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ee366-chap-4-2.ppt

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    Example 2

    A dc step down chopper has aninductive load of 1 ohm resistance and

    10 mH inductance. Source voltage is 24

    V. The chopper operates at a frequencyof 100 Hz with on-time of 5 ms.

    Determine

    (a) the average load current

    (b) maximum and minimum load

    currents.

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    Solution

    (a) Period 10010001 fT ms10 And duty cycle 105 Tton 5.0

    Average output voltage245.0 So VV V12

    Average load current

    112 RVI oo A12

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    Solution(b) During the on-period )exp(1)exp()( 1 LRt

    R

    VLtRIti So

    At the end of the on-period

    5.010)1105.0( LTRLtR and

    )5.0exp(11

    24)5.0exp(12 II

    44.9607.0 12 II (b.1)During the off-period )exp()( 2 LtRItio

    At the end of the off-period

    5.010)1105.0()1( LTRLtR and

    )5.0exp(21 II

    21 607.0 II (b.2)

    Substitute (b.2) into (b.1):

    44.9)607.0(607.0 22 II which gives A95.142 I

    95.14607.0607.0 21 II A07.9

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    DC step-up chopper operation

    The dc chopper can also be used to stepup a dc voltage.

    The circuit of a step-up chopper is

    given on the next slide.

    To obtain an average value of the

    output voltage greater than VS, acapacitor must be connected in parallel

    with the load.

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    DC step-up chopper circuit

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    When the switch Sis turned on for

    time ton

    , the current rises linearly in

    the inductor and energy is stored.

    When the switch is turned off for

    time toff, the inductor voltage

    reverses and acts together with the

    input voltage to forward bias thediode. It then transfers energy to

    the capacitor.

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    When the switch is turned on again,- the load current is maintained by the

    capacitor,

    - energy is stored in the inductor and

    - the cycle starts again.

    Assuming a continuous source current

    the waveform for the current in the

    inductor would be as shown on the next

    slide.

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    During the chopper on-period, the

    voltage across the inductor is

    From this

    Over the on-time of ton, the source

    current changes by

    dt

    diLVv ssL

    tL

    Vi ss

    ons

    s tL

    VI

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    During the off-periodAnd hence the average output voltage

    This simplifies to

    dt

    diLVv

    s

    so

    tiLVV sso

    off

    sso

    t

    ILVV

    s

    off

    onso Vt

    tVV

    off

    onso

    t

    tVV 1

    T

    TVV so )1(1

    1

    s

    o

    VV

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    If the capacitor is sufficiently large,

    the output voltage will be

    continuous and vo will become the

    average value Vo.

    The above equation shows that the

    load voltage can be stepped up by

    varying the duty cycle .

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    If losses are neglected and the capacitoris very large

    Or the average source current

    Therefore,

    ooss IVIV

    osos IVVI )(

    the average source current )1( os II

    the maximum source current )2(2 sss III

    the minimum source current )2(1 sss III

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    Example 4The step-up chopper is to deliver 3A into

    a resistive load R of 10 ohms. The source

    voltage is 12 V, L = 20H and the

    chopper frequency is 50 kHz. Thecapacitor is very large. Determine

    (a) the on-time of the chopper

    (b) the average, minimum and maximum

    source current.

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    Solution(a)The average voltage 310 oo RIV V30

    From equation (4.12),

    30121 os VV 4.0

    Therefore 6.0

    (b)Period )105(101 46 fT s20 206.0

    Tton

    s12

    12)2012()( onss tLVI A2.7

    )6.01(3)1( os

    II A5.7

    6.3-5.7)2(1 ss III A9.3

    6.35.7)2(2 ss III A1.11

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    Transfer of powerfrom a lower voltagesource to a higher voltage source

    The step-up chopper can be used to

    transfer power from a lower voltage

    source to a higher voltage source asshown on the next slide

    The voltage E and inductance L couldbe representing a dc motor supplying

    power to the dc supply during braking.

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    For continuous source current, the

    current waveform would be similar to

    the waveform in Figure 4.5. repeated on

    the next slide.

    During the chopper on-period, thevoltage across the inductor is

    This gives the source current as

    dt

    diLEvL

    1)( ItL

    Eti

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    I1is the initial current for the on-period.During the off-period

    For the system to be stable the current

    should fall.Thus or

    The source current during off-period isgiven by

    dt

    diLVE s

    0dt

    diLVE s

    sVE

    2)( ItL

    VEti s

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    Switch-Mode DC Power SuppliesSwitch-mode mode dc power supplies use

    dc choppers to convert unregulated dc inputinto regulated dc output.

    The regulation is achieved by pulse-widthmodulation and the switching device is

    normally power BJT, MOSFET or IGBT.

    At the output of the dc chopper is a smallfilter which is treated as an integral part of

    the chopper.

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    Switch-mode dc power supplies contdThe load is represented by an equivalent

    resistance which is usually the case inswitch mode dc power supplies.

    Two basic converter topologies, namelystep-down (buck) converter and step-up

    (boost) converter are discussed.

    Other topologies like buck-boost and Cukconverters are combinations of the two

    basic topologies.

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    Step-Down (Buck) DC-To-DC ConverterThis converter provides an average output

    voltage lower than the dc input voltage.

    Where the input voltage is ac, the converter

    is very often used with an isolation

    transformer. In such converters, the ac input

    is first rectified and smoothed.

    The smoothed dc is then chopped at a highfrequency to feed the isolation transformer

    which is ferrite cored transformer, much

    smaller than its 50 Hz counterpart.

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    Step-down (Buck) dc-to-dc convertercontd

    The figure on the next slide shows

    the circuit of non-isolated converter

    using a power BJT as switch.

    It is like the step-down chopper in

    Figure 4.2 and it operates in thesame manner as that step-down

    chopper.

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    Buck converter contdWaveforms in the converter are shown on

    the next slide.

    They are obtained under the assumption that

    the capacitance is very large thus causing

    the output voltage vo(t)to be equal to Vo

    (the average output voltage).

    This assumption is very reasonable becausein switch mode dc power supplies, the

    percentage ripple in the output is usually

    less than 1 %.

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    Buck converter contdDepending on the switching frequency,

    filter inductance and capacitance, the

    inductance current may be continuous

    or discontinuous,giving a mode ofoperation called

    - the continuous conduction mode

    (CCM) and

    - discontinuous conduction mode

    (DCM) respectively.

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    Buck converter contd

    It is not common to mix these twooperating modes because they

    require different control algorithms.

    We consider only the CCM.

    When the transistor is turned on andoff, the voltage across the diode will

    be as shown on the next slide.


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