+ All Categories
Home > Documents > Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8...

Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8...

Date post: 18-Jan-2018
Category:
Upload: alvin-scott
View: 222 times
Download: 0 times
Share this document with a friend
Description:
Find the Perimeter 6 in 11 in Answer: = 34 in
22
Finding Perimeter and Area Review
Transcript
Page 1: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Finding Perimeter and

Area Review

Page 2: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

PerimeterThe distance around the outside of an object.

10 feet

8 feet 8 feet

10 feet

Perimeter = 10 + 8 +10 +8 = 36 feet

Page 3: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Find the Perimeter

6 in

11 in

Answer: 6+6+11+11 = 34 in

Page 4: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

13 cm

10 cm

12 cm

Answer: 10+10+13+13 = 46 cm

Find the Perimeter

Page 5: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

13 in

5 in 5 in

4 in

8 in

Answer: 13 + 4 + 5 + 5 = 27 in

Find the Perimeter

Page 6: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

15 cm 15 cm

12 cm

Answer: 15 + 15 +12 =42 cm

11 cm

Find the Perimeter

Page 7: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Finding Area of a Rectangle

Area of a Rectangle: L x W (length x width)

Square 4 sides all sides equal right angles

Rectangle 4 sides opposite sides equal right angles

Area of a Square: L x W (length x width)

Which is also S x S or S2

Page 8: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Find the Area

6 in

11 in

Answer: 6(11)= 66 in2

Page 9: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Find the Area

4 in

4 in

Answer: 4(4) = 16 in2

Page 10: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Finding Area of a Triangle

Area of a Square = S2

Area of Triangle = ½ S2

S

S

L

WArea of a Rectangle = L x WArea of Triangle = ½ L x W

= b

= h

Area of Triangle = ½bh

Page 11: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Find the Area

13 cmAnswer:

12 cm

27821213 cmA

Page 12: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Find the Area

13 cm

10 cmAnswer:

12 cm

10 x 12A = 2 = 60 cm2

Page 13: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Finding Area of a Parallelogram

Area of a Rectangle = L x W

= b

S

Area of Parallelogram = bh

h

L

W

Page 14: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Finding Area of a Rhombus

Area of a Square = S x S or S2

= b

Area of Rhombus = bh

h

S

S

Page 15: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Find the Area

7 cm

3 cm

5 cm

Answer: 3 (5) = 15 cm2

Page 16: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Find the Area

9 cm

5 cm

7 cm

Answer: 7 (5) = 35 cm2

Page 17: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Finding Area of a Trapezoid

Area of Trapezoid = b1 + b2 x h 2

b1

b2

h

Page 18: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Find the Area. 10 in

4 in 4 in

2 in

Answer:

8 in

2482

8)210( in

Page 19: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Finding Area of a Kite

Area of a Kite = pq 2

p

q

Page 20: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Find the Area

Answer = 10 x 8 = 40 cm2

2

p

10 cm

8 cm

Page 21: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Finding Area and Circumference of Circles

π = 3.14

Diameter – the distance from one side of a circle to the other through the center

Radius – the distance from the center of a circle to the side

½ of the diameter

Area of a Circle = πr2Circumference of a Circle = 2πr or πd

Page 22: Finding Perimeter and Area Review. Perimeter The distance around the outside of an object. 10 feet 8 feet 10 feet Perimeter = 10 + 8 +10 +8 = 36 feet.

Find Area and Circumference

A= πr2C= πd

d = 14 cm

C= 3.14(14) C= 43.96 cm

A= 3.14(7)2A= 153.86 cm2


Recommended