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Slide 2 Fig 26-CO, p.795
Consider two conductors carrying charges of equal magnitude but of
opposite sign, Such a combination of two conductors is called a capacitor.
The capacitance C of a capacitor is the ratio of
the magnitude of the charge on either conductor
to the magnitude of the potential difference
between them:
V
QC
The SI unit of capacitance is the farad (F) = coulombs per volt,
Volt
ColumFarad 1
Slide 3
26.2 CALCULATING CAPACITANCE
1. Parallel-Plate Capacitors
A parallel-plate capacitor consists of two parallel
conducting plates, each of area A, separated by a
distance d. When the capacitor is charged by
connecting the plates to the terminals of a battery,
the plates carry equal amounts of charge. One
plate carries positive charge +Q, and the other
carries negative charge -Q.
0 0
QE
A
The value of the electric field between the plates is
Slide 4 Fig 26-3a, p.799
0
QV Ed d
A
0
QC
VQQd
A
The capacitance of a parallel-plate capacitor is proportional to the area of its plates and inversely proportional to the plate separation
0
AC
d
Slide 5 Fig 26-3b, p.799
0
AC
d
C = 8.85 x 10-12 (C2/N.m2) . 2x 10-4(m2)/ 1x 10-3 (m)
1.77 x 10-12 F = 1.77 pF
Example A parallel-plate capacitor has an area A = 2.00 x 104 m2 and a plate separation d = 1.00 mm. Find its capacitance.
Slide 6 Fig 26-6, p.801
2 ln( )e
Cb
ka
2. The Cylindrical Capacitor
A cylindrical capacitor consists of
a solid cylindrical conductor of
radius a and length surrounded
by a coaxial cylindrical
shell of radius b.
Slide 7
3.The Spherical Capacitor
A spherical capacitor consists of an inner sphere ofradius a surrounded by a concentric spherical shell of radius b.
( )e
abC
k b a
Slide 10
26.3 COMBINATIONS OF CAPACITORS
Parallel Combination
Let us call the maximum charges on the two capacitors Q 1 and Q 2 . The total charge Q stored by the two capacitors is
Q= Q1+Q2
Q1= C1 V Q2= C2 V
The equivalent capacitor Q= Ceq V
Ceq V= C1 V+ C2 V
Ceq = C1 + C2
Slide 13 Fig 26-11, p.806
Example : Find the equivalent capacitance between a and b for the combination of capacitors shown in Figure
Slide 14
26.4 Energy stored in a charged capacitor
Suppose that q is the charge on the
capacitor at some instant during the
charging process. At the same instant, the
potential difference across the capacitor is
V = q/C.
We know that the work necessary to transfer
an increment of charge dq from the plate
carrying charge -q to the plate carrying
charge +q (which is at the higher electric
potential) is
dW dqV
Slide 15
0
0
Q
Q
W dqV
qW dq
c
21
2
QW
C
21
2
QU
C
221 1 1
2 2 2
QU QV CV
C
This result applies to any capacitor, regardless of its geometry. We
see that for a given capacitance, the stored energy increases as the
charge increases and as the potential difference increases
Slide 16
0
AC
d
2 20
20
1 1( ) ( )
2 21
( )2
AU CV Ed
d
Ad E
Energy stored in a parallel-plate capacitor
For a parallel-plate capacitor, the potential difference is related to the
electric field through the relationship V = Ed.. The capacitance is given by
By substituting
The energy per unit volume known as the energy density, is
The energy density in any electric field is proportional to the square of the magnitude of the electric field at a given point
202
1 EAd
UUE
Slide 17
26.5. Capacitors with Dielectrics
Dielectric is a non-conducting material, such as rubber, glass, or
waxed paper. When a dielectric is inserted between the plates of a
capacitor, the capacitance increases. If the dielectric completely fills
the space between the plates, the capacitance increases by a
dimensionless factor k , which is called the dielectric constant.
0
0
o
o
V ECkC V E
Slide 18
For a parallel-plate capacitor, we can express
the capacitance when the capacitor is filled
with a dielectric as
0 0&A A A
C k kd d d
We see that a dielectric provides the following
advantages:
• Increase in capacitance
• Increase in maximum operating voltage
• Possible mechanical support between the
plates, which allows the plates to be
close together without touching, thereby
decreasing d and increasing C