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FACULTATIVEFACULTATIVEPONDSPONDS
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acu a ve pon sacu a ve pon s
Terminology: Primary fac. ponds:Primary fac. ponds: receive raw
removal)
Secondary fac. ponds:Secondary fac. ponds: receive effluent
from anaerobic onds or se tic tanksUASBs; or from settled sewerage
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Profuse presence of various speciesProfuse presence of various species
of mainlyof mainly motilemotile microalgaemicroalgae~~ −−
So facultative ponds are (or shouldSo facultative ponds are (or shouldbe) dark greenbe) dark green
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--O2, used by heterotrophic bacteria which
2 .
thin sludge layer in facultative ponds that
digestion & CH4 production).
– – 90%). This “algal” BOD is very different90%). This “algal” BOD is very different
“ ”“ ” . .
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Algae produce O2, but only during daylight hours
diurnaldiurnal variation in DO levels in pond:variation in DO levels in pond:
○ ~10 cm● ~ cm
below
surface
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Diurnal variation of pH as well:Diurnal variation of pH as well:
• Algal photosynthesis consumes CO2
• 2 2
bacterial metabolism or from atmosphere, thenbicarbonate and carbonate ions dissociate:
2HCO2HCO33−− → → COCO33
22−− + H+ H22O +O + CO2
COCO3322−− + H+ H22OO → → CO2 ++ 2OH2OH
−−
CO used b al ae; OHOH−− accumulates, soaccumulates, so HH
risesrises
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, .
Im ortant for dieIm ortant for die--off of faecal bacteria:off of faecal bacteria:
pH >9.4pH >9.4 is rapidly lethal to faecal bacteria,
including E. coli−
main exception is
r o c o erae w c s e o y
sul hides in anaerobic onds[see later in ‘Maturation Ponds’]
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ep o acu a ve pon sep o acu a ve pon s• Usuall 11– –2 m2 m commonl 1.5 m
• If
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LengthLength--toto--breadth ratio of fac. pondsbreadth ratio of fac. ponds
– – o pon rece ves raw was ewa er o pon rece ves raw was ewa er
if more than this slud e accumulates near
inlet (rather than being reasonably well
distributed across pond bottom) and can
block the inlet] can be >3 to 1 if pond receives anaerobiccan be >3 to 1 if pond receives anaerobic
pond effluentpond effluent
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Design of Facultative PondsDesign of Facultative Ponds
Man methods − mostl bad!
The best is based on:The best is based on:
the surface BOD loading ratethe surface BOD loading rate
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λλ , kg BOD/ha daykg BOD/ha day L = influent BOD m /l *
Q = flow, m3/day
A = pond area, m2ss ii
NOTE UNITS !!NOTE UNITS !!mpor anequation!
Design loading is a function of temperature:Design loading is a function of temperature:
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McGarry & Pescod’s
envelope of failure
O = failed pond
λλss ==60(1.099)60(1.099)TT
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McGarry & Pescod’s
envelope of failure
O = failed pond
Shape of McG&PShape of McG&P
λλss ==60(1.099)60(1.099)TT
influenced by:influenced by:
points at ~0points at ~0 °°C, andC, and
“ ”“ ”
points at atypicallypoints at atypically
(>>500 kg/ha d)(>>500 kg/ha d)
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• But ponds should not be designed to
opera e a e r po n o a ure
• Therefore various desi n e uationsdesi n e uations have
been introduced
• es s ara s g o a es gn equa onara s g o a es gn equa on:
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MARA’ L BAL DE I N E ATI NMARA’ L BAL DE I N E ATI N
λλss = 350(1.107 − 0.002T)= 350(1.107 − 0.002T)T−25T−25
Note:Note:
2525°°CC Another important equation Another important equation
(a) T = 8 °C, λs = 80 kg/ha day [experience in Europe & NZ]
(b) T = 25 °C, λs = 350 kg/ha day [experience in NE Brazil]
(c) T = 35 °C, λ = 500 kg/ha day [arbitrary upper limit]
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The McGarry & Pescod (A) and Mara (B) equations
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•• MinMinθθ
f f = 4 days= 4 days
• ,then take θf = 4 days, and
AA = Q= Qθθ /D /D
• .
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B D removal in facultative ondsB D removal in facultative onds
λλr r = a= aλλss + b+ b
=r ,
= 10(Li – Le)Q/A
•
λλr r = 0.725= 0.725
λλss + 10.75+ 10.75
close to zeroUsuall 0.7Usuall 0.7−−0.8 in0.8 in
warm climateswarm climates
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McGarry & Pescod’s data:McGarry & Pescod’s data:
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r swhere α = 0.7−0.8 usuall
ie, BOD removal is some 70ie, BOD removal is some 70––80%80%********************************************************
McGarry & Pescod’s data were for
– e, eye, ey nnc u e e o e a gae nc u e e o e a gae n
the effluentthe effluent
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E r n ni n:E r n ni n:
Urban Waste WaterUrban Waste Water
Treatment DirectiveTreatment Directive
For WSP effluentsFor WSP effluents::
andand ≤150 mg SS/l≤150 mg SS/l
If OK in the EU, why not inIf OK in the EU, why not in
developing countries ???developing countries ???
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PURPLE PONDSPURPLE PONDS
(or red or reddish brown) colour. This is due
to the growth of photosynthetic bacteria……photosynthetic bacteria……
ponds:1. Sulphate reduction to hydrogen sulphide
y anaero c su p a e-re uc ng ac er a
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. x a on o y rogen su p e osulphur and sulphate by anaerobic
photosynthetic purple and green bacteria
– 22 u yu y
bacteria oxidize Hbacteria oxidize H22S, not HS, not H22OO
– Equations:
2121HH22SS + 10CO+ 10CO22 + 2NH+ 2NH33
lightlight -
2(C2(C55HH88OO22N) +N) + 2121SS +16H+16H22OO
and, when no H2S........
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2121SS ++ 30CO30CO22 + 6NH+ 6NH33 + 36H+ 36H22OO++lightlight
two important groups of photosynthetic
bacteria in WSP:
– purple sulphur bacteriasu p ur granu essu p ur granu es
depositeddeposited withinwithin
– green sulphur bacteriasulphursulphur
ChlorobiaceaeChlorobiaceae
outsideoutside cellscells
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Thios irillum Thios irillum s .s .
CC
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Chromatium Chromatium sp.sp.
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Thi hrixThi hrix ..
[Oscillatoria ]
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wavelength than algal chlorophyll – ,
So photosynthetic bacteria occur inSo photosynthetic bacteria occur in nonnon--overloaded facultative ondsoverloaded facultative onds belowbelow thethe
algae andalgae and aboveabove the anaerobic zonethe anaerobic zone
They thus act as a sulphide filter sulphide filter –pro ec ng e a gae rompro ec ng e a gae rom su p e ox c ysu p e ox c y(see later), andand also helping to controlalso helping to controlo our re easeo our re ease..
f
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Anoxic facultative pond treating sugar mill
,