+ All Categories
Home > Documents > Data Communication Networks

Data Communication Networks

Date post: 29-Jan-2016
Category:
Upload: cynara
View: 29 times
Download: 0 times
Share this document with a friend
Description:
Data Communication Networks. Lec 10. Multilevel Schemes. Goal is to increase the number of bits per baud. m data elements encoded into a pattern of n signal elements. - PowerPoint PPT Presentation
32
Data Communication Networks Lec 10
Transcript
Page 1: Data Communication Networks

Data Communication NetworksLec 10

Page 2: Data Communication Networks

Multilevel Schemes

• Goal is to increase the number of bits per baud.• m data elements encoded into a pattern of n signal

elements.• Design are in coding of mBnL, m is the length of binary

pattern, B means binary data, n is the length of signal pattern, L is the number of levels in the signaling.

• A letter is often used in the place of L: B(binary) for L=2, T (ternary) for L=3 and Q(quaternary)for L=4.

• First two letters define the data pattern and second two define signal pattern.

Page 3: Data Communication Networks

4.3

In mBnL schemes, a pattern of m data elements is encoded as a pattern of n

signal elements in which 2m ≤ Ln.

Note

Page 4: Data Communication Networks

2B1Q(two binary, one quaternary)

• In this encoding, m=2, n=1 and L=4.• Have four different signal level, receiver has to

discern four different thresholds.• Used in DSL , to provide high speed

connection by using telephone lines.

Page 5: Data Communication Networks

4.5

Figure 4.10 Multilevel: 2B1Q scheme

Page 6: Data Communication Networks

8B6T(eight binary, six ternary)

• Used for 100BASE-4T cable.• Idea is to encode a pattern of 8 bits as a

pattern of 6 signal elements.• Each pattern has a weight of 0 or +1.

Page 7: Data Communication Networks

4.7

Figure 4.11 Multilevel: 8B6T scheme

Page 8: Data Communication Networks

4D-PAM5(four dimensional five-level pulse amplitude modulation )

• 4D means data is send over four wires at a time.

Page 9: Data Communication Networks

Multiline Transmission(MLT-3)

• Three levels(+V,0, and -V)and three transition rules to move between levels.– If next bit is 0, no transition.– If next bit is 1, and current level is not 0, the next

level is 0.– If next bit is 1, the current level is 0, the next level

is opposite of the last nonzero level.

Page 10: Data Communication Networks

Multiline Transmission(MLT-3)

• One wonder, the signal rate is same as that for NRZ-I, but greater complexity.

• Look at the worst –case.• A non-periodic signal as changed to periodic

signal.

Page 11: Data Communication Networks

4.11

Figure 4.13 Multitransition: MLT-3 scheme

Page 12: Data Communication Networks

4.12

Table 4.1 Summary of line coding schemes

Page 13: Data Communication Networks

Block Encoding

• Need redundancy , to ensure synchronization and to provide some kind of inherent error detecting.

• Block encoding changes a block of m bits into a block of n bits,where n is larger than m.– Division– Substitution– Combination

Page 14: Data Communication Networks

Block Encoding

• In division step, a sequence of bits is divided into group of m bits, e.g. 4B/5B , the original sequence is divided into 4-bit groups.

• In substitution , m-bit group for n-bit group, e.g. 4-bit code to 5-bit group.

• Finally , combine to form a stream.

Page 15: Data Communication Networks

4.15

Block coding is normally referred to as mB/nB coding;

it replaces each m-bit group with an n-bit group.

Note

Page 16: Data Communication Networks

4.16

Figure 4.14 Block coding concept

Page 17: Data Communication Networks

4B/5B(four binary/five binary)

• Designed to use in combination with NRZ-I.• NRZ-I is synchronization problem(long

sequence of 0s).• One solution is to change the bit stream , to

having no sequence of 0s.• 4B/5B achieve this goal.• A block encoded scheme does not have more

than three consecutive 0s.

Page 18: Data Communication Networks

4.18

Figure 4.15 Using block coding 4B/5B with NRZ-I line coding scheme

Page 19: Data Communication Networks

4.19

Table 4.2 4B/5B mapping codes

Page 20: Data Communication Networks

4.20

Figure 4.16 Substitution in 4B/5B block coding

Page 21: Data Communication Networks

4.21

We need to send data at a 1-Mbps rate. What is the minimum required bandwidth, using a combination of 4B/5B and NRZ-I or Manchester coding?

SolutionFirst 4B/5B block coding increases the bit rate to 1.25 Mbps. The minimum bandwidth using NRZ-I is N/2 or 625 kHz. The Manchester scheme needs a minimum bandwidth of 1 MHz. The first choice needs a lower bandwidth, but has a DC component problem; the second choice needs a higher bandwidth, but does not have a DC component problem.

Example 4.5

Page 22: Data Communication Networks

4.22

Figure 4.17 8B/10B block encoding

Page 23: Data Communication Networks

Disparity Controller

• To prevent a long run of consecutive Os or Is, the code uses a disparity controller which keeps track of excess Os over Is (or Is over Os).

• If the bits in the current block create a disparity that contributes to the previous disparity (either direction), then each bit in the code is complemented (a 0 is changed to a 1 and a 1 is changed to a 0).

Page 24: Data Communication Networks

4.24

4-3 TRANSMISSION MODES

The transmission of binary data across a link can be accomplished in either parallel or serial mode. In parallel mode, multiple bits are sent with each clock tick. In serial mode, 1 bit is sent with each clock tick. While there is only one way to send parallel data, there are three subclasses of serial transmission: asynchronous, synchronous, and isochronous.

Parallel TransmissionSerial Transmission

Topics discussed in this section:

Page 25: Data Communication Networks

4.25

Figure 4.31 Data transmission and modes

Page 26: Data Communication Networks

4.26

Figure 4.32 Parallel transmission

Page 27: Data Communication Networks

4.27

Figure 4.33 Serial transmission

Page 28: Data Communication Networks

4.28

In asynchronous transmission, we send 1 start bit (0) at the beginning and 1 or more stop bits (1s) at the end of each

byte. There may be a gap between each byte.

Note

Page 29: Data Communication Networks

4.29

Asynchronous here means “asynchronous at the byte level,”

but the bits are still synchronized; their durations are the same.

Note

Page 30: Data Communication Networks

4.30

Figure 4.34 Asynchronous transmission

Page 31: Data Communication Networks

4.31

In synchronous transmission, we send bits one after another without start or

stop bits or gaps. It is the responsibility of the receiver to group the bits.

Note

Page 32: Data Communication Networks

4.32

Figure 4.35 Synchronous transmission


Recommended