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Page 1: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Edward Wen

Solutions

Page 2: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

2

Learning Outcomes

• Solutions (applying solubility rules, calculations with concentrations and dilutions)

• Definition and description of the properties of Colloids

• Definition and description of the properties of Suspensions

• Osmotic pressure effects on cells – defining isotonic, hypotonic, hypertonic

Page 3: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Solution• Homogeneous mixtures

composition may vary from one sample to anotherappears to be one substance, though contains multiple

materials

• most Homogeneous materials are actually SolutionsGas state: common airLiquid: Gasoline (dozens of compounds), Soda water

(sugar or asparatame, CO2, citric acid, fructose)Solid: Alloy such as brass

Page 4: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Solutions: Solute + Solvent

• Solute: the dissolved substance. Sugar in Sodaseems to “disappear”“takes on the state” of the solvent

• Solvent: the substance solute dissolves in. Water in Sodadoes not appear to change state

• Aqueous solutions: solutions in which the solvent is water.

Page 5: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Common Types of Solution

Solution PhaseSolute Phase

Solvent Phase Example

Gaseous solutions gas gas air (mostly N2 & O2)

Liquid solutions

gas

liquid

solid

liquid

liquid

liquid

soda (CO2 in H2O)

vodka (C2H5OH in H2O)

seawater (NaCl in H2O)

Solid solutions solid solid brass (Zn in Cu)

•Alloys: solutions that contain Metal solutes and a Metal solvent, such as Nickel (5 cents of 1$), Brass, Stainless steel

Page 6: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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How Soluble? Solubility

• Soluble: when one substance (solute) dissolves in another (solvent) Homogeneous Salt and Sugar are soluble in water: Saline and

SodaAcetic acid (HC2H3O2) in water: VinegarOxygen gas in Nitrogen gas: Air

• Insoluble: when one substance does not dissolve in another Heterogeneous Oil is insoluble in water: Italian salad dressing

Page 7: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Will It Dissolve?Chemist’s Rule of Thumb –

Like Dissolves Like• a chemical will dissolve in a

solvent if it has a similar structure to the solvent

• when the solvent and solute structures are similar, the solvent molecules will attract the solute particles at least as well as the solute particles to each other

Page 8: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Classifying Solvents

Solvent Class

Structural

Feature

Water, H2O polar O-H

Ethyl Alcohol, C2H5OH polar O-H

Acetone, C3H6O polar C=O

Toluene, C7H8 nonpolar C-C & C-H

Hexane, C6H14 nonpolar C-C & C-H

Page 9: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Solubility in Water, A Polar Solvent?• Ionic compound (Yes): Ions are attracted to polar Water.

Salt NaCl dissolve in water

• Polar molecules (Yes): attracted to polar solvents table Sugar, Alcohol, glucose

• Nonpolar molecules are NOT attracted to Water -carotene, (C40H56), is not water soluble; it dissolves in fatty

(nonpolar) tissues

Those molecules with both polar and nonpolar structures: depends on structural features in the molecule

Page 10: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Salt Dissolved in Water

Page 11: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Solubility• Definition: the maximum amount of solute that

can be dissolved in a given amount of solvent• Usually a limit to the solubility of one substance

in anotherExceptions: gases are always soluble in each

othertwo liquids that are mutually soluble are said to

be miscible alcohol and water are miscibleoil and water are immiscible

Page 12: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Descriptions of Solubility• Saturated solutions have the maximum amount of

solute that will dissolve in that solvent at that temperature

• Unsaturated solutions can dissolve more solute• Supersaturated solutions are holding more solute

than they should be able to at that temperatureunstable

Page 13: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Solubility of Solid Depends on Temperature

Higher temp higher solubility of solid in liquid

Lower temp higher solubility of gas in liquid

Page 14: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Solubility of Gases Decreases at higher Temperature

Observation 1: Warm soda pop fizzes more than cold soda pop Cause: Solubility of CO2 in water decreases as temperature increases.

Observation 2: When water is heated up, gas bubbles appear even before boiling occurs.Cause: Solubility of air in water decreases as temperature increases.

Page 15: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Solubility of Gas depends on PressureHenry’s Law:

•higher pressure = higher solubility

•CO2 is dissolved under Pressure into bottled/canned soda

Page 16: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Under which conditions does sugar have the best solubility?

A. high temperature and high pressure

B. high temperature and low pressure

C. low temperature and low pressure

D. low temperature and high pressure

Page 17: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Under which conditions does oxygen gas have the best solubility?

A. high temperature and high partial pressure (PO2)

B. high temperature and low partial pressure

C. low temperature and low partial pressure

D. low temperature and high partial pressure

Page 18: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Solution Concentration Descriptions

• Concentrated solutions have high solute concentrations. Example: Soda syrup before mixed with carbonated water.

• Diluted solutions have low solute concentrations. Example: Soda drink from adding carbonated water to syrup

Page 19: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Concentrations – Quantitative Descriptions of Solutions

• Solutions have variable composition. Salt vs. Water in Seawater

• To describe a solution accurately, you need to describe the components and their relative amounts

• Concentration = amount of solute in a given amount of solutionSeawater: Salt concentration 3.4%Dead Sea: Salt concentration 30%Vinegar: Acetic acid concentration 5%

Page 20: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Weight/Volume Percent (w/v)%

• mass of solute (gram) in every 100 mL of solutionVinegar is 5% (w/v) solution of acetic

acid by mass, then there are 5 grams of acetic acid in every 100 mL of vinegar

Mass of Solute, g(w/v)% 100%

Volume of Solution, mL

Page 21: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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InformationGiven: 0.35 g phenol. 25 mL

solutionFind: (w/v)%

Example:Chloraseptic sore throat spray contains 0.35 g of phenol in 25 mL of solution. Find the weight/volume percent concentration of phenol.

0.35 g phenol(w/v)% 100% 1.4% (w/v) phenol

25 mL solution

Page 22: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Volume/Volume Percent (v/v)%

• Volume of solute (mL) in every 100 mL of solutionCommon rubbing alcohol is 50~91%

(v/v) solution of isopropanol (or 2-propanol) in every 100 mL of solution.

Volume of Solute, mL(v/v)% 100%

Volume of Solution, mL

Page 23: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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InformationGiven: 101 mL ethanol, 750

mL solution (wine)Find: (v/v)%

Example:A 750-mL bottle of wine contains 101 mL of ethanol. Find the volume/volume percent concentration of ethanol.

101 mL ethanol(v/v)% 100% 13.5% (v/v) ethanol

750 mL solution

Page 24: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Mass Percent (%)• mass of solute (gram) in every 100

gram of solution if a solution is 0.9% by mass, then there

are 0.9 grams of solute in every 100 grams of solution

• Mass of solution = Mass of solute + Mass of solvent

Solution of Mass Solvent of Mass Solute of Mass

%100g Solution, of Mass

g Solute, of Mass Percent Mass

Page 25: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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%.

%

100nsol' g 5220

OHC g 7.52Percent Mass

100solution mass

solute mass Percent Mass

62

= 13.5802%

Information

Given: 27.5 g C2H6O; 175 g H2OFind: % by massEq’n:

Example:Calculate the mass percent of a solution containing 27.5 g of ethanol (C2H6O) and 175 g of H2O

%100nSol' g

Solute g % Mass

= 13.6%

Page 26: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Parts per million (ppm) concentration

• mass of solute (gram) in every 1,000,000 gram of solution

• Orvolume of solute (mL) in every 1,000,000 milliliter of

solution

6Mass of Solute, gppm 10

Mass of Solution, g

6Volume of Solute, mLppm 10

Volume of Solution, mL

Page 27: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Using Concentrations asConversion Factors

• concentrations show the relationship between the amount of solute and the amount of solvent12% by mass sugar(aq) means 12 g sugar 100 g solution

• The concentration can then be used to convert the amount of solute into the amount of solution, or visa versa

Page 28: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Information

Given: 85.2 g C12H22O11

Find: mL sol’n

CF: 11.5 g C12H22O11 100 mL sol’n

SM: g sucrose → g sol’n → mL sol’n

Example:A soft drink contains 11.5% (w/v) sucrose (C12H22O11). What volume of soft drink in milliliters contains 85.2 g of sucrose?

741 mL

Page 29: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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InformationGiven: 500. mL rubbing alcoholFind: mL sol’n

CF: 85 g isopropanol 100 mL rubbing alcohol

Example:Rubbing alcohol contains 85% (v/v) isopropanol. What volume of isopropanol is contained in 500. mL rubbing alcohol?

4.3 x 102 mL

Page 30: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Molarity Concentration

READ the label in the reagent bottleREAD the label in the reagent bottle! “What does ‘6 M HCl’ mean?”•Definition: Moles of solute per 1 liter of solution•Purpose: describing how many molecules of solute in each liter of solution

•Unit: mole/L, abbreviated as “M”.•If a sugar solution concentration is 2.0 M , 1 liter of solution contains 2.0 moles of sugar, 2 liters = 4.0 moles sugar, 0.5 liters = 1.0 mole sugar

molarity = moles of soluteliters of solution

Page 31: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Why Molarity?Many reagents used in chemistry, even many biology

labs, are in the form of solution. Molarity concentration of solution is particularly

important and useful because

• Easy to prepare a solution to a given molarity• Easy to use: To obtain given amount (mole) of

reagent, just calculate the volume of solution to be used:

Volume (L) = mole molarity

Page 32: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Example:

Calculating Molarity

Page 33: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Information

Given: 250 mL solution; 15.5 g NaCl NaCl;

Example:Calculate the molarity of a solution made from 15.5 g of NaCl in 250 mL solution.

solution liters

solute moles Molarity

1.06 M NaCl

Page 34: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Calculations involving Molarity

Molarity = mole Volume (L)

• Solve for mole:

Mole = Molarity Volume (L)

• Solve for volume of solution in liters:

Volume (L) = mole molarity

Page 35: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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10.9 L solution

Information

Given: 1.24 mol NaOH

Find: L solution

CF: 0.114 mol = 1 L

SM: mol → L

Example:How many liters of a 0.114 M NaOH solution contains 1.24 mol of NaOH?

Page 36: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Information

Given: 0.2334 M (NH4)2S solution

V = 11.25 mL

Find: mol (NH4)2S

CF: 0.2334 mol = 1 L

Example:How many moles of (NH4)2S are in 11.25mL 0.2334 M (NH4)2S solution?

0.002626 mol

Page 37: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Information

Given: 0.2000 M NaCl solution

V = 10.00 mL

Find: gram NaCl

CF: 1 L = 0.2000 mol

1 mol NaCl = 58.44 g NaCl

Example:How many grams of NaCl are in 10.00 mL 0.2000 M NaCl solution?

0.1169 g

Page 38: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

• When mixing more solvent into a solution, the volume of final solution is greater than the original solution

• The mole of solute remains the same before and after mixing more solvent

• The final concentration of solution is lower than in the beginning (diluted)

Dilution: More Solvent Added

Page 39: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Making a Solution by Dilution

Dilution: mole solute is the same = MM11 x V x V11 = M = M22 x V x V22

Example:

A student added 1.00 L water to 2.00 L 1.00 M HCl. The final volume became 3.00 L. What is the final concentration?

0.667 M.

Page 40: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Example: Making solution from concentrate: What Volume of 12.0 M KCl Is Needed to Make

5.00 L of 1.50 M KCl Solution?Given:

Initial solution Final solution

Concentration 12.0 M 1.50 M

Volume ? L 5.00 L

0.625 L

Page 41: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Example—Determine the Concentration of the Solution after dilution

• A solution made by diluting 125 mL of 0.80 M HCl to 500 mL.

M2 = 0.20 M

Page 42: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Physical Properties Affected by Concentration

Change in Concentration affects the physical properties of solution.•Vapor pressure of solvent•Freezing point of solution•Osmotic pressure

Page 43: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Boiling Point Elevation: Reduced evaporation in solution

A liquid solution containing a nonvolatile solute has higher boiling point than the pure solvent

Page 44: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Freezing point Depression

• A water-antifreeze mixture has a higher boiling point and lower freezing point than pure water. This will reduce the chance of engine coolant being frozen or being evaporated too quickly.

• Spray salt on icy road help preventing ice on the road.

A liquid solution containing a nonvolatile solute has lower freezing point than the pure solvent.

Page 45: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Osmosis

Higher concentration of solution has stronger tendency to uptake solvent

The liquid level in the tube rises until equilibrium is reached.

Page 46: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Osmosis

Semi-permeable membrane separating (a) pure water and a salt-water solution, and (b) a dilute salt-water solution.

Worm cruelty: salt on earthworm or snail too.

Page 47: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Osmotic Pressure and Reverse Osmosis (RO)

Osmotic pressure is the amount of pressure needed to prevent the solution in the tube from rising as a result of the process of osmosis.

RO: When the added pressure exceeds the osmotic pressure, pure water leaves the concentrated solution.

Page 48: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Red blood cell in NaCl solutions

(a) Hyptonic solution. In pure water, cell absorbs water and swells.

(b) Crenation in concentrated sodium chloride solution. Cell loses water and collapses.

(c) Cells neither swell nor shrink in physiological saline solution.

Copyright David M. Phillips/Visuals Unlimited

Page 49: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

Dialysis

Through the semipermeable membrane, there is a net movement of ions and small molecules from a region of higher concentration to a region of lower concentration.

Larger molecules such as protein remains inside the membrane.

Page 50: Edward Wen Solutions. 2 Learning Outcomes Solutions (applying solubility rules, calculations with concentrations and dilutions) Definition and description.

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Dialysis in Real World


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