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Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC ∆DBC. Find the value of...

Date post: 06-Jan-2018
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In Lesson 4-5, you proved triangles congruent by showing that all six pairs of corresponding parts were congruent. Luckily for us! There is a short cut!!
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Example: Using Corresponding Parts of Congruent Triangles Given: ABC DBC. Find the value of x. BCA and BCD are rt. s. BCA BCD mBCA = mBCD (2x – 16)° = 90° 2x = 106 x = 53 Def. of lines. Rt. Thm. Def. of s Substitute values for mBCA and mBCD. Add 16 to both sides. Divide both sides by 2.
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Page 1: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

Example: Using Corresponding Parts of Congruent Triangles

Given: ∆ABC ∆DBC.

Find the value of x.

BCA and BCD are rt. s.

BCA BCD

mBCA = mBCD

(2x – 16)° = 90°

2x = 106

x = 53

Def. of lines.

Rt. Thm.

Def. of s

Substitute values for mBCA and mBCD.

Add 16 to both sides.

Divide both sides by 2.

Page 2: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

Example: Using Corresponding Parts of Congruent Triangles

Given: ∆ABC ∆DBC.

Find mDBC.

mABC + mBCA + mA = 180°

mABC + 90 + 49.3 = 180

mABC + 139.3 = 180

mABC = 40.7

DBC ABC

mDBC = mABC

∆ Sum Thm.

Substitute values for mBCA and mA.

Simplify.

Subtract 139.3 from both sides.

Corr. s of ∆s are .

Def. of s.

mDBC 40.7° Trans. Prop. of =

Page 3: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

In Lesson 4-5, you proved triangles congruent by showing that all six pairs of corresponding parts were congruent.

Luckily for us! There is a short cut!!

Hurray!!

Page 4: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

What do you think SSS stands for?Side-side-side

What do you think SAS stands for?Side-angle-side

Page 5: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

Adjacent triangles share a side, so you can apply the Reflexive Property to get a pair of congruent parts.

Remember!

Reflexive Property is your new best friend

Page 6: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =
Page 7: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

OUR FIRST PROOF is here!!!!!

yay

Page 8: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =
Page 9: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

A two-column proof has…surprise… TWO columns…

Statements Reasons

“Word” stuff“Math” stuff

You will always be given 1 or more “Givens” and you will always be given a “Prove”

Page 10: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

Step 1: MARK IT UP!!!Step 2: Decide what you are usingStep 3: ATTACK! Check off the useStep 4: Get to the end goal, the PROVE

Page 11: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

Example 1: Using SSS to Prove Triangle CongruenceProve:∆ABC ∆DBC.

1. Given2. Given3. Reflexive Property4. SSS

SS

S

USE: SSS

Statements Reasons

✔ ✔ ✔

Page 12: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

The letters SAS are written in that order because the congruent angles must be between pairs of congruent corresponding sides.

Caution

Page 13: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

An included angle is an angle formed by two adjacent sides of a polygon.B is the included angle between sides AB and BC.

SAS is sassy and particularAn example of SAS

S

SA

Page 14: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

An example of a SAS impersonator

S

S

A

Yes, the impersonator forms a bad word. We will be discussing this one later…

Page 15: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =
Page 16: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

Example 2: Engineering Application

Prove: ∆XYZ ∆VWZ.

1. Given2. Vertical angles are congruent3. Given4. SAS

SA

S

USE: SAS

Statements Reasons

✔ ✔ ✔

Page 17: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

Example 3: Proving Triangles Congruent

Given: BC ║ AD, BC AD

Prove: ∆ABD ∆CDB

ReasonsStatements

5. SAS5. ∆ABD ∆ CDB

4. Reflex. Property

1. Given

3. Alt. Int. s Thm.3. CBD ABD

2. Given2. BC || AD

1. BC AD

4. BD BD

USE: SAS

Step 1 MARK IT UP!

S

S

A

Page 18: Example: Using Corresponding Parts of Congruent Triangles Given: ∆ABC  ∆DBC. Find the value of x.  BCA and  BCD are rt.  s.  BCA   BCD m  BCA =

Check It Out! Example 4

Given: QP bisects RQS

Prove: ∆RQP ∆SQP

ReasonsStatements

R

Q

SP

Not enough info!


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