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    Brief summery-report of the functioning of Mr. Afif Abouraphaels power plant of

    patent no US 6990809, and an engineering study of his new invention (SELF-

    PROPELLED ENERGY GENERATOR) that includes a power plant of the above

    mentioned patent, in addition to a modular hydraulic air compressor.

    C O N T E N T S

    1. Historical development

    2 Engineering planning

    2.1 Gas system

    2.1.1 Compression phase

    2.1.2 Heating phase

    2.1.3 Expansion phase

    2.2 Liquid system

    2.2.1 Waters down flowing through a fall pipe

    2.2.2 Water pumping by main water-circulating pump

    2.2.3 Providing heat to the expanding compressed air of the ascending containers

    2.3 Mechanical system

    2.3.1 Water pumps

    2.3.2 Bucket turbine

    2.3.3 Power generator

    3 Ragged Chutes Hydraulic Air Compressor supplying compressed air to said power

    plant

    4 Conclusion

    5 Literature

    1. Historical development

    Mr. Arthur G. Platt [1] registered patent no US 2135110 that comprises a renewable energy

    power generating apparatus including a water-filled pool, an endless chain looping around

    lower and upper cogwheels, containers attached to chain links where only ascending

    containers receive compressed air in bottom of pool during the functioning of said apparatus

    (fig. 1). Said ascending containers are propelled by a growing buoyant force during their

    ascent. According to Boyle's Law, the volume of compressed air injected into each ascending

    container expands and displaces an increasing quantity of water at shallower depths due to

    lower hydrostatic pressure. The weight of the water displaced by air in ascending containers

    creates a steady torque on the axle of the upper cogwheel. The resultant rotation is

    transformed into an abundant source of energy adaptable to a wide range of applications.

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    The needed compressed air for the

    functioning of Mr. Platts apparatus

    was to be supplied if needed by all

    kind of conventional compressors or

    by Taylors type hydraulic air

    compressors [2], as the one that wasbuilt in Cobalt-Ontario in 1910 [3]

    and [4] and that supplied the mines of

    the Cobalt area with their needed

    compressed air until 1981.

    Said Taylors type hydraulic air

    compressor is an effective air

    compressing apparatus where a huge

    quantity of air is compressed by

    flowing water of waterways at a

    condition to have a difference inheight in the waterways bed in order

    to be able to build effectively a water

    down-take pipe that communicates

    with a first end of an underground

    tunnel which communicates at its

    second end with a water up-take tail

    pipe that discharges water back into

    the bed of said waterway. Fig. 1 Cross-sectional view of Platts power

    apparatus.

    The basic principle that is employed in Taylors type hydraulic air compressors is essentiallythe same as for all hydraulic air compressors. This basic principal consists of a stream of

    water to be allowed to fall in a vertical down-take pipe where air bubbles are entrained by

    falling water on beginning of its down motion through a mixing head in order to form an air-

    water mix. The entrained air is then compressed by the weight of the down flowing water.

    Then, when the direction of flow changes suddenly to the horizontal and the velocity of said

    flow is lessen, the air bubbles will be liberated then, and may be collected in a suitable

    container or separating chamber from which compressed air will be carried out by a suitable

    piping system (Fig. 2).

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    Fig. 2 Cross-sectional view ofRagged Chutes hydraulic air compressor By Taylor.

    Mr. Afif Abou-Raphael [5] has invented an effective air injection system for ascending

    containers of the apparatus that was invented in 1937 by Mr. Platt. This injection system of

    patent no CA 2328580 or US 6990890 helps transferring effectively compressed air coming

    from a compressor to the ascending containers of Mr. Platts apparatus without any lost of air

    bubbles, that means without energy lost at the lower cogwheels level in bottom of said powerplants pool, while Mr. Platt had compressed air bubbles supplied ineffectively to ascending

    containers.

    2 Engineering planning

    The needed engineering study of this invention according to its extraordinary potential is the

    calculation of the total useful energy of the self-propelled energy generator that equals the

    total addition of all lost and net energy of the system including the modular hydraulic air

    compressor according to the equation (2.1):

    usefulmechanicheatdragPumpstotalEEEEEE )(energynet (2.1)

    And because of the multitude of mediums of said self-propelled energy generator, the present

    engineering study is divided into three chapters.

    Chapter 1 that includes the study of air cycle of the gas system.

    Chapter 2 that includes the study of water cycle of the liquid system.

    Chapter 3 that includes the study of the mechanical system that includes all pumps (Mainwater transferring pumps) and (secondary water transferring pumps that are needed for

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    water-flows to fulfil the continuity equation), a bucket turbine and an electrical generator

    as it is shown in fig.3.

    Fig. 3 Schematic view, showing all of gas, liquid and mechanical systems of the

    apparatus.

    It is of course understood that a forth chapter that includes the study of the energy output of

    said power plant of invention [5], is needed alongside the study of chapters 1, 2 and 3.

    2.1 Gas system

    Air is the only gas element in the system of said self-propelled energy generator the subject of

    the present invention, where the cycle from the time atmospheric air enters the system letting

    us to take advantage of its physical properties, until it exits said system heated at atmospheric

    pressure too, is an open cycle.

    The following are phases to be followed in order to have a detailed study of the above-

    mentioned air-open cycle that permits us to calculate the systems lost and positive energy

    2.1.1 Compression phase

    Pump

    Air cycle

    Water cycle

    Bucket turbine Generator

    Liquid system

    Gas system

    Mechanical system

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    We take a pre-determined quantity of atmospheric air with volume0

    V , pressure0

    p and air

    temperature0t .

    First of all, an airflow discharge pressure of said modular hydraulic air compressor of the

    actual self-propelled energy generator has to be pre-determined.

    Study of these variations of air-physical properties to the volume1

    V , pressure1

    p , and the

    temperature1t , From the time the predetermined atmospheric airflow enters the air-water

    mixing head entrained by falling water into the head-pipe, until said air-water mix reaches the

    lower air-water separating device.

    Fig. 4 Schematic simplified cross-sectional view of a self-propelled energy generator.

    Variations of an adiabatic study of all air-physical properties according to equations (2.2) and

    (2.3), see literature [6], [8], [9] and [10]

    1

    001

    ppVV (2.2)

    1

    0

    101

    p

    ptt (2.3)

    Real study of said physical properties, where the reality of this process is that air bubbles of

    the falling air-water mix from the mixing head until the lower air-water separating device, are

    steadily compressed by the weight of the column of water that existsbetween the pools water

    surface and the depth where said bubbles are located. The consequences of that compression,is a huge elevation of the air bubbles temperature, where a big quantity of heat will be lost to

    the surrounding water that lowers the air temperature according to (2.4).

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    1

    '

    11 ttT (2.4)

    In the lower air-water separating device the real air temperature will be '1t and the real water

    temperature will be 1T .

    2.1.2 Heating phase

    Heating is the phase where we return to the compressed air a part of the lost heat that was due

    to the direct contact of air with water. This phase is the heat exchange that permits to elevate

    air temperature to1t , where

    1t should not exceed 90 degrees in order to keep the surrounding

    waters temperature below 100 Celsius that avoids water ebullition and evaporation according

    to (2.5)

    9011 tt (2.5)

    Thus, in order to complete this phase without losing a big amount of energy, the heat

    exchanger could be supplied with a part of the lost heat that is generated through the

    functioning of the water-transferring pumps and the main electrical generator.

    The quantity of heat that can be useful in this phase can be calculated as follow:

    )( 111 ttcmQ v (2.6)

    Where:

    1Q Heat quantity

    m Quantity of air passing in the heat exchanger

    vc Specific heat at constant volume.

    This heating phase is beneficial to air cycle in two points:

    The elevation of air temperature that lowers the energy lost of the system and, the elevation of compressed air pressure

    1p in the heat exchanger where this

    beneficial elevation of air pressure at this level of the air cycle could be done without

    the need of any additional air compressor.

    2.1.3 Expansion phase

    The expansion phase starts from the injection of a pre-determined quantity of hot air into

    ascending containers. But, the physical properties of this quantity of compressed air present

    inside said ascending containers change during the air ascent toward the pools water surface,where the hydrostatic pressure that exerts on this air is lighter according to the depth of every

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    container. Thus, the consequences of this low pressure, is volume expansion and colder

    temperature of this quantity of air.

    Thus, the equation (2.7) is used to calculate the changes of air temperature without heat

    exchange.

    1

    1

    012

    p

    ptt (2.7)

    Where:

    2t Air temperature at the end of air-expansion phase without heat exchange

    1t Temperature of compressed air exiting the heat exchanger

    1p Pressure of compressed air exiting the heat exchanger

    Isentropic constant.

    Thus, because t2 is a very low temperature, the water that surrounds the expanding

    imprisoned air becomes ice. But, in order to avoid ice formation in the water cycle, we try todistribute hot water that exits the main water-transferring pump all along the ascending route

    of the ascending containers, from bottom of pool until the dumping of air at the surface of

    water of said pool. This hot water distribution permits us to use the heat that was gained by

    water in the first phase, while, the calculation of the quantity of that heat can be calculated as

    follow:

    tAkQ 2 (2.8)

    Where:

    2Q Heat quantityk Heat transfer coefficient

    A Transfer surface area

    t Difference of temperature between air temperature inside ascending container and watertemperature that surrounds the container.

    Because this part of the air cycle is a function of the ascending linear speed of the containers,

    thus, the useful heat-gain in this part of this cycle can be calculated as follow:

    v

    hQW 22'

    (2.9)

    Where:

    'W Heat gain

    2Q Quantity of heat

    2h (Height of the column of water) or Depth from pools water surface until bottom of pool

    where compressed air is injected

    v Ascending containers linear speed

    That means the ascending containers linear speed has to provide a heat balance in this part ofthis cycle. Thus, the control of the containers ascending linear speed can be done through the

    injected quantity of compressed air that can be calculated according to

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    tRm

    W

    1(2.10)

    Where:W quantity of heat needed for air in order to keep the cycles balance

    m Quantity of air

    R Gas constant

    Isentropic constant

    21 ttt

    1t Temperature of compressed air exiting the heat exchanger

    2t Temperature of air exiting the air cycle

    Thus, in order to provide a good functioning between air cycle and liquid- water cycle,

    without having ice accumulation, and to reduce the heat lost, it is always very important to

    calculate iteratively the rotation speed of the mechanical system of the bucket turbine

    according to equations (2.8), (2.9) and (2.10), because this part of this cycle is the one that can

    allow a bigger energy production.

    But, because water is the element that is used in the liquid cycle, and water has a liquid

    specific character between 0 and 100 Celsius (0

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    Where:

    m Flow mass

    t Time

    Thus, In order to study the equation (2.11), we take a pre-determined Flow mass waterairm 0

    of

    an air-water mix at a temperature0

    T , a pressure0

    p and a speed0v This pre-determined mass

    has to fulfil the continuity equation too at the exit of the fall pipe in said lower separating

    device with different physical properties, Flow mass waterairm 1 , temperature 1T , pressure

    1p ,and speed

    1v

    )(1)(0 waterairwaterairmm (2.12)

    airwaterairwatermkmkmkmk 11110000 )1()1( (2.13)

    Where:

    0k and

    1k are ratios of air-water mixes at the upper water reservoir and at the lower

    separating device.

    111111000000 )1()1( vAkkvAkk airwaterairwater (2.14)

    Considering that the diameter D of the fall pipe does not change from top to bottom. Then

    10 AA And as water is an incompressible liquid waterwater 10 , then we simplify (2.14)

    1

    0

    1110

    0

    000 )1()1( vkkvkk

    water

    air

    water

    air

    (2.15)

    Where the values of air0 and air1 are very small comparing with water0 .

    Then after simplification, equation (2.15) becomes (2.16).

    1100 vkvk (2.16a)

    Or

    0

    1

    0

    1 vk

    kv (2.16b)

    Thus, the calculation process of water temperatures change is very easy, because the quantity

    of heat gained by water is the same quantity of heat that is lost by air during its compression

    cycle.

    Lost heat by air:

    )( 01 ttcmtcmQ vairvairair (2.17)

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    Gained heat by water:

    )( 01 TTcmTcmQ FwaterFwaterwater (2.18)

    Because (2.17) and (2.18) are equals, then:

    )( 0101 ttm

    m

    c

    cTT

    water

    air

    F

    v (2.19)

    Wherevc and

    Fc are the specific heat constants for air and water

    At 20 Celsius,

    kg.K

    j4190Fc .

    Where:

    0T Waters temperature at the top of the fall pipe

    1t Can be calculated from equation (2.3)

    airm and waterm are the weight of the pre-determined quantity of air and water that exit from

    the fall pipe to the lower separating device.

    2.2.2 Water pumping by main water-circulating pump

    This phase begins at the lower air-water separating device and ends at the exits of the hotwater distributing pipes that are affixed face to the ascending containers and used to spry hot

    water around said ascending containers. Thus, it is mandatory that the equation of water

    continuity has to be respected at this point of this phase.

    And because air is separated from the air-water mix in the lower separating device, and in

    order to respect the continuity equation, it is imperative to provide an equal quantity of water

    by a secondary water-circulating pump that is controlled by a level sensor in order to control

    the acceptable lower level of water in said lower separating device, during the functioning of

    the apparatus.

    112211 vAvAvA (2.20)

    Where:

    1A and

    1v are the sections surface area of pipe and speed of water by the secondary water-

    circulating pump

    In this phase, main and secondary pumps do not affect the waters physical properties at all;

    their only work is to provide a continuous water-circulation between their intake and their

    outlet respectively that means they do not need to provide water pumping to a certain head.

    2.2.3 Providing heat to the expanding compressed air of the ascending containers

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    In this phase, heat has to be provided to the expanding air inside said ascending containers in

    order to close up the isothermal compressing cycle of air without letting ice formation inside

    said ascending containers. Thus, the lost heat during phase 1 of the air compression process

    (phase 1 in air cycle), and that is recuperated by water contained inside the lower separating

    device, will be given back to the expanding air by circulating this hot water around saidascending containers through the above mentioned pipes that are affixed face to these

    ascending containers.

    After circulating around said ascending containers and giving heat to the expanding air, this

    water floats to the pools surface in order to start a new cycle.

    2.3 Mechanical system

    The Mechanical system of this apparatus has three independent parts:

    2.3.1 Water pumps

    These pumps are divided into two groups:

    A- Main pumps: The main function of a main pump is to provide a continuous watercirculation in said closed liquid system of said apparatus as shown in figure 4. This

    type of circulation-pump does not require a lot of energy because of its simple

    function where water-circulation is done without any head.

    B- Secondary pumps: The main function of a secondary pump is to transfer waterfrom the main pool into said lower separating device during the functioning of the

    apparatus, in order to respect the continuity equation for the above referred main

    pumps as shown in figure 4. The functioning of these secondary pumps is

    intermittent, because water is needed into said lower separating device only when

    water reaches the lower acceptable level. In addition, these secondary pumps can

    be replaced if needed, by valves that can provide equally, the needed water for the

    good functioning of said main pumps. Moreover the control of these secondary

    pumps or said valves can be done through (min-max level sensors).

    Of course, the needed energy for the good functioning of all main and secondary pumps

    is a function of the needed airflow. This energy is a lost one, and according to the

    engineering studies of many different examples of this apparatus, the value of this energy

    was between 15% and 22% of the total energy output of said power plant of any studied

    self-propelled energy generator.

    2.3.2 Bucket turbine

    This bucket turbine is an endless chain of buckets moving around upper and lower cogwheels

    as shown in figure 3 and 4. In addition said bucket turbine is always built solid, in a way that

    supports the result drive force developed by the buoyant force of the total volume of

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    imprisoned compressed air into ascending containers. This buoyant force can be calculated

    according to the following equation

    n

    iwaterires

    gVF1

    (2.21)

    Where:

    n Number of ascending containers between upper and lower cogwheels.

    iV Compressed air volume in container i

    water Water density

    g Gravity

    Thus, before calculating the final energy of the above mentioned force, we should calculate

    the drag that affects directly this part of the mechanical system according to the following

    equation:

    AvF waterw 2

    2

    (2.22)

    Where:

    Drag resistance

    water Water density

    A Area of container

    v Linear speed of containers

    And in order to facilitate the calculation of this drag, we consider the up or down moving

    containers as a pipe having one diameter D.

    The drag resistance of the up and down moving containers is calculated according to [10] and

    [12]

    D

    h

    1

    (2.23)

    Where:

    , is the pipes Coefficient of resistance that can be calculated according to Nikuradse [12].

    2

    lg.214,1

    D

    k (2.24)

    Where:

    k is the roughness of tubes surface. In our case k = 0.2-0.5 [mm]

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    For the five containers that drag in bottom of pool, the value of drag according to [10] is:

    05,112

    Thus, the total value of drag can be calculated as follow:

    21 .5.2 (2.25)

    The resulting useful force of any power plant, can be calculated as follow:

    dragresuseful FFF (2.26)

    Then, from this useful force, it is possible to calculate the resulting energy of said power plant

    without taking in consideration all of the lost energy of the pumps, of all mechanical friction

    of the system, and of the air heating, according to the following equation:

    2LFE usefulres (2.27)

    Where:

    L Driving radius that is equal to the sum of: driving wheels radius, thickness of endless

    chain and containers radius.

    Rotating speed

    2.3.3 Power generator

    This power generator is an electrical generator that produces the calculated useful energy that

    goes through distributing lines and the lost energy used by said main and secondary water

    pumps, after deducting all of the added lost energy in drag, in mechanical friction and in air

    heating. This means, the result of equation (2.1) of this study is equal to the value of the final

    positive energy of this generator.

    The above mentioned mechanical system is the most important part of this self-propelled

    energy generator. Thus, the lost mechanical energy is the biggest among all of the lost energy

    of this apparatus. And because this machine is the first machine in its kind, then, it is difficult

    to say how much the exact value of this mechanical energy lost is. But, in sum it is frictioncaused by the rotation of the wheels shafts in their bearings, by direct contact between

    cogwheels and endless chain, and by the power transmission systems.

    In the present time with the precision of the mechanical construction, we can give a primary

    value for this mechanical energy lost in the order of about 15% from the total produced

    energy.

    The following chart gives percentage of calculated and approximate values for energy lost of

    the apparatus.

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    resE 100 %

    dragE (2-4) %

    pumpE (16-23) %

    heatE (6-23) %

    mechanicalE (15) %

    usefulE (35-61) %

    3 Ragged Chutes Hydraulic Air Compressor supplying compressed air to said power

    plant

    During the study of this power plant I made sure to study it with compressed air being

    supplied bythe ragged chutesthat is located in one of the coldest area of the planet.

    Surely, the result came very positive and encouraging. While, if the same power plant would

    be located in a hot area and a similar hydraulic air compressor located in the same hot area

    supplies the compressed air, thus, the energy output of the power plant would be much higher.

    STUDY OF THE USEFULL POWER OF A POWER PLANT THAT WORKS WITH

    COMPRESSED AIR PRODUCED BY THE RAGGED CHUTES FOR ONE STAGE

    Distance from surface of water to the opening ofbottom vertical container m 85,00

    Rotation speed of driving wheel per minute rpm 10

    Linear speed of chain m 0,76

    Length of container m 0,75

    Radius of container m 0,46

    Radius of driving wheel. m 0,91

    Atmospheric pressure bar 1,0133

    Temperature of injected heated air into ascending

    containers

    C 90

    Temperature of water that surrounds the ascending

    container

    C 20

    Driving radius, or distance between the center of the

    driving shaft and the center of gravity of the

    container

    m 1,37

    Free airflow per minute m/min 37,755

    Hydrostatic pressure at opening of bottom vertical

    container

    bar 8,50

    Volume of expanded air in all ascending containers m 14,63

    Output energy without any lost MW 0,205

    Lost energy by DRAG [3,76]% MW 0,0077

    Lost energy by mechanical friction 15% MW 0,0307Lost energy by Heating [23]% MW 0,0476

    Ragged Chutes doesnt need pumps because of the MW 0

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    Montreal River

    Useful output energy from 37,755 m of air MW 0,119

    according to the following calculations, and, if full airflow of the ragged chutes would be used

    in an appropriate power plant having the needed number of stages that can contain this

    airflow, thus, the results would be as follow:

    Number of stages needed to contain the full airflow of 1132.66m:1132.66m/ 37,755m (One stage) = 30 stages.

    Full potential-energy production out of full airflow of 1132.66m:0,119MW x 30 = 3,56MW.

    The ragged chutes compressor was using a water flow of 22.7 m/sec in order to produce the

    40000 cfm or 1132.66 m of free airflow, while the average full water flow of the Montreal

    River is about 67.5 m/sec.

    Then, if this full water flow were to be used in a bigger hydraulic compressor, the following

    airflow would be produced:

    (67.5m / 22.7m3) x 1132.66m = 3368.0185m

    Thus, the full potential energy of this airflow would be:

    (3368.0185m / 1132.66m) x 3,56MW 10.5 MW.

    It should be understood of course that the ragged chutes does not need neither main nor

    secondary water transferring pumps, that makes energy production according to this

    technology much higher then energy being produced through the new invention. But, becausewaterways do not exist wherever we need them to be, then, the use of the new technology of

    said (Self-propelled energy generator) would be highly recommended in replacing

    conventional power generation.

    In addition, said power plant can be built in shallower pools if needed where more stages can

    be used in order to produce enough energy without having the risk to having ice accumulation

    in the buckets.

    4 Conclusion

    In the beginning when I was approached by the inventor to do an engineering study for his

    invention, I thought that he was loosing his time, because a lot of people before him have

    studied the issue without getting any positive result, and that it is unlikely to produce energy

    from nothing, and that perpetual motion machine does not exists.

    But, because of my technical curiosity I decided to see from where this positive energy is

    coming. Thus, I decided to search deeper, and then I started reading the documents including

    the patents texts; searching for mistakes the inventor has committed, while being sure to find

    them.

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    When I didnt find any mistake whatsoever, I got attached to the issue and I started revising

    very carefully the calculations that were done by the inventor. Happily and surprisingly, I

    came up with a positive result. And the following are my findings:

    This invention is a unique Self- propelled energy generator that includes a unique submergedair Bucket Turbine, powered By the volume (not the pressure) of compressed air produced

    by unique modular hydraulic air compressors.

    The subject of this invention:

    1- Is self-propelled and it eliminates all of the disadvantages of conventional powergenerators (wind intensity, solar-beam, etc.) while ensuring ease of operation and

    an ecological process that uses non-polluting, renewable and clean energy. In

    addition this apparatus needs only atmospheric air and a recycled limited quantity

    of water.

    2- Has the capacity to be located anywhere in the world including cities, remoteareas, mountains or deserts, and to produce any amount of cheap energy according

    to the needed design without any limitation whatsoever. Moreover, this

    extraordinary machine that is self-propelled can produce clean and renewable

    energy even in the coldest regions of the globe.

    3- Includes a power generating plant of the type described in the Canadian patent noCA 2328580 or in US patent no US 6990809that uses the compressed air volume

    as fuel instead of air pressure, and a modular hydraulic air compressor that

    produces artificially the needed airflow for the good functioning of said power

    plant by circulating same water in a closed and looping path in order to entrain and

    compress air according to the same basic principle of all hydraulic air

    compressors, including Taylors type hydraulic air compressors that were the

    biggest in the world in their kind. But said basic principle is used in this modular

    hydraulic air compressor in a better, easy and efficient way, where air is

    compressed and expanded in an isothermal process.

    Thus, this self-propelled energy generator can produce for the first time in history a huge

    amount of positive energy, of course, without forgetting that this clean and renewable energy

    generation can be without limitations and without the use of any conventional outside source

    of energy. In addition, this apparatus needs only maintenance after it is started, and, the use ofthis technology could reduce drastically pollution and greenhouse gases.

    5 Literature

    [1] Arthur G. Platt: Power apparatus. /1938/ Patent no US2135110[1] Charles Havelock Taylor: Hydraulic Air-Compressor. /1908/ Patent no

    US892772[3]Arthur A. Cole: Mining and power development. /1910/ Toronto[4]Allan Auclair: Ragged chutes. /1957/ Canadian mining journal.

    http://ipcet.com%20-%20all%20patents%27%20description%20%28of%20afif%20abou-raphael%29%20-%2022-06-07.doc/http://ipcet.com%20-%20all%20patents%27%20description%20%28of%20afif%20abou-raphael%29%20-%2022-06-07.doc/http://ipcet.com%20-%20all%20patents%27%20description%20%28of%20afif%20abou-raphael%29%20-%2022-06-07.doc/
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    [5]Afif Abouraphael: Hydroelectric power plant designed to transform the potentialenergy of compressed gas into mechanical and electrical energy through the

    potential energy of liquid. 2003 patent no CA2328580 or 2006 patent no

    US6990809

    [6]William L. Haberman and James E.A. John: Engineering Thermodynamicswith Heat Transfer. 1989

    [7]Joseph H. Spurk: Einfrung in die Theorie der Strmungen. Springer 1996[8]Reiner Decher: Energy conversion systems, Flow Physics and Engineering.

    /1994/ Oxford University Press

    [9]Hans Dieter Baehr: Thermodynamik. Springer /1988/[10] H. E. Siekmann: Strmungslehre. Springer 2000[11] M. Halk Aksel, O. Cahit Eralp: Gas Dynamics. /1994/ Prentice Hall[12] E.Truckenbrodt: Fluidmechanik Band I and II. /1989/ Springer

    International Project Consulting for Environmental Technology

    Dr. Ing. Elias Masri

    Hooverstr. 8 B

    86156 Augsburg

    Germany


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