Copyright2006 McGraw-Hill Ryerson Limited, a subsidiary of the McGraw-Hill Companies. This page may be reproduced for classroom use by the purchaser of this book without the written permission of the publisher. Extra Practice Answers BLM 4 GR Chapter 4 Get Ready 1. a) 6 11 b) 5 11 c) 2 11 d) 11 11 or 1 e) 0 2. a) 9 18 or 1 2 b) 8 18 or 4 9 c) 4 18 or 2 9 d) 6 18 or 1 3 3. a) 9 18 or 1 2 b) 10 18 c) 14 18 or 7 9 d) 12 18 or 2 3 e) No, just subtract complement from 1. 4. a) 1 8 ; 12.5%; 0.125 b) 7 8 ; 0.875; 87.5% c) 1 5. a) 1 – 1 2 – 1 6 = 2 6 or 1 3 b) 6, 12, 18, 24, or any multiple of 6, as their fractions could all be reduced to sixths. 6. a) Blue 7 15 , green 2 15 , and yellow 6 15 or 2 5 b) Green 5 25 or 1 5 , yellow 11 25 , and blue 9 25 ; c) Experimental probability. 7. a) Black socks White socks Blue socks Green socks shoes Black socks White socks Blue socks Green socks sneakers b) c) 25% or 0.25 or 1 4 d) 50% or 0.5 or 1 2 Black socks White socks Blue socks Green socks Sneakers Sneakers and black Sneakers and white Sneakers and blue Sneakers and green Shoes Shoes and black Shoes and white Shoes and blue Shoes and green
Transcript
Copyright 2006 McGraw-Hill Ryerson Limited, a subsidiary of the McGraw-Hill Companies.This page may be reproduced for classroom use by the purchaser of this book without the written permission of the publisher.
Extra Practice Answers BLM 4 GRChapter 4 Get Ready
1. a)
6
11
b)
5
11
c)
2
11
d)
11
11 or 1
e) 0
2. a)
9
18or
1
2
b)
8
18 or
4
9
c)
4
18 or
2
9
d)
6
18or
1
3
3. a)
9
18or
1
2
b)
10
18
c)
14
18 or
7
9
d)
12
18or
2
3e) No, just subtract complement from 1.
4. a)
1
8; 12.5%; 0.125
b)
7
8; 0.875; 87.5%
c) 1
5. a) 1 –
1
2 –
1
6 =
2
6or
1
3
b) 6, 12, 18, 24, or any multiple of 6, as theirfractions could all be reduced to sixths.
6. a) Blue
7
15, green
2
15, and yellow
6
15 or
2
5
b) Green
5
25 or
1
5, yellow
11
25, and blue
9
25;
c) Experimental probability.
7. a)Black socks
White socks
Blue socks
Green socks
shoes
Black socks
White socks
Blue socks
Green socks
sneakers
b)
c) 25% or 0.25 or
1
4
d) 50% or 0.5 or
1
2
Blacksocks
Whitesocks
Bluesocks
Greensocks
Sneakers Sneakersandblack
Sneakersandwhite
Sneakersand blue
Sneakersandgreen
Shoes Shoesandblack
Shoesandwhite
Shoesand blue
Shoesandgreen
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Extra Practice Answers BLM 4.14.1 Experimental and Theoretical Probability
1. a) 50%; A coin has two sides and each side hasan equal probability of appearing.
c) Answers may vary. They may not be exactly50% heads, but should be close
d) Answers may vary, but probably closer to 50%heads and 50% tails than one individualexperiment. The more experiments you do, thecloser to the theoretical result you get.
2. a) 40%, 0.4, 25
b) 52%, 0.52, 1325
c) 0%, 0, 025
d) 92%, 0.92, 2325
3. a)
Heads
Blue
Green
Blue
Blue
Yellow
Tails
Blue
Green
Blue
Blue
Yellow
2
10 or
1
5
b)310
Blue Blue Blue Green YellowHeads B&H B&H B&H G&H Y&HTails B&T B&T B&T G&T Y&T
c) 30 trials should be the closest as the moretrials one does, the closer the result gets to thetheoretical example.
4. a) Answers may vary.b) Answers may vary.c) Answers may vary, but the one with 60 trials
should be closer to the theoretical results
5. a) 30% Jones, 60% Hernandez, 10% Wilsonb) 30% Jones, 52% Hernandez, 18% Wilsonc) Nita, because she did more trials.
6. a) No. Leslie has more chances to win. The
probability that Ada will win is1236
. The
probability that Leslie will win is 1436
.
b) Yes, for example, if Leslie could win with asum of 4, 6, or 9, then he would have a chance
of 1236
to win, which is the same as Ada’s.
Copyright 2006 McGraw-Hill Ryerson Limited, a subsidiary of the McGraw-Hill Companies.This page may be reproduced for classroom use by the purchaser of this book without the written permission of the publisher.
Extra Practice Answers BLM 4.24.2 Dependent and Independent Events
1. a)R R B G G G
R RR RR BR GR GR GRB RB RB BB GB GB GBB RB RB BB GB GB GBB RB RB BB GB GB GBG RG RG BG GG GG GG
b)1430
or 715
c)830
or 415
d)2230
; Subtract the complement, 1 – 830
= 2230
,
or count the number that doesn’t match.2. a) Pepperoni, salami; Pepperoni, mushrooms;
Pepperoni, green peppers; Pepperoni, onions;Salami, mushrooms; Salami, green peppers;Salami, onions; Mushrooms, green peppers;Mushrooms, onions; Green peppers, onions.
b) Yes, because on a pizza the toppings aremixed together.
c)410
, 0.4, 40%
d)310
, 0.3, 30%
e)110
; Use the complement 1 – 310
– 610
= 110
or count the number of all-meat pizzas.
3. a) Answers may vary.b)
$1 $5 $10$1 $2 $6 $11
$5 $6 $10 $15$10 $11 $15 $20
c) Answers may vary.d)
$1 $5 $10$1 impossible $6 $11$5 $6 impossible $15
$10 $11 $15 impossible
e) Answers may vary. For example, it is better toreturn the piece of paper because there is an11.1% chance to get $20; it is better not toreturn the piece of paper because there is nochance of getting $2.
4. a) P(yellow, yellow): 25×25
= 425
b) P(red, yellow): 15×25=225
c) P(blue, blue): 15× 15
= 125
d) P(green, blue, red): 15×15×15=1125
e) P(yellow, yellow): 25×14=220
or 110
P(red, yellow): 15×24=220
or 110
P(blue, blue): 0 (there is only one blue marble)
P(green, blue, red): 15×14×13=160
Copyright 2006 McGraw-Hill Ryerson Limited, a subsidiary of the McGraw-Hill Companies.This page may be reproduced for classroom use by the purchaser of this book without the written permission of the publisher.
Extra Practice Answers BLM 4.34.3 Solve Problems Involving Compound Events
1. a)
3
12 or
1
4
b)
2
11
c)
5
10 or
1
2d)
plainplainplain
barbecuebarbecuecheesyall-dressedall-dressed
For Friday
2
8 or
1
4
2. a)1627
×1526
=
240
702 or
40
117
b)
1127
×1026
=110702
or 55351
c) 1 −
240702
−110702
=352702
or 176351
3.
27
37
27
17
37
37
27
27
37
28
38
38
red
red
red
blue
blue
blue
green
green
green
red
blue
green
4. a)
5
8
b)
3
7c) Dependent as they depend on what was chosen
the first time.
5. a)
1
6
b)16×16
=136
c)16×16×16
=1216
d)16n
where n is the number of times
6.724
×623
×922
=
37812 144
or 63
2024
7.521
×620
+621
×520
= 60420
or 17
8. a)
2
5b) 10 with 4 sunflower seeds, 2 raisins, 1 almond,
and 3 peanuts.
c)12
Copyright 2006 McGraw-Hill Ryerson Limited, a subsidiary of the McGraw-Hill Companies.This page may be reproduced for classroom use by the purchaser of this book without the written permission of the publisher.
Extra Practice Answers BLM 4.44.4 Make Decisions Based on Probability or Judgment
1. Answers may vary. For example, it’s going to be80% probability rain tomorrow so we’re not goingto the beach; I won the game wearing blue socks,therefore, I have to wear my blue socks tomorrow.
2. a) Blueb) Greenc) No. Other factors influence the game.d) He set up a table so he did an experimental
probability, but his idea that sock colouraffects wins is subjective judgment.
3. a) Gillian because she has 1236
or 13
probability
of getting a point and Samantha has 1036
probability of getting a point so Gillian has theadvantage.
b) Answers may vary. Gillian could get a point ifshe rolls odd numbers and Samantha could geta point if she rolls even numbers.
4. Black has a probability of 13
and white has a
probability of 23
, so in three spins Joan will
probably get 5 points and Roger will get 4 points.Joan has the better probability.
5. a) 0.2% or 1500
b) 2% or 10500
c) 150 tickets
6. a) White. It gives the most points and has thesame or more squares than the other colours.
b) Total points: 129 ÷ 20 possibilities = 6.45points per square.
Answers may vary. For example, with the newchoice, the probabilities for Liam to get $2, $6,and $10 are 30%, 60%, and 10%, respectively.Since he has a 70% chance to get more than hisguaranteed $5, it is a good idea to try the newoffer.
Copyright 2006 McGraw-Hill Ryerson Limited, a subsidiary of the McGraw-Hill Companies.This page may be reproduced for classroom use by the purchaser of this book without the written permission of the publisher.
Extra Practice Answers BLM 4RChapter 4 Review
1. An experimental probability is calculated usingthe experimental results. Theoretical probability isfound by dividing the number of favourableoutcomes by the total number of outcomes.Subjective judgment is usually made by one’spersonal experience or feeling. For example, iffive 5’s are obtained by rolling a number cube 10
times,
5
10 is an experimental probability, but
since there is only one 5 on a number cube, the
theoretical probability of getting a 5 is
1
6. Also,
because 5’s are obtained frequently, one can makea subjective judgment that the next roll willproduce another 5.
2. a)
red
greenyellow
yellowyellowyellow
red
red
greenyellow
yellowyellowyellow
red
red
greenyellow
yellowyellowyellow
red
yellow
greenyellow
yellowyellowyellow
red
yellow
greenyellow
yellowyellowyellow
red
blue
greenyellow
yellowyellowyellow
redb) First bag
R R R Y Y BG R,G R,G R,G Y,G Y,G B,GY R,Y R,Y R,Y Y,Y Y,Y B,YY R,Y R,Y R,Y Y,Y Y,Y B,YY R,Y R,Y R,Y Y,Y Y,Y B,YY R,Y R,Y R,Y Y,Y Y,Y B,YR R,R R,R R,R Y,R Y,R B,R
c) • P(Red, Green) = 36×16=336
or 112
• P(Yellow, Yellow) =26×46=836
or 29
• P(Blue, Red) = 16×16=136
• P(Yellow, Green) =26×
16=
236
or 1
18
3. Answers may vary, but the more trials completed,
the closer it will be to the theoretical value of 336
Copyright 2006 McGraw-Hill Ryerson Limited, a subsidiary of the McGraw-Hill Companies.This page may be reproduced for classroom use by the purchaser of this book without the written permission of the publisher.
7. a)4
10 or
25
b)310
c)610
or 35
d)4
10 or
25
e)910
8. a)436
or 19
b)2636
or 1318
; 636
or 16
9. a) and b) If there are 10 lollipops, 5 are green, 1.5are red, 1 is purple, 2 are orange, and 0.5 isyellow, but it is not possible to have parts of alollipop, so multiply all values by 2. Then theminimum number of lollipops is 20; 10 are green,3 are red, 2 are purple, 4 are orange, and 1 isyellow. Multiply the numbers of each colour by anatural number to get other answers for part a).
Copyright 2006 McGraw-Hill Ryerson Limited, a subsidiary of the McGraw-Hill Companies.This page may be reproduced for classroom use by the purchaser of this book without the written permission of the publisher.
Extra Practice Answers BLM 4PTChapter 4 Practice Test
1. B)
2. D)
3. A)
4. B)
5. a)
red
redgreen
pinkblue
green
redgreen
pink
blue
pink
redgreen
pink
blue
blue
redgreen
pink
blueb)
Flared Tapered Boot-cutFlared F,F T,F B,F
Tapered F,T T,T B,TBoot-cut F,B T,B B,B
c)1144
6.
white
123456
white
123456
red
123456
red
123456
yellow
123456
7. No the game is not fair. With 12 games,theoretically, Ajit can get 5 × 4 points = 20points, and Francis can get 7 × 3 points = 21points. In order to make the game fair, let Ajit get7 points for getting each black box, and letFrancis get 5 points for getting each white box.
