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Entity-Relationship Diagram

Relationships: Faculty members teach classes

o One faculty member may teach zero or more classeso Each class is taught by only one faculty member

Each Course may have zero or one Course as a prerequisite

o One prerequisite is associated with one Course Each Course becomes a specific class with a section number

o One Course may have many Class offeringso One Class belongs to one Course

Students enroll in classes (ClassEnrollment)o One Student has zero or more entries in classEnrollmento Each entry in classEnrollment is associated with one Studento One Class has zero or more entries in ClassEnrollmento Each entry in ClassEnrollment is associated with one Class

Each Class has a grading policyo One Class has one gradingPolicy

o

One GradingPolicy is associated with one Class Students in ClassEnrollment turn in Assignments

o Each Student enrolled in a Class has one or more assignmentso One Assignment is turned in by one Student

Each Assignment is associated with a GradingPolicyo Each GradingPolicy has many associated Assignmentso One Assignment is associated with one GradingPolicy

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Data DictionaryFaculty

Relation schema

Faculty(facultyNo, fName, lName, address, city, state, zipcode, phone)

Primary Key

facultyNo

Alternate Key

Foreign Key

Attributes

Name Description Data Type DomainCharacteristics

Required Defaultvalue

facultyNo Uniquelyidentifiesa faculty

NUMERIC(10,0) Yes

fName Facultyfirst name

VARCHAR(25) Yes

lName Faculty

last name

VARCHAR(25) Yes

Address Facultyaddress

VARCHAR(30) No

City Facultycity

VARCHAR(25) No

State Facultystate

VARCHAR(2) No

Zipcode Faculty zip NUMERIC(5,0) NophoneNumber Faculty

phoneVARCHAR(13) (XXX)-XXX-XXXX No

Enterprise constraints

None

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Students

Relation schema

Students(studentNo, fName, lName)

Primary Key

studentNo

Alternate Key

Foreign Key

Attributes

Name Description Data Type DomainCharacteristics

Required Defaultvalue

studentNo Uniquelyidentifiesa student

NUMERIC(10,0) Yes

fName Studentfirst name

VARCHAR(25) Yes

lName Studentlast name

VARCHAR(25) Yes

Enterprise constraints

None

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Courses

Relation schema

Courses(CourseNo, cost, description, prereq)

Primary Key

courseNo

Alternate Key

Foreign Key

Prereq REFERENCES Courses(courseNo)

Attributes

Name Description Data Type DomainCharacteristics

Required Defaultvalue

courseNo Course Numberof course

VARCHAR(10) Yes

Cost Cost ofcourse

Decimal(10,2)

No

Description Desc ofcourse

VARCHAR(50) Yes

prereq Prereqs forcourse

VARCHAR(10) No

Enterprise constraints

None

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Classes

Relation schema

Classes(courseNo, sectionNo, facultyNo, roomNo, hours)

Primary Key

courseNo, sectionNo

Alternate Key

Foreign Key

courseNo REFERENCES Courses(courseNo)

facultyNo REFERENCES Faculty(facultyNo)

Attributes

Name Description Data Type DomainCharacteristics

Required Defaultvalue

courseNo Course Numberof course

VARCHAR(5) Yes

sectionNo Sectionnumber ofcourse

NUMERIC(3,0) Yes

roomNo Room numberof course

VARCHAR(5) Yes

facultyNo Uniquelyidentifies afaculty

NUMERIC(10,0) Yes

Hours Hours ofcourse

NUMERIC(1,0) Yes

Enterprise constraints

None

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GradingPolicy

Relation schema

GradingPolicy(courseNo, sectionNo, activity, weight, droplowest)

Primary Key

CourseNo, sectionNo

Alternate Key

Foreign Key

courseNo, sectionNo REFERENCES Classes(courseNo, sectionNo)

Attributes

Name Description Data Type DomainCharacteristic

Required Defaultvalue

courseNo Course Number ofcourse

VARCHAR(5) Yes

sectionNo Section numberof course

NUMERIC(3,0) Yes

Activity Activityclassification

VARCHAR(10) Yes

Weight Percentageweight

NUMERIC(2,2) Yes

droplowest Drop lowest ornot

NUMERIC(1,0) No

Enterprise constraints

None

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Assignment

Relation schema

Assignment(CourseNo, sectionNo, studentNo, assignmentType, assignmentNo, grade)

Primary Key

courseNo, sectionNo, studentNo, assignmentType, assignmentNo

Alternate Key

Foreign Key

courseNo, sectionNo, studentNo REFERENCES ClassEnrollment(courseNo, sectionNo,studentNo)

courseNo, sectionNo, assignmentType REFERENCES GradingPolicy(courseNo, sectionNo,activity)

Attribute

Name Description Data Type DomainCharacteristics

Required

Defaultvalue

courseNo CourseNumber of

course

VARCHAR(5) Yes

sectionNo Sectionnumber ofcourse

NUMERIC(3,0) Yes

studentNo Student IDnumber

NUMERIC(10,0)

Yes

assignmentType Assignmentcategory

VARCHAR(10) Yes

assignmentNo Number ofassignmentforspecifiedtype

Grade Grade ofassignment

NUMERIC(10,2)

Yes

Enterprise constraints

None

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DDL Source Code

Faculty:CREATE TABLE Faculty( facultyNo numeric(10,0) NOT NULL, fName varchar2(25) NOT NULL,lName varchar2(25) NOT NULL,address varchar2(30),city varchar2(25),state varchar2(2),zipCode numeric(5,0),phone varchar2(13),CONSTRAINT faculty_pk PRIMARY KEY (facultyNo)

);

Students:CREATE TABLE Students(

studentNo numeric(10,0) NOT NULL,fName varchar2(25) NOT NULL,lName varchar2(25) NOT NULL,CONSTRAINT students_pk PRIMARY KEY (studentNo)

);

Courses:CREATE TABLE Courses(

CourseNo varchar2(5) NOT NULL,cost numeric(10,2),description varchar2(40) NOT NULL,prereq varchar2(5),CONSTRAINT Courses_pk PRIMARY KEY (CourseNo),CONSTRAINT fk_Courses FOREIGN KEY (prereq)

REFERENCES Courses(CourseNo));

Classes:CREATE TABLE Classes(

courseNo varchar2(5) NOT NULL,sectionNo numeric(3,0) NOT NULL,facultyNo numeric(10,0) NOT NULL,roomNo varchar2(10) NOT NULL,hours numeric(1,0) NOT NULL,CONSTRAINT classes_pk PRIMARY KEY (CourseNo, sectionNo),CONSTRAINT classes_fk1 FOREIGN KEY (CourseNo)

REFERENCES Courses(CourseNo),CONSTRAINT classes_fk2 FOREIGN KEY (facultyNo)

REFERENCES Faculty(facultyNo));

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ClassEnrollment:CREATE TABLE ClassEnrollment(

studentNo numeric(10,0) NOT NULL,CourseNo varchar2(5) NOT NULL,sectionNo numeric(3,0) NOT NULL,CONSTRAINT enrollment_pk PRIMARY KEY (studentNo,CourseNo,sectionNo),CONSTRAINT enrollment_fk1 FOREIGN KEY (studentNo)

REFERENCES Students(studentNo),CONSTRAINT enrollment_fk2 FOREIGN KEY (CourseNo, sectionNo)

REFERENCES Classes(CourseNo, sectionNo));

GradingPolicy:CREATE TABLE GradingPolicy(

CourseNo varchar2(5) NOT NULL,sectionNo numeric(3,0) NOT NULL,activity varchar2(10) NOT NULL,weight numeric(2,2) NOT NULL,dropLowest numeric(1,0),CONSTRAINT grading_pk PRIMARY KEY (CourseNo, sectionNo, activity),CONSTRAINT grading_fk FOREIGN KEY (CourseNo, sectionNo)

REFERENCES Classes(CourseNo, sectionNo));

Assignment:CREATE TABLE Assignment(

CourseNo varchar2(5) NOT NULL,sectionNo numeric(3,0) NOT NULL,studentNo numeric(10,0) NOT NULL,assignmentType varchar2(10) NOT NULL,assignmentNo numeric(2,0) NOT NULL,grade numeric(10,2) NOT NULL,CONSTRAINT assignment_pk PRIMARY KEY (CourseNo, sectionNo, studentNo,

assignmentType, assignmentNo),CONSTRAINT assignment_fk1 FOREIGN KEY (studentNo, CourseNo, sectionNo)

REFERENCES ClassEnrollment(studentNo, CourseNo, sectionNo),CONSTRAINT assignment_fk2 FOREIGN KEY (CourseNo, sectionNo,

assignmentType)REFERENCES GradingPolicy(courseNo, sectionNo, activity)

);

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Temporary Objects

VIEW Get Grades calculates final scores for all students in all sections of all courses.

Source Code for View GetGrades

CREATE OR REPLACE VIEW GetGrades ASSELECT COURSENO,SECTIONNO,STUDENTNO, TO_CHAR(SUM(SCORE), 00.00) as scoreFROM(

SELECT courseno,sectionno,studentno , assignmenttype,CaseWhen droplowest = 1 then (sum(Score)- min(Score))/(count(*)-1)Else sum(score)/count(*)End as score

From(Select aa.courseno, aa.sectionno, aa.studentno, aa.assignmenttype, aa.assignmentno,

aa.score,gg.droplowestFrom(

Select courseno,sectionno,studentno,assignmenttype,assignmentno, sum(weight *grade) as score

From(Select a.courseno,a. sectionno, a.studentno,a.

assignmenttype,a.assignmentno,g.weight,a. gradeFrom assignment aJoinGradingpolicy gOna.sectionno = g.sectionno and a.courseno = g.courseno

and a.assignmenttype = g.activity)group by courseno,sectionno,studentno,assignmenttype,assignmentno) aa

join gradingpolicy ggonaa.sectionno = gg.sectionno and aa.courseno = gg.courseno

and aa.assignmenttype = gg.activityorder by studentno)

group by courseno,sectionno,studentno , assignmenttype,droplowestorder by studentno)

GROUP BY COURSENO,SECTIONNO,STUDENTNOORDER BY COURSENO;

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Surrogate Key DefinitionsThe following surrogate keys were used in this logical design:

studentNoo A unique integer value assigned to students, beginning with 1.o studentNo identifies students.o It is incremented based on alphabetical order of last names.o This value is used to relate students to the courses they are taking and the assignments they turn

in for those courses. facultyNo

o A unique integer value assigned to faculty members, beginning with 1.o facultyNo identifies faculty members.

o

It is incremented based on alphabetical order of last names.o This value is used to relate faculty members with the courses they teach

assignmentTypeo Identifies the type of assignment (i.e. PA, HM, QZ, Midterm, Final)o This value is used to relate the Assignment and GradingPolicy tables through a foreign key

relationship. assignmentNo

o Identifies the number of the assignment for a given class.o For example, if CS20 Section 1 has two assignments of assignmentType QZ then the

assignmentNo for these assignments would be 1 and 2.

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Source CodeCalcGradeReport:

CREATE OR REPLACE PROCEDURE CalcGradeReport(cNo IN VARCHAR2, sNo IN VARCHAR2, p_cursor

OUT SYS_REFCURSOR)ASBEGINOPEN p_cursor FOR

SELECT s.lName, s.fName, g.courseNo, g.sectionNo, g.scoreFROM GetGrades gJOIN Students sON g.studentNo = s.studentNoWHERE g.courseNo = cNo AND g.sectionNo = sNo;

END CalcGradeReport;.RUN;

CalcTranscript:CREATE OR REPLACE PROCEDURE CalcTranscript(stufName IN VARCHAR2, stulName IN VARCHAR2, p_cursor

OUT SYS_REFCURSOR)

ASBEGINOPEN p_cursor FOR

SELECT s.lName, s.fName, g.courseNo, g.sectionNo, g.scoreFROM GetGrades gJOIN Students sON g.studentNo = s.studentNoWHERE s.fName = stufName AND s.lName = stulName;

END CalcTranscript;.RUN;

CourseEnrollment:CREATE OR REPLACE PROCEDURE CourseEnrollment(cNo IN VARCHAR2, p_cursor OUT SYS_REFCURSOR)ASBEGINOPEN p_cursor FOR

SELECT courseNo, stuCountFROM(

SELECT courseNo, COUNT(studentNo) AS stuCountFROM ClassEnrollmentGROUP BY courseNo

)WHERE courseNo = cNo;

END CourseEnrollment;.RUN;

CourseInfo:CREATE OR REPLACE PROCEDURE CourseInfo(cNo IN VARCHAR2, p_cursor OUT SYS_REFCURSOR)ASBEGINOPEN p_cursor FOR

SELECT c1.courseNo, c2.description, c1.stuCountFROM(

SELECT courseNo, COUNT(studentNo) AS stuCountFROM ClassEnrollmentGROUP BY courseNo

) c1JOIN(

SELECT courseNo, descriptionFROM Courses

) c2ON c1.courseNo = c2.courseNoWHERE c1.courseNo = cNo;

END CourseInfo;.RUN;

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DML Query Source Code Set pagesize 1000

Set linesize 1000

1.) List detail of all different courses (neither class nor section) for this institute.

SELECT *FROM COURSES;

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2.) How many active students stored in current database application?

SELECT COUNT(studentNo)FROM(

SELECT DISTINCT studentNoFROM ClassEnrollment

);

3.) How many different instructors? List their names and classes taught respectively. Order results byinstructor last name.

SELECT COUNT(*) AS InstructorCountFROM Faculty;

SELECT F.lname, F.fname, c.CourseNo, c.SectionNoFROM Faculty FLEFT OUTER JOIN Classes CON f.facultyNo=C.facultyNoORDER BY lname ASC;

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4.) How many students enrolled in a given course (For example, CS20, Intro to Computers)?

VAR rc REFCURSOREXEC CourseEnrollment(CS20,:rc);Print rc

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5.) Generate grade report for any given class/section (For example, CS25, Section 4) Order results by studentlast name.

VAR rc RefcursorEXEC CalcGradeReport('CS25', '4',:rc);Print rc

6.) Generate transcript for any given student with first name and last name only. (For example, studentYvonne Williams) Order results by ascending order of course number.

VAR rc REFCURSOREXECUTE CalcTranscript('Yvonne','Williams',:rc);Print rc

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Change LogThe following changes have been made to the original logical design:

Faculty Tableo Attributes address, city, state, zipcode, and phone are no longer required

Studentso No changes

Classo Class has been split into two separate tables

Courses Consists of attributes courseNo, cost, description, and prereq Added prereq foreign key constraint that references courseNo to prevent

inserting prerequisites for nonexistent classes Values for cost and prereq can now be NULL

Classes Consists of attributes courseNo, sectionNo, facultyNo, room, and hours Added foreign key constraint courseNo, referencing Courses table Added foreign key constraint facultyNo referencing Faculty table

CourseRecordso This table is now called classEnrollmento Primary constraint key has been added for courseNo, sectionNo, and studentNo to prevent

students from registering for the same class multiple times GradingPolicy

o Attributes participation, homework, quiz, midterm, and final have been replaced with a singleattribute, activity

o Primary key constraint has been updated to include courseNo, sectionNo, and activity Assignment

o Attribute assignmentID has been changed to assignmentNoo Old foreign key has been droppedo Added foreign key constraint courseNo, sectionNo, studentNo referencing ClassEnrollment tableo Added foreign key constraint courseNo, sectionNo, assignmentType referencing grading policy