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Page 1: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Easy Average Difficult Clincher

1 6 11 14

2 7

3 8 12 15

4 9

5 10 13 16

Page 2: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

109876543210END10

Consistent with vanadium being a transition metal,

the name for VSO4 should be

A. vanadium sulfide.

B. vanadium (I) sulfite.

C. vanadium (I) sulfate.

D. vanadium (II) sulfate.

E. vanadium sulfur tetraoxide.

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Answer Main

3029282726252423222120191817161514131211109876543210END30

Consider the element with the electron

configuration [Kr]5s24d7. This element is

A. an alkali metal.

B. a transition metal.

C. a nonmetal.

D. an actinide element.

E. a noble gas.

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Answer Main

20191817161514131211109876543210END20

Which of the following represents an acid-base

neutralization reaction?

A. 2Al(s) + 3H2SO4(aq) Al2(SO4)3(aq) + 3H2(g)

B. SO2(g) + H2O(l) H2SO3(g)

C. LiOH(aq) + HNO3(aq) LiNO3(aq) + H2O(l)

D. 2KBr(aq) + Cl2(g) 2KCl(aq) + Br2(l)

E. CaBr2(aq) + H2SO4(aq) CaSO4(s) + 2HBr(g)

Page 5: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

For what order reaction does the half-life

remains constant as the initial concentration

increases?

A. zeroth order

B. first order

C. second order

D. none of them because half-life is always

independent of the initial concentration

20191817161514131211109876543210END20

Page 6: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

According to the collision theory, all collisions do not lead to

reaction. Which choice gives both reasons why not all

collisions between reactant molecules lead to reaction?

1.The total energy of two colliding molecules is less than

some minimum amount of energy.

2.Molecules cannot react with each other unless a catalyst is

present.

3.Molecules that are improperly oriented during collision will

not react.

4. The temperature is not high enough.

20191817161514131211109876543210END20

Page 7: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

Consistent with vanadium being a transition metal,

the name for VSO4 should be

A. vanadium sulfide.

B. vanadium (I) sulfite.

C. vanadium (I) sulfate.

D. vanadium (II) sulfate.

E. vanadium sulfur tetraoxide.

Page 8: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

Consider the element with the electron

configuration [Kr]5s24d7. This element is

A. an alkali metal.

B. a transition metal.

C. a nonmetal.

D. an actinide element.

E. a noble gas.

Page 9: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

Which of the following represents an acid-base

neutralization reaction?

A. 2Al(s) + 3H2SO4(aq) Al2(SO4)3(aq) + 3H2(g)

B. SO2(g) + H2O(l) H2SO3(g)

C. LiOH(aq) + HNO3(aq) LiNO3(aq) + H2O(l)

D. 2KBr(aq) + Cl2(g) 2KCl(aq) + Br2(l)

E. CaBr2(aq) + H2SO4(aq) CaSO4(s) + 2HBr(g)

Page 10: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

For what order reaction does the half-life

remains constant as the initial concentration

increases?

A. zeroth order

B. first order

C. second order

D. none of them because half-life is always

independent of the initial concentration

Page 11: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

According to the collision theory, all collisions do not lead to

reaction. Which choice gives both reasons why not all

collisions between reactant molecules lead to reaction?

1.The total energy of two colliding molecules is less than

some minimum amount of energy.

2.Molecules cannot react with each other unless a catalyst is

present.

3.Molecules that are improperly oriented during collision will

not react.

4. The temperature is not high enough.

Answer: 1 and 3

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Answer Main

6059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END60

A 3.682 g sample of KClO3 is dissolved in

enough water to give 375. mL of solution.

What is the chlorate ion concentration in

this solution?

Page 13: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

6059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END60

A glass containing 200. g of H2O at 20°C

was placed in a refrigerator. The water

loses 11.7 kJ as it cools to a constant

temperature. What is its new temperature?

The specific heat of water is 4.184 J/g·°C.

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Answer Main

6059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END60

The reaction C4H10 C2H6 + C2H4 has an

activation energy (Ea) of 350 kJ/mol, and the

Ea of the reverse reaction is 260 kJ/mol.

Estimate H, in kJ/mol, for the reaction as

written above.

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Answer Main

For the reaction

BrO3 + 5Br+ 6H+ 3Br2 + 3H2O

at a particular time, [BrO3]/t = 1.5 10-2

M/s. What is [Br]/t at the same instant?

6059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END60

Page 16: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

The appropriate unit for a first-order rate constant is

A. M/s

B. 1/M·s

C. 1/s

D. 1/M2·s

6059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END60

Page 17: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

A 3.682 g sample of KClO3 is dissolved in

enough water to give 375. mL of solution.

What is the chlorate ion concentration in

this solution?

Ans = 8.01 102 M

Page 18: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

A glass containing 200. g of H2O at 20°C

was placed in a refrigerator. The water

loses 11.7 kJ as it cools to a constant

temperature. What is its new temperature?

The specific heat of water is 4.184 J/g·°C.

Answer: 6°C

Page 19: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

The reaction C4H10 C2H6 + C2H4 has an

activation energy (Ea) of 350 kJ/mol, and the

Ea of the reverse reaction is 260 kJ/mol.

Estimate H, in kJ/mol, for the reaction as

written above.

Answer: +90 kJ/mol

Page 20: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

For the reaction

BrO3 + 5Br+ 6H+ 3Br2 + 3H2O

at a particular time, [BrO3]/t = 1.5 10-2

M/s. What is [Br]/t at the same instant?

Answer: 7.5 102 M/s

Page 21: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

The appropriate unit for a first-order rate constant is

A. M/s

B. 1/M·s

C. 1/s

D. 1/M2·s

Page 22: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

9089888786858483828180797877767574737271706968676665646362616059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END90

For the reaction:

C(graphite) + O2(g) CO2(g), H° = 393 kJ/mol

How many grams of C(graphite) must be burned to

release 275 kJ of heat?

Page 23: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

9089888786858483828180797877767574737271706968676665646362616059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END90

Ammonia reacts with diatomic oxygen to form

nitric oxide and water vapor:

4NH3 + 5O2 4NO + 6H2O

When 1.20 mol NH3 and 1.75 mol O2 are

allowed to react, which is the excess reagent

and by how much?

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Answer Main

The isomerization of cyclopropane to propene

follows first-order kinetics. At 700 K, the rate

constant for this reaction is 6.2 104 min 1. How

many minutes are required for 10.0% of a sample of

cyclopropane to isomerize to propene?

C3H6 (cyclopropane) C3H6 (propene)

9089888786858483828180797877767574737271706968676665646362616059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END90

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Answer Main

For the reaction:

C(graphite) + O2(g) CO2(g), H° = 393 kJ/mol

How many grams of C(graphite) must be burned to

release 275 kJ of heat?

Answer: 8.40 g

Page 26: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

Ammonia reacts with diatomic oxygen to form

nitric oxide and water vapor:

4NH3 + 5O2 4NO + 6H2O

When 1.20 mol NH3 and 1.75 mol O2 are

allowed to react, which is the excess reagent

and by how much?

Answer: 0.25 mol O2

Page 27: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

The isomerization of cyclopropane to propene

follows first-order kinetics. At 700 K, the rate

constant for this reaction is 6.2 104 min 1. How

many minutes are required for 10.0% of a sample of

cyclopropane to isomerize to propene?

C3H6 (cyclopropane) C3H6 (propene)

Answer: 170 min

Page 28: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

1801791781771761751741731721711701691681671661651641631621611601591581571561551541531521511501491481471461451441431421411401391381371361351341331321311301291281271261251241231221211201191181171161151141131121111101091081071061051041031021011009998979695949392919089888786858483828180797877767574737271706968676665646362616059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END180

Given:

2Al(s) + (3/2)O2(g) Al2O3(s), H°f = 1,670 kJ/mol

Determine H for the reaction:

2Al2O3(s) 4Al(s) + 3O2(g)

Page 29: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

The isomerization of cyclopropane follows

first order kinetics. The rate constant at 700

K is 6.20 104 min1, and the rate constant

at 760 K is 0.024 min 1. Calculate the

activation energy for this reaction.

1801791781771761751741731721711701691681671661651641631621611601591581571561551541531521511501491481471461451441431421411401391381371361351341331321311301291281271261251241231221211201191181171161151141131121111101091081071061051041031021011009998979695949392919089888786858483828180797877767574737271706968676665646362616059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END180

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Answer Main

Given that Ea for a certain biological

reaction is 48 kJ/mol and that the rate

constant is 2.5 102 s1 at 15C, what

is the rate constant at 37C?

1801791781771761751741731721711701691681671661651641631621611601591581571561551541531521511501491481471461451441431421411401391381371361351341331321311301291281271261251241231221211201191181171161151141131121111101091081071061051041031021011009998979695949392919089888786858483828180797877767574737271706968676665646362616059585756555453525150494847464544434241403938373635343332313029282726252423222120191817161514131211109876543210END180

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Answer Main

Given:

2Al(s) + (3/2)O2(g) Al2O3(s), H°f = 1,670 kJ/mol

Determine H for the reaction:

2Al2O3(s) 4Al(s) + 3O2(g)

Answer: 3,340 kJ/mol

Page 32: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

The isomerization of cyclopropane follows

first order kinetics. The rate constant at 700

K is 6.20 104 min1, and the rate constant

at 760 K is 0.024 min 1. Calculate the

activation energy for this reaction.

Answer: 270 kJ/mol

Page 33: Easy Average Difficult Clincher - WordPress.com · Easy Average Difficult Clincher 1 6 11 14 2 7 3 8 12 15 4 9 5 10 13 16. Answer Main END108096543271 Consistent with vanadium being

Answer Main

Given that Ea for a certain biological

reaction is 48 kJ/mol and that the rate

constant is 2.5 102 s1 at 15C, what

is the rate constant at 37C?

Answer: 0.104 s1


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