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EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100...

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EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 EE 42/100: Lecture 8 1 st -Order RC Transient Example, Introduction to 2 nd -Order Transients
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Page 1: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

EE 42/100: Lecture 8

1st-Order RC Transient Example, Introduction to 2nd-Order Transients

Page 2: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Circuits with non-DC Sources

Recall that the solution to our ODEs is Particular solution is constant for DC sources. Allows us to plug in final condition found using

DC steady-state. But in general, the particular solution may

not be constant!

Page 3: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

RC Example: Sinusoidal Source

This circuit looks like another innocent RC circuit, but… the source is sinusoidal! Governing ODE:

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Page 4: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

RC Example: Sinusoidal Source

Because the forcing function is now sinusoidal, so is the particular solution. We now want a part. solution of the form

We will plug this solution back into the

ODE to solve for the constants No DC steady-state final condition!

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Page 5: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

RC Example: Sinusoidal Source

We plug into the ODE: The sine terms must sum to 5, while the

cosine terms must sum to 0.

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Page 6: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

RC Example: Sinusoidal Source

We obtain a system of linear equations: The solution is

Thus,

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Page 7: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

RC Example: Sinusoidal Source

Last step: homogeneous solution Combine with the particular solution:

Finally, use initial condition to solve for K.

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Page 8: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

RC Example: Sinusoidal Source

Capacitor is initially uncharged: We have finally completed the solution:

Notice frequency is unchanged!

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Page 9: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

RC Example: Sinusoidal Source

Take a look at the voltage waveform: As before, an exponential natural

response initially dominates; then it yields to the forced response as time passes

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Page 10: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

2ND-ORDER RLC CIRCUITS

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Page 11: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

2nd-Order Circuits

When we have more than 1 energy storage device, we get higher order ODEs. Comp. solution becomes much more

complicated than just exponential function. Effects: Oscillation, ringing, damping

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Page 12: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

LC Tank

Suppose C has some initial charge Close the switch at t = 0 What’s the behavior of i(t)?

Neither element dissipates

energy! We should not see anything

like a decaying exponential.

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Page 13: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

LC Tank

KVL loop: Differentiate and rearrange:

where is the resonant frequency

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Page 14: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

LC Tank Solution

We want to solve The complementary solution is

Initial conditions: Inductor current cannot change instantly

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Page 15: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

LC Tank Solution

Can solve for the amplitude constant using 1st derivative initial condition More importantly, we see that the natural

response is a sinusoidal function Frequency determined by values of L and C

Current, voltage, and energy simply slosh

back and forth between the two devices!

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Page 16: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Series RLC Circuit RLC Circuit

Voltage Current Capacitance Inductance Resistance

Spring-Mass-Damper

Force Velocity Spring Mass Damper

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Page 17: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Series RLC Circuit

KVL loop:

Differentiate:

Divide by L:

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Page 18: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

General Form of ODE

RLC ODE: All ODEs can be written as follows:

The particular solution / forced response

depends on the form of forcing function

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Page 19: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Homogeneous Equation

The complementary solution is much more

complex now! Depends on the following parameters:

Damping coefficient Resonant frequency Damping ratio

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Page 20: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Damping Coefficient

Larger coefficient = more damping Mechanical analogue: friction

Intuitively, resistance slows down current

flow -> greater decay But inductance tries to keep current going

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Page 21: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Damping Ratio

The damping ratio tells us whether

damping or oscillating dominates We get THREE (3!) different comp.

solutions depending on its value Physically, does the current oscillate first,

or does it just die out exponentially?

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Page 22: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Overdamped Response

Damping dominates; resistance is too

(damn) high, preventing oscillations. Current decays at a rate determined by

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Page 23: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Underdamped Response

Damping is still present, but not strong

enough to prevent oscillation Frequency of oscillation proportional to

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Overshoot

Ringing

Page 24: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Critically Damped Response

This response decays as fast as possible

without causing any oscillations. Important for systems that need to settle down

quickly without overshooting.

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Page 25: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Summary

Comparison of responses with different damping ratios

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Source: Wikipedia, RLC Transient Plot.svg

Notice the tradeoff between initial overshoot and decay rate

Page 26: EE 42/100: Lecture 8 - Carnegie Mellon School of Computer ...tdear/ee/lec8_slides.pdfEE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8 RC Example: Sinusoidal Source Because the

EE 42/100 Summer 2012, UC Berkeley T. Dear Lecture 8

Summary We will not be quantitatively solving for the

comp. solutions for 2nd-order ODEs. You should still be able to derive the ODEs. Understand qualitatively what’s happening.

Conclusion: These circuits are a b!tch to

solve, especially with sinusoidal sources. Next time we’ll approach this problem from an

entirely different perspective.

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