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Baseflow for Subbasins A = 100 cfs

Initial infiltration for the first hr = 0.5 in

Constant infiltration = 0.25 in

0

100

200

300

400

500

600

700

0 2 4 6 8 10 12 14

   Q    (

  c   f  s   )

Time (hr)

Storm Hydrograph for Subbasin A

0

0.5

1

1.5

2

2.5

3

3.5

1 2 3

   I  n   t  e  n  s   i   t  y    (   i

  n   /   h  r   )

Time (hr)

Rainfall hyetograph

(Subbasin A)

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DRO = Total Runoff – Base Flow

Total Runoff = 12 hr * 600 cfs *!

 * (3600 s/ hr) * (1 ac-ft/ 43,560 ft3

)= 297.5 ac-ft

Base Flow = (12 hr + 10 hr)/2 * 100 cfs * (3600 s/ hr) * (1 ac-ft/ 43,560 ft3)

= 90.9 ac-ft

DRO = 297.5 ac-ft – 90.9 ac-ft

DRO = 206.6 ac-ft

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!  Q, P IIE =0/

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?@R P IIE =0/ S G 2$ S T

?@R P GGE =0/U2$ P GGE )=U-*

GGE )=U-* V GGE )= P H -*

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Time(0.5

hr) 

Q(cfs) 

0 0

1 55

2 110

3 165

4 220

5 183.333

6 146.667

7 110

8 73.333

9 36.667

10 0

0.5 in 0.5 in1 in1.5 in

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*"4+@"# 8" 01-234$ DH C-(8 ,Time(0.5

hr) 

Q(cfs) 

0 0

1 55

2 110

3 165

4 220

5 183.333

6 146.667

7 110

8 73.333

9 36.667

10 0

Time (0.5 hr) P1*Un P2*Un P3*Un P4*Un Qn

0 0 0 

1 27.5 0 27.5 

2 55 55 0 110 

3 82.5 110 82.5 0 275 

4 110 165 165 27.5 467.5 

5 91.6665 220 247.5 55 614.2 

6 73.3335 183.333 330 82.5 669.2 

7 55 146.667 274.9995 110 586.7 

8 36.6665 110 220.0005 91.6665 458.3 

9 18.3335 73.333 165 73.3335 330 

10 0 36.667 109.9995 55 201.7 

11 0 55.0005 36.6665 91.7 

12 0 18.3335 18.3 

13 0 0 

Unit Hydrograph

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*"4+@"# 8" 01-234$ DH C-(8 ,Time

(0.5 hr)

Qn

(cfs)

0 0 

1 27.5 

2 110 3 275 

4 467.5 

5 614.2 

6 669.2 

7 586.7 

8 458.3 

9 330 

10 201.7 

11 91.7 

12 18.3 

13 0 

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G#.8 RB?("A(-3: -#? JK3$(."? %8"(2 /"( *+,,-%.# '

Time(0.5 hr) 

Q(cfs) 

0 0.0

1 70.0

2 140.0

3 210.0

4 280.0

5 240.0

6 200.0

7 160.0

8 120.0

9 80.0

10 40.0

11 0

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*8"(2 RB?("A(-3: S"()%:$$8UH for C 

Time(0.5 hr)  Qn 

0.0 0

70.0 1

140.0 2

210.0 3

280.0 4

240.0 5

200.0 6

160.0 7

120.0 8

80.0 9

40.0 10

0 11

12

13

14

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