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TERM PAPER
OFENGINEERING MATHAMETICS-I
MTH101
Topic: Write about the method of undetermined
coefficients & method of variation of parameters. Discuss
& compare the advantages and disadvantages of eachmethod.
Illustrate your findings with examples
Sub. To: Sub. By:
Mr. Bharpur Singh Name: - Vaibhav Kumar Tripathi
(Deptt. Of Mathematics) Roll no- RG4003A34
Program-B.Tech-M.Tech (ME)
Program code-1208-D
Reg.no-11000653
Section-G4003
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ACKNOWLEDGEMENT
I would like to thank all those who have encouraged me to Submit a
project related to Write about the method of undetermined
coefficients & method of variation of parameters. Discuss
& compare the advantages and disadvantages of each
method.
Illustrate your findings with examplesas a term paper.It is an extremely arduous job to acknowledge the invaluable help
rendered by all those venerated souls who directly or indirectlycontributes to make feat as possible for me. I certainly feel elated and
privileged to express my deep sense to gratitude to all of them.
The entire term paper would not have come to a state of fruition
without them. During term paper work, I learnt many things.
Everybody was extremely co-operative. I thank all the members of
LOVELY PROFESSIONAL UNIVERSITY who extended theirhands for help, co-operation and kindness whenever and wherever
required
VAIBHAV KUMAR TRIPATHI
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CONTENT TABLE
1. INTRODUCTION TO METHOD OF UNDETERMINED
COEFFICIENTS.
2. METHODOLOGY
3. TYPICAL FORM OF SOLUTION
4. EXAMPLES
5. INTRODUCTION TO METHOD OF VARIATIONS OF
PARAMERTERS
6. METHODOLOGY
7. EXAMPLES
8. ADVANTAGES AND DISADVANTAGES OF EACH
METHOD WITH EXAMPLES
9. REFERNCES
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INTRODUCTION TO METHOD OF UNDETERMINED
COEFFICIENTS
In Mathematics, the method of undetermined coefficients, otherwise
known as the Lucky Guess Method, is an approach to finding a
particular solution to a certain inhomogeneous ordinary differentialequations and recurrence relation. It is closely related to annihilator
method (variation of parameter method), but instead of using a
particular kind of differential operator (the annihilator) in order to find
the best possible from of the particular solution, a guess is made as to
the appropriate form , which is then tested by differentiating the
resulting equation. For complex equations, the annihilator method or
variation of parameters is less time consuming to perform.
METHODOLOGY
Considering a linear non-homogeneous ordinary differential equation
with the form
any(n) + a(n 1)y(n 1) + ... + a1y' + a0y = g(x)
The method consists of finding the homogeneous solution yc for the
complementary function and a particular solution yp based on g(x).
Then the general solution y to the equation would be
y = yc + yp
If g(x) consists of the sum of two functions h(x) + w(x) and we say that
yp1 is the solution based on h(x) and yp2 the solution based on w(x).
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Then, using the superposition principle, we can say that the particular
solution yp is
yp = yp1 + yp2
TYPICAL FORM OF SOLUTION
In order to find the particular solution, we need to 'guess' its form, with
some coefficients left as variables to be solved for. This takes the form of
the first derivative of complementary function. Below is a table of some
typical functions and the solution to guess for them.
Function of x Form for y
If a term in the above particular solution for y appears in the
homogeneous solution, it is necessary to multiply by a sufficiently large
power of x in order to make the two solutions linearly independent. If
the function of x is a sum of terms in the above table, the particular
solution can be guessed using a sum of the corresponding terms for y.
EXAMPLES
EXAMPLE1
Find a particular solution of the equation
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The right side t cos t has the form
With n=1, =0, and =1.
Since + i = i is a simple root of the characteristic equation
We should try a particular solution of the form
Substituting yp into the differential equation, we have the identity
Comparing both sides, we have
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Which has the solution A0 = 0, A1 = 1/4, B0 = 1/4, B1 = 0. We then have
a particular solution
Example 2
Consider the following linear inhomogeneous differential equation:
This is like the first example above, except that the inhomogeneous part
(ex) is not linearly independent to the general solution of the
homogeneous part (c1ex); as a result, we have to multiply our guess by a
sufficiently large power of x to make it linearly independent.
Here our guess becomes:
Yp= A x ex.
By substituting this function and its derivative into the differential
equation, one can solve for A:
Axex + Aex = Axex + ex
A = 1.
So, the general solution to this differential equation is thus:
y = c1ex + xex.
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Example 3
Find the general solution of the equation:
f(t), t2, is a polynomial of degree 2, so we look for a solution using the
same form,
yp = At2 + Bt + C, where
Plugging this particular solution with constants A, B, and C into the
original equation yields,
2At + B = t2 (At2 + Bt + C), where
T2 At2 = 0 and Bt = 2At and C = B
Replacing resulting constants,
Yp = t2 2t + 2
To solve for the general solution,y = yp + yh
Where yh is the homogeneous solution yh = c1e-1 therefore the general
solution is:
y = t2 2t + 2 + c1 e-t
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INTRODUCTION TO METHOD OF VARIATIONS OF
PARAMERTERS
In Mathematics, Variations of Parameters, also knownas variations ofconstant, is a general method to solve inhomogeneous linear ordinary
differential equations. It was developed by Joseph Louis Lagranges.
For first-order inhomogeneous linear differential equations its usually
possible to find solutions via integrating factor or undermined
coefficient with considerably less effort, although those methods are
rather heuristic that involve guessing and dont work for all
inhomogeneous linear differential equations.
Variations of parameters extend to linear partial differential equations
as well, specifically to inhomogeneous problems for linear evolution
equations like that heat equations, wave equations, and vibrating plate
equations. In this setting, the method is more often known as Duhamels
principle, named for Jean-Marie Duhamel who was first applied the
method to solve the inhomogeneous heat equations.
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METHODOLOGY
Given an ordinary non-homogeneous linear differential equation of
order n
(i)
Let be a fundamental system of the corresponding
homogeneous equation
(ii)
Then a particular solution to the non-homogeneous equation is given by
(iii)
Where the ci(x) are continuous functions which satisfy the equations
(iv)
(Results from substitution of (iii) into the homogeneous case (ii); )
And
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(v)
(Results from substitution of (iii) into (i) and applying (iv);
Ci'(x) = 0 for all x and i is the only way to satisfy the condition, since allyi(x) are linearly independent. It implies that all ci(x) are independent of
x in the homogeneous case b(x)=0. )
This linear system of n equations can then be solved using Cramer's
rule yielding
Where W(x) is the Wronskian determinant of the fundamental system
and Wi(x) is the Wronskian determinant of the fundamental system
with the i-th column replaced by
The particular solution to the non-homogeneous equation can then be
written as
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EXAMPLES
SPECIFIC SECOND ORDER EQUATION
Let us solve
We want to find the general solution to the differential equation, that is,
we want to find solutions to the homogeneous differential equation
From the characteristic equation
Since we have a repeated root, we have to introduce a factor of x for one
solution to ensure linear independence.
So, we obtain u1 = e2x, and u2 = xe2x. The Wronskian of these two
functions is
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Because the Wronskian is non-zero, the two functions are linearly
independent, so this is in fact the general solution for the homogeneous
differential equation (and not a mere subset of it).
We seek functions A(x) and B(x) so A(x)u1 + B(x)u2 is a general solution
of the non-homogeneous equation. We need only calculate the integrals
That is,
Where C1 and C2 are constants of integration.
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General second order equation
We have a differential equation of the form
And we define the linear operator
Where D represents the differential operator. We therefore have to
solve the equation Lu(x) = f(x) for u(x), where L and f(x) are known.
We must solve first the corresponding homogeneous equation:
By the technique of our choice. Once we've obtained two linearly
independent solutions to this homogeneous differential equation
(because this ODE is second-order) call them u1 and u2 we can
proceed with variation of parameters.
Now, we seek the general solution to the differential equation uG(x)
which we assume to be of the form
Here, A(x) and B(x) are unknown and u1(x) and u2(x) are the solutions
to the homogeneous equation. Observe that if A(x) and B(x) are
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constants, then LuG(x) = 0. We desire A=A(x) and B=B(x) to be of the
form
Now,
And since we have required the above condition, then we have
Differentiating again (omitting intermediary steps)
Now we can write the action of L upon uG as
Since u1 and u2 are solutions, then
We have the system of equations
Expanding,
So the above system determines precisely the conditions
We seek A(x) and B(x) from these conditions, so, given
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We can solve for (A(x), B(x))T, so
Where W denotes the Wronskian of u1 and u2. (We know that W is
nonzero, from the assumption that u1 and u2 are linearly independent.)
So,
While homogeneous equations are relatively easy to solve, this method
allows the calculation of the coefficients of the general solution of the
inhomogeneous equation, and thus the complete general solution of the
inhomogeneous equation can be determined.
Note that A(x) and B(x) are each determined only up to an arbitrary
additive constant (the constant of integration); one would expect two
constants of integration because the original equation was second order.
Adding a constant to A(x) or B(x) does not change the value of LuG(x)
because L is linear.
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ADVANTAGES AND DISADVANTAGES OF EACH METHOD
WITH EXAMPLES.
Undetermined Coefficients
Advantages:
a. Easy mathematics: involves NO integration.
b. Can be used to find a particular solution without having to find
eigenvectors.
Disadvantages:
a. Only works when g contains nice functions (polynomials,
exponentials, and trigs).
b. P must have constant coefficients.
Variation of Parameters
Advantages:
a. May be applied to solve any problem.
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b. Easy to remember: the only formulae you need are are u0 = g
And xP= u.
Disadvantages:
a. Solving equations can get ugly because each component of the
vectors involved can contain a complicated expression and row-
reduction becomes cumbersome.
b. Integrating equationto find solution can sometimes be difficult.
c. Doing the matrix multiplication of equations can be tedious.
REFERENCES
1. Boyce, W. E.; DiPrima, R. C. (1965). Elementary Differential
Equations and Boundary Value problems. Wiley Interscience.
2. ^ Kenneth H. Rosen: Handbook of Discrete and Combinatorial
Mathematics. CRC Press 2000. (3.3.3 Nonhomogeneous
Recurrence Relations)
3. ^ Kenneth H. Rosen: Handbook of Discrete and Combinatorial
Mathematics. CRC Press 2000. (3.3.3 Nonhomogeneous
Recurrence Relations)