+ All Categories
Home > Documents > CSC 8505 Compiler Construction

CSC 8505 Compiler Construction

Date post: 24-Feb-2016
Category:
Upload: doyle
View: 55 times
Download: 0 times
Share this document with a friend
Description:
CSC 8505 Compiler Construction. Optimization. Compiler Code Optimizations. A Code optimizer sits between the front end and the code generator. Works with intermediate code. Can do control flow analysis. Can do data flow analysis. Does transformations to improve the intermediate code. . - PowerPoint PPT Presentation
Popular Tags:
32
CSC 8505 Compiler Construction Optimization
Transcript
Page 1: CSC 8505 Compiler Construction

CSC 8505Compiler Construction

Optimization

Page 2: CSC 8505 Compiler Construction

Compiler Code Optimizations

• A Code optimizer sits between the front end and the code generator.– Works with intermediate code.– Can do control flow analysis.– Can do data flow analysis.– Does transformations to improve the

intermediate code.

Optimization 2

Page 3: CSC 8505 Compiler Construction

Compiler Code Optimizations

• Optimizations provided by a compiler includes:– Inlining small functions – Code hoisting – Dead store elimination– Eliminating common sub-expressions – Loop unrolling– Loop optimizations: Code motion, Induction variable

elimination, and Reduction in strength.

Optimization 3

Page 4: CSC 8505 Compiler Construction

Another Way to Organize Them• Local Optimizations

– Constant Folding– Constant Propagation– Copy Propagation– Reduction in Strength– In Lining– Common sub-expression elimination

• Loop Optimizations– Loop Invariants– Reduction in strength due to induction variables– Loop unrolling

• Global Optimizations– Dead Code elimination– Code motion

• Reordering• code hoisting

Optimization 4

Page 5: CSC 8505 Compiler Construction

Unnecessary Operations• Common subexpression elimination

– Save partial values instead of recomputing them• E.g. t = (a*a / (a*a + b*b))

• Dead code elimination– Don’t generate unreachable code

• Jump optimization– Avoid jumping to jump statements

• Useless code– Store X ; Load X

Optimization 5

Page 6: CSC 8505 Compiler Construction

Costly Operations: Constant Folding

• Don’t generate operations on constants; do them at compile time– Circ = 2 * PI * r

• If a variable will act like a constant for part or all of a program, transform its expressions also (constant propagation)

Optimization 6

Page 7: CSC 8505 Compiler Construction

Constant Folding• Subexpressions whose operands are all constants can be carried

out at compile-time.• E.g.

X := 2 * 4Rather than generating

Movi 2 r5Movi 4 r7Prim "*" [r5,r7] r9

Generate this instead

Movi 8 r9

. . .

• Code like this is not ordinarily written by programmers but is often the result of translation of index calculations.

Optimization 7

Page 8: CSC 8505 Compiler Construction

Constant Propagation• Sometimes we know a symbolic value is a constant. So

we can propagate the constant and generate better code:1 step := 42 total := 03 i := 14 total := x [i + step]

• Note that because there are no possible paths to 4 that do not pass through 1, 2 and 3 we know that i+step can be computed by (1+4) which is known at compile time to be 5.

Optimization 8

Page 9: CSC 8505 Compiler Construction

Copy Propagation• Assignments of one variable to another also propagate

information: x : = y . . . total := Z[x]• Note if my translation knows that y is stored in some

register, R7, I can use R7 rather than fetching x from memory

• Copy propagation my remove all references to x completely. This allow makes the assignment to x dead code and a candidate to further optimization.

Optimization 9

Page 10: CSC 8505 Compiler Construction

Costly Operations : Reduction in Strength

• Don’t call a power function if you can multiply – (x*x vs x^2)

• Don’t multiply when you can shift – (x<<4 vs. 16*x)

Optimization 10

Page 11: CSC 8505 Compiler Construction

Reduction in Strength• Some sequences of code can be replaced with simpler (or less

expensive) sequences.

x := 2 * y

could be replaced by

x := y + y

• Exponentiation by 2 by multiply– x ^2 == x * x

• Multiplication by factor of 2 by shift

Optimization 11

Page 12: CSC 8505 Compiler Construction

Costly Operations: Function Calls

• Function calls have overhead– Create a new activation frame– Set up parameters & return value– Remove activation frame & jump to return

• Avoid by inlining (insert function code directly

• Eliminate tail recursion with loop

Optimization 12

Page 13: CSC 8505 Compiler Construction

Compiler Code Optimizations

• Inlining small functions– Repeatedly inserting the function code

instead of calling it, saves the calling overhead and enable further optimizations.

– Inlining large functions will make the executable too large.

Optimization 13

Page 14: CSC 8505 Compiler Construction

Inlining• Some calls to

functions (especially primitives like +, -, *, absolute value, ord and char) can be inlined as a sequence of machine instructions instead of a call to a library routine.

i := abs(j)

Bneg j L2 Mov j i Br L3 L2: Neg j R2 Mov R2 i L3:

Optimization 14

Page 15: CSC 8505 Compiler Construction

Common Sub-expressions• Common subexpressions can be exploited by

not duplicating code

x := z[j+2] - w[j+2]

T1 := j+2 x := z[T1] - w[T1]

Optimization 15

Page 16: CSC 8505 Compiler Construction

Common Sub-expressions• Note that common subexpressions often occur

even when they are not in the user level code.– E.g. Subscript computations on two multi-

dimensional arrays with the same dimensions will often have common sub expressions even if the index to the arrays are completely different

Optimization 16

Page 17: CSC 8505 Compiler Construction

Loop Invariants

• Computations inside loops which remain invariant each time around the loop can be computed once outside the loop rather than each time around the loop.

• Note that index calculation may also introduces computations which are invariant around the loop.

Optimization 17

Page 18: CSC 8505 Compiler Construction

Loop Invariants

For i := 1 to N do { total := x[i] / sqr(n) + total }

T1 := sqr(n) For i := 1 to N do { total := x[i] / T1 + total }

Optimization 18

Page 19: CSC 8505 Compiler Construction

Induction Variables and reduction in strength

• Variables which vary in a regular way around loops are called induction variables.

• For loop variables are obvious cases, but implicit induction variables give much opportunity for optimization.

For i := 1 to 10 do { k := i * 4; total := x[i] + w[k] }Optimization 19

Page 20: CSC 8505 Compiler Construction

Induction Variables (2)

• Note that k varies as a linear function of i. i := 1 k := 4 while i <= 10 do { total := x[i] + w[k] i := i + 1; k := k + 4 }

Optimization 20

Page 21: CSC 8505 Compiler Construction

Loop Unrolling• Loop with low trip count can be unrolled. This

does away with the loop initialization and test for termination conditions.

list := [1,2]while (list <> nil) do { total := total + hd(list); list := tail(list) }total := total + hd(list)list := tl(list)total := total + hd(list)Optimization 21

Page 22: CSC 8505 Compiler Construction

Dead Code Elimination• Automatic generation techniques often generate code

that is unreachable.debug := false;if debug then print x;f(x);

• Because of constant propagation it is possible to tell at compile-time that the then branch will never be executed.

Optimization 22

Page 23: CSC 8505 Compiler Construction

Compiler Code Optimizations

• Dead store elimination – If the compiler detects variables that are

never used, it may safely ignore many of the operations that compute their values.

Optimization 23

Page 24: CSC 8505 Compiler Construction

Code hoisting

• Code hoisting– Moving computations outside loops– Saves computing time

Optimization 24

Page 25: CSC 8505 Compiler Construction

Code Hoisting (2)

• Code hoisting– In the following example (2.0 * PI) is an invariant

expression there is no reason to recompute it 100 times.

DO I = 1, 100ARRAY(I) = 2.0 * PI * I

ENDDO

– By introducing a temporary variable 't' it can be transformed to:

t = 2.0 * PIDO I = 1, 100

ARRAY(I) = t * IEND DO

Optimization 25

Page 26: CSC 8505 Compiler Construction

Code Motion (reordering)

• Sometimes reordering statements that do not interfere, allows other more powerful optimizations to be come applicable.

Push R2Movi 7 R3Pop R4

Movi 7 R3Push R2Pop R4

Movi 7 R3Mov R2 R4• Now copy propagation might remove R2 altogetherOptimization 26

Page 27: CSC 8505 Compiler Construction

Code Motion (Code Hoisting)

• Branches in code sometimes repeat identical calculations.• These calculations can sometimes be “hoisted” before the branch,

then they don’t have to be repeated.• This saves space, but not time.

if g(x) then x := (d*2) + w / k else x := (d*2) - w / j

T1 := (d*2);if g(x) then x := T + w / k else x := T - w / j• Multi branch “case” statements can make this quite a space saver

Optimization 27

Page 28: CSC 8505 Compiler Construction

Register Allocation

• Task: Manage scarce resources (registers) in environment with imperfect information (static program text) about dynamic program behavior.

• General aim is to keep frequently-used values in registers as much as possible, to lower memory traffic. Can have a large effect on program performance.

• Variety of approaches are possible, differing in sophistication and in scope of analysis used.

Optimization 28

Page 29: CSC 8505 Compiler Construction

Spilling

• Allocator may be unable to keep every ``live'' variable in registers; must then ``spill'' variables to memory. Spilling adds new instructions, which often affects the allocation analysis, requiring a new iteration.

• If spilling is necessary, what should we spill? Some heuristics:– Don't spill variables used in inner loops.– Spill variables not used again for ``longest'' time.– Spill variables which haven't been updated since last

read from memory.Optimization 29

Page 30: CSC 8505 Compiler Construction

Simplistic approach

• Assume variables ``normally'' live in memory.

• Use existing (often redundant) fetches and stores present in IR1.

• So: only need to allocate registers to IR temporaries (T5 etc.).

• Ignore possibility of spills.• Use simple linear scan register allocator

based on liveness intervals.Optimization 30

Page 31: CSC 8505 Compiler Construction

Liveness

• To determine how long to keep a given variable (or temporary) in a register, need to know the range of instructions for which the variable is live.

• A variable or temporary is live immediately following an instruction if its current value will be needed in the future (i.e., it will be used again, and it won't be changed before that use).

Optimization 31

Page 32: CSC 8505 Compiler Construction

Example

| live after instruction:

T2 := 3 | T2T3 := T2 | T2 T3T4 := T3 + 4 | T2 T4T4 := T2 + T4 | T4a := T4 | (nothing)

Optimization 32


Recommended