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End Show © Copyright Pearson Prentice Hall Slide 1 of 46 Concentrations of Solutions Water must be tested continually to ensure that the concentrations of contaminants do not exceed established limits. These contaminants include metals, pesticides, bacteria, and even the by-products of water treatment. You will learn how solution concentrations are calculated. (molarity; % v/v; %m/m; ppm) 16. 2
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Page 1: End Show © Copyright Pearson Prentice Hall Slide 1 of 46 Concentrations of Solutions Water must be tested continually to ensure that the concentrations.

End Show© Copyright Pearson Prentice Hall

Slide 1 of 46

Concentrations of Solutions

Water must be tested continually to ensure that the concentrations of contaminants do not exceed established limits. These contaminants include metals, pesticides, bacteria, and even the by-products of water treatment. You will learn how solution concentrations are calculated.(molarity; % v/v; %m/m; ppm)

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Molarity

The concentration of a solution is a measure of the amount of solute that is dissolved in a given quantity of solvent.

• A dilute solution is one that contains a small amount of solute.

• A concentrated solution contains a large amount of solute.

16.2

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Concentrations of Solutions>

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16.2 Molarity

Molarity

How do you calculate the molarity of a solution?

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Molarity

Molarity (M) is the number of moles of solute dissolved in one liter of solution.

To calculate the molarity of a solution, divide the moles of solute by the volume of the solution.

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Molarity

To make a 0.5-molar (0.5M) solution, first add 0.5 mol of solute to a 1-L volumetric flask half filled with distilled water.

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Molarity

Swirl the flask carefully to dissolve the solute.

16.2

Fill the flask with water exactly to the 1-L mark.

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16.2

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16.2

Page 9: End Show © Copyright Pearson Prentice Hall Slide 1 of 46 Concentrations of Solutions Water must be tested continually to ensure that the concentrations.

for Sample Problem 16.2

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16.3

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Sample Problem 16.3

16.3

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for Sample Problem 16.3

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Concentrations of Solutions>16.2 Making Dilutions

Making Dilutions

What effect does dilution have on the total moles of solute in a solution?

Diluting a solution reduces the number of moles of solute per unit volume, but the total number of moles of solute in solution does not change.

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Making Dilutions

The total number of moles of solute remains unchanged upon dilution, so you can write this equation.

M1 and V1 are the molarity and volume of the initial solution, and M2 and V2 are the molarity and volume of the diluted solution.

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Making Dilutions

Making a Dilute Solution

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Making Dilutions

To prepare 100 ml of 0.40M MgSO4 from a stock solution of 2.0M MgSO4, a student first measures 20 mL of the stock solution with a 20-mL pipet.

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Making Dilutions

She then transfers the 20 mL to a 100-mL volumetric flask.

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Making Dilutions

Finally she carefully adds water to the mark to make 100 mL of solution.

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Making Dilutions

Volume-Measuring Devices

16.2

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16.4

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16.4

Page 22: End Show © Copyright Pearson Prentice Hall Slide 1 of 46 Concentrations of Solutions Water must be tested continually to ensure that the concentrations.

for Sample Problem 16.4

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Concentrations of Solutions> Percent Solutions

Percent Solutions

What are two ways to express the percent concentration of a solution?

The concentration of a solution in percent can be expressed in two ways: as the ratio of the volume of the solute to the volume of the solution or as the ratio of the mass of the solute to the mass of the solution.

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Percent Solutions

Concentration in Percent (Volume/Volume)

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Percent Solutions

Isopropyl alcohol (2-propanol) is sold as a 91% solution. This solution consist of 91 mL of isopropyl alcohol mixed with enough water to make 100 mL of solution.

16.2

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16.5

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© Copyright Pearson Prentice Hall

SAMPLE PROBLEM

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16.5

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Practice Problems For Sample Problem 16.5

for Sample Problem 16.5

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Percent Solutions

Concentration in percent (mass/mass)

16.2

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© Copyright Pearson Prentice Hall

Concentrations of Solutions> Parts per million

Concentration in parts per million (ppm)

(To complete)

16.2

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Section Quiz

-or-Continue to: Launch:

Assess students’ understanding of the concepts in Section

16.2 Section Quiz.

16.1.

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© Copyright Pearson Prentice Hall

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16.2 Section Quiz.

1. To make a 1.00M aqueous solution of NaCl, 58.4 g of NaCl are dissolved in

a. 1.00 liter of water.

b. enough water to make 1.00 liter of solution

c. 1.00 kg of water.

d. 100 mL of water.

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© Copyright Pearson Prentice Hall

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16.2 Section Quiz.

2. What mass of sodium iodide (NaI) is contained in 250 mL of a 0.500M solution?

a. 150 g

b. 75.0 g

c. 18.7 g

d. 0.50 g

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© Copyright Pearson Prentice Hall

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16.2 Section Quiz.

3. Diluting a solution does NOT change which of the following?

a. concentration

b. volume

c. milliliters of solvent

d. moles of solute

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© Copyright Pearson Prentice Hall

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16.2 Section Quiz.

4. In a 2000 g solution of glucose that is labeled 5.0% (m/m), the mass of water is

a. 2000 g.

b. 100 g.

c. 1995 g.

d. 1900 g.

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© Copyright Pearson Prentice Hall

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16.2 Section Quiz.

4. In a 2000 g solution of glucose that is labeled 4.0 ppm, the mass of glucose is

a. 2000 g.

b. 100 g.

c. 1995 g.

d. 0.0080 g.

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END OF SHOW


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