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Example 2
A dc step down chopper has aninductive load of 1 ohm resistance and
10 mH inductance. Source voltage is 24
V. The chopper operates at a frequencyof 100 Hz with on-time of 5 ms.
Determine
(a) the average load current
(b) maximum and minimum load
currents.
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Solution
(a) Period 10010001 fT ms10 And duty cycle 105 Tton 5.0
Average output voltage245.0 So VV V12
Average load current
112 RVI oo A12
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Solution(b) During the on-period )exp(1)exp()( 1 LRt
R
VLtRIti So
At the end of the on-period
5.010)1105.0( LTRLtR and
)5.0exp(11
24)5.0exp(12 II
44.9607.0 12 II (b.1)During the off-period )exp()( 2 LtRItio
At the end of the off-period
5.010)1105.0()1( LTRLtR and
)5.0exp(21 II
21 607.0 II (b.2)
Substitute (b.2) into (b.1):
44.9)607.0(607.0 22 II which gives A95.142 I
95.14607.0607.0 21 II A07.9
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DC step-up chopper operation
The dc chopper can also be used to stepup a dc voltage.
The circuit of a step-up chopper is
given on the next slide.
To obtain an average value of the
output voltage greater than VS, acapacitor must be connected in parallel
with the load.
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DC step-up chopper circuit
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When the switch Sis turned on for
time ton
, the current rises linearly in
the inductor and energy is stored.
When the switch is turned off for
time toff, the inductor voltage
reverses and acts together with the
input voltage to forward bias thediode. It then transfers energy to
the capacitor.
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When the switch is turned on again,- the load current is maintained by the
capacitor,
- energy is stored in the inductor and
- the cycle starts again.
Assuming a continuous source current
the waveform for the current in the
inductor would be as shown on the next
slide.
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During the chopper on-period, the
voltage across the inductor is
From this
Over the on-time of ton, the source
current changes by
dt
diLVv ssL
tL
Vi ss
ons
s tL
VI
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During the off-periodAnd hence the average output voltage
This simplifies to
dt
diLVv
s
so
tiLVV sso
off
sso
t
ILVV
s
off
onso Vt
tVV
off
onso
t
tVV 1
T
TVV so )1(1
1
s
o
VV
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If the capacitor is sufficiently large,
the output voltage will be
continuous and vo will become the
average value Vo.
The above equation shows that the
load voltage can be stepped up by
varying the duty cycle .
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If losses are neglected and the capacitoris very large
Or the average source current
Therefore,
ooss IVIV
osos IVVI )(
the average source current )1( os II
the maximum source current )2(2 sss III
the minimum source current )2(1 sss III
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Example 4The step-up chopper is to deliver 3A into
a resistive load R of 10 ohms. The source
voltage is 12 V, L = 20H and the
chopper frequency is 50 kHz. Thecapacitor is very large. Determine
(a) the on-time of the chopper
(b) the average, minimum and maximum
source current.
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Solution(a)The average voltage 310 oo RIV V30
From equation (4.12),
30121 os VV 4.0
Therefore 6.0
(b)Period )105(101 46 fT s20 206.0
Tton
s12
12)2012()( onss tLVI A2.7
)6.01(3)1( os
II A5.7
6.3-5.7)2(1 ss III A9.3
6.35.7)2(2 ss III A1.11
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Transfer of powerfrom a lower voltagesource to a higher voltage source
The step-up chopper can be used to
transfer power from a lower voltage
source to a higher voltage source asshown on the next slide
The voltage E and inductance L couldbe representing a dc motor supplying
power to the dc supply during braking.
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For continuous source current, the
current waveform would be similar to
the waveform in Figure 4.5. repeated on
the next slide.
During the chopper on-period, thevoltage across the inductor is
This gives the source current as
dt
diLEvL
1)( ItL
Eti
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I1is the initial current for the on-period.During the off-period
For the system to be stable the current
should fall.Thus or
The source current during off-period isgiven by
dt
diLVE s
0dt
diLVE s
sVE
2)( ItL
VEti s
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Switch-Mode DC Power SuppliesSwitch-mode mode dc power supplies use
dc choppers to convert unregulated dc inputinto regulated dc output.
The regulation is achieved by pulse-widthmodulation and the switching device is
normally power BJT, MOSFET or IGBT.
At the output of the dc chopper is a smallfilter which is treated as an integral part of
the chopper.
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Switch-mode dc power supplies contdThe load is represented by an equivalent
resistance which is usually the case inswitch mode dc power supplies.
Two basic converter topologies, namelystep-down (buck) converter and step-up
(boost) converter are discussed.
Other topologies like buck-boost and Cukconverters are combinations of the two
basic topologies.
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Step-Down (Buck) DC-To-DC ConverterThis converter provides an average output
voltage lower than the dc input voltage.
Where the input voltage is ac, the converter
is very often used with an isolation
transformer. In such converters, the ac input
is first rectified and smoothed.
The smoothed dc is then chopped at a highfrequency to feed the isolation transformer
which is ferrite cored transformer, much
smaller than its 50 Hz counterpart.
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Step-down (Buck) dc-to-dc convertercontd
The figure on the next slide shows
the circuit of non-isolated converter
using a power BJT as switch.
It is like the step-down chopper in
Figure 4.2 and it operates in thesame manner as that step-down
chopper.
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Buck converter contdWaveforms in the converter are shown on
the next slide.
They are obtained under the assumption that
the capacitance is very large thus causing
the output voltage vo(t)to be equal to Vo
(the average output voltage).
This assumption is very reasonable becausein switch mode dc power supplies, the
percentage ripple in the output is usually
less than 1 %.
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Buck converter contdDepending on the switching frequency,
filter inductance and capacitance, the
inductance current may be continuous
or discontinuous,giving a mode ofoperation called
- the continuous conduction mode
(CCM) and
- discontinuous conduction mode
(DCM) respectively.
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Buck converter contd
It is not common to mix these twooperating modes because they
require different control algorithms.
We consider only the CCM.
When the transistor is turned on andoff, the voltage across the diode will
be as shown on the next slide.