EQ-502 Curve Fitting - 2 Constants Data Linear is at Ion

8/14/2019 EQ-502 Curve Fitting - 2 Constants Data Linear is at Ion

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Curve fitting by Data Linearisation of a line defined by 2 constants

Select the sheet containing the order of polynomial to be fitted.

Introduction:Welcome to Computer Aided Analysis excel package.Using this application we cou

the following problem quickly.Curve fitting(2 constants)-This will solve the curve fitting problem of line definedconstants.For detailed information you can seek help which is available at every

Important Notes:1.Every input is to be given in pink cells

2.The results are to be shown in various colors to your clear visibility.So at any cost do nany values in cells other than pink cells

3.In every page there will be red color circle which guide you through step by step progcalculation

y=ax-1+b

y=a(x+b)-1

y=(ax+b)-1

y=x(a+bx)-1

y=a log x+b

y=b eax

y=bxa

y=(ax+b)-2

y=bx eax

y=c/(1+beax )-1


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y=ax^(-1)+b'!A1

y=a(x+b)^-1'!A1

y=(ax+b)^-1'!A1

y=x(a+bx)^-1'!A1

y=a logx+b'!A1

y=b.exp(ax)'!A1

y=b.x^a'!A1y=(ax+b)^(-2)'!A1

y=bx.exp(ax)'!A1

y=c.{1+b.exp(ax)}^(-1)'!A1
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Next

d solve

by twoheet.

t input

ess of


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Curve fitting of a line defined b

Input values: Data for fitting the curvea = 2 x y

b = 6 1 8

xmin = 1 2 7xmax = 5 3 6.67

4 6.5

dx= 1 5 6.4

SolutionX Y X^2 XY

1 8 1 8

0.5 7 0.25 3.5

0.33 6.67 0.11 2.22

0.25 6.5 0.06 1.63

0.2 6.4 0.04 1.28

2.28 34.57 1.46 16.63Normal Equation

1.46 2.28 A = 16.63

2.28 5 B 34.57

Solution

A = 2 a = 2

B 6 b 6

0.5 1 1.5 2

0

1

2

3

4

5

6

7

8

9


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y=a/x+b Back Menu Next

2.5 3 3.5 4 4.5 5 5.5


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Curve fitting of a line defined by


b = 2 -5 -0.33

xmin = -5 -2.5 -2

xmax = 5 0 0.5

2.5 0.22

dx= 2.5 5 0.14

SolutionX Y X^2 XY

1.67 -0.33 2.78 -0.56

5 -2 25 -10

0 0.5 0 0

0.56 0.22 0.31 0.12

0.71 0.14 0.51 0.1

7.94 -1.47 28.6 -10.33

Normal Equation28.6 7.94 A = -10.33

7.94 5 B -1.47

SolutionA = -0.5 a = 1

B 0.5 b 2 -6 -4-2.5

-2

-1.5

-1

-0.5

0

0.5

1


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y=a/(x+b) Back Menu Next

-2 0 2 4 6


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Curve fitting of a straight line defi


b = 3 0 0.33

xmin = 0 1.25 0.24xmax = 5 2.5 0.18

3.75 0.15

dx= 1.25 5 0.13

SolutionX Y X^2 XY

0 3 0 0

1.25 4.25 1.56 5.31

2.5 5.5 6.25 13.75

3.75 6.75 14.06 25.31

5 8 25 40

12.5 27.5 46.88 84.38Normal Equation

46.88 12.5 A = 84.38

12.5 5 B 27.5

SolutionA = 1 a = 1

B 3 b 3

0 1

0

0.05

0.1

0.15

0.2

0.25

0.3

0.35


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ed by y=1/(ax+b) Back Menu Next

2 3 4 5 6


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Curve fitting of a straight lin


b = 1 0.1 0.09

xmin = 0.1 1.58 0.61xmax = 6 3.05 0.75

4.53 0.82

dx= 1.48 6 0.86

SolutionX Y X^2 XY

10 11 100 110

0.63 1.63 0.4 1.04

0.33 1.33 0.11 0.44

0.22 1.22 0.05 0.27

0.17 1.17 0.03 0.19

11.35 16.35 100.59 111.94Normal Equation

100.59 11.35 A = 111.94

11.35 5 B 16.35

SolutionA = 1 a = 1

B 1 b 1

0 1

0

0.1

0.2

0.3

0.4

0.5

0.6

0.7

0.8

0.9


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defined by y=x/(a+bx) Back Menu Next

2 3 4 5 6 7


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b = 2 0 -4.91

xmin = 0 1.25 2.22xmax = 5 2.5 2.92

3.75 3.32

dx= 1.25 5 3.61

SolutionX Y X^2 XY

-6.91 -4.91 47.72 33.9

0.22 2.22 0.05 0.5

0.92 2.92 0.84 2.67

1.32 3.32 1.75 4.39

1.61 3.61 2.59 5.81

-2.84 7.16 52.94 47.27Normal Equation

52.94 -2.84 A = 47.27

-2.84 5 B 7.16

SolutionA = 1 a = 1

B 2 b 2

0 1

-6

-4

-2

0

2

4

6


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ed by y=a logx+b Back Menu Next

2 3 4 5 6
http://opt/scribd/conversion/tmp/scratch2361/http://opt/scribd/conversion/tmp/scratch2361/


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Input values: Data for fitting the curvea = 1.2 x y

b = 1.2 -5 0

xmin = -5 -2.5 0.06xmax = 5 0 1.2

2.5 24.1

dx= 2.5 5 484.11

SolutionX Y X^2 XY

-5 -5.82 25 29.09

-2.5 -2.82 6.25 7.04

0 0.18 0 0

2.5 3.18 6.25 7.96

5 6.18 25 30.91

0 0.91 62.5 75Normal Equation

62.5 0 A = 75

0 5 B 0.91

SolutionA = 1.2 a = 1.2

B 0.18 b 1.2

-6 -4

0

100

200

300

400

500

600


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ed by y=b exp(ax) Back Menu Next

-2 0 2 4 6


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b = 2 1 2

xmin = 1 2 64xmax = 5 3 486

4 2048

dx= 1 5 6250

SolutionX Y X^2 XY

0 0.69 0 0

0.69 4.16 0.48 2.88

1.1 6.19 1.21 6.8

1.39 7.62 1.92 10.57

1.61 8.74 2.59 14.07

4.79 27.4 6.2 34.32

Normal Equation6.2 4.79 A = 34.32

4.79 5 B 27.4

SolutionA = 5 a = 5

B 0.69 b 2

Curve fitting of a line defin

0.5 1 1

0

1000

2000

3000

4000

5000

6000

7000


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d by y=b xa Back Menu Next

.5 2 2.5 3 3.5 4 4.5 5 5.5


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b = 5 1 0.02

xmin = 1 2 0.01xmax = 5 3 0.01

4 0.01

dx= 1 5 0

SolutionX Y X^2 XY

1 7 1 7

2 9 4 18

3 11 9 33

4 13 16 52

5 15 25 75

15 55 55 185

Normal Equation55 15 A = 185

15 5 B 55

SolutionA = 2 a = 2

B 5 b 5

Curve fitting of a line defined b

0.5 1 1

0

0.01

0.01

0.02

0.02

0.03


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y y=1/(ax+b)2 Back Menu Next

.5 2 2.5 3 3.5 4 4.5 5 5.5
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Input values: Data for fitting the curvea = 0.5 x y

b = 0.55 1 0.91

xmin = 1 2 2.99xmax = 5 3 7.39

4 16.26

dx= 1 5 33.5

SolutionX Y X^2 XY

1 -0.1 1 -0.1

2 0.4 4 0.8

3 0.9 9 2.71

4 1.4 16 5.61

5 1.9 25 9.51

15 4.51 55 18.53

Normal Equation55 15 A = 18.53

15 5 B 4.51

SolutionA = 0.5 a = 0.5

B -0.6 b 0.55

Curve fitting of a line defined by y

0.5 1 1.5

0

5

10

15

20

25

30

35

40


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b.x.eax Back

2.5 3 3.5 4


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Input values:

a = 1 Data for fitting the curveb = 3 x y

c = 1 0 0.25

xmin = 0 1.25 0.09

xmax = 5 2.5 0.03

3.75 0.01

dx= 1.25 5 0

SolutionX Y X^2 XY

0 1.1 0 0

1.25 2.35 1.56 2.94

2.5 3.6 6.25 9

3.75 4.85 14.06 18.18

5 6.1 25 30.49

12.5 17.99 46.88 60.61

Normal Equation

46.88 12.5 A = 60.61

12.5 5 B 17.99

Solution

A = 1 a = 1

B 1.1 b 3

Curve fitting of a line defined by y=c/(1

0 1

0

0.05

0.1

0.15

0.2

0.25

0.3


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+beax) Back Menu

2 3 4 5 6

Curve fitting line:y=c/(1+beax)

Date post:	30-May-2018
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EQ-502 Curve Fitting - 2 Constants Data Linear is at Ion

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