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  • 7/30/2019 DPS-01, GOC

    1/13

    DPS-01 (GOC) Subject: Chemistry Class: 10 + 2 Dated : 17.04.13

    ELECTRONIC EFFECTS Inductive Effect

    Q1. Which of them shows incorrect representation of inductive effect

    Q2. Which of them is false for order ofI effect

    (a) F > Cl > Br > I (b)233 NOHNRN >>

    Q3. What is the % S character in hybridization of carbon when it exerts strongest I effect

    (a) 25% (b) 50% (c) 75% (d) 100 %

    Q4. Choose correct statement

    (a) I effect transfers e from one carbon atom to another

    (b) I effect operates in both / bond

    (c) I effect creates net charge in molecule

    (d) I effect is distance dependent

    Resonance

    Q5. Which is correct

    (a) Orbitals which are in same plane participate in resonance

    (b) Resonating structures have fixed arrangement of atomic nuclei

    (c) All resonating structures have equal energy

    (d) Resonating structures are real

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    (a) (b) (c) (d)

    CH3

    CH3

    O

    C OH

    O

    C O

    CH3

    CH2

    CH3

    C

    O

    (a) (d)23 NHOHOCH >> > C CH >H

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    Q6. During resonance, which is incorrect

    (a) Net charge remains same

    (b) Number of paired electron remain same

    (c) Number of unpaired electron remain same

    (d) Energy of resonating structures always remains same

    Q7. Following are not involved in resonance

    (a) bonds (b) Positive charge (vacant orbital)

    (c) Negative charge (lone pair) (b) Sigma bond

    Q8. Which of the following pairs of structures in not a pair of resonating structures?

    (a) HNCH;HNCH =

    (b) 22333 CHCHCHCH;CHCHCHCH ==

    Q9. Which of the following is not a permissible resonating form:

    Q10. Which of the following is not resonating structure of diazomethane

    Q11. Which of the following resonating structure is the minor contributor to the real structure

    (a) I (b) II (c) III (d) all are equally stable

    Q12. HNCO is isocyanic acid exists as following resonating streucutres

    The correct order of stability is(a) I > III > II (b) I > II > III (c) II > III > I (d) II > I > III

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    (c)3333 CH

    O||CCH

    O||CCH;CH

    O||CCH

    O|CCH =

    (d) ;

    (b) (c) (d)(a) O

    CH|NCH

    3

    2 +

    O

    CH|NCH

    3

    2

    +

    O

    CH|NCH

    3

    2 O

    CH|NCH

    3

    2

    +

    (b) (c) (d)(a) CH2

    N

    N

    +

    == NNCH 2

    +

    = NNHC 2 thesofall

    CH3 C OCH

    3

    I

    O

    CH3 C OCH

    3

    O

    II

    CH3 C OCH

    3

    O

    III

    +

    )III()II()I(

    OCNHOCNHOCNH ==

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    Q13. Which will be the least stable resonating structure:

    Q14. Which of the following example has both the resonating structure contributing equal to the

    resonance hybrid

    (a) 3

    3

    |33

    3

    3 CHHCCH

    CH

    CCHCHCHCH

    CH|CCH ==

    Q15. Least contributing structure in nitroethene is

    Q16. Which will be the least stable resonating structure:

    Q17. Which of the following pairs of structures do not represent resonating structures?

    Q18. Select the correct option for stability of following structures

    (a) I > II > III (b) II > I > III (c) II > III > I (d) III > I > II

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    22 NHCHCHCHCH =

    (a) (b) 22 NHCHCHCHCH =

    22 NHCHCHCHCH ==

    (c) (d) 22 NHCHCHCHCH =

    2323 HN

    O|CCHNH

    O||CCH

    =

    (b)

    (c) CH3 C CH3 C

    O

    O

    O

    O

    OCHCHHCOCHCHCH 22 ===

    (d)

    (b) (c) (d)(a) CH2

    = CH

    N

    O

    OCH

    2= CH

    N

    O

    O

    + + +CH

    2 CH N

    O

    O

    ++CH

    2 CH =

    N O

    + +O

    NO

    O

    (b) (c) (d)(a) NO

    O

    NO

    O

    N

    O

    O

    (b)(a) CH3 C

    CH3

    O

    ; CH3 C =

    CH2

    OH

    O ; O

    (d)(c) CH3 C

    CH3

    OH

    ; CH3 C =

    CH3

    OH

    CH2

    = C = O CH2 C =

    O

    O CH2

    I

    O CH2

    II

    O CH2

    III

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    Hyperconjugation

    Q19. Give the number of hydrogens involved in hyperconjugation in the following compounds?

    Application of 1-effect resonance and hyperconjugation

    Q20. Give the stability order of alkene

    Q21. Compare the following molecules with respect to:

    )I(

    2 ClCHCH =)II(

    23 ClCHCH

    (a) C Cl bond length

    (b) Dipole moment

    (c) C C bond length of (I) with respect to ethane

    (d) Boiling point

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    C = C

    CH3

    CH3

    CH3

    CH3

    C = C

    CH3 CH

    CH3

    CH3

    CH2 CH

    3

    II

    CH3

    C = C

    CH3 CH

    CH CH3

    CH2 CH

    3

    III

    CH3

    CH3 CH

    2

    CH3

    I

    C = C

    CH3 CH

    CH3CH

    CH

    CH3

    IV

    CH3

    CH

    CH3

    CH3CH

    3

    CH3

    C = C

    CH3 CH

    2

    H

    C CH3

    V

    CH3

    CH3

    CH CH3

    CH3

    Ph CH2 HC = CH C CH

    3

    CH3

    CH3

    VI

    CH3 CH CH = CH C CH

    3

    CH3

    CH3VII

    CH3

    CH3 HC = CH

    CH3

    VIII

    CH3 CH

    2

    IX

    CH3 CH CH CH

    3

    X

    CH3

    XI

    CH3 C CH

    2

    CH3

    CH3

    CH3

    XII XIII

    XIV

    CH3

    CH3

    CH3 C CH

    2

    CH3

    III

    22 CHCH =

    I

    23 CHCHCH =

    II

    H3C C

    CH3

    C CH3

    CH3

    IV

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    Q22.The electron density at benzene ring in the following compounds follows the order:

    (a) IV > III > II > I (b) I > II > III > IV (c) IV > II > I > II (d) IV > II > III > I

    Q23. Which of the following molecule has longest C = C bond length?

    (a) CH2 = C = CH2 (b) CH3 CH = CH2

    (c) 2

    3

    3

    3 CHCH

    CH|

    CH|CCH = (d)

    2

    3

    3 CH

    CH|CCH =

    Q24.The decreasing order of bond length of C = C bond in the following compounds is:

    (a) II > I > IV > III (b) III > I > II > IV (c) IV > II > I > III (d) IV > I > II > III

    Physical Properties

    Q25. Following is true for stability between the two structures.

    (a)3323 CHCH

    O|CCHCHCHH

    O|CCH =

    >=

    (b)

    2

    2

    222 CHCH

    CH||CHCCHCHCHCHCH =>==

    (c)

    232

    3

    2 HCCHCHHCHC

    CH|CCH

    =>=

    Q26. Which is ordered correctly for heat of hydrogenation

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    COOEt

    (I)

    OCOEt

    (II)

    CH3

    (III)

    NHCOCH3

    (IV)

    (I) (II)

    H3C

    H3C

    (III) (IV)

    O

    O

    O

    CCH||

    3 >

    (d)(c) > >

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    Q27. Select the option that incorrectly defines the order of electron density in benzene ring.

    INTERMEDIATE CARBOCATIONS

    Q28.The number of electrons present in the valence shell of carbon of carbonation bearing positive

    charge.

    (a) 8 (b) 7 (c) 6 (d) 4

    The most stable carbocation amongst the following is: (Q.29- Q37)

    Q29.

    (a)223 HCCHCH

    (b) 323 CHCHHCCH

    (c)

    C)CH( 33(d) (CH3)3C

    2HC

    Q30.

    (a)23 HCCH

    (b) 22 CHClHC

    (c) ClCHHC 22

    (d)

    222 NOCHHC

    Q31.

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    (a)

    OH

    > > >

    Cl NO2

    (b)

    NH2

    > > >

    CN NO2

    NO

    (c)

    CN

    < < > >

    OH OCH3O

    (b) (c) (d)(a)

    CH2

    Cl

    CH2

    NO2

    CH2

    OCH3

    CH2

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    Q32.

    (a)23 HCCH

    (b) OCCH 3 =

    (c) NHCCH 3 =

    (d) HCCH 2

    =

    Q33.

    Q34.

    Q35.

    Q36.

    (a)2462 HCHCNOp

    (b) 256 HCHC

    (c)246 HCHCClp

    (d) 2463 HCHCOCHp

    Q37.

    Q38.The most unstable carbocation is

    (a)23 HCCH

    (b)

    22 HCCHCl

    (c) CHOHC 2

    (d)32 CHOHC

    Q39.The most unstable carbocation is

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    (b) (c) (d)(a)

    CH2

    CH3

    CH2

    CH3

    CH2

    CH3

    H C CH3

    (b) (c) (d)(a)

    CH3

    CH3

    CH3

    CH2

    (b) (c) (d)(a) CH2 CH

    2

    CH2

    ( ) HCCHCH 223

    ( ) CCHCH 323

    (a)

    (b)

    23 CHOCH 2

    3

    2 HCH

    CH|CCH

    23 CHOCH 3

    3

    2 HC

    CH|CCH

    (c) 23 CHOCH 3

    3

    CHH

    CH|CHC

    (d) HCOCH 3

    3

    3

    2 CHH

    CH|CCH

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    (a)3HC

    (b)23 HCCH

    (c)2CH

    (d)

    32HC

    Q40.The species having maximum electron deficiency is

    (a) ( ) CCH 33 (b) 23 HCCH

    (c) ( ) HCCH 23

    (d)3HC

    Q41. Nonplanar cation is

    (a)4HN

    (b)

    3HC

    (c)

    OCCH 3

    (d) (CH3)3C+Sb

    6F

    Q42.The stability order of following carbocation is

    (a) I > II > IV > III (b) III > I > II > IV (c) IV > II > III > I (d) II > IV > III > I

    Q43. Following carbocation changes to more stable carbocation:

    Q44. In the following reaction, most stable intermediate is

    += HBrCHCHCH|

    CH|CCH 2

    3

    3

    3

    3

    3

    3

    3 CHHC

    CH|

    CH|CCH)a(

    22

    3

    3

    3 HCCH

    CH|

    CH|CCH)b(

    3

    33

    3 CHH

    CH

    |C

    CH

    |CCH)c(

    BrCHHC

    CH|

    CH|CCH)d(

    2

    3

    3

    3

    Q45.The following carbocation rearranges to

    3

    3

    33

    CH|

    CH|

    OH|

    CHCCCH

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    III

    CH2

    IVIII

    2HC

    (b) (c) (d)(a) 2HC

    CH3

    CH3

    CH2

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    (a) 3

    3

    2

    3 CHH

    CH|

    OH|CH

    HC|CCH

    (b) 3

    3

    3

    3 CHH

    CH|C

    OH|

    CH|CCH

    (c)3

    3

    3

    3 CH

    OH|C

    CH|

    CH|CCH

    (d) None of above

    Q46.The following carbocation rearranges to

    Q47.The following carbocation rearranges to

    Space for Rough Work

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    CH2

    = C CCHCH H

    H3C CH

    3

    CH3

    CH3

    (b)(a) CH2

    = C CH CH CH H

    CH3

    CH3

    CH3

    CH2

    CH2

    = C C CH2 C H

    CH3

    CH3

    CH3

    CH3

    (d)(c) CH2

    = C C CH C CH3

    CH3

    CH3

    CH3

    CH3

    H

    CH2

    = C C CH CH CH3

    CH3

    CH3

    CH3

    CH3

    N

    C

    CH3H

    3C

    (b) (c) (d)(a)

    N C

    H3C

    CH3

    N C

    CH3

    CH3 CH

    3

    CN

    CH

    3

    CH3

    N C

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    Q48. Match the correct order for stability of following positive charges

    Column I Column-II

    (A

    )

    (a) II > IV > III >

    I

    (B

    )

    (b) III > I > IV>

    II

    (C

    )

    (c) IV > II > III >I

    Q49. Statement 1: (CH3)3C+ is more stable carrbocation than (CD3)3C

    +

    Statement 2: C H bond is weaker than C D bond.

    (a) Statement-1 is True, Statemetn-2 is True; Statemetn-2 is a correct explanation for

    statement-1

    (b) Statement-1 is true, Statement-2 is True; Statemetn-2 is NOT a correct explanation for

    Statement-1

    (C) Statemetn-1 is True, Statemetn-2 is False

    (d) Statement 1 is False, Statement-2 is true

    ANIONS

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    (I)

    (II)

    CH2

    (III)

    CH2 CH

    2

    (IV)

    CH CH3

    (I)

    (II)

    OH

    (III)

    CH2

    (IV)

    NO2

    CH2

    OHHO

    O2N

    NO2

    OH

    NO2

    CH2

    O2N

    CH2

    HO

    (I) (II) (III) (IV)

    CH3

    OCH3

    Cl

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    Q50. Arrange the following carbanions in decreasing order of stability

    (a) III > IV > I > II (b) III > IV > II > I (c) III > I > IV > II (d) IV > III > I > II

    Q51. Arrange the following carbanions in decreasing order of stability

    (a) III > II > IV > I (b) III > II > I > IV (c) III > I > II > IV (d) II > III > I > IV

    Q52. Arrange the following carbanions in decreasing order of stability

    (a) IV > III > I > II (b) IV > II > III > I (c) IV > III > II > I (d) III > IV > II > I

    Q53. Arrange the following carbanions in decreasing order of stability

    (a) III > I > IV > I (b) III > II > I > IV (c) I > III > II > IV (d) III > I > II > IV

    Q54. O||

    HCHC

    O||CHCCHCIf 3

    S

    2

    R

    2

    Q

    3

    P

    is mixed with NaOH solution. Acid base reaction occurs

    and HO snatches H from organic molecule. Which carbon will loose H+ easily?

    (a) P (b) Q (c) R (d) SQ55. Which of the following intermediate have the complete octet around the carbon atom

    (a) Carbonium ion (b) Carbanion (c) Free radical (d) Carbene

    Q56. Select the correct options

    (a) Carbanion are good lewis acids

    (b) Number of e- in outermost shell of methyl carbanion is 6

    (c) Electron withdrawing groups stabilizes carbanion

    (d) Carbanions can rearrange to form more stable anions

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    22 CHCH

    (I)

    332 )CH(CCH

    (II)

    CH2

    (III) (IV)

    3CH

    CH2 Cl

    (I)

    CH2 CN

    (II)

    CH2 NO

    2

    (III)

    CH2 CH

    3

    (IV)

    CHOCH 2

    33 CHCCHCCH

    O O

    HCCHCH

    O O

    CHOCOHC

    CHO

    (I) (II) (III) (IV)

    CH2

    (I)

    CH2

    CH3

    CH2

    NO2

    CH2

    OCH3

    (II) (III) (IV)

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    Q57. Which of these reaction can form carbon

    (a) + LiBrCH 3 (b) + MgICH 3

    Q58. In which set first is more stable than second

    FREE RADICALS

    Q59. Arrange the radicals in their decreasing order of stability

    (a) IV > I > III > II (b) IV > III > II > I (c) I > II > III > IV (d) IV > III > I > II

    Q60. Following is incorrect about radicals

    (a) They are plannar in shape

    (b) They are paramagnetic

    (c) They have incomplete octate

    (d) They are very less reactive as compared to other cations/ anions

    Q61. Most stable radical is

    Q62. In which case first is more stable than second

    Q63. Arrange the radicals in their decreasing order of stability

    PIE CLASSES:- SHOP NO. 13,F-TYPE, SEC.3 MARKET,CBD BELAPUR NAVI MUMBAI MOB.-9702015327/9820430684

    Cl

    + NaNa

    (C) (d) +CuClLiCH 3

    (a)

    (b)

    (c) (d)

    3CF 3CCl

    CHCHCHC 2 =

    ( ) 333 CHCCH

    (I) (II) (III) (IV)3CH 23 CHCH 23 CHCH

    CH3

    CCH 3

    CH3

    CH3

    (a)

    (b)

    (c) (d)

    (a)

    (b)

    (c) (d)

    ( ) CCHCPh 333

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    (a) III > II > IV > I (b) III > IV > II > I (c) III > II > I> IV (d) II > III > IV > I

    CH2

    (I) (II) CH2

    (III) C (IV)


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