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8/20/2019 Electrical Engineering Objective Questions Part 8
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when
it
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mes to n
ois
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rman
ce .
Wh
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rrect
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l
, 2
a
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b)
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I
. T
he frequ
ency
spect
rum
o a
n
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plitud
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gnal
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ins
10.
11.
(a)
canier
frequency onl
y
(b ) sideb
and
freque
nc
ies on
ly
·
c)
mQdu
lating
freq
uency
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r a
nd si
d
eba
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reque
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im um
amp
litud
e A
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a
m in
im u
m e ·t
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a posit
ive
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n t
he m o
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is
giv
en
by
a)
A ..
A.,...
c)
A..
,.,. - Anun
A.. . ,
.+ A
,,n
In
•
b)
of the
fouri
er
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tnon o
f
Time
with
List
an
d
selec
t th
e c
o
rrect
b
elow
the
Lis t s
:
U
st -11
I
.
IF
oo) I
2.
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1
4
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orki
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ith t
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plies
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ltage
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)
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15.
a t c
h ~
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eedba
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List-
11
P
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re
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ect
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er
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ists :
t t ~
l
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st·II
rrr<:
nt series
l .
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nput ·imp
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c reas
es,
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ut i
mped
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ce
decre
a ses
. Curr
ent S
hu
nt
2.
Input
im
peda
nce d
ecreas
es,
.
. ..._
ou
tput
im
pedan c
e
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ecreas
es
~
-
C.
V<
>ltage
se
ries
:3. I
nput im
peda
n
ce
inc
reases.
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ou
put im
pedan
ce inc
rease s
D. V
oltage
S
t lunl
4 Inp ut
imp
edan
ce decre
ases
ou
tp
u t
impe
dance
i
nc rea
ses
A
B
c
D
A
B
c
a}
4
2 I
b)
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l
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2
d)
2
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1
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v,.,
a)
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c)
v
'
· · · · · · · · · · · · · · · · ~ ·
: : : r
17
. Th
H ~ r llr.J i
p
{C)
0·
30
d) 0·60
d
d
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19
:w
.
2
1.
A
bu
nlc
d con
du c
10r
has
3 c
o n d
u cto
r
s,
sp
ace
d
sho
w n a
bov
e. D is
t
he G
MR
in
d iv id
u al
·
c
ondu
cto
r. W
hat
is
the
GM
R c>
f
th(l bun
dled
cn
ndu
ctor
?
(
D , "
<J) '
(c
) (D,
"
d
1
) : .
(b)
(D,
<l)
''
(u
) D,x
d
2
In
a shor t
transm is sion
i in
c,
i f
the intpcdant
l
of th <
lin
e is
0 ·01
+j
O
IS
p e r
un i
t
w
h n t h e
lo
ad nm
en
l
s 1
·0 p
.u .
at 0·
8 la
g po
wer
fact
o r
a nd
the
en
d
vo
l
t
a g e
Vn
= 1
·
0
p.u .,
w
ha t is
th
e re
gul
at ion
of
the
lin
e?
0
a) 0
·8 %.
(hl
0·
9 '':.
(c
) l·8'\
\
·,
(d )
J ,
r
~
Wh i
ch
o n<:
of
the
y
ields
the
v
ah
lc of
of
w
ndu
cto r
s betw
een
tw
o po
I es
?
(W i
s
w
u
n it
~ o
f co
nd u
cto r
in
:'llfm,
L
is
th
l
betw een
IWO
pol
es
in
m ete r,
f
iS l
ir\
con
du
c
w
r
in
N
)
a)
\Vl}
ti6T
<:) W
l
2
t
T
ts g
ive n
b
y
22.
is eorr l l'l :
In
a
for a
ti ir
\lq;
r<)t0.
d pow e
r
I
he
re
pres
en ts
th e
~ q ~ y co
ntrih
ua:rl
by
on
(b )
m aj
or c
h(:rm
al s
ta t io
n
bydr
o or
g
as
:il<
Hi > l
b
·onv
enti
ona l
po
wer
stal io
ns
e r
th e
f
o
llow
ing
sta t
e m
ents
for
a
Tor
que
is
con
stan
t fm
m slan
(b ti
ll
up t <
syn
ch ro
not:;
;
SJ C
· etl
N
'
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21.
25
2.
Ho Or is providecl with narrow
slots
embedded with
bars.
:5.
Tor(jue at swning is :some
w h < ~ t
m o n ~ than
that
at
syncht·oncms
speed N ~ .
4. As
the name
st1ggests,
only hysleresis
torque
s
produced from
zero speed
:right
up to t- :r
5. Hotor nli.'lt( rial
p l : s s c s s t ~ s
very wide hysteresis
loop.
\ ~ h i c h · » ~ : . · t ~ H ~ : ~ l . a t t m H : n t s given_ ~ h ~ J v ~ are c o r r e c t ~ ?
{<t)
J,
•. t ~ m l ., (b)
J
.H.d
;
(C) J an<l 1 (d) 2. and 5
Th4
field eurrcnt of
a
synchronous motor is inc
while
it:; load is c()nstant.
How
will it.s
pow
and )Ower
factor
change·:
(<lJ P o w ~ r
<'lr.lgle
decreases
and.
p o w t . ~ r ·
f<tctor
(b) P(JWt:r a n ~ l e
remains
- ~ H n H : t h r o u r t
H
p }WCr
factor
imf)roves
(c)
Powe ·
angle
n c r ~ l S : : ;
white
ils
Sj
or
gradually
de(r(;'a:;es
(d) P o w e ~ r angle and power f ~ increase
Two
<oltcnlato:rs
(M
1
ansJ. J:ve
been pr(>perly
:>ynchronizcd
and conn · c ·n
parallel to
a c o m m ~ m
bu >ha r. f
h e r ~
is
n ) I o · busbar, at·ld
the the
fic .d
exdtati(m
~ > f
th( s
n
· l ternawr (Mz)
is
inct·casc<l
j ;radu.ally
by s ~
ul)t, frQm its
·nNmal
x c i t < ~ t i < > u
for
w:hkh the , e.m.f.'s
f
and
E:: of
the two
m;H:hines arc q the armature reaction
due
t-o the
circulatin a c current would be
ia)
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List-1
A Capaciwr-run
otor
)
Capacitor-start
end run
otor
C
Shaded-pole motor
D
Resistor-sp ir
phase
moter
A
a)
2
<) 3
27.
List-11
T o ~ q u e
3
2
- · · · · · - · r · · ·
1
·-·----- "\
0
~ p e e d
\
B
c
D
(t))
2
4
d)
: 2
•
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3 >
C
.S.
E.
Electri
cal En.gg. (
PRELI
M. -2
005
2X.
29.
I
·c;)
s
(d)
I
- S
s
To prC\ C
l1 t
s h
~
of
t
he
mag
netic
n ~
a xis,
(:<IUS
.( d
hy th
e . l lr l
t urc
react io
n ' i :
a
d.c;
,
m h
i n ~
the most cffc
ctwe m
etho
d to
ncutr
ah1..c
t
he n
rm a tur
nux i
s to
0
(<:)
shift r
hc
x i : ; ·
(h) p
ro vid
e high
-re luc
ta
nce main
pole t i p ~
r ~
c) c
u t
hor
izonw
slo
ts in
th
e
ma
in po
les
( .i)
l : : ~ c c com
pcnsa
ing w
ind in g
s on t
h '
·n · f¥> 1c face
s
Ht
• ·· --()
.
\
' \ .
.
'
.
r. .
I
l
§
I
4
v
C o(
r >
0
~
0\
l
t .
r
•
ri
1
3
40
0V
f.'
ig
.
2 Fig . 3
·
I
·g
.
e o n ~ c
t c d an au
to l
ransfo
rm er
shown
in
hg.
llw
t i o n s
of the
100
V w in
d ing arc
rev
er sed
()\
\ II in F
ig
.
a. w
hat is
the
\ <t
iUC
of the
vOlta
ge
V
1
i red
lu he a
ppli
e d acr
oss tre
mina
ls
X ~ and H
, to
ob
tain t
lw same
40
0 V
ou
tput?
\ ~ 1 ) 5t) f
) \,'
(b)
. () () v
{(
)
o o v
{d) 1
o
n v
3
0.
Two
t r a n s
f o n m
wi
th i
dcntie
al vo lt ag
e r
atings
o re
wo
rk in g
in
paralle
l to
s
upply
a com
mon
loa
d. The
p
erccma
ge im
ped a
nce <
>f on
e tran
sfo
rmer is hig
her
ro
mparc
d to th
at of
th
e
oth
er.
The
load
sha
ring
i W < ~
the
two
r a n s
f o r m e
v.'i l
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:n.
(a) be proportionate to their percentage lmpc danees
(b) be independant c>f their pen.:entage impedanC( S
(c) he
nvcrs.ely proportional to
their
respc<:t
ive
impedances
(d) depl;)nd on the resistance to k a k a ~ e reactance ratto
of
each
transformer
ConsidN
a
< > Y S l ( ~ m
having
forward
path
and
feedback
path tran•,fer functi(ms as
}j()
(s(s+0·8))
n d ~ l
·
res.pceth•. ly. \Vhich is the
characteristic
poly
1ia
of the
system?
~ 1 } ~ Z . + J · 8 ~ ; i · · I G b) :sZ·I·2·8s+·loo
(C) s
2
; ;32
·8s r H) (d) : ·
:J2so ·
i
Whkh of the ioll.owing correct?
The feedbadz affects the eontrot system fott()wing
ways: e·
. h i c ~ C < ~ s c s
.:accuracy
but
t·edu
'
:::itivi:y of
g:<lin
1o
vanauon
tn
system
parap.c-r
: . l n u e < ~ s e s b m d w i t h ~ ~ c s the
cffcd
of r ~ o n ·
mean y.
Increases
ten<.le
t<
v·
· s
o.citlation or l e a d ~
even
tn inst.abirity.
(a) I and
2 (b) I
and
(c) 2 n d ~ (dl
I,
2 and :.3
The tr·
f t Vnc t ion
B s)
si mpllfi<:ation
< f which
oM
of
the f<lllowing
diagrams'
{sf >
, L ~
B s)
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h)
R
A s) I
r
ln s
)
I
l
A
I 1
d )
1
I
C s}
)
C s)
+ 1
l
I
< t ~ J I
1
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35
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s
l l
·····;····
-··
······
-;:·
s· ·<
u
>
W
hat
will
be
the o
utput
v
ol
tage
if the
i11
p
u
t v
oltag
e
is b t ?
(
a)
,fi
i11
61
t ...
l't
/ 4
)
(b)
cos j
- si
n
u)t
c) c o ~
w
t
(
d) [
2 si
n(l:lt t·
r
/
4 )
Whkh
<_>f th
e
follo
wing
cha
racter
istics
of y
~
a
rc
m
e
b y
y
t) =
x ( t
> C<>s
(1 O ~ t
?
L h
is l
inear
.
:2 It
i
s time
invari
o - .
h
cau
sal.
4. 1t
is <\
stahl<
;
·J. it
ts sne
rnory l
ess.
Selec
t th
e co-rf
ect a nsw
er
using
the
r :ooe
giv
low
:
{a ) l, 2
3 an
d 4
(b
2
, 3
~
·
(c)
4
<1nd
5
d)
d
5
·10
. Ma
tch Lis
t-
(Po
le
Loca
tion) wa
.
i
s
t Jl
Tim
e
1 ?e
spom;e
u e
l.o
lnilia
l
~
an
d :;ele
ct th
e
torrcc
t ?ns
wer u
s ing
t h e
en _
b elow
th e L
ists :
l . ISt · l
a
st
-II
f ~ > k
im
e-
e s p o n
due t
Q
.
ni
tial Co
nditio
n)
( t )
:\
j t
.
g ( t )
I
=v
t
- - 1 - -
+-+
---1-
-\-...
~
·
T
.....
..........
..
~
2
g(
t)
I
--
-
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4
1
c
D
j
l)
.
.
I
•
·
l
;
0
w
i
..
;)
-
A
a)
C
)
2
B
C
1 4
3
0
3
4
3
.
g
t
)
_
_
.
.
·
·
·
4
.
x
.
l
j
.o
r
t
h
e
n
e
t
w
o
rl
s
h
o
w
n
a
b
o
v
e
?
.
r
u
<
:to
·
t
h
)
••
d
)
f
.
4
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' - ' )
i .
r + r
.
'
__
._.
r
r:: j
. . - - - ~
00 0
c
·-·
v 5 c o s c ~ t + L
-..,
5
)2
- - - · · · · ·
l·o r
t
ll<.: ;._ c
d
r(:ttit
; ~ i \'(' > l ilh<>vt:,
i f GO\\ < r
dissipat'Cd by
the
5 0 resistor is
e r ~
Pcn
w h . ~ l
is
the
power
factor of the drcit?
{<l)
0
l
ing;g;ing
(b)
0( '1J.,
·
(<:) (Hl k ~ ; 1 d i n g (d).
~ i n ~
A 2-terminal
nctwor·k
is 1 ~ H ~ R-1.-C
clements..
The ~ ~ l c m e n t
is
c o n n e ~ · ~ a.c
supply.
The
rurn:nt
through the
·• 1 l is
I
When a
capacitor
b
ins« rtcd in seri
c c n the source and
the
elemerlt, the ( 'U T t ·ough
the
e.lement
becomes
21 The c.lem
(a) t i ;:
(-(1
;s
a
(b)
is an inductm
(d) oeannot
be
a
s i n g k ~
cleme:ni
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4
5.
46
.
Fb
r
lll
c
a
bo
ve
c i
rc
ui
t,
i t
he
.
cu
rre
nt
t an
d
1
·5
A
f
or
R
1
_=
0
an
d
2
D
r
es
p
c
<:t iv
:ly
,
t
he
n
w
h
at
is
(
he
va
lu
e
o
f
I
fo
r
R
I.
1
)?
a
) 0
·5
A
(
b
l
} A
c}
Z
·O
A
d
)
:3-
0
A
l
2 4
5
G
,,,.,
_
_
[
1
L
l
0
0
A
()
l
0
0
·-
l
0
0
1
)
n
30
V
W
ha
t
a
lu
e
o
f t
he
c
u
rr
e
nt
l
i
tiH
:
)
,
e
.
/
\
\
(
h
:
.ll
\
(
dl
:
\
4
-b
it,
2
s
m
p
l
e m
e n
~
r
ep
re
cn
l<H
io
n (
tf
a
dc
t:
irn
al
mb
c
r
is
1
00
0.
\V
h
at
i
s
the
r
m
mt
le
r
.,
a
)
o
<1}
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4
8.
50
.
1
<
>f
X
y
T
ht\
o
ut
pu
t f
of
t
he
<Ho
-1
M
U
X sh
ow
n
in
t
he
ab
ov
e
f
igu
re
i
s
(a
}
()()
)
+
x
(c)
x
·
+
y
·
0
Cl
k
b)
x +
y
(d
)
y
+
x
Q
a
·
T
he
r
req
uen
ey
o
f t
he
cl
oc
ks
ed
ge
t
rig
ge
red
D
f
lip
-fl
o
ab
ov
e
is
I0
kH
z
.
\\
ha
t ·
:w
ail
ab
ll
at
Q
?
a
.
} 2
0 I<H
;
;
{c
5
k
Hz
G
0
{ou
t
pu
t
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51.
52.
53.
T
he ci
rcuit
i n the
f
i g ure g
iven
above
ha
s two
l
\1
0S
NO
R g
~ e s Thi
s
<:ircui
t func
tions
a s a
an
a} fl i
p -
f
lop
(b) mono
stabl
e m
ul r iv i
b r a to
r
c)
Sch
mit
t
t rig
ger
(d}
a s t
able
mul ti
vibrat
or
W
hat
is th
e n
u.mbe
r th
e comp
arato
rs
r
equ
ir
e d
in
a
3-b
it co
mpar
a to r- t
y
pe
AD
C?
a} 2.
b
} 3
c)
7
(
d)
8
T
he
a
vaila
ble mu
ltiple
ac
cess and
br
oa
dcas
t
syste
ms
are
0
; ~ ~
~
~ i ~
~ ~
~
5
. S
DMA
-
J
W h
ich
of t he
a
bove
a re em
plo
y z
o
r • s
at e ll
i te
co
mmun
icati
ons?
(a}
l ,
2
and
:3
b)
2 ,
;
c)
l
a
nd
4
{d) l
.
::1 4
a
nd
5
f the
max
imum
Ra
dar r
n
~
e
do
ubl
e
d , the
pow
er o-f
the
d ~
t r
~
s to be
i
ncrea
s
e
d
l
<eep in
g : a
U o t ~ c r
p a ra
te
ntac
t)
a}
tw
o
im
es
f
our tim
es
C) eigh
t
time
s
)
six
teen
tim
es
5 4 . \ \ hic
h on
e of l
o· in
g state
ment
s
is
o ?
bi
ts half-
wave s
ymm
e try,
then
Qu
ri e
r s
er
ies
s
va
ni
sh
hann
oni<:
s n
v ~
p r
v a
nd
arr
ay p
ro-cess
or·s
Jd?
S
l: ;i
J
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57.
58.
5 ~ ) .
60.
What is/are the
di:sadvantage(s) of Gauss-Seidel
m€thod
over
Newton's method in load·flow
prog:ra mmes "
(a) More iteration
b) Mor'c rncm<)i'y rcquitemonr and less
accuracy
(<:) Less
iterations but
more memory
(d) More accuracy and
more
memory
Match List-
with L i s ~ - I I
and select the correct
a n l w ~ r
using the code given below the Lists :
Ust-I
Ust-U
A.
Buchholz relay I. lim ines 0
B. Mho
relay
2.
Shm1
lines
C.
Jrnpedance relay
3. M e d i u m ~ ~
0.
H e a c t a n < ~ e
relay 4.
Transfor s
\BCD A B ~ D
(a)
4
i
3 2
(b)
3
•4
(C)
4
2 (d)
3 ~
I
If
the fault current is
2 0 0 t 8 ·h relay
scuing
is
50% and CT r.ado is 400: , • what is
the
plug
setting
multiplier?
(a) 25 'b) 5
(<:)50 ~
10
In a static
over·
re relay, hov.; are inverse time
c h a r a c t e r i s t i c ~ e ?
(a)
By
us in,. a ·
stor amplifier
(h)
r ~ y
u:'
n a .
egratlng circuit
(<:)
ltzi
, ransistor switch
(d) I ' i a
d i f f e r e r . ~ i a t i n g
circuit
. <nis · · · tum·off of ; > ~ thyristor
t a k t ~ s p l a c ~
if the
~ ~ r ~
bias
peri:nl
or
t h { ~
d e v k ~ ~ .
aft-c '
its eurl ent
·
" heeonw
:r.ern, b
~ n : < : t t c r th::tn its tu:·n-off
tjrnc
~ n )
]es:;
i h c ~ n ~ ~ s turn·
off
t i r n ~
(C) } £ r c a t : ~ ·
l
hitn
·he
(:in:uit
rirnc-Cil)f iSUHH
'
\C.
I
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61.
10 A
I
1
1
0
T/2
~ ' : '
2 •
62.
A MOSFET rated
for
20 A, carries a periodic current as
shown
in the above figure. The or1-slate resistance
l f
the MOSFEf is 0·2 ohm. What is the average on-state
power loss of device per cyc e : . 0
(a)
20W
(b)
i5W
J
(c) lOW
(d)
5W
0 .
l v.,<•mt fl CJ
(bl 180•
(C) 200" (dl 240°
63. Match Li h List -II and select the correct answer
usin the e given below lhe Lists :
. st-1 List-11
. verter) (Application)
factor
B H•lf·<OOtn>lled ooo rt
2.
So ft ' ' ' . ' · '
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l i5
.
motor
C.
: -
pha se a.<
.:.
vo ltag
e
nm t
roitc
r
3. S
peeo
revc r
.;a
l
D . C
ycloco n
vcrtcr
4. S
moo
th low
sp cc
tl
rever
s ib le
high
p o w e r
a
.c.
drive
s
5. S
ynch
r
o
nous
moto-
r
corlln
>
B
CD
B
CD
a) :l
l
2 ·
(h
) 2
4
5
(C ) :\
2
l
(
d) 2
5
4
a
Vhi
<'h
or
I
he
f
>l
low
ing
.are t
he adv
ant
ag
es fr
w
l H ~ l ' l
i n
g
of
Load
c u
rrent
in ph
asc -
r J .d
e o
~ l i i
?
.
II rTduc
es r c < ~
p
o
wer d
eman
d of the
co
r
2.
I
i mpr'
O'
CS
t
ht:
d is p
lacemen t
•
·L
r e q
u l n l r g <
r i
ndiclaJ
1Ce
pt
v c
< O
n
tinuou
s
L
It i
n
1prov
es
d is t.tlrt i
on fac
to
r .
c
onduc
tion.
ij
,
Sdc ·
( ' l th(;
( ~ M r
a n
w ( " '
~ l l
·
c o d ~ ~ ~ t i v
b
elow
:
l
''
.,
I 1
·t .
)
.,
; ) . <
• <
ln (
(
- <trl(l
t:i
I
and 4
1 2.
:l
an<l ,I
\\.'hi
<:h o
f th
e fr) llo
a
funct
ion s
of f
cNib
ac
k
;
-
.
: : .
l
.
>VI .
c r e1urn
pa:h
i
o
r t h e r·
cac li
ve cm r
cnr M
k d
' l
.
T( ·
d e : a r
<:rth
fo
r
the exce
ss of
com
rnun i <at
ion
UITl'n
l
ab
ov
e th
e
l o ~ 1 d
u r r c
·1
tw
t ~ r u
smg
he
eo<k
g
iv e n
be
l
ow
. .
:; < tnd
-1
<h)
2
and -
,
. 2 a
nd J
(d)
:J and
-t
)
,\
: -ph
ase indu c
tion
mot
or o
pNatc
-s at c
ons la n
t slip
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0 to rated value. Which one of
the
followi.ng
statements is corrocc:t?
The torque developed by the motor
is
a)
proportional to speed
(b) proportional to square of speed
(c) inversely pn>portionai
to speed
{d) constant in the
complete
n m ~ up to
base
speed
l)irections : The following 6 (six)
i tems
consist of two
statements; one a
belled s
the
Assertion (A)·
m1
the other as Reason (R) . You are to examine t
two
statements carefully and select.
the
£msw
hese i tems
usin.g the code
given below:
(a)
Both
A and H are
indiv[dually
rwe a1 ... ......
correct explanation of A.
b)
Both A
and
R are individually tnw
but
H
correct
.explanation of
A • n.
+
(c} A
is tme
but
R is
a l s < ~ (J
(d) A
is false but
R
is true.
r
~
67.
Assertion
A) A
s i n ~ ~ b ~
s;unpkd
<H
:wi<:e \ ~ t J ; . i m u m frequency oi
Reason (R) ; ng is to be d()ne at Nyql)ist
) avoid aliasing.
68.
Assertion
A ) ~ good degree- of relative
y vstabi l i ty a control system should
have a phase margin
of
about
40° and a gain margin
nf 0·5.
Reaso : A large gain
margin
or a largt
phase
margin corresponds
to
a
+
highly
oscillatory system. and a
very small gain margin or a
ph.a:;e
ma.rgin
approaching 0° indicatt':s
a v t ~ r y ~ > t a h l t botH sluggish system .
...._
A.r;;serlion (A)
SiC
1
is added
to
Cl
2
in
order t<
~ .
dry
etch aiuminium
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R
ea
son {
R
)
70
.
As
s
e r
tion
(A)
e a
~ o n
{)
71.
H
cas
)n
( I {)
n
\
sS(:.
rtion
(A
}
(
U)
110
is
orropic
a ly
.
Cl
2
e
tches
a
lum
iniu
m w h
ile
SiC
.
etc llcs
nat
ive
alu
min
ium
o
xid
f;
and
a
lso
pro
vide
s
~ n i
s o t r
o p y
by
form
in g
inhi
bit<ws
.
r1
d isc
re te
as
we
ll as
JC de
vice
r
b
rica
t
ion ·v
re t o
x:id :
ation
of Si
in t
o its
na
t
ur<l
l oxi
de is
p r
r
r e ~ d
Th
e
ra1
e of
gro
wrh
o
f w
e
oxi
c a
t ion i
s
low
er
th
an th a
t
f
d
r·y
oxid
adon,
h
e n
ce a
n
,
tt
n lity
oxi
de
<:a
n b
e
gro
.
Dif
fe r
enti
al
amp
lifi
er
·
w
·it
h <
curr
(mt
so
urce
o
.r 1ig
h
C
M J
m .
D
iffe
rent
ia l
a m ~
. \
fi ll
ha
ve
h i
giH r
gain
u · ~
O n
m o
de
sign
als
.
t
s
c
·
s
ync
hro
nou
s
r
a
CS
I
nee
d
n
ot
a.
w
ind
in
gs.
D
' v
ind
ings
are
r
e
s
p
onsi
ble
. t r
~ t n ~
i e n t
a
n e in
·
·y
n
ro
no
u
s m
oto
rs.
7
3.
sys
tem
G(s),.
H
s s
+ 4)
ra ti
o
of
0·5
is
C) 4
(d)
2
/.t.
1
Mlst-1
w i
th L
is t-
:
md
~ l e c
the
<
:orre
ct .an
sw e
r
the
co
d e g
ive
n
bel
ow t
he
Lis
ts
l. .
ist- 1
Li
st-
C h
arac
teri
sti
c
(N
at
ure
o
f U
n
it S
~ e p
E
qu
atio
n)
n
csp
on
se
)
~
-
A.
sz + 8
s ;
15
0
1.
Un
dam
ped
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75.
76.
77.
B
. s
+ 24
.s + 225
'
0
c.
s
2
+ 20·2
5
, 0
D .
s
2
+
20s
+
t O
O = 0
A
B
c
D
(a) 1
3
:2
4
(:}
l
4 J
2
2.
3 .
4 .
(b
)
(d )
U
nderd
ampe
tl
Cri
t
ica
lly
d
a
mped
Ove
rdam
ped
A
B
C
D
4
3 I
2
4
2
:.
Given
the
m.
atr
ix
ro
'
1
0
A
~ lo
0
1
I
\-G
<.
- 1 I -·
)
\Vhat
are th
e
e
igenv
alues
o
f A?
J
(a)
-1 , - 2
,
-3
(h )
- 1. 2
,
-·3
(c
)
0
, 0.
- 6
d)
6.
•
Co ns
id e
f the
follow
ing
a t c m
a
s d on
ga i n
ma
rgin a
nd
ph
ase of .a
s
yste .
les
s ·t
h an
ph ase
c r
o
s
s -(>V
en c
y .
l.
Fo
r
stab
le
t i le g \.
· S
·
vcr f reque
ncy
is
:. .
Fo
r lJOsta
h te s y s t e
m s
~
· c r
os s-o
ver
freque
ncy
is
gr
eater
th a
n ph a
· -
sS··<
)VeJ·
fre
quen y
.
:3.
For mar
ginall
y
· ·
1k
s em
s, the
gain
ft
N}l.iC:: \
CY is c I
h
ase cw
ss-<
wer c q
u ~ n c y
W
hich
of the
strt
·S
give
n ab
ove arc
CMr'l:
l: t ?
(a
} I a
nd 2
b )
2 a
nd :
) l
d ) I.
2 a n
d 3
hic
h
n
liit
1c f
ilow
ing
re
prese
nts the
t r a nsf
er
u n c t i
p
hase -
lag co
n
trolle
r?
_ ~
a < 1
(h) l t < l
I : S
a > 1
1 ;. rs
·
l
·t·
T
s
T
llllilo
(
d)
l··· aT
s
.._.....
..
a > 1
l-t T
s
lhc ~ l
e a d y
s t a t ~
) f
a
con
trol
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79.
so
sy
stem .
w
hich
one o
f th
e
fo
llow i
ng
co
ntrol
wm
be
empl{
)ye d ?
a
)
c
ascad
e
PO
(b)
Casc
ade P
I
s c
hemes
(c)
Ra
te reedb
a <:k
d) I
ntegr<
il
fee
dbac
k
The
res is t
an ce
m
ea
s
ured
betw
een th
~
r
T
w -t
Jo
op and
an
in in
itely long
co
nduct
or,
e
a h
s
eur
r
c
m I
IS s how
n in
f igur
e gi
ven
above.
is
th e
fo r e
on
w
loop
'
..
._ \.
C•
e•
'
Y
fmm
th e
ctmd
uc<m
~ .
•l
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81.
2.
(b)
l l.I•
·- towards the conductor
41t
l [2
(c) ~ ; · l o g , 2 away
from
the conductor
d)
The m g n e t i c ~ tentia at the point
I-'
due to the
current
1 < ~ 0 n i11 the above
flgure is in
the
dire(·tion
< ~ )
0
{b) 5,.
> •
~ .
a , ' < ~ ,
• f(J ,I ,
s
'·
S' h (ll\<.: v t h ~
following
statements is correct'?
oC> ;' <HI
electromagnetic
wave strikes the air-
di le nk interface
a t
<HI .angle
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85
.
(b)
the
ta
ngen
tial magn
etic
fi
e
ld
com
ponen
ts a
r
e
cont
inuou
s
c) the el
ectrom
agn
e
tic
w
ave
is ref l
ec ted
b ck acco
rding
to
n
ell s l a
w
(d
)
the
c l e c t
r o m a g n
< . · wave
is
diffra
ct
e
d
I
r =
l
~ B
t
1
0
I
v
Fo
r
the
c
urren
t 1
d
ecre
asing
in
the
d
ir
eC1io n
,
the e.
m.f.
in th e
tw
o 111
0ps
A an
d B
Lh
fi
gure
above. is
in
the d i
rc<
:
tion
h)
antic
ockw
is in A an
d. c
·
·e
i
n B
{c)
c
lockw
i
se
in both
~
.
d) an
t ' ic oc
k
wi
se
in
tl<
H
A / 4
~ - A
. / 4 - -
4 i l
•
R
st
u<
. lure
C<lllS
isting:
M two
loss·l
ess
lin es
,
e
ach X/4
figur
-e giv
en a
Th<.-
I in
es
have c
harac
terist
ic
;
m po
d ' '
of
' z
n•
>p.oH
•oly
., >h o
w .
W h
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8 6
.
i
s lh
e
i
mp
ed
a
nee
m ea
su
red
a t
th
e
en
d
XX
?
~
R
O
»
R
c
) Z
r/
fR
(d
)
4Z
o•/R
M
at
ch
Li
s
t -
E
xp
re
ssi
on
w
ith
L
is
t
-
IJ
{
Coe
ffi
cie
nt
an
d s
>Ci
ect
t h·c
cor
re
ct
a n
sw
er
usi
ng
th
e
code
giv
·e n
be
low
th
e
Li s
ts
A.
B
.
D
Li
st
· I
Ex
pr
ess
ion
)
Z
.
.. 1
. '
'·(I
p
·;
:
: '
;:··
z
. .
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Circuit/Rectifier with Ust-11 Type
of
Clipper/
l ~ e c t i { i e r and select the correct answer using the
eode given below the Lists :
List·
(fransfer Characteristics
ofClipper CircuittRectifier)
A
l.
Vout
~ : . . . . ~
Vin
List-11
Type
of
Clipper
Rectifier)
Doubled-ended clipper
2 Positive lipper J
n.•
- . , . ' - - - ~
Vin (J
Vout
c
_
out
D
~ ·
/\
l3
c
, t
I 2
·I
J)
fl CJ
·ve clipper
Full-wave positive rectifier
and no: a clipper
8
.
.
3
4
I
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89.
Co
n sid
er
th e
foll
ow in
g c ir
cuits
v
l
d t:al
;
I
den
t
1
~
I
;
i
iJ
·
Vo
~
Vo
.
u
t
V
I
*
L
*
ld
caJ
f
r
v
i l
3
I
1
Whi
ch
of
the
follow in g
circuits
~ ~
t: e
f
ollo
wing
inp
ut-o
utpu
t ch
arac
te ri
stics
v
o = v
, fo
r
v;
<
V
f i
=
V
for
v.
>
V
S
elec
t th e
co
r ect
a
n ~ w
us·
· co
e
giv
en bel o
w :
(a)
1 on
ly
.l}
y
(c)
l a
nd
3
l
, 2 a
nd
:
9Q.
B
y add
itio
n
of
nt
or whi
ch
on
e of t
he
f
ollow
in g
p
o
r S
i0
2
in
IC
fab
rica
lion
b
e im
pro
ved
?
a)
Bo
ron
(b)
Ch
lori
r.e
ci Z i
rco
Q
_
(
d) I
nc iu
m
H.
Con
side
r
l
o w
n
sta
tem
e n ts
:
l
~ o n
e pro
cess
is u
~ d
for
r in
i ng
S
i fr
om
s ha
ving
seg
reg
ation
co
dfic
ien
K
< 1.
T he
he l
d
ver
tical
ly and
the
zone
is
m o
ved
from
o
ttom
to
top
of the
ing
o t. A
fte r
each
run
a
nd i s
to be
cu
t thro
wn
b d
t
he n
ext
run .
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H.2
.
n : ~ .
2.
th
e
bot
tom
en
d of
the
ingot
conta
in
s
m ax
i mu m
inp
ur·itics
and
is
to be
cut
and 1
hrown
b
efore
t h ( ~ next
r
un.
3.
there
is no
need of
cunin
g
t he bo
ttom e n
d befo
re the
next ru
n a
s it cont
"ains m
i n i
mum
impur
i ties .
W
hi<:h
of
the
>aatem
cnts gi
ven
abo
ve
i
s/a
n ; <;;
(lrrecl
'
(a
)
l
only
(b )
2 only
(c)
2
anrJ
Cll)
I
and
;i
W
hich
of
the
follow
ing
la tem
ents ar
e co
rret•
t ?
I M
ol( \ u
lar
H ~ a
m
E
p itaxy
(M
BE)
i s .a p
hy
si c
(
VI 'E)
involv
(:S d w
mi
cal rea
ct ion
.
1
I
n-silL'
etchi
ng of s
il icon
is pos
sible
on ly i
t l
01
in
V
PE
sy
stem
l .
M l iE
of silic
on is
carrie
d out at
a
lower
te rn
aturc
com
p< re
d
to
~
•
4. The g
ro-wth
rate
of
lhe
1
accuratdy
n
mtt
·()JI
ed durin
g B ~
E
tha
n
d r n
( ) r r { a
n swe
r ~
· .
give n
belo
w:
(<l) 1 and
2
f
4
(('}
l. .a
nd ·i
d)
a
nd 4
Con
sider
th
e fo
llowi
·:
Ients
:
Hapid
Therm
al A
ng
(HT
A} i
s prd
crroed
o
ver
(' o nv
cn t i(
mal
c.
·mr
aling a
fter io
n -im
plant
ation
bec
aus t·
1.
RTA
do
c.
t a
. c any
ch n
ge in
th e
dopin
g prof
ile
.
2.
Then
' is lowe r if IU A
i:;
used
.
3,
R T
a
icd ou
t at lo
wer te
rm pe
raturc
.
W h
i ~ : h _
h
_statc
rn etm
i v e ~
a ~
) o v c
iS.
f
are cor
rect '?
(
2
, · 5
(bJ
1
a
nd
2
• • y
(
d) 2
on v
f
der
th
e folll'rW
i •IJ1:
t ; ~ l e
c n t s
~ ~ t h o
<
f crys ta l
pul inK
is
a
popu .l<lr
t< :
chni4lW
f<l'
r
v ~ ~ n h l
v
.:lk
a t e . to
t
rystal_
c c a
u
. . . . .
1 'l
.,
o
smg;
e crys
l< :l to
JnttJate
th e
~ .
I
U'\lW h
.
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2.
t
he
s
e
e
d
cr
ys
tal
sh
ou
ld
b
e
p1
JfC
an
d
fr
ee
f
or
h
ig
h q
ua l
ity
g
ro
wth
.
:3
. in
ten
ti
on
al
ly
d
op
e
d s i
ng
le
c
ry
st
al
s ca
nn
ot
ob
ta
in
ed
by
t
hi
s
te c
h
ni
qu
e .
W
h
ich
o
f th
e s
t
at
em
en
ts
gi
ve
n
a t
)ov
c
a
oe
co
rr
e
c
t'?
<
l
l,
2
a
n
d 3
(b
)
I
a
nd
2
c)
2 a
nd
3
{d
)
l
an
d
3
9
5.
W
h
at
is
t
he
c
o m
~ c
t
s
eq
u
en
ce
o
r t
he
f
o l
low
i
n g
s
te
ps
ur
in
g
is
ol
at
io
n
b
y
L
OC
O
S
te
ch
n
iq
ue
?
I
.
Si
e t
ch
i
n
g
2.
G r
ow
t
h
of
th
in
p
ad
o
x
id e
.
D
ep
o
s
it
ion
a
nd
pa
tt
ern
in
g
o f
s
il ic
o
n
nit
ri
de
4
.
G
roW
1
h
of
i
~
S e
le
c
t t
he
co
rrec
t
a
n
sw
e r
us
in
g
th
e
c
od
e g
iw
:n
b
c
l
o
-
J
a
) I
-
3 -
4
-
2
b
)
2 -
3
-
I
-
·
(c
)
4
- 2
... 1
-
3
d
)
: -
I
-
4
- 2
f
>
•
96.
Consider
the
fo llow ing statem
e
nts
ar; -fs:
i
F
er
rit
e:;
ha
ve
h
ig
h
re
s
ist
iv
ity
.
2
.
F
er
ri
tc
s
ha
ve
lo w
e
dd
v
·.
3
.
F
e
rri
te
s a
re
u
se
d
as
co
re
m
I
n
g
h
fr
eq
ue
n
ct
M
Hz
)
tr a
n
sfo
rm
e
rs
.
\V
hi
ch
o
ne
of
th
e
st
atc
rn
(
O
5
•
h
ov
e
a
n
<:o
r
rec
t
)
a)
1,
2
an
d
3
.n
d
2
c) 1
a
n
d 3
d)
2
an
d
3
9
7.
A
n
ec
es
sa
ry
b
ut
r
f i
c ie
n
t
c
on
d it
io
n
fo
r
a
cr
ys
t
al
to
s
h
ow
e
r
·
ct
.ri
cit
y
i
s
a)
absenc
e
<
symmetry
(
b)
p
r e
s e
trc
of
s
ym
m
et
ry
c
)
pr
e
se
b
o
th
tra
n
sla
ti
o
na
l a
n
d
r
ot
ati
on
<l
l
m
e
ns.
o
f b
ot
h t
ra
ns
la
tio
na
l
n
d
ro
tz
t io
na
l sy
m
m
et
ry
98
.
m
at
er
i
a l
th
er
e
a
re
fo
u
r
co
n
tr i
bu
ti
on
s
o
la
l
p
ol
ar
isa
i
<>
n.
O
ut
o
f
th
es
e on
ly
o
ne
· is
p
e
nd
en
t
o
n
te
m
per
atu
re
an
d
th
is
co
n
tri
bu
ti
on
is
..
.. .
._
e
le
ctro
n i
c
po
la
ri
sa
tio
n
~
-
(
b)
s
p
ac
c
-c
ha
r·
ge
p
ol
a
r
is
at i
on
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(
c)
io
n
i
c
p
o
la
r
is
<ll
i
o
n
d
}
o
ric
n
ta
tio
n
al
p
o
ln
r
isa
ti<
m
H
m
:
pe
rm
an
e
nt
di
po
le
m
o
m
en
t
,
k
B
ol
t l.m
a
nn
c
o
n ~
a
n
d
T
:
ab
s
ol
u
te
t
em
p
e
ra
t
ur
e ,
th
en
M
i
o
n
p
ola
ri
sah
il
it
y
i
s e
qu
a
l
·t
o
m
( (
t)
3kT
(
b}
m
(
<;)
:J
k
Tm
Hl
O
.
W
h i
~ :
h
<
M
of
C
o
pp
e
r
a n
d
s i
li c
cm
cq
u
ili
hr
i u
m
)
h)
(
C)
I 0
1
1
02
.
cy
e x
p
eri
m
e
n
t
m
in
ciu
c
ed
c u
rr
en
l
d
eca
y
ex
p
er
i
me n
t
:
0
M
as
s
S
p
o p
e
x
pe
ri
m
en
t
a
w
hi
ch
o
ne
o '
t
he
f
ol
l o
w
in
g s t
a t
em
e
nL
< ;
r
r
c
ct
?
1e
\ )
t:: l
n
um
b
•:;
r e
lf p
o
ss
ib
le
w
av
e
in
a
n
y
e
n
er
gy
b
an
d
-eq
ua
l w
th
e
n
um
b
u
o
f
u
ni
t c
e ll
s
T
h
<:
t
>ta
nu
m
b
r,:
r o
f
f:x
>S
Si
blc
w
ave
f
un
c
t i
on
s
in
a
ay
en
cr
h'Y
b
a
nd
i s
e
qu
a
l
t•
>
f
•ic
e
he
n
u
m
be
r
o
f u
ni t
c
ell
s
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103.
according: to Pauli principle
c) The ;otal number of pos.sible wave f:Jnctions
in
any
energy band
is
equal
to
the total number oi free
electrons :n the band
d) The number of possible wave functions in any m ~ r g v
band is independent of the number of unit wiis
104 While ~ · n the value of distributed capacitance
by Q-mc
h
eson nces were obtained
l ith
values
of t
l·ng dtor
s c,
nd C
2
for
the frequencies
d
~ >
f
1
nd 2f
1
respectively. What is the
_
~ ~ distributed c a p a ; i t : ~ ~ ; ; ~ ?
~ ~ ~ ··· -,--··- (b)
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I05
lOl
L
- (
<
e
::
• .
: , I.
.,
•.I
(d
)
~ -
~
3
. , . · · ·
-
• I
(:
-
· ~ >
-
-
--
;
v
=
I
o
.-
...
a
_
-
~
~
I
n t
he
f i
~ u n
s
lw
w
n a
b
tw
e,
A
I,
A2
a
A
id
ea l
am
m
ete
rs . I
f \2
an
d
A
re a
d
lA
an
0
e¥
>e
c
tiv
c l
y
wh
at
i
s l
h()
rca
djn
g
of
A
l ?
{i
l \
~
(
h )
3 A
-
J
te
l )
\
~
d
c
:an
not
be
ca l
cu
la
l
<
d ~
r i
V
e
va
lue
s o
f
:m
d
C
W
a g
n ~
r
E
a rt
h
D ~
v i
·
c
u
s ~ d
f
o r
a .
c . b
ridg
e
r
in.:
u it
:; f
or
t<t)
<
·l im
in a
t in
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