 17 18 22 11
Nice 20 1 23 23 2 8 1 6 22 16 2
Orl ?ns 4 13 8 13 15 15 24 17 3 11 14
Paris 12 4 25 8 19 1 25 25 25 25 1
Rennes 12 14 8 7 21 11 11 15 12 15 7
Rouen 6 22 20 1 22 25 22 13 7 8 20
Saint-Etienne 15 24 12 19 8 21 9 1 13 2 25
Strasbourg 20 9 21 9 14 16 10 15 17 20 15
Toulon 8 18 4 24 1 10 3 2 15 4 5
Toulouse 22 5 20 20 10 7 2 20 21 17 12
Tours 17 15 14 15 18 22 20 8 8 6 9
Valenciennes 2 21 3 5 25 23 14 10 1 18 23
81
Arthur CHARPENTIER - Analyse des donnees
Cumul des emboutillagesAngers 14 19 12 12 11 19 19 7 6 14 21
Bordeaux 20 7 18 18 9 3 7 19 19 23 13
Caen 8 17 16 6 24 13 15 12 5 13 18
Clermont-Ferrand 14 25 8 16 7 20 5 5 9 1 24
Dijon 17 20 18 14 13 24 16 11 11 10 16
Douai-Lens 1 23 3 5 23 17 21 3 2 5 19
Grenoble 22 11 16 21 7 4 8 23 14 7 6
Lille 10 6 8 5 20 6 24 21 16 3 8
Lyon 10 8 23 17 5 2 13 22 23 24 4
Marseille-Aix-en-Provence 24 3 24 25 3 5 6 5 24 19 3
Metz 4 12 3 2 13 14 19 9 10 12 22
Montpellier 25 2 14 22 4 12 4 18 20 9 10
Nancy 24 16 12 10 16 18 19 24 5 21 17
Nantes 6 10 12 12 17 9 12 17 18 22 11
Nice 20 1 23 23 2 8 1 6 22 16 2
Orl ?ns 4 13 8 13 15 15 24 17 3 11 14
Paris 12 4 25 8 19 1 25 25 25 25 1
Rennes 12 14 8 7 21 11 11 15 12 15 7
Rouen 6 22 20 1 22 25 22 13 7 8 20
Saint-Etienne 15 24 12 19 8 21 9 1 13 2 25
Strasbourg 20 9 21 9 14 16 10 15 17 20 15
Toulon 8 18 4 24 1 10 3 2 15 4 5
Toulouse 22 5 20 20 10 7 2 20 21 17 12
Tours 17 15 14 15 18 22 20 8 8 6 9
Valenciennes 2 21 3 5 25 23 14 10 1 18 23
82
Arthur CHARPENTIER - Analyse des donnees
> add=read.table("http://perso.univ-rennes1.fr/arthur.charpentier/ADD-ex-villes.txt",header=TRUE)
> base=add[,2:ncol(add)]
> rownames(base)=add$Agglo
Considerons comme matrice D la matrice1n
I pour l’espace des individus, et la
matrice identite pour l’espace des variables, ∆ = I.
On diagonale alors1nX ′X, et on note v1, · · · ,vq les vecteurs propres associes aux
valeurs propres λ1 > · · · > λq. On obtient alors les vecteurs uk engendrant les axes
principaux, qui expliquent chacun 100× λk∑kj=1 λj
% de l’inertie totale.
> X <- as.matrix(base)
> n <- nrow(base)
> eigen(1/n * t(X) %*% X)
> eigen(1/n * t(X) %*% X)$vectors
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11]
[1,] -0.31 -0.29 -0.2684 -0.254 -0.493 -0.331 -0.096 -0.097 -0.242 0.3880 0.318
[2,] -0.29 0.38 -0.2735 0.016 0.190 0.272 -0.083 -0.122 0.527 0.2165 0.492
[3,] -0.32 -0.27 0.0340 0.099 0.236 -0.590 0.156 0.108 0.539 0.0492 -0.277
[4,] -0.29 -0.29 -0.4430 -0.157 0.208 0.393 -0.380 -0.080 -0.062 -0.0011 -0.506
83
Arthur CHARPENTIER - Analyse des donnees
[5,] -0.30 0.30 0.3507 -0.013 0.039 -0.054 0.104 -0.742 -0.161 0.1818 -0.270
[6,] -0.30 0.35 -0.2859 0.022 -0.051 -0.337 -0.153 -0.042 -0.174 -0.7280 0.073
[7,] -0.30 0.26 0.3767 -0.412 0.344 -0.078 -0.236 0.493 -0.262 0.1879 0.034
[8,] -0.31 -0.16 0.4032 -0.329 -0.485 0.346 0.075 0.063 0.349 -0.3510 -0.022
[9,] -0.29 -0.39 -0.0098 0.013 0.409 0.190 0.560 -0.059 -0.304 -0.1865 0.341
[10,] -0.30 -0.19 0.3090 0.734 -0.073 0.097 -0.423 0.081 -0.113 0.0173 0.152
[11,] -0.30 0.35 -0.2256 0.288 -0.301 0.161 0.476 0.384 -0.131 0.2088 -0.325
> eigen(1/n * t(X) %*% X)$values
[1] 1940.974149 275.990875 123.372428 31.594830 28.553309 23.945216
[7] 14.283394 12.950240 10.841242 6.205078 4.849239
Pour mieux comprendre quelle part est expliquee par les premiers axes propres, on
utilise
> valp <- eigen(1/n * t(X) %*% X)$values
> 100 * valp/sum(valp)
[1] 78.4688525 11.1576382 4.9876465 1.2773020 1.1543407 0.9680467
[7] 0.5774428 0.5235466 0.4382850 0.2508562 0.1960429
i.e. le premier axe explique 78.5% de l’inertie, et le second 11% de l’inertie (soit pres
de 90% pour le plan principal).
84
Arthur CHARPENTIER - Analyse des donnees
Une autre possibilite est d’utiliser dudi.pca de library(ade4).
> acp <- dudi.pca(base, scale = F, center = F,scannf = F, nf = ncol(base))
> acp$c1
CS1 CS2 CS3 CS4 CS5 CS6 CS7 CS8 CS9 CS10 CS11
Medecins -0.31 -0.29 -0.2684 -0.254 -0.493 -0.331 -0.096 -0.097 -0.242 0.3880 0.318
Crimin -0.29 0.38 -0.2735 0.016 0.190 0.272 -0.083 -0.122 0.527 0.2165 0.492
Musees -0.32 -0.27 0.0340 0.099 0.236 -0.590 0.156 0.108 0.539 0.0492 -0.277
Soleil -0.29 -0.29 -0.4430 -0.157 0.208 0.393 -0.380 -0.080 -0.062 -0.0011 -0.506
Polution -0.30 0.30 0.3507 -0.013 0.039 -0.054 0.104 -0.742 -0.161 0.1818 -0.270
Embout -0.30 0.35 -0.2859 0.022 -0.051 -0.337 -0.153 -0.042 -0.174 -0.7280 0.073
LienParis -0.30 0.26 0.3767 -0.412 0.344 -0.078 -0.236 0.493 -0.262 0.1879 0.034
Cadres -0.31 -0.16 0.4032 -0.329 -0.485 0.346 0.075 0.063 0.349 -0.3510 -0.022
CreatEntrp -0.29 -0.39 -0.0098 0.013 0.409 0.190 0.560 -0.059 -0.304 -0.1865 0.341
Revenu -0.30 -0.19 0.3090 0.734 -0.073 0.097 -0.423 0.081 -0.113 0.0173 0.152
PrixImmob -0.30 0.35 -0.2256 0.288 -0.301 0.161 0.476 0.384 -0.131 0.2088 -0.325
Les valeurs propres sont elles
> acp$eig
[1] 1940.974149 275.990875 123.372428 31.594830 28.553309 23.945216 14.283394
[8] 12.950240 10.841242 6.205078 4.849239
85
Arthur CHARPENTIER - Analyse des donnees
Les projections sur les deux premiers axes sont donnees par acp$c1[,1 :2]. Toutes les
variables contribuent a l’axe 1 (sens negatif).
On utilise s.label(acp$li) et s.label(acp$co) pour projeter lignes et colonnes
respectivement
d = 10
Angers
Bordeaux
Caen ClermontFerrand
Dijon
Douai
Grenoble
Lille
Lyon
Marseille
Metz
Montpellier
Nancy
Nantes
Nice
Orléans
Paris
Rennes
Rouen
SaintEtienne
Strasbourg Toulon
Toulouse
Tours
Valenciennes
d = 5
Medecins
Crimin
Musees Soleil
Polution
Embout
LienParis
Cadres
CreatEntrp
Revenu
PrixImmob
86
Arthur CHARPENTIER - Analyse des donnees
ACP centree ou pas
Parmi les transformations usuelles des variables, on peut les centrer. La nouvelle
origine G a pour coordonnees (C1, · · · , Cq), correspondant au centre de gravite du
nuage de points.
On note Cj les colonnes (centrees) de X, i.e. Cj = Cj −Cj . Alors la norme de Cj
correspond a l’ecart-type de Cj , puisque
‖Cj‖2 =1n
∑i=1
n(xi,j − Cj)2 = V ar(Cj).
87
Arthur CHARPENTIER - Analyse des donnees
d = 10
Angers
Bordeaux
Caen
ClermontFerrand
Dijon
Douai
Grenoble
Lille
Lyon
Marseille
Metz
Montpellier
Nancy Nantes
Nice
Orléans
Paris
Rennes Rouen
SaintEtienne
Strasbourg
Toulon
Toulouse Tours
Valenciennes
d = 2 d = 2
Medecins Crimin
Musees
Soleil
Polution
Embout
LienParis Cadres
CreatEntrp
Revenu
PrixImmob
88
Arthur CHARPENTIER - Analyse des donnees
ACP normee ou pas
Parmi les transformations usuelles des variables, on peut les normer. Ceci permet de
reequilibrer des variables qui peuvent etre exprimees dans des unitees differentes. d = 2
Angers
Bordeaux
Caen
ClermontFerrand
Dijon
Douai
Grenoble
Lille
Lyon
Marseille
Metz
Montpellier
Nancy Nantes
Nice
Orléans
Paris
Rennes Rouen
SaintEtienne
Strasbourg
Toulon
Toulouse Tours
Valenciennes
d = 0.5 d = 0.5
Medecins Crimin
Musees
Soleil
Polution
Embout
LienParis Cadres
CreatEntrp
Revenu
PrixImmob
Attention On a seulement normalise les variables.
89
Arthur CHARPENTIER - Analyse des donnees
Angers
Bordeaux
Caen
ClermontFerrand
Dijon
Douai
Grenoble
Lille
Lyon
Marseille
Metz
Montpellier
Nancy Nantes
Nice
Orléans
Paris
Rennes Rouen
SaintEtienne
Strasbourg
Toulon
Toulouse Tours
Valenciennes
Medecins Crimin
Musees
Soleil
Polution
Embout
LienParis Cadres
CreatEntrp
Revenu
PrixImmob
L’etude de ces inerties peut se faire a l’aide de plot(princomp(base)) sous R.
biplot(princomp(base)) permet de projeter les individus sur le premier plan principal.
90
Arthur CHARPENTIER - Analyse des donnees
Comp.1 Comp.3 Comp.5 Comp.7 Comp.9
Var
ianc
es
050
100
150
200
250
−0.4 −0.2 0.0 0.2 0.4
−0.
4−
0.2
0.0
0.2
0.4
Comp.1
Com
p.2
Angers
Bordeaux
Caen
ClermontFerrand
Dijon
Douai
Grenoble
Lille
Lyon
Marseille
Metz
Montpellier
NancyNantes
Nice
Orléans
Paris
RennesRouen
SaintEtienne
Strasbourg
Toulon
ToulouseTours
Valenciennes
−30 −20 −10 0 10 20 30 40
−30
−20
−10
010
2030
40
MedecinsCrimin
Musees
Soleil
Polution
Embout
LienParisCadres
CreatEntrp
Revenu
PrixImmob
Attention le signe peut changer d’un logiciel a l’autre. Par exemple, le calcul
complet a partir de la diagonalisation donne
x=as.matrix(base)
n <- nrow(x); p <- ncol(x)
centre <- apply(x, 2, mean)
91
Arthur CHARPENTIER - Analyse des donnees
x <- x - matrix(centre, nr=n, nc=p, byrow=T)
e1 <- eigen( t(x) %*% x, symmetric=T )
e2 <- eigen( x %*% t(x), symmetric=T )
variables <- t(e2$vectors) %*% x
individus <- t(e1$vectors) %*% t(x)
variables <- t(variables)
individus <- t(individus)
valeurs.propres <- e1$values
plot( individus[,1:2],
xlim=c( min(c(individus[,1],-individus[,1])),
max(c(individus[,1],-individus[,1])) ),
ylim=c( min(c(individus[,2],-individus[,2])),
max(c(individus[,2],-individus[,2])) ),
xlab=’’, ylab=’’, frame.plot=F )
par(new=T)
plot( variables[,1:2], col=’red’,
xlim=c( min(c(variables[,1],-variables[,1])),
max(c(variables[,1],-variables[,1])) ),
ylim=c( min(c(variables[,2],-variables[,2])),
max(c(variables[,2],-variables[,2])) ),
axes=F, xlab=’’, ylab=’’, pch=’.’)
92
Arthur CHARPENTIER - Analyse des donnees
axis(3, col=’red’)
axis(4, col=’red’)
arrows(0,0,variables[,1],variables[,2],col=’red’)
●
●
●
●
●
●
●
●
●
●
●
●
●●
●
●
●
●●
●
●
●
●●
●
−30 −20 −10 0 10 20 30
−20
−10
010
20
−30 −20 −10 0 10 20 30
−20
−10
010
20
−0.4 −0.2 0.0 0.2 0.4−
0.4
−0.
20.
00.
20.
4
Comp.1
Com
p.2
Angers
Bordeaux
Caen
ClermontFerrand
Dijon
Douai
Grenoble
Lille
Lyon
Marseille
Metz
Montpellier
NancyNantes
Nice
Orléans
Paris
RennesRouen
SaintEtienne
Strasbourg
Toulon
ToulouseTours
Valenciennes
−30 −20 −10 0 10 20 30 40
−30
−20
−10
010
2030
40
MedecinsCrimin
Musees
Soleil
Polution
Embout
LienParisCadres
CreatEntrp
Revenu
PrixImmob
93
Arthur CHARPENTIER - Analyse des donnees
Explication des axes
Pour interpreter le premier axe, rappelons que
> names(base)
[1] "Medecins" "Crimin" "Musees" "Soleil" "Polution"
[6] "Embout" "LienParis" "Cadres" "CreatEntrp" "Revenu"
[11] "PrixImmob"
> acp$co[, 1]
[1] 0.6847162 -0.8499417 0.7013389 0.7029398 -0.6656761
[6] -0.7872159 -0.5619327 0.3887672 0.9139772 0.4715448
[11] -0.7837233
94
Arthur CHARPENTIER - Analyse des donnees
variable axe 1 axe 2
Medecins 0.6847162 ↗ -0.27456842 ↘Criminalite -0.8499417 ↘ -0.31990547 ↘Musees 0.7013389 ↗ 0.20111087 ↗Soleil 0.7029398 ↗ -0.63249825 ↘Polution -0.6656761 ↘ 0.63938379 ↗Embouteillages -0.7872159 ↘ -0.30661893 ↘Lien Paris -0.5619327 ↘ 0.65398028 ↗Cadres 0.3887672 ↗ 0.72323380 ↗Creation Entreprises 0.9139772 0.04395415
Revenu 0.4715448 ↗ 0.58525352 ↗Prix Immobilier -0.7837233 ↘ -0.22212682 ↘
95
Arthur CHARPENTIER - Analyse des donnees
Recherche des points affluents
L’etude de la projection de l’espace des individus permet d’associer ou de dissocier
des individus au comportement proche, ou radicalement different : deux points tres
eloignes sur le premier axe sont tres eloignes dans le nuage initial.
L’intertie du nuage s’ecrit
I(X,D,u) =n∑
i=1
< Li,u >2D .
On peut ainsi chercher les points qui contribuent le plus au positionnement de l’axe,
i.e. i pour lequels < Li,u >2D est grand.
Definition 17. On appelle contribution (absolue) du point Li a la position del’axe uk la quantite
CTk(Li) =< Li,uk >
2D
λk.
96
Arthur CHARPENTIER - Analyse des donnees
Notons quen∑
i=1
CTk(Li) =I(X,D,uk)
λk= 1.
97
Arthur CHARPENTIER - Analyse des donnees
Qualite d’une projectionDefinition 18. On appelle qualite de la representation du point Li sur l’axe uk
la quantite
QRk(Li) =< Li,uk >
2D
‖Li, ‖D.
Notons que
q∑k=1
CTk(Li) = 1. On parle aussi de contribution relative
> intacp <- inertia.dudi(acp, col.inertia = T,row.inertia = T)
> intacp$row.rel[, 1]
Angers Bordeaux Caen ClermontFerrand
-5500 7565 -5479 -2464
Dijon Douai Grenoble Lille
-2131 -8886 5132 -144
Lyon Marseille Metz Montpellier
6621 8075 -5311 6134
Nancy Nantes Nice Orleans
-455 572 7660 -4276
Paris Rennes Rouen SaintEtienne
98
Arthur CHARPENTIER - Analyse des donnees
2726 -559 -6401 -1760
Strasbourg Toulon Toulouse Tours
1865 150 8115 -2283
Valenciennes
-7911
> intacp$row.abs[, 1]
Angers Bordeaux Caen ClermontFerrand
210 483 251 243
Dijon Douai Grenoble Lille
72 1212 347 12
Lyon Marseille Metz Montpellier
678 1168 374 523
Nancy Nantes Nice Orleans
30 19 1024 226
Paris Rennes Rouen SaintEtienne
444 16 681 172
Strasbourg Toulon Toulouse Tours
60 17 605 94
Valenciennes
1040
Le signe indique le signe de la coordonnee sur l’axe 1.
99
Arthur CHARPENTIER - Analyse des donnees
acp$co fournit l’interpretation des axes µk dans l’espace des variables ,
acp$c1 fournit l’interpretation des axes uk dans l’espace des individus
Les valeurs sont identiques a une constante de normalisation pres.
=⇒ Les axes uk et µk ont la meme interpretation par rapport aux variables initiales.
On peut alors envisager une repesentation simultanee des espaces individus ou
variables.
On peut regarder la projection des villes, en fonction de differentes variables
explicatives,
s.value(acpli, scale(base$Medecins))s.value(acpli, scale(base$Crimin ))
100
Arthur CHARPENTIER - Analyse des donnees
d = 2
−1.5 −0.5 0.5 1.5
d = 2
−1.5 −0.5 0.5 1.5
d = 2
−1.5 −0.5 0.5 1.5
d = 2
−1.5 −0.5 0.5 1.5
d = 2
−1.5 −0.5 0.5 1.5
d = 2
−1.5 −0.5 0.5 1.5
101
Arthur CHARPENTIER - Analyse des donnees
d = 2
−1.5 −0.5 0.5 1.5
d = 2
−1.5 −0.5 0.5 1.5
d = 2
−1.5 −0.5 0.5 1.5
d = 2
−1.5 −0.5 0.5 1.5
d = 2
−1.5 −0.5 0.5 1.5
102
Arthur CHARPENTIER - Analyse des donnees
Retour sur la mthodologie de l’ACP
Pour resumer, on part d’un nuage de n individus dont on connaıt p variables
quantitatives, notees x.
On general, on centre et on rduit les variables pour obtenir une matrice z.
La matrice p× p de correlation de z possede des valeurs propres que l’on ordonne
λ1 ≥ λ2 ≥ · · · ≥ λk ≥ 0.
Les facteurs principaux uk sont les vecteurs propres orthonormes de la matrice de
correlation, associes aux valeurs propres λk. uk,j est le poids de la variable j dans la
composante k.
Les composantes principales ont les vecteurs ck = zuk, de taille n. ck,i est la valeur
de la composante k pour l’individu i. Notons que la variance de ck vaut λk.
Le cercle des correlation permet de visualiser les correlations entre les variables avec
les axes principaux. Seules les variables au bord du cercle sont interpretables (car bien
representes par les deux axes).
103
Arthur CHARPENTIER - Analyse des donnees
Petite digression : modeliser des taux
Considerons le jeu de donnees suivant,
load(url("http://pbil.univ-lyon1.fr/R/donnees/pps066.rda"))
Trois tableaux croisent 20 pays et 39 annees pour la consommation individuelle de
biere, vin et spiritueux. Le but est detudier la repartition entre ces trois types d’alcool
(et non pas les niveaux d’alcool consommes).
Pour cela, comme on est en dimension 3 (3 alcools possibles), on peut utiliser une
representation dite triangulaire.
104
Arthur CHARPENTIER - Analyse des donnees
0 1
Vin
10 Bière 1
0
Spiriteux
●●
●
● ●
●
●
●
●
●
●
●●
●
●
●
●●●
●
All Aut
Bel
Chy Dan
Esp
Fin
Fra Gre
Hon
Irl Ita Lux
PBa
Pol
Por
Rep RU Slq
Sue
0 1
Vin
0.90 Bière 0.9
0.1
Spiriteux
●
●
●
●
●
●
●
●
●
●
●● ●
●
●
●
●
●
●
●
All
Aut
Bel
Chy Dan
Esp
Fin
Fra
Gre Hon
Irl Ita Lux
PBa
Pol
Por Rep
RU
Slq
Sue
105
Arthur CHARPENTIER - Analyse des donnees
Retour sur la methodologie de l’ACP
Sous R, plusieurs fonctions permettent de faire des ACP
• dans library(base), la fonction princomp,
• dans library(ade4), la fonction dudi.pca, qui permet simplement de centrer et
reduire les variables.
• dans library(FactoMineR), la fonction PCA
106
Arthur CHARPENTIER - Analyse des donnees
L’ACP avec dudi.pca
Cette partie sera inspiree de Dufour & Lobry (2008), tdr601.pdf.
Considerons les donnees survey de library(MASS). On retiendra 4 variables,
• survey$Wr.Hnd correspondant a l’empan de la main d’ecriture
• survey$NW.Hnd correspondant a l’empan de la main qui n’ecrit pas
• survey$Height correspondant a la taille de la personne
• survey$sex correspondant au sexe de la personne.
107
Arthur CHARPENTIER - Analyse des donnees
L’ACP avec dudi.pca
108
Arthur CHARPENTIER - Analyse des donnees
L’ACP avec dudi.pca
109
Arthur CHARPENTIER - Analyse des donnees
L’ACP avec dudi.pca
survey.cc <- survey[complete.cases(survey), ]
mesures <- survey.cc[, c("Wr.Hnd", "NW.Hnd", "Height")]
La premiere commande permet de ne garder que les individus ne presentant pas de
valeurs manquantes. L’ACP se fait en utilisant simplement acp <- dudi.pca(mesures,
scann = FALSE, nf = 3).
Pour recuperer toutes les informations, on peut utiliser la fonction suivantes
> eval(acp$call)
Duality diagramm
class: pca dudi
$call: dudi.pca(df = mesures, scannf = FALSE, nf = 3)
$nf: 3 axis-components saved
$rank: 3
eigen values: 2.509 0.4568 0.03445
vector length mode content
1 $cw 3 numeric column weights
2 $lw 168 numeric row weights
110
Arthur CHARPENTIER - Analyse des donnees
3 $eig 3 numeric eigen values
data.frame nrow ncol content
1 $tab 168 3 modified array
2 $li 168 3 row coordinates
3 $l1 168 3 row normed scores
4 $co 3 3 column coordinates
5 $c1 3 3 column normed scores
acp$tab est la matrice z obtenue en centrant puis en reduisant la table initiale x.
acp$cw contient des points attibues a chaque variable (colonne), i.e. ici 1 partout.
acp$lw contient des points attibues a chaque individu (ligne), i.e. ici 1/n partout.
acp$eig contient le vecteur des valeurs propres.
acp$c1 donne les coordonees des variables sur les 3 permiers axes principaux. Ces
vecteurs sont de norme 1.
acp$co donne les coordonees des variables sur les 3 permiers axes principaux. Ces
vecteurs sont de norme√λ.
> acp$c1
111
Arthur CHARPENTIER - Analyse des donnees
CS1 CS2 CS3
Empan1 0.6084890 -0.3420962 0.71603859
Empan2 0.6040404 -0.3855223 -0.69750107
Taille 0.5146613 0.8569380 -0.02794614
> acp$co
Comp1 Comp2 Comp3
Empan1 0.9637816 -0.2312213 0.132897100
Empan2 0.9567355 -0.2605728 -0.129456527
Taille 0.8151685 0.5792006 -0.005186817
> t(t(acp$c1)*sqrt(acp$eig))
CS1 CS2 CS3
Empan1 0.9637816 -0.2312213 0.132897100
Empan2 0.9567355 -0.2605728 -0.129456527
Taille 0.8151685 0.5792006 -0.005186817
acp$l1 donne les coordonees des individus sur les 3 permiers axes principaux, ces
vecteurs etant unitaires
acp$li donne les coordonees des individus sur les 3 permiers axes principaux, ces
vecteurs etant unitaires
> head(acp$l1)
112
Arthur CHARPENTIER - Analyse des donnees
RS1 RS2 RS3
1 -0.18511289 0.35854289 0.7771789
2 0.65642982 -0.01654562 -2.0459458
5 0.24122137 -1.63843055 0.1095513
6 -0.35270516 0.54186131 0.3453116
7 -0.08047126 1.91845520 -0.4136080
8 -1.14527378 -1.08502402 -0.6698669
> head(acp$li)
Axis1 Axis2 Axis3
1 -0.2931990 0.24233756 0.14424478
2 1.0397147 -0.01118311 -0.37972849
5 0.3820689 -1.10740798 0.02033277
6 -0.5586473 0.36624167 0.06409000
7 -0.1274579 1.29667540 -0.07676584
8 -1.8139913 -0.73336294 -0.12432761
> head(t(t(acp$l1) * sqrt(acp$eig)))
RS1 RS2 RS3
1 -0.2931990 0.24233756 0.14424478
2 1.0397147 -0.01118311 -0.37972849
5 0.3820689 -1.10740798 0.02033277
6 -0.5586473 0.36624167 0.06409000
113
Arthur CHARPENTIER - Analyse des donnees
7 -0.1274579 1.29667540 -0.07676584
8 -1.8139913 -0.73336294 -0.12432761
Enfin, pour faire quelques graphiques, on utilise s.label ou s.class pour visualiser les
individus
> s.label(acp$li, xax = 1, yax = 2)
> s.class(acp$li, fac=sexe,col=c("red","blue"),xax = 1, yax = 2)
114
Arthur CHARPENTIER - Analyse des donnees
d = 2
1 2
5
6
7
8
9 10
11
14
17
18
20
21 22
23
24
27 28 30
32
33 34 36
38
39
42
44
47
48
49 50
51 52
53 54
55
57 59
61 62
63
65
71
73 74
75 76
77
79
82
85
86
87
88
89
91
93 95
97
98 100 102
104
105 106
109
110 111
112
113 114 115
116 117
118 119
120
122
123 124 125
127
128
129 130
131 132 134
135
136 138
140
141
143 144 145
146
147
148
149 150
151
152
153 154
155
156 158
160
161
163
164 166
167
168
170 172
174
175
176
177
178 180 181
182
183 184
185
186
187
188
189
190
191
192
193
194
196
197
198 199 200
201
202 204
205
206
207
208
209
211
212 214 215
218
220
222
223
227
228
229
230
231 233
234
236 237
d = 2
●●
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●
●●
●
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●
Female Male
Pour visualiser les variables, on utilise s.corcircle ou pour tout representer ensemble,
la fonction scatter
> s.corcircle(acp$co, xax = 1, yax = 2)
> scatter(acp)
115
Arthur CHARPENTIER - Analyse des donnees
Empan1 Empan2
Taille
d = 2
1 2
5
6
7
8
9 10
11
14
17
18
20
21
22
23
24
27 28 30
32
33 34
36
38
39
42
44
47
48
49
50
51
52
53 54
55
57
59
61 62
63
65
71
73
74 75
76
77
79
82
85
86
87
88
89
91
93 95
97
98 100 102
104
105 106
109
110 111
112
113 114 115
116 117
118
119 120
122
123 124 125
127
128
129 130
131 132
134
135
136 138
140
141
143 144
145
146
147
148
149 150
151
152
153 154
155
156 158
160
161
163
164
166
167
168
170 172
174
175
176
177
178 180 181
182
183 184
185
186
187
188
189
190
191
192
193
194
196
197
198 199 200
201
202 204
205
206
207
208
209
211
212 214 215
218
220
222
223
227
228
229
230
231 233
234
236 237
Empan1 Empan2
Taille Eigenvalues
116
Arthur CHARPENTIER - Analyse des donnees
Travaux diriges
Le TD portera sur la base de donnees departement.xls (dont une codification est
donne dans le fichier code-departement.xls) telechargeables sur ma page internet.
117