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Example – 8” Concrete Wall

Date post: 03-Jan-2016
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Example – 8” Concrete Wall. perm = grain/(hr∙ft 2 ∙in Hg). Review of Terms. -ity terms – material properties ( k , µ ) Inverse of 1. (resistivity, diffusion resistivity) -ance terms – 2. × thickness ( R , Z ) Inverse of 3. ( U , M ). Governing Equation For Diffusion. - PowerPoint PPT Presentation
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Example – 8” Concrete Wall Conductivity , k BTU∙in/(h ft 2 °F) Resistivity h ft 2 °F/(BTU∙in) Resistance, R h ft 2 °F/(BTU) Conductance, U BTU/(h ft 2 °F) ~15 0.067 0.53 1.9 Permeabili ty, µ perm∙in Diffusion Resistivity rep/in Diffusion Resistance, Z rep Permeance , M perm ~3.2 0.31 2.48 0.40 perm = grain/(hr∙ft 2 ∙in Hg)
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Page 1: Example – 8” Concrete Wall

Example – 8” Concrete Wall

Conductivity, k

BTU∙in/(h ft2 °F)

Resistivity

h ft2 °F/(BTU∙in)

Resistance, R

h ft2 °F/(BTU)

Conductance, U

BTU/(h ft2 °F)

~15 0.067 0.53 1.9

Permeability, µ

perm∙in

Diffusion Resistivity

rep/in

Diffusion Resistance, Z

rep

Permeance, M

perm

~3.2 0.31 2.48 0.40

perm = grain/(hr∙ft2∙in Hg)

Page 2: Example – 8” Concrete Wall

Review of Terms

1. -ity terms – material properties (k, µ)

2. Inverse of 1. (resistivity, diffusion resistivity)

3. -ance terms – 2. × thickness (R, Z)

4. Inverse of 3. (U, M)

Page 3: Example – 8” Concrete Wall

Governing Equation For Diffusion

• w water vapor flux [M/t/A, kg/s/m2]

• µ permeability [perms∙in, perm = grain/(hr∙ft2∙in Hg)]• Permeance [ng/(s·m2·Pa)]

• p is water vapor pressure

• x is distance along flow path

• Water diffuses from high vapor pressure to low vapor pressure

• Permeability is a function of temperature in materials• Very ugly non-linear relationship

x

pw

d

d

Page 4: Example – 8” Concrete Wall

Series Moisture Transfer

rep

permZ

Z

P

x

pw

1,

d

dtotal

i

total

i

Z

Z

P

P

ΔP = water vapor pressure difference

Z = Diffusion resistance

Page 5: Example – 8” Concrete Wall

Saturation Vapor Pressure

• Function of temperature

Ref: ASHRAE Handbook of Fundamentals

Page 6: Example – 8” Concrete Wall
Page 7: Example – 8” Concrete Wall
Page 8: Example – 8” Concrete Wall
Page 9: Example – 8” Concrete Wall

If Condensation Occurs

• Set vapor pressure to saturation pressure at most likely point

• Divide wall into two sections

• Use relationship on each side of condensation

• Recalculate vapor pressures

total

i

total

i

Z

Z

P

P

Page 10: Example – 8” Concrete Wall
Page 11: Example – 8” Concrete Wall

Cautionary Notes

1. 1-D moisture and thermal transport

2. Assumed steady-state and equilibrium conditions

Page 12: Example – 8” Concrete Wall

Equilibrium Moisture Content

• Mass (or volume) ratio between moisture in material and wet (or dry) material

• http://www.forestprod.org/cdromdemo/wd/wd4.html

Page 13: Example – 8” Concrete Wall

Review moisture transport

• Moisture transport• Liquid flow• Vapor diffusion• Air movement• Capillary action

• What driving force is responsible for each one?

• What do you need for each transport method?


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