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C H A T E
Transmissionines
8-1 GeneralConsiderations
8-2 Lumped-ElementModel
8-3 Transmission-LineEquations
8-4 Wave Propagationon a Transmission ine
8-5 The Lossless iansmission ine
8-6 Input Impedanceofthe Lossless ine
8-7 SpecialCasesof the Lossless ine
8-8 PowerFlow on a Lossless iansmission ine
8-9 The Smith Chart
8-10 ImpedanceMatching
8-11 Transientson Ttansmission ines
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TnRrslilssr0NrNEs
3-1 Generalonsideralions
.\tthough he amilyof transmissioninesmayencom-
:J5s llstructuresndmediathatservetotransferenergyr
:brmation betweenwopoints,ncluding erve ibersn
= human ody,acousticwavesn fluids, andmechanical
ressurewavesnsolids,weshall ocus urtreatmentinhis
:3pteron ransmissionines sedorguiding lectromag-
:ericsignals. uch ransmissionines nclude elephone.rres,coaxial ables arryingaudioandvideo nforma-
:.)n o TV sets r digitaldata o computermonitors, nd:rdcal ibers arryingightwavesor the ransmissionf:Jaatveryhighrates. undamentally,transmissionine: a two-portnetwork,with eachportconsisting f twocrminals, s llustratedn Fig.8-1.Oneof thepons sthe<ndingendand heother s the eceivingend.Thesource::,rnnectedo its sendingend may be any circuit with anr.rtput oltage, uchasa radar ransmittet anamplifier,or
I :omputererminal operating n the transrnissionmode.--:om
circuit theory any suchsourcecanberepresented
by a Thdvenin-equlvalenteneratorcircujl consisting fa generatorvoltage V, in serieswith a generatoresis-tanceRr,asshownn Fig.8-1.Thegeneratoroltagemayconsist f digitalpulses, rnodulatedime-varying inu-soidal ignal, r anyother ignalwaveform.n thecase fa-csignals,hegeneratorcircuits representedyavoltage
phasorYgandan mpedance r.Thecircuitconnectedo the eceiving ndofthe rans-
missionine s called he oadcircuit,or simply he ood.This may be an antennan the caseof a radar,a com-
puter erminal peratingn the eceivingmode, he nputterminals f anamplifier, r anyoutput ircuitwhosen-put terminals an be representedy an equivalentoadresistance 1,or a oad mpedance 1 in thea-ccase.
8-1.1 TheRole lWavelength
In low-frequencylectrical ircuits,weusually sewiresto connect he elements f the circuit in the desired
I
r Sending-endI Dortt '
[igurr 8-l: A nansmissionine is a two-portnetworkconnecting generatorircuit at the sending nd o a load at the:eceiving nd,
245
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246
configuration.lnthecircuitshowninFig.-2, orexample,
thegenerators connectedo a simpleRC loadvia apair
of wires. n view of ourdefnition in thegeccdingpara-
graphs fwhatconstitutes ransmissionine,weposehe
followingquestion:sthepairof wiresbetwe€nerminals
AA'and erminalsB' a ransmissionine? f so,why s timportant? fter all,weusuallysolveor thecurrentn the
circuitand hevoltageacrosstselementswithoutregard
for thewiresconnectingheelements. heanswero this
questionsyes;indeedhepairofwires onstitutes rans-
missionine,but he mpact f the ineon hecurrent nd
voltagesn thecircuitdependsn he engthoftheine and
thefrequency ofthesignalprovidedbyhegenerator'As
we will seeater, hedetermining actor s theratioof the
lengthto hewavelengthofthewave ropagatingn he
transmissioninebetween A' andBB'.) If thegenerator
voltages cosinusoidaln time, hen hevoltageacrossheinput erminals A' is
VM,=Vs(t) : Yocosot (V) ' (8.1)
wherea.r 2rl is heangularfrequency,nd fweassume
thatthecurrent lowing through hewirestravelsat the
speed f light, c = 3 x 108m/s, hen hevoltageacross
theoutput erminalsBB' will have o be delayedn time
relativetothatacross.AA'bythetraveldelaytime//c.Thus'assumingosignificanthmic ossesn the ransmission
line,
Vtt,G)-- Vtx(t - l/c)
= Vocos[a(t l/c)] (V). (8.2)
I-et us comPareVsp, to Vp' at t : 0 for an
ultralow-frequencylectronic ircuitoperating t a fre-
quency / = I kHz. For a typical wire length
I : 5 cm, Eqs. 8.1)and(8.2) giveV11' = y0 and
Vss, : Vocos(2ltl lc) :0.999999999998V6 Thus,
forallpracticalurposes,heengthofhetransmissionline
maybegnorednderminalAA' maybe reateds denti-
calwithB B'. On heotherhand,ad he inebeen 20-km
long elephoneable arryinga l-kHz voicesignal,henthesame alculation ouldhave ed o Vps' : 0.91V0'
CHAPTER8 TRANSMISSION
The determining factor is the magnitude of r.-rl/c.Eq.(7.91),he velocityof propagationo of a
wave srelatedo heoscillationfrequency and he
length . by
ur: f)' (r/s).
In thepresentcase,rp : c' Hence, hephaseactor
u l 2nf l - I= :
--:--!-:2z - radians.
c c i '
When /l is verysmall, ransmission-lineffectsignored, utwhen /). ] 0.01, t maybenecessaryo
count not only for thephase shift associatedwith the
delay, utalsoor hepreserrcef eflected ignals
havebeenbouncedback by the load toward the
Porver osson the ine anddispersiveeffectsmay
beconsidered swell. A dispersive
on which thewave velocity is not constantasa
the frequency / . This means hat the shapeof arectan;
lar pulse,which throughFourieranalysis s composed
manywaves fdifferentrequencies,ill bedistorted
travelsdown he ine becausets different requency
ponents ill notpropagatet hesame elocity Fig'E-
,j Transmissionine ,tj
|<-l----------{
Figure8-2:Generatoronnectedo anRCcircuit hroqf
a transmissionine of length .
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.1 GENERALCONSIDERATIONS 247
rL[LfL* -- Jl_fLlL-D
Dispcrsionlcssine
rLfLfL* -. J\-AJL-Shortdisoersiveine
IJLIL*
acterized yelectricandmagneticields hatareen-thely transverseothedirectionofpropagation, hisis calleda TEM mode.A goodexamFles the coax-ial line shown n Fig. 8-5;the electric ield linesarein the radialdirectionbetweenhe innerand outerconductors,he magnetic ield forms circlesaroundthe nnerconductor, ndhenceneitherhasanycom-ponents long he engthof the ine (thedirectionofwavepropagation). therTEM transmissioninesincludehe wo-wireine and heparallel-plateine,bothshowninFig.-4.Althoughhe ields resenrna microstrip ine donot adhereo theexactdennitionof a TEM mode,he nontransverseieldcomponentsaresufficiendymall n comparisonothe ransversecomponentss o be gnored,hereby llowing heinclusionofmicrostripinesntheTEMclass. com-mon eature mong EM ines sthat hey
consist ftwoparallel onductingurfaces.
Higher-orderyansmis ion ines..Waves ropagat-ingalong heseines ave t east ne ignificantieldcomponentn the direction f propagation.ollowconducting aveguides,ielectricods,andoptichlfibers elongo hisclass flines.
Only TEM-moderansmissionineswill be reatednthischapter. his s becauseessmathematicaligor s re-quiredor treatinghisclass flines han hatrequiredortreating avescharacterizedyhigher-ordermodesnd,naddition, EM inesaremore ommonly sednpractice.Westartour treatment y representinghe ransmissionline n terms fa lumped-elementircuitmodel, nd henweapplyKirchhoff's oltage ndcurrentaws o derivesetof wogoveming quationsnownastheelegrapher'sequations.Byombininghese quations,eobtainwaveequationsor the voltage ndcurrent t anypointon the
line. Solutionof the waveequationsor the sinusoidal
---.,_ryyLLong dispenive line
Figure -3:A dispersionlessine does ot distort ignals:=ssinghrought regardlessf its ength,whereas dis-rersiveine distortsheshape fthe inputpulses ecause
:e differcnt requency omponents ropagate t different:iocities.The degreeof distortion s proportional o the::sth of thedisDersiveine.
ofpulseshapes very mportantn high-speedtransmission,oth between erminalsas well as nspeedntegated ircuits n which ransmission-line
4n and abricationprocessesrean ntegralpartof thersignprocess. t l0GHz, orexample,hewavelength= I cm n airand s on heorderof I cm n a semicon-
:-ormaterial.Hence,evenconnection engthsbetween:ces n heorderofmillimetersbecome ignificant,andpresenceas o be ncorporatedn theoveralldesign
ir circuit.
' .2 Plopagationodes
.:"rexamples fcommon ypesoftransmissioninesare
.- ninFig.8-4.Transmissioninesmaybeclassifidinto: basic ypes:
t Transverse electromagnetic (TEM) transmission
/rnes.'Wavespropagating along these ines arechar-
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248 CHAPTER8 TRANSMISSION
p*
(b) Two-wire inea) Coaxial line
metalstrip conductor
metalgroundplane
di€l€ctric spacing
TEM Transmission
(e) Microstrip line
Lines
#-n"",.,r"dielectriclayers
<net8l
L,/
/^"tut grounapunz dieleclric spacing
(h) Coplanarwaveguide(f) Rectangularwaveguide (g) Optical fiber
Higher Order Transmission ines
Figure 8-4: A few examples of transverseelectomagnetic (fEM) and highef-order ransmission lines.
melal
dielectricspacing
(c) Parallel-plate.ine
diel€ctricspacing
(d) Strip ine
steady-stateaseeadso a setofformulas hatcanbeused
forsolvingwide ange fpractical roblems.n he atter
partof thischapter e introduce graphicalechnique
known s heSmitftclrarl, which acilitateshesolutionof
manyransmissionJineroblems ithouthavingoper-form aboriousalculationsnvolving omplex umbers.
8-Z Lumped-ElementModel
When we draw a schematicof an electronic
use specific symbols to represent esrstors,
inductors,diodes,and the like. In eachcase, he
representshe functionalityof the device, ather
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i2 LUMPED-ELEMENTMODEL u9
- - - Magnetic ield lines
- Elcctic field lincs
G€nerator
Crosssection
Figurr E-5: n a coaxial ine, the electricfield lines are n the radialdirectionbetweenhe inner andouter conducto$,and hemagnetic ield formscircles aroundhe innerconductor
r.,shape, izeor otherattributes.Weshalldo thesamer:th regard o transmissionines; we shall represent
'rsntissionine b1,a parallel-wireconfguration,asrown nFig.8-6(a),egardlessf hespecifc hape f the
i under onsideration.hus,Fig.8-6(a)may epresenti:oaxial ine,a wo-wire ine,or anyotherTEM ine.
Drawingagain on our familiarity with electroniccir-rts, wheD eanalyzeacircuitcontainingransistotwerpresenthe unctionalityof the hansistorby an equiva-ertcircuit omposedf sources,esiston, nd apacitors.i. will apply hesame pproachothe ransmissionine
:"'orientinghe ine along hez-direction, ubdividingtmodifferential ections achof lengthAz tFig.8-6(b)lr,1 hen epresentingach ection yanequivalent ircuit,r illustratedn Fig. 8-6(c).This representarion,hich slledthe lumped-eementcircuit model, onsistsf four'rsicelements, hichhenceforth ill becalledhe razs-nissionEneparamelers.Theseare
; : Thecombinedesistancefbothconductorserunitlength,n Q/m,
-. : Thecombinednductanceofbothconductorsperunitlength,n Vm,
G': Tlte conductanceofthe insulationmediumoer unitlength, n S/m, and
C': The capacitance of the two conductorsper unitlength, n F/m.
Whereashefour line parametersavedifferentexpres-sions or differentypes nddimensionsf transmissionlines, heequivalent odel epresentedy Fig.8-6(c) sequally pplicableo all transmissioninescharacterized
by TEM-modewave ropagation-heprimesuperscriptis used.sa reminderhat he ineparametersredffir-entialquantitiesvhose nitsareper unit ength.
Expressionsor the ine parametersR' L' , G', andC ,
aregivenn Table -l for he hreeypes fTEMtransmis-sion inesdiagrammednparts a) hroughc)ofFig. 8-4.For eachof theseines, heexpressionsre unctions ftwosets fparameters:1)geometricarametersefiningthe cross-sectionalimensionsf thegiven ine and 2)electromagneticonstitutivearametersharacteristicfthematerials f which heconductorsnd he nsulating
materialbetweenhemaremade.Thepertinentgeometricparametersreas ollows:
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CHATTER8 TRANSMISSION
(a) Parallel-wire cprcsentation
(b) Differential ections achAz ong
(c) Each ections representedy an equivalent ircuit
Figur€ E-6: Regardless f its actualshape, TEM transmissionine is representedy theparallel-wireconfigurationshownin (a).To analyz€hevoltage ndcurrcnt elations,he ine s subdividedntosmalldifferential ectionsb),each f which sthen epresentedy anequivalentircuit c).
C'Az G' C'Lz G', C'Az G'
l-<-&--.--.--------- l-<-&________+l<_Az--"."._-------- l-r_Az_______-.'l
Coaxial line IFig. 8-4(a)]
a : outer adiusof inner conductor,m
b : inner radiusofouter conductor,m
Two-wire ine I Fig. 8-4(b) :
a = radiusofeach wire,m
d : spacingbetweenwires'centers,m
Paralle -p ate line I Fie. 8-4(c :
rr,l width ofeachplate,md : thickness finsulationbetweenplates,m
The constitutiveparameters pply to all three inesconsistof two groups:l.[cand o" are the magneticmeability and electricalconductivityof theande, p, and o arethe electricalpermittivity,permeability,andelectricalconductivityof thematerialseparatinghe conductors.AppendixBtabulated alues or these onstitutiveDarametersorious ypesof materials. or thepurposes f thechapter. eneed otconcem urselves irh he eriresponsibleortheexpressionsivennTable - Themulationsecessaryorcomputing' L' G',and,C'
madeavailable n eadierchapters or the generalcaseany wo-conductor onfiguration.
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i.2 LTJMPED-ELEMENTMODEL 251
Table 8-1: Transmission-line arametcrsR' L', G', andCt for three ypesof lines.
PNrameter Coaxial Ttvo Wirt Parallel Plate Unit
C '
#(:.;)f;nP1"1
2tt o
l"(b t)
2n e
l"U t)
Rs
TA
2R,
w
ttd
w
q w
d
tu-;a
f,2lm
Lnl<a/utr L l rd/r". . . t ) lVm
,fo
nl lapt+J@lZf-t ]S/m
TE
nl<apt+,/@/r"7-tlF/m
Notes: l ) Refer o Fig. 8-4 or definitions f dimensions.2) p, e, ando p€rtaino theinsulatingmaterialbetween he conductors.3) Rs= JnTpJ\. (4) g," and o" pertain
to rheconductors.5) t (d/2a)2 >> l,t}ler nl@/2al + ,t@p8 11- In(d/a).
The lumped-element odel shown n Fig. 8-6(c)trresents the physical processes ssociatedwith the:Jrents and voltages n any TEM transmissionine.-r-herequivalent models are available also and are-:uallyapplicableswell.All thesemodels, owever,lead: exactly he same etof telegrapher'squations,rom
rtch all our uture esultswill be derived.Hence, nly:e model escribedn Fig.8-6(c)will beexaminedntherlsent treatment. t consistsof two serieselements,R'
rd Z', and wo shuntelements, ' andC' . By way of::,vidingaphysical xplanationor the umped-element:,iel, letusconsider smallsection fa coaxial ine,asrown n Fig.8-7.The ineconsists fan nnerconductorr zdiusa separatedromanouter onductingylinder f-"irusb by a materialwithpermittivity ,permeability ,
adconductivityo. The wo metalconductors remade f.:aterial with conductivityo" andpermeability r"When
. .oltase ources connectedcrosshe woconductorst
thesending ndofthe ine,currents ill flow hroughheconductors, rimarilyalong he outer surface f the nnerconductorandhe nner urface ftheouterconductor.heline resistance ' accountsor the combined esistanceperunit ength fthe nnerandouterconductors.heex-pressionor R' wasderivedn Chapter and s givenby
Eq. 7.151)s
R i : (o/rn), (8.5)
where Rr, which representshe surface esistance f the
conductors,s called he ntinsic resisrarrce nd s given
byEq. (7.147a) s
*,:rE (a). (8.6)
#(j . ;)
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CHAPTER8 TRANSMSSION
model. tsexpressionsgiven y Eq. 4.76) s
Figure 8-7: Crosssectionof a coaxial ine with innercon-
ductor of radius c and outer conductor of radius b. The
conductorshavemagneticpermeabilityp., and conduc-
tivity o6, and the spacingmaterial b€tween the conductors
haspermittivity s, permeability p, and conductivity o.
The ntrinsic esistanceependsot only on hematerial
properties f the conductorso" and/."), but on thefre-
quency of thewavehaveling nthe ineaswell. Fora
perlectconiluctorwith o" = oo or a high-conductivity
material uch hat f p./o"\ (( 1, R' approachesero,
and odoesR'.
Next, et usexaminehe nductanceerunit engtha'.Application f Ampdre'saw n Chapter5o hedefinition
ofinductanceed othe ollowingexpressionEq. 5.99)l
for he nductance€runit ength fa coaxialine:
f | _
Theshunt onductanceerunit engthG' accountsor
currentlowbetweenheouter nd nnerconductors,ade
possibley hematerialconductivityof he nsulator.tis
preciselyecausehe urrentlow s romoneconductorto
theotherhatG'is ashunt lementn the umped-element
t:ffi (S/m).
Ifthe materialseparatinghe nnerandouteraperfect dielectic with a = 0, thenG' = 0.
The ast ineparameternourlist s he
unitlength '. Whenequalandoppositecharges
onany wononcontactingonductors,voltage
will be nduced etweenhem.Capacitances
the atioof chargeo voltage ifference.or he
line,C isgiven yEq. 4.17) as
7 r c
C ' : . : ' . , : . , ( F / m ) .ln\b a' )
All TEM transmissioninesshare he following
relations:
and
L 'C ' : pe , (8 .10)
REVIEWUESTIONS
Q8.1What s a transmissionine?Whenshould
missionline ffects econsidered?
+^(:)
If the nsulatingmedium etweenheconductorss
transmissionineiscalledanairize(e.g.,
two-wire ir ine).Foran ir ine,e = eo 8.854 I
( rVm) . (8 .7 )F lm 'p : Fo :4n x 10-7Vm'o :0 'andG ' :O
G ' 6
e(8 . r )
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i-3 TRANSMISSION-LINE EQUATIONS ,<1
Q6,2 What is the differencebetweendispersiveandndispersive transmission ines?What is the practicalognificance?
Q63 What constitutes TEM transmissionine?
J6.4What purposedoes he lumped-element
ircuitr.:delserve?Howarethelineparameterst, ',G',and,C'Elated o the physicalandelectromagnetic onstitutiveTrDerties f the ransmissionine?
=CRCISE.1 UseThble8-1 o computehe ineparam-=rs of a two-wire air line whosewires areseparatedy. :stance f2 cm,andeachs I mm n radius. hewires:,r be reated soerfect onductors itho" : m.
r:s. R' : 0, L' : l.2O QtWm), G' = 0,-
: 9.29 pF/m). (SeeC)8.2 Calculatehe ransmissioninenarameters
. MHz or a rieid coaxial ir inewith an nnerconduc-Jiameterof 0.6 cm and an outer conductordiameter1.2cm. The conductorsare made of copper seeAp-
dix B forp" ando" ofcopperl.
R' : 2.O8 l0-2 (Q/m), t' : 0.14 pWm),o)0, C' :80.3 (pF/m). (See
3 Transmission-Linequations:ansmissionine usually onnects source noneendr loadon theotherend.Beforewe considerhecom-: circuit, however,we need o developequationshat
ibe the voltageacross he transmissionine and he
carriedby the ine asa unctionoftime I andspatialionz. Usingthe umped-elementmodeldescribedn8-6(c),we beginby consideringa differential ength
: s shownn Fig.8-8.Thequantities 2, ) and (2, \the instantaneous oltageandcurrent at the left
of the differentialsection nodeN), andsimilarly: - Az, t) and (z + Ae, ,) denotehesame uantities
1<-Aa
FigureE-8:Equivalentircuitofa differentialengthAzof a two-conductorransmissionine.
at the right end(nodeN * l). Application of Kirchhoff'svoltage aw accounts or the voltagedrop acrosshe seriesresistanceR'Az and nductanceL' A.z'.
u(2, ) - R'Lz i (2, )
2 ( " , \- t ' t z -
- r l : " - t ) (z+ Lz, r )=0 . (8 .12 )i l t
Upon dividing all termsby Az and rearrangingerms,weobtain
Iu(z Lz - r \2, t ) t )
AZ
In the imit asAz -+ 0,Eq.(8.13)becomes differential
eouatlon:
: n ' k , , l t ,u f ' ' )
0u(2 .). , o i ( 2 .
)- a , = K t l z ' t t+ L - -T l -
(8.13)
(8.14)
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254
Similarly,applicationof Kirchhoff's current aw at node1V+ I in Fig.8-8 eadso
i(2, ) - G' Lzu(z+ Az, )
- C , L ZAUQ Lz, )
Upondividingalltermsbyz andtakingthelimitasz --+
0,Eq. 8.15) rovides second ifferential quation,
\ i ( z . t \ . , } u ( z , t )- ; = G ' u t z , r )+ C ' : : i : : - : . ( 8 . 1 6 )
The irst-order ifferential quationsivenbyEqs. 8.14)
and 8.16)are he ime-domainorm of the ransmission
Iineequations, therwise alledhe elegrapher's qua-
tions.Except or the astsection, urprimary nterestn thischapterisnsinusoidalteady-stateonditions.o hisend,we shallmakeuseof phasors ith the cosine eferencenotation soutlinedn Section -1.4.Thus.wedefine
Line
The wo i rst-ordercoupledequationsivenbyEqs.
-i(z* Lz, ) = 0. (8.15)
and 8.18b)canbecombined ogive wosecond-ordr
coupledwaveequations,neor V(z)andanotherfaThe waveequation or V(x) is derivedby
CHAPTER8 TRANSMISSION
8-4 Wave lopagationnaTra
bothsides fEq.(8.18a) ithrespectoz,giving
-{:P = rn, .t,tdt!r\ .az ' 4z
+f v2i(z):0, s.21)
s2 i t - t
# - y 2 r ( z ) : 0 .( s . 2 3 )
at
anduponsubstituting q. (8.18b) nto Eq. (8.19)
d (z)/dz,Eq. 8.19) ecomes
a'7e)- (R'+ jaL')G' -t ac' t i tzl -- o,dz2
u(2,) :ne[i (a ej ' ' ] ,
i(2, ) : nef k) ej''),
(8.17a)
(8.17b)
where7(z) and (7) arephasor uantities,ach f whichmaybe realor complex.Uponsubstituting qs. 8.17a)
and 8.17b)ntoEqs. 8.14) nd 8.16) ndutilizingheproperty ivenby Eq. 7 45) hat0 0r in the imedomainbecomesquivalento multiplication y rr-rn thephasor
domain,weobtain he ollowingpairof equations:
where
(R '+ j aL ' ) (G '+ j aC ' ) (8.22)
Application f thesame tepso Eqs. 8.18a) nd 8.
but n reverserder,leadso
dV(z l(R + jaL ' ) I ( z ) . (8 .18a )
az
d i t z t(G + j@c ' ) Y (z ) . (8 .18b )
dzEquations8.21) nd 8.23) re alled apeV(z) and 1(2), respectively,
ndy
is called theThese re he elegrapher'squationsnphasororm. propagationconsrdntof the ransmissionine. As
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{ WAVEPROPAGATIONONA TRANSMISSIONLINE , {<
= n . (
--'osistsofa realpadrl, calledtJileancualion constontof
:e line with unitsofNp/m,andan maginaryPartp,called
Ephase const4n!of the inewith unitsof rad/m.Thus,
y - _ u + l f (E.24)
t = Be(y)
wave amplitudes yo-, /o-) of the *z propagatingwaveand Vf , If ) of the-z propagatingwave.Wecaneasilyrelatehc currentwavearnpliodes,1o+ nd f , to thevolt-agewaveamplitudes,Vo+ nd Vf, respectively, y usingEq. 8.26a)n Eq. 8.18a) nd hensolving or thecurrent1(z) oget he esult
iOl : _ J - lvn+e-vz -v;erz). G.271R '* iaL ' ' "
Comparisonf each ermwith hecorrespondingerm ntheexpression given by Eq. (8.26b) leads o the conclusion
that
: Z o = (8.28)
where
is defined as the characteristic impedance of the line- lt
shouldbenoted haitZo s equal o theratio ofthe voltage
amplitude o the curent amplitudeor eachof the avel-
ing waves ndivirlually (with an additional minussign inthe caseof the -z propagating uave),but it is not equal
to the ratio of the total vobageV (z) to the total current
I (z\, unlessone ofthe two v'ayes s absent n termsof 26,
Eq. (8.27)can berewritten n the orm
I : lm(y)
(Np/m),
(8.25a)
(radlm).
(8.2sb)
-: Eqs. 8.25a) nd(8.25b),we choosehe square-root-ues hatgivepositive aluesor a andp. Forpassive
:--rsmissionines, is either eroorpositive.Mosttrans---.sionlines, nd ll hose onsideredn his hapter,re f:c passiveype.Theactive egion fa lasers anexampler :n active ransmissionine with anegative .ThewaveequationsivenbyEqs.8.21) nd 8.23) ave
--.ielingwave olutions f the ollowing orm:
i 127 v; "-" t vo eYz (v), (8.26a)
I1z'1 I;e-t, ,, J;"", (A), (S.26b)
-ere,analogouso theplane-wavecasein ection7-3,the: termrepresents avepropagationn the+z-directionthe e/z term representswavepropagationn the -z-
:::ction. Verification hat hese re ndeed alid solutions
:asily accomplishedby substituting he proposedex-
aswell as heir second erivatives,nto Eqs.I I )and 8.23).n heirpresentform,hesolutions iven
Eqs. 8.26a) nd 8.26b) ontain our unknowns,he
zo=R'+ u)L ': ,W- (or . (8.29)
Y \ G ' + i a ; (
-v;Io
v 0
r
- v^+ v^I t?\ = --:Le-Yz - --LeYz.
Zs Zo(8.30)
In later ections, ewill applyboundary onditions t heload nd tthe ending ndof he ransmissionine oobtain
expressionsor the remainingwaveamplitudes n+ nd
(R'+ jaL')(G' + jaC'\
(R'+ jaL')(G' + joC')
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256
Vf . Ingeneral, achwill beacomplexquantitycomposedof amagniode ndaphase ngle. hus,
vo+- 1v{1"io*
v; : lv ; le io- .
(8.31a)
(8.31b)
Uponsubstitutinghese efinitionsn Eq. 8.26a) nd e-placing withEq. 8.24),wecanconvert ack o he imedomain o obtainan expressionor r(z,t), the nstanta-neous oltage n he ine:
u(2, ) :rie(V k)ej'' )
:nel(vie-", + v;eYz) j.tl
= ne[lv{ leio+ jate-@+ia)z
+ lV; leio-ei 't et"+iq)zl
: lvdle-", cos(e)t pz + O+)
* lVo e"'cos(at+ Fz + Q ). (8.32)
Fromourreview ftravelingwavesnSection - .2, werecognizehe irst erm n Eq. 8.32) sawaveravelingnthe+z-direction thecoefficientsft andzhave ppositesigns) nd hesecondermasa wave ravelingn the z-
directionthe oefficientsft and arebothpositive),othpropagating ithaphaseelocityupgiven y Eq. 7.14):
(t)
; (8.33)
The factor e-"2 accounts for the attenuation of the *z
propagating wave, and he e"z accounts or the attenuation
of the -z propagating wave. The presenceof two waves
on the ine propagatingn oppositedirectionsproduces
standing wave.Togaina physicalunderstanding fwhat
this means,we shall irst examine he relativelysimplebut
importantcaseofa losslessine (a : 0) and henextend
the results o the moregeneral aseof lossy ransmissian
lines (a * 0). In fact, we shall devote he next several
sectionso thestudyoflosslessransmissioninesbecause
inpracticemany inescanbedesigned o exhibit very ow-
losscharacteristics.
CHAPTER8 TRANSMISSION
ffi ntuntAt ab Ene s a transmissionine for which air
dielectric materialpr€sentbtween the twowhich rendersG' : 0.In addition, hemadeof a materialwith high conductivityso hatNi'For an air line with characteristicmpedance f 50phase onstant f20rad/mat700MHz, findpermeterand he capacitanceermeterof the ine.
Solution: he ollowing uantitiesre iven:
Zo :50Q, f :20 rad lm ,
f :7NMHz:1 x IOB z.
with R' : G' : 0, Eqs. 8.25b) nd 8.29) educe
fl:
Jn \t/(
t'tL'\{ l. C'))
= tn ( .,[rc '\ = .J L'c ,\- ,/
I t a L t LZ n : l - : . / - ."
\ i ' c ' \ c '
The atio sgivenby
2 n x i x 1 0 8 x 5 0
:9.09 x 10-tt(F/m) 90.9 pF/m).
From22Z6JT /C'-,
L'= z1c': (50)2 90.9x 10-12
:2.27 x t0-7(Wm) - 227 nHtm). I
Rc ' = '
aZ o
4
20
-
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3.5 THELOSSLESSTRANSMISSIONLINE 257
IIEBCISE.3 Verify hatEq. 8.26a)s ndeed solutioncf hewave quation ivenbyEq. 8.21). (SeeO)
UERCISE.4 A two-wireair ine has he ollowing inera.ameters: ' : 0.404 ms2/m), ' : 2.0 (p.Wm),
G' : O,andC' - 5.56 pF/m).Foroperation t5 kHz,trermine (a) heattenuationonstant.r,b) hephase on-lant p,(c)thephase elocityno,and d) hecharacteristic.npedance6. (SeeO)
rns. (a)a : 3.37x 10-7 Np/m), b)f : 1.05xD-a (radlm), (c) llo : 3.0 x 108 (m/t, (d)
6: (600 j2.qa=$$Q/-o.re"d2.
E-SThe osslessransmissionine
\;cording otheprecedingection, ransmissionine s:ir.rracterized y two fundamental roperties,ts propa-Frionconstant andcharacteristicmpedances,both:i whicharespecified y the angular requencyr-r nd::- lineparameters ' L', G' andC '. In manypracti-zl situations,he ransmissionine can be designedomnimize hmic osses y selecting onductors ith veryrehconductivitiesnd ielectricmaterialsseparatingher ductors) ith negligible onductivities.s a esult,R'
mdG'assume erysmall alues uch hatR' ( rr.rl'andI ( arC'.Theseosslesslineonditions llowus osetr = G' : 0 in Eq. 8.22),which hengiveshe esult
Application f the osslessline onditionso Eq.(8.29)gives hecharacteristicmpedance s
Z o : (losslessline), (8.36)
which s nowa realnumber.Using he ossless-linex-pressionforB iven yEq. 8.35),weobtain he ollowingrelationsor thewavelength, and hephaseelocity o:
2n
p
t -t';-;;- '
I
(8.37)
(8.38)
(8.42)
Juc ' 'UponusingtherelationivenbyEq.8. 0), whichissharedby all TEM ransmissionines,Eqs. 8.35) nd 8.38)maybe ewritten s
y : a + j f = j a { U C ' ,
.hichmeanshat
wherep ande are, espectively,hemagnetic ermeabilityandelectricalpermittivityof the nsulatingmaterialsepa-rating heconductors. aterials sed or thispurpose reusually haracterizedy apermeability t : ps, where
po : 4tr x l0-7 H/m s thepermeability f freespace,and hepermittivity s usuallyspecifiedn termsof therelative ermittivity .defined s
er e eo, (8.4r
wherees 8.854 l0-r2F/m (1 l36n)x 10-eF/misthepermittivity f freespace. ence, q. 8.40) ecomes
l l'
Jpn€,€o ,ltro€o
where : l/Jtloeo : 3 x 108m/s s the velocityof
light n avacuum.f the nsulatingmaterial etwe€nhe
f = roJuc (rad/m), (8.39)
u,--+ (m/s), (8.40)'JPe
(8.34)
a:0 (losslessine),
p - a^[Lrc' (losslessine). (8.35)
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25E
conductorss air, then8r = I andap = c. In view of
Eq. 8.41) nd he elationshipetween anduogiven y
Eq. t.33),thewavelcnglhsgivenby
CHAPIER8 TRANSMISSION
EXERCISE.5 For a lossless transmission
I = 20.7cm at I GHz. Findc, ofthe insulating
Ans. e.:2.1. (SeeO)
EXERCISE.6 A losslessransmissionineusestric nsulatingmaterialithe. = 4.Ifitsli
C'= l0 (pF/m),ind a) hephaseelocity p, b)
inductanceL'. and c) thecharacteristicmpedance
Ans. (a)uo 1.5x 106rn/s),b)L' -- 4.45(c)Zo : 667l O. (SeeO)
8-5.1 V0llageRellecti0nCoeflicient
Withy = jp for the osslessine, heexpressions
by Eqs. 8.26a)and 8.30) or the otal voltageand
on the ine become
u^) - - l -
.l++=+ . (8 .43 )! ^/Er J€,
where 6 c// is thewavelengthn aircorrespondingo
a requency. Note lat, becauseoth lp and depend
one,, hechoice fthetypeofinsulatingmaterial sedna ransmissionine s dictated otonlyby its mechanical
properties,utby ts electrical ropertiesswell.
When hephase elocityof a medium s independent
of frequency,he medium s callednondispersivewhich
clearlys the case or a lossless EM transmissionine.
Thiss an mportant eature or the ransmission fdigital
datan he ormofpulses. rectangularulse raseries f
pulsess composedf manyFouriercomponents ith dif-
fercntrequencies.f thephase elocity s the same or all
frequencyomponentsorat eastor thedominant nes),
thepulse hape ill remainhesame s hepulseravelson he ine. In contrast,he shapeof apulsepropagating
in a dispersivemediumgetsprogressively istorted,and
thepulseength ncrcasesstretches ut)asa function of
distancen themedium,herebymposing imitation n
themaximu data ate whichs elatedo he engthofthe
individualulsesndthe pacing etweendjacentpulses)
that anbe ransmittedhroughhe mediumwithout oss
ofinformation.
Table -2provides listoftheexpressionsor ,20, and
uo or hegeneralase fa lossyineand or severalypes
oflosslessines.Theexpressionsor the osslessinesarebasedn heeouationsor L'and C' sivenn Table - .
i (z) : Yo+- io' + v; ejlz
i{d:! i"- iu, -\" '0,.
These expressions contain two unknowns, y0+and
the voltageamplitudes fthe incidentand eflected
respectively.odetermine0+andyt, weneed
theosslessransmissionine n he ontext f he
circuit,ncluding generatorircuitat ts nputandaloadat ts outputterminals,asshown nFig.
line, of length , is terminated n an arbitrary oad
dance Zy. For convenience,he referenceof the
coordinatez is chosensuch that z : 0
the ocationof the ocd At the sendingendatz :
line s connectedtoasinusoidaloltagesourcewith-V, and an ntemal impedanceZB.At the load, he
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i.5 THELOSSLESS RANSMISSIONLINE 259
Table 8-2: Characteristic arameters f transmissionines.
PmpagationConstant
y = d + jp
PhaseVelocity
CharacteristicImpedance
Zs
General case
Lmsless(R' = G' :0 )
Lossless oaxial
Lossless
two wire
Losslessparallel plate
u : Q , f l : ( D J € r / c
q = 0 , F : t o J E / c
a : O , f l : < o J e , / c
up= @/p Zo=
up: c/Ji zo: y/L ' /c '
up = c/Jer
u p : c / J d
zo = ($/J-e)rn(b/a)
zo:Qn/J-€).rnt@/24 u4d/23-- r)
zo- (120/.trs)h(d/a),i f d ) > e
q : 0 . F : - J E / c up:c/Je, Zs: \ lZ ln/J-e) (d/w)
(R t+ jaLt ) (Gt j j toC ' )(Rt t jtoL')
(Gt jaCt )
Notes: (l) tt = tto, € = €rtO, c : l/JtLoEo, andJ/ffi - (l20tt) fl, wherce. is the relativepermittivityof insulatingmaterial.2) For coaxial ine,c andb are adii of innerandouterconductors.(3) For two-wire line, a = wire radius andd = sepa.rationetweenwire centers. 4) For parallel-platelilg. u : width of plateand d : separation etweenheplates.
uri.igeacross t, V1,and hephasorcurrent hrough t, iL,
:elated y the oad mpedanceZL as ollows:
Uponusing hese xpressionsn Eq. 8.45),weobtain heresult:
roltage V1 is equal to the total voltageon the line
: given yEq.18.zl4a),nd i isequalo 17;given y3.44b),both evaluated tz : 0:
VZ r , : *
I L
iy:717:s1: yJ + yt,
v: v^-L : I ( z : 0 ) = ; - *
o:(#+)"Solving or Vf gives
,;=(ffi),;
(8.45)
(8.46a)
(8.46b)
(8.47
(8.48)
The ratio oJ he amplitudeof the reflectedvoltage waveto lhe amplitud.e fthe incident voltage waveat the load
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zffi
is krtovn as the voltage reflection coefficient l. From
Eq. 8-48), hisdefinitiongives he result
andinviewofEq. (8.28), he atioofthecurrentamplitudes
ls
V; Zr -ZnF - _ _ _ L -' -
vd - Z t+ zo
=t=t/,1: . l (dimensionless).8.49a)Z1-/Zs +
CHAPTER8 TRANSMISSION
for which Zr = R * jarl. Hence, n generalcomplex lso:
f : lf leie, (S.50)
where f I s themagnitude f f andd. s tsphascNote hat l-l < l.
A load is said to be matched o the line if Zy =
because hentherewillbe no refectionby the oad(l
andv; : 0).Ontheotherhand, hen he oad sancircuit Z; : oo), = | andVf : Vo*. ndwhenshort ircuit .Z1 0), = -l andyt : -y0+.
Relleclionoeffcienlol a Ssries C Load
A 100-(])ransmissionine s connectedo a oadsisting fa 50-Q esistorn series itha 10-pFFind the reflectioncoefficientat the load for a I
sisnal.
Solution:The ollowingquantitiesregiven Fig.&
Rr : 50O, Cr_ l0 pF 10-rrF,
Zo 100O'
The oad mpedances
Zr: Rr- i /aCr
,f : 100MHz : 108Hz.
: 5 0 - i -r2n x 108x l0- l l
: (s0 j159)
t r : - [ = -. . (8.4eb)6 v j
Wenote hat isgovemedy a single arameter,he oadimpedanceL,normalizedtothecharacteristicmpedanceofthe ine,Zo.As ndicated y Eq. 8.36),Zoofa lossless
line sa ealnumber. owever, 1 is n general complexquantity,s n thecase fa seriesRl circuit, or example,
IVLI
{
Vi
_+G€nerator
z = - l z = 0
Figure8-9: Transmissionine of length connectednone end o a generator ircuit and on the other end to aload21. The oad s located t z = 0 and hegeneratorterminals reatz : -r.
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!5 THELOSSLESS RANSMISSIONLINE 261
:romEq. 8.49a),thevoltagereflctioncoefficientisiven:v
Z r Z a - lF :
- ' "'
ZL/Zg * |
_0.5 j l .s9 - l
0 . 5 - j 1 . 5 9 + l
_-0.5 - j 1.59_
-1.6'I i72.6': _o 16.,jrle.3"
1.5 i1.59 2.19e-tst"
-risresultmay be convertednto a form with positive
:.rgnitudeor f by replacingheminus ignwithe-l180'.nus,-
= 0.76ei te.3"e-jt8o"
O.76e-6o.7':0.j6//-$.1" ,
(
l f | : 0 .76, 0, : -60.1" . t
trample-3 lf I 0rPrrely eaclivooad
Showhatfl : I for apurelyeactiveoad.
..:lution: The oad mpedance fa purelyreactive oad s
;'. enby
Z y : j X y .
rm Eq.(8.49a), he reflectioncoefficient s
zt - Zo
Zy* Zs
- j X r - Z ojXL* Zs
__ - (Zo - j x )
(Zo+ j Xt)
.:ere 0 : tan-L XLlZo.Hence
l l : | - e-)201: [1e-ze1p- tze1*]1/2 l . t
EXERCISE.7 A5GQ losslessransmissionine s ermi-natedinaloadimpedance -- (3O- j200)Q.Calcularcthevoltage eflectioncoefficientat the oad.
Ans. f _ 0.93,/_27.5..SeeO)
EXERCISE.8 A 150-A osslessine is terminatedn acapacitorwhoseirnpedanceisy : -j30Q.Calculatef .
Ans. f :1,/-157.a' . (SeeO)
8-5.2 Standingaves
Using he elationVo : f Vo+n Eqs. 8.zl4a)nd 8..14b)givesheexpressions
71zy
yo*
1"-
a. +teifz1, (8.51a)
r r +
i e t= l ! 1 " - 1z y " i f z1 . (8 .5 Ib )z"
which now containonly one, yet to be determined,unknown,Vo+.Before we proceed oward that goal,however, et us examine he physicalmeaning repre-sentedby theseexpressions.We begin by deriving anexpressionor ly(z)|, the magnitudeof V(z). Uponugng Eq. (!.50)ln (8.51a)and alplying rhe rclar.ion
lV (z)l : IV-12'y.1111'tz,hereV-(z) is thecomplexconjugate f 712),wehave
1712;1 { vo+1e-oz1 1ypie,ilz1]
' l{vd1'1"i0' lrle-o'e-il')]l/2
: lvo+lIltrl'
+ lllkjQfz+o')a "- i tzOz+e4]L/z
: ly0+ l I l l r l , +2 l f coszpr+q] ' / ' (s .sz)
wherewe haveused he dentity
e ] r + e - J x : 2 c o s - r (8.s3)
, - i20z l+ x le
zl+ x/e ie
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CHAPTERS TRANSMISSION
the positionon the line at which the incident and
flected waves are in phase [202 * 0, = -2n*
Eq.(E.52)land hcrefore ddconstructivclyogivce
egualo (l + lf l)lyo*l= 1.3V. Thcminimum alu
lV(z)l conespondso destructivenlerference,hich
curswhen he ncidentand reflectedwavesarc inopgosition 2Fz * 0, - -(2n + l)tr). In this
lv(z)l = (l - lf l)ly0*l 0.7V. whereashe epl
for any realquantity . By applying he same teps o
Eq. 8.5b),asimilarexpressionanbederivedor l1(z)Lthemagnitudefthecxrrent (z)._
Thevariationsf lV(z)l and 1(z)lasa function f z,thepositionon the line relative o the oadat z : 0,
are llustratedn Fig. 8-11 or a line with ly.+l : 1 Y
lf l = 0.3,0r : 30, md Zs : 50 O. The sinusoidalpattern s calle.da standing wave, and t is causedby
the nterlbrencef the wo waves. he maximum alue
of thesianding-waveatternof lfr(z)l conespondso
oeriod sI forthe incidentandreflected
therepetitionperiod ofthe standing-w)areattern is
The standing-waveatterndescribeshespatial
of the magnitude f V(z) as a function of z. If one
to observehevariations f the nstantaneousoltage
functionof timeat any ocationz,correspondingo
themaximain hestanding-wavepattem,orexample,
variation would be as cos artand would have an
equalo 1.3V [i.e.,u(t) wouldoscillate etweenand 1.3Vl. Similarly,he imeoscillation f u(2, )
any ocation will havean amplitude qual o lV(z)lthatz.
Close inspection of the voltage and
standing-wavepatterns shown in Fig. 8-11
that he wopatterns re n phase pposition when
atamaximum,heother s ataminimum, ndvice
This is a consequencef the fact that the second
Eq.(8 5 a) sprecededy aplussign,whereashe
term n Eq. 8.51b)sprecededya negativeign.
The standing-waveattemsshown n Fig. 8-11 are
a typical situationwith f : 0.3 ei30'.The peak
variation of thepatterndepends n lf l, which can
between and 1. Forthe special ase f a matchedwithZs : 20,wehavef | = 0 and i tz l t = l tfor all valuesof z, as shown n Fig. 8-12(a).Mlh
refected u,avepresent, therc will be no interft
and no stundingwcves.The other end of the lfl
at ll.l : 1, correspondso when he load s a
circuit (f = -1) or an opencircuit (f - 1).
standing-waveattems or these wo cases re showtr
Figs. 8-12(b)and(c), both of which havemaxima
to 2 yo+| andminimaequal o zero,but thetwo
fI
q
ti(z)l
lvlln.r1.41.21.0
0.80.6o.4
ltl,nin - -
lll'na,(- - -
l7lr;n - t- - - - - :
-l -).
z 4
) v\z)t versusz
Figure8-ll: Standing-waveattern or (a) ly(z)l and(b) 1(z) for a osslessransmissionine of characteristic
impedance = 50 I, terminated n a load with a re-
flection oeftcient = 0.3ej30'.The magnitudc f the
incidentwavelVo+l
= I V. Tbe standing-waveatio s
s = lY lma,( / lv lnnn1.3/o.7 = 1.86-
-31
(b
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TIIE LOSSLESS RANSMISSION INE 263
from he oadat which 7(z)l isa maximum,hen
$rzll - l7l,"-= lyo+ltl lrll, (8.54)
and hisoccurswhen
2 fz *0 , - -2 / l ^u *Q = - lnn , (8.5s)
with n : 0 or apositiventeger.SolvingEq.(8.55) or1."r,wehave
. 0,* 2nn 0,x n),-: =,mar = --;-;- = ;--r -
2 p 4 n 2 '
I n - 1 . 2 . . . i f 6 .< 0 . , o z \
l n = 0 . 1 . 2 . . . . i f d , 0 .
( 6 ' 1 0 )
{-- shifted in z relative to each other bv a distanceofJ
\ow letusexaminethe aximum ndminimum aluesrirhe oltagemagnitude.romEq. 8.52),l7(z)lisamax-num when heargument f thecosineunctions equalr:zero r multiples f 2n . Noting hat he ocation n here alwayscorresponds
o negative aluesof z(since
he,:ads atZ = 0), f wedenotema* -z as hedistance
wherewe haveused he relationA : 2tr/^. Thephaseangle f thevoltageeflection oefficient, r,is boundedbetweenz andz radians.f 4 > 0, theirst voltagemaximum occursat l^"^ : 0,)./4tt , correspondingon : 0,but f4 < 0, he irstphysicallymeaningful ax-imumoccurs t mo : (0.),/4n) * l,/2, correspondingtoa : I . Negative aluesof /Itl.*correspondo locations"beyond"the oadat heendof the ineand herefore aveno physical ignificance. s wasmentioned arlier,helocationson the line corresponding o vohagemaximaalso correspond o currentminima, and yiceyersa.
Similarly, the minimum valuesof l7(z)l occur at dis-tances .1n : -z conesponding o when he argumentofthe cosine unction n Eq. (8.52) s equal o -(2n * I )2,which gives heresult
l 7 l . i " : l yo+ l t l l r l l ,
when8 - zpl",i') -(2n + t)n, (8.57)
with-n
S 0, < r . The irstminimumorresDondson : 0. The spacing etween maximum r,* and he
lv(z)l
Figure 8-12: Voltage standing-wavepattems for (a) amatched
load,(b)
a shon-circuited line, and (c) anooen-circuitedine.
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l-6
adjacent inimumri" is L/4. Hence,lheftrstminimum
occursat
,,"'.
{ffii',1:,i',Xli',| (8 8)
The ratio of lVl.o to lVlmin is called tlte voltage
standing-waveatiaS,which romEqs. 8.54) nd(8.57)
isgivenby
Thisquantity,whichoften s referredo by its acronym,
VSWR,or the shorteracmnymSWR,providesa measure
of the mismatchb€tween he load and the transmissionline;foramatchedoadwith f : 0, wegetS : I, and or
a inewith l-l : I, S : oo.
CHAPTER8 TRANSMISSION
ffi sbnding-waveRaiio
A 5GO transmissionine is terminatedn a load
ZL : offi + j50) Q. Find hevoltage efle.tion
cient and hevoltagestanding-waveatio(SWR).
Solution:FromEq. 8.49a), isgivenby( 1 0 0 + j s0 ) - 5 0
rw l-h
9 c&*
-nk
Z r - Z nn: --:---------:
Zt* Zo ( 1 0 0 + j s O ) + 5 0
50+ jso
150 jso'
cv@
^ l y l . * l + l f lS= j ; i "* : - (dimensionless).8.59)
l Y l m i n r -l r I
7o'7eits"" :
#;, '*:0.4sei266'.
Using hedefinitionor Sgivenby Eq. 8.59),wehave
l + l F t | + 0 . 4 5
r = f f i = r _ o / s : 2 . 6 .
Converting he numeratorand denominator o polar
and hensimplifyingyields
0.5 llleasuringL
L slofted-lineorobe s an nstrumentused o
unknown mpedance fa load, Zr. A coaxialslotted
contains narrowonsitudinal lit n theouter
A smallprobe ns€rtedn the slit canbe us€d o
the mlgninrdeof the electric ield and,hence, hetudeyl ofthevoltage n he ine Fig. -13). ytheprobealong he eqgthofthe slotted ine, tis possil
measure V | nr,and IV | in and he distances rom the
REVIEWUESTIONS
QE,s The attenuation onstanto represents hmic
losses.n view of the modelgiven n Fig. 8-6(c),what
shouldR' and G' be in order to have no losses?Verify
yourexpectationhrough he expressionor a givenby
Eq.8.25a).
Q8.6 How is the wavelength , of the wave travel-
ing on the transmission ine related to the free-space
wavelength6?
QE.7 Whens a oadmatchedo the ine?Why s t im-
portant?
Q8.8 Whatisastanding-wavepattem?Whysitsperiod
l/2 andnot ?
Q8.9 What s the separation etween he locationof a
voltage aximum nd headjacenturtentmaximumn
the ine? Figure 8-13: Slotted coaxial ine (Example8-5).
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i6 INPTTTMPEDANCE OF THELOSSLESS INE 265
1 which theyoccur.Use of Eq. (8.59)then provides hedage standing-waveatio .S.Measur€ments ith a5G;- slottedine connectedo anunknown oad mpedance,demined thatS : 3. Thedistance etween uccessiverttageminimawasound obe30cm,and he irstvoltaeenoimumwas ocated r 12cm from he oad.Determiie
r loadmpedance1.
:ilution: The ollowingquanritiesregiven:
Z o : 5 0 Q , S : 3 , / m i n : 2 c m .
:rce thedistance etweenuccessiveoltaseminima sxualtoL/2,
) , : 2 x 0 . 3 : 0 . 6 m .
i--':
^ 2n 2t lOn
(rad/m).I 0 . 6 3::m Eq. 8.59),olvingor f lin termsof gives
. t _ | 3 _ I/ l _ = _ = n <s + 3 +
N.rr.weuse hecondition ivenby Eq. g.57) or the o_:con of a voltageminimumo finde:
i7 - 2pl^in : -v, forn : 0 (firstminimum).
.r;chgives
- :2Qlmin rlOr r
=2x; ' x 0 .12 - r : -O .2 r Iad ) -36" .
EXERCISE.9 If I. : 0.5 -60.and : 24sm,6.6 th,locationsof the voltagcmaxirnumandminimumnearrsttothe oad.
Ans.l,or,, l0cm,lmin4cm. (SeeO)
EXERCISE.10 A tzt0-S2osslessine s terminatedn aload rnpedanceL -- (28O+ j 182)O. f ), : 72 cm,find (a) the reflecrioncoefficienr l, (b) the voltagestanding-waveatioS, c) he ocationsf voltagemaxima,and d) he ocationsfvoltage inima.
Ans. (a) : 0.5 2e.,(b).s 3.0, c)/.", : 2.9 m' 2, d) ^in= 20.9 m n),2.where = 0,1,2,. . . .
(SeeOt
8-6 Inputmpedancef heLosslessine
Thestanding-waveattemsndicatehatoramismatchedlinethe oltage ndcurrentmagnitudesreoscillatoryithposition n he ineandn phaseoppositionitheachLrher.Hence,hevoltageocurrent atio,cal edthe nput impe-danceZin,mustvary ithposition lso.UsingEqs.g.5la)and 8.51b), ;n sgiven y
i t , tZi"Q) : -=:::
I (z\
- vf 1e-ia' leir ' l - vi le-ipz fei l4Lo
- f | + f e j 2 0 z 1: zoLt- rei ' p,l(sl) (8'60)
Note that Z;nk) is the ratio of the total voltase(incident- and reflected-wave oltages)
o he total(;r-
rent at anypoint z on the ine, in contrastwith thechar_
:fe,
r - -Ekio ' :0.5e- j36":0.405 - j0.294.
' ,'. ngEq. (8.49a) or ZL,vtehaye
- =z^r* r l"L l f J
-^f I +0.405 i0.2941
= )uL : olos l02%l = (8s i67tQ' t
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26
acteristicmpedance f the line Zs, which relates he
vohage nd currentof eachof thenuowaves ndividually(zo - vd t; = -v; /6 ).
Of particularnterestn many ransmission-linerob-
lemsistheinputimpedanceattheinputofthelineatz-r,
which sgivenby
f eiPI le- jPIlzaGt):zt l4, _y; :1gi)
f 1 + l e - i 2 q t 1:z" l t : i t ,a,) (8'6r)
By replacing with Eq. 8.49a) ndusinghe elations
CHAPTER8 TRANSMISSION j5
Ja- l&
eiqt cosFl + j sinBl,
e-i?t = cosFI - j sinpl,
Eq. 8.61) anbe ewrittenn terms f ZL as
(8.62a)
(8.62b)
From the standpointof thegeneratorcircuit, the transmis-sion ine can bereplacedwith an mpedanceZin, as shown
in Fig. 8-14.ThephasorvoltageacrossZin s givenby
Equating q. 8.64)o Eq. 8.65) nd hen olvingc
leads o the esult
(8.64) This comDleteshe solutionofthe transmissionline
equations,iven y Eqs. 8.21)and 8.23),or the
caseofa losslessransmissionine. We started ut
general olutionsgivenbyEqs. 8.26a)and(8.26b),
includedourunknown mplitudes, ; , V; , ry ,We hen ound ut h^tzo : vo+ It : -v; lI; ,reducinstheunknownsothe wo
Uponapplyingheboundaryondition t he oad,we
i.z,^V i = I t Z i n : # ,
LA + Li l
butfrom he tandpointf he ransmissionine, he oltage
acrosstat he nputoftheine sgiven yEq. 8.51a) ith
z : - l :
ii: i1-4 : vd[ejtl + re-iPIL (s.6s)
l \
i )i ^e I ) :ZD(
: 2 " (
Zlcos Pl * j Zn sinPsinB/
)
Zscosp l * jZ r -
Zt 'f j Zotan ll
Zo* jZutanfl(8.63)
r+vi ztn+ h
t
1ti
_i
Figure 8-14: At thegeneratorend, he t€rminatedrdE
mission ine canbe replacedwith the input mpedance
the ine Zin.
';=(fu)(t"+;-) (866)
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}5 INPUTIMPEDANCEOFTIIE LOSSLESS INE 267
eM (2, \
A 1.05-GHz enerator ircuitwith seriesmpedance= | 0 Oandvoltage ource ivenby
ug(t) 10sin(a.rr 30') (V)
_. onnectedo a loadZL : (100+ i50) A throughai,!Q, 67-cmlong osslessransmissionine.Thephase
:locityof the ine s0.7c,where is thevelocity i light: avacuum.indu 2, ) and(z,l) on he ine.
rrlution: From herelationship p : Lf, we find the: velensth:
. u o 0 , 7 x 3 x 1 0 8^ : - - - : - - _ _ n . -
" f t .OS lOe- " ' - " ' '
$le torelateyt to Vo+kough f, and, inally,by applyingie boundary onditionat thesendingendof the ine, we$ained anexpressionor 7o+.
With referenceo Fig. 8-14,the input impedance f theline,givenbyEq. 8.63),s
. , . -o f z t+ jzo.nf l lL ' n - L o L 4 +
i z t t ^ p t l
- . f z t /zo+ j ta t t f l 1-Lt + j(zL/zdtn pr)
: 5o f ( z + i t ) + i * t ' u ' '
L + i(2 + 11)a 126": (21'9 i r7 4) '
Rewriting heexpressionorthegeneratoroltagewiththecosineeference,wehave
ur(t) : l0 sin(a.rr 30')
: 1O oskr2 - al/ - 30")
= 10cos(arr 60.)
= n lt1e-j$'
ei@tl nelisei.,l (V).
Hence,hephasor oltage7, isgivenby
7, : 1g2-ia" 1y)_ t0/:& (V).
Application fEq.(8.66) ives
,r:(#h)G;*llt)
f tqe-i$"et.9+ t7.4t1L t0+2r .9+ j17.4).fe
t26'L"9.45"26.6'e- t26"l-
l
: l1.2eitss' v) : lO.Ztss. (V).
Thephasor oltage n he ine s then
71zy=y ;1 " - i o , te ipz)
: 10.2eise"k- jP.+ 0.45ei26.6'ipz,
CompfeteolulionorD(2,)
= tan126'
( 1 0 0 + l s0 ) - 5 0: 0.45ei26.6"(100 j50) + 50
t "@t): ,""(+r)
:t^(fr"o.et): tan6.7r : tan0.7n
r*re we havesubtractedmultiples of 22. The voltase:lection coefficienrat the oad s
. Z t - ZoI = + :Zt* Zo
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i.7 SPECIALCASESOF THE LOSSLESS INE 269
:E rnput mpedancef $e lineatz = -l isgivenbyrrio of V*(-/) to 1*(-l). DenotingZff as he nput
for ashort-circuitedline.wehave
:rt of Zff/lZo versusnegarivez is shown in!r5(d).
h reneral,he nput mpedanceinmayconsistofareal.rtnputresistancein, ndan maginaryart, rinput
Xn :
Zin: R;n jX in . (8.69)
,: drecaseof the short-circuitedosslessine, he nputrgedance spurelyreactive R6 = 0). If tan / > 0, the
j:dappearsnductive, cting ikeanequivalentnductor_-.whosempedances equalo Z,sfThus,
jtltL"o= jZotanpI, if tanBl > 0, (8.70a)
(8.70b)
Since isapositivenumber,he shortestenglh for whichtanpl < 0 correspondso the range /2 < pt < t.Hence,heminimum ine length that wouldresult n aninput impedance iT equivalento thatof a capacitorofcapacitancecos
/ | \ tl - ; - l l ( m ) . ( 8 .7 1 c )\aLqzo, / - )
Theseresultseanthat,hroughproperchoiceofhelengthof a short-circuitedine,wecanmakesubstitutesor ca-pacitors nd nductors ithanydesiredeactance.uchapractices ndeed ommonn thedesignofmicrowave ir-cuitsandhigh-speedntegratedircuits, ecause akineanactual apacitorr nductorsoftenmoredifficult haimaking shortedransmissionine.
$7-l Equivalanteactivetements
Choose he length of a shorted50-O lossless rans_mission ine (Fig. 8-16) such hat ts input impedanceat2.25GHz s equivalento the eactance fa capacitorwithcapacitanceC", : 4 pF. The wavevelocityon the ine is0.75c.
t : ) 1 " - " " '
L"4:z-!g Pt (H).
--minimumine ength thatwould esult n an nput
uedance Z,Tequivalentothatofan inducror find;c-:rte l* is
t : ) tan- ' (+) (m). (8.70c)
rilarly, iftan p/ < 0, the nput mpedanceis apacitive,- : hichcase he ineacts ike anequivalent apacitorCeq-. h hat
I, . . -
= iZotanPI. i f t : ,n l < 0. (8.71a.1l aLeq
/ - - l
" . --
h . t ^ p l (F). (8.71b)
: j Zotan l.
u--f
vf -..-- t7- r|
'jaC,q
---6
FigurcE-16:ShortedineasequivalentapacitorExam-Dle8-7).
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270
Solution:Wearcgiven
up=0.75c 0.75x 3 x 108 2.25x l08n/s,
z o = 5 0 Q ,
f = 2.25GHz 2.25 x l}e Hz,
C* = 4pF:4 x 10-12.
Thephaseonstants
CHAPTER8 TRANSMISSION
8-7.2 0pen-Circuiledine
WithZL = oo.as llustratedn Fig.8-17(a), e| - I, S: oo,and hevoltage, unent,and nput
2nR - -, \ =Zof :2" :=?'25,\" lot 62.8 (rad/m).
up 2.25 106
dance regiven y
ink) : vdt"-iPz+ eiPzfZvd cos z, (8.
i,,<O\f,-jfz
- "iuzl#
rr Ur, r.
-- v*(-l lZ: -- ::-:--- : - jZ6cotpl. (8.73)"'
1*(-/)
Frorn q. 8.71a),
tanPl =ZsaCeq
50 2n x2 .25x lOex4x0- r2
The tangentunction is negativewhen ts argument s in
the second r fourth quadrants.The solution for the second
quadrants
l l t t : 2 . 8 r a dr 11T : # :4 .4 6 cm .
andhesolutionor the ourthquadrants
5 9 4f l z :5 .94 rad or 12 - =9 .46 r^ .
Wealso ouldhaveobtainedhevalueof 11 y applying
Eq. 8.71c).he ength/2sgreaterhan rby exactly"/2.
In act, ny ength = 4.46cm*nl12, wherensapositive
integer,salso solution. I
Plotsof these uantities redisplayedn Fig. 8-17
function fnegative .
8-7.3ApplicationlSh0rt-Circuitnd0pen-Circuileasuremenls
A network analyzer s a radio-frequencyRF)
capablef measuringhempedancef anyoad
to ts nput erminal.Whenusedomeasure ,sfthe
impedancefa losslessine erminatedn a shortandagainZff, the nput mpedancef the ine whenminated n an opencircuit, he combination f the
measurementsanbe used o determine heimpedancef the ine Zs and ts phase onstant .product fEqs. 8.68) nd 8.73) iveshe esult
7 - - (8.74\
and he ratio ofthe sameequationseads o
: -0.354.
'iq
I
q
l . *
r / z *(8.75)
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SPECIALCASESOF T}IE LOSSLESS INE 271
,27fi _+
Figurc 8-17: Transmission line terminated in an open cir-
:uit: (a) schematic r€presentation, O) normalized voltage
rn the line, (c) normalized current, and (d) normalized
-:rput mpedance.
Because f thez phase mbiguityassociated ith the an-gent unction, he ength shouldbe ess hanor equal ol/2 toprovideanunarnbiguousesult.
Find Zn md p of a 57-cm-longosslessransmis-sion line whose nput impedancewas measured sZff: j4O.42A when erminatedn a shortcircuitandasZff : - j 121.24Q when erminatedn anopen ircuit.Fromothermeasurements,eknow hatthe ine sbetween3and3.25wavelengthsong.
Solution:FromEqs. 8.74) nd 8.75),
zo: {lzff zff : JQ4o.42)(-r21.24):70e,f - *
r ^ ^ a t - l - L i a -'*'"' -,1 zff-
Since isberween), and3.25),,l : (2zl/t) isbetween6z radians nd 3rrl2) radians. hisplaces l in the ustquadrant 0 to r/2) in apolarcoordinate ystem.Hence,theonly acceptable olution or theabove quationsp/ =
z/6 radians.This value,however,does not include the2z
multiplesassociated ith the nteger multiplesof I .Hence,he ruevalueof 6l is
p l : 6 r *
in which case
l9.4 (rad),
R - : 34 (rad/m). r
1t
o
19.4
057
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Microwavevens
Percy Spencer,while workingthe 1940s on the design andmagnetronsor radar,observed
TECHNOLOCYBRIEF: MICROWAVE
bar that had unintentionallyeen exposed ocrowaves ad melted n hispocket. hecooking ymicrowave aspatentedn 1946enthe 1970s.microwave/ens had becomehouseholdtems.
tor Raythoon nconstruction f
that a chocolate
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IECHNOLOGY RIEF:MICROWAVE VENS z I t
l l icrowavebsorption
micro$ra'vesan electromagnetic avewhose re-
S.,encyies n the 300 MHz-€00GHz range. SeeFrg.1-9.)Whena material ontainingwater s ex-posedo microwaves,he watermoleculeeac,tsyotating tselfso as io align ts own electricdipolealong he directionof the electric ield of the mi-crowave. he rotationmotioncreatesheat in thenaterial, esultingn the conversion f microwave3nergynto hermalenergy.Microwave bsorptionJywater xhibits spectrum itha peak hatoccurseta resonantfrequenc/ whose rEllueepends nh€ temperaturef the waterand on theconcentra-lonof dissolved altsor sugars resentn hewater.-he
lrequencymostcommonly sed n microwave:venss 2.54GHz,and hestandard ource orgen-
erating nergyat this frequencys the magnetron.rvhereasmicrowavesre readilyabsorbed y wa-'er,fats, and sugars, hey can penetrate hrough-ost ceramics, lass,or plasticswithoutossof en-:rgy, hereby mparting o heat o thosematerials.
Ovenperation
Togeneratehigh-powermicrowaves- 70Owatts)the microwavevenusesa magnetronube,whichrequires he application f a voltageon the or-der ot 4000volts.The ypicalhouseholdoltageof115volts s increasedo the required oltage evelthrough high-voltageransformer.he microwaveenergygenerated y the magnetrons transferredinto a cookingchamberdesigned o contain hemicrowaves ithin t through he use of metalsur-facesandsafety nterlockwitches.Microwavesrereflec'tedby metal surfaces,so they can bouncearound he nterior f the chamber r be absorlredby the food, but not escape o the outside. f theovendoor s madeof a glasspanel,a metalscreenor a layero{ conductivemesh sattachedo it to en-
sure the necessary hielding;microwaves annotpass hrough he metal screen f the mesh widthis muchsmaller han the wavelengthf the mi-crowave- 12cm at 2.5GHz). n hechamber,hemicrowavenergy stablishes standing-waveat-tern,which eads o an uneven istribution. his smitigated y usinga rotatingmetalstirrer hatdis-perses he microwave nergy o differentpartsofthe chamber.