ESCUELA DE INGENIERÍA DE PETROLEOS

RUBEN DARIO ARISMENDI RUEDA

ESCUELA DE INGENIERÍA DE PETROLEOS

CHAPTER 4: ‘Direct Methods to solve lineal ecuation systems’

ESCUELA DE INGENIERÍA DE PETROLEOS

Types of Matrix.

1. RECTANGULAR:The Matrix that has different number of lines and columns mxn, Where ‘m’ is different of ‘n’.

2. Transpossition Matrix: Is the new matrix, that is obtain when the files and columns are changed.

ESCUELA DE INGENIERÍA DE PETROLEOS

3.Void Matrix. When all the elements of the Matrix are cero.

4.Simetric Matrix. Is square matrix equal to the trnsposition matrix.

5.Diagonal Matrix. Is a square matriz with all the elements cero except the element of the main diagonal.

ESCUELA DE INGENIERÍA DE PETROLEOS

6.Identical Matrix. Is a square Matrix that has all the elements cero except the element of the main diagonal that are 1.

7. Triangular. (Inferior or Superior)

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8. Inverse Matrix. A matrix is inverse when:

ESCUELA DE INGENIERÍA DE PETROLEOS

METHODS.

SIMPLE GAUSS.

This method has two main steps.

a- Forward elimination: Consist in convert the Matrix into a Superior Triangular

b- Backward sustitution: With the Inferior Matrix the last unkown value is obtained and then we have to start making substitutions.

ESCUELA DE INGENIERÍA DE PETROLEOS

We can change the order of the lines to make it easier to solve

ESCUELA DE INGENIERÍA DE PETROLEOS

F2-3f1

f3-5f1

F3-2f2

ESCUELA DE INGENIERÍA DE PETROLEOS

NOW WE START TO MAKE THE SUSTITUTIONS.

ESCUELA DE INGENIERÍA DE PETROLEOS

GAUSS-JORDAN.

This method consist in treat the Matrix and convert it into a identical Matrix, and then is more easy to solve the system.

ESCUELA DE INGENIERÍA DE PETROLEOS

F1 *(1/2)

(F1*-3)+f2

(F1*-5)+f3

(F2*(-2/13))

(F3*-2)

ESCUELA DE INGENIERÍA DE PETROLEOS

(F2*17)+f3

(F3*13/96)

(F3*-1/2)+f1

(F3*-11/13)+f2

ESCUELA DE INGENIERÍA DE PETROLEOS

(F2*-3/2)+f1

x= 1y= -1z= 2

SOLUTION:

ESCUELA DE INGENIERÍA DE PETROLEOS

3. Inverse Matrix. The inverse matrix could be used to solve a system as well.

2x + 4y + 3z = 6 y – z = - 43x + 5y + 7z =3

THE SYSTEM COULD BE WRITTEN LIKE A *x=B

ESCUELA DE INGENIERÍA DE PETROLEOS

THE INVERSE

x= 25y= -8z= -4

THE SOLUTION IS