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Forces

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Unit 2, Chapter 6 CPO Science Foundations of Physics Chapter 9 Chapter 9
Transcript
Page 1: Forces

Unit 2, Chapter 6

CPO ScienceFoundations of Physics

Chapter 9Chapter 9

Page 2: Forces

Unit 2: Motion and Force in One Dimension

6.1 Mass, Weight and Gravity

6.2 Friction

6.3 Equilibrium of Forces and Hooke’s

Law

Chapter 6: Forces and Equilibrium

Page 3: Forces

Chapter 6 Objectives1. Calculate the weight of an object using the

strength of gravity (g) and mass.2. Describe the difference between mass and weight.3. Describe at least three processes that cause

friction.4. Calculate the force of friction on an object when

given the coefficient of friction and normal force.5. Calculate the acceleration of an object including

the effect of friction.6. Draw a free-body diagram and solve one-

dimensional equilibrium force problems.7. Calculate the force or deformation of a spring

when given the spring constant and either of the other two variables.

Page 4: Forces

Chapter 6 Vocabulary Terms mass weight weightless g-force friction static friction sliding friction rolling friction viscous

friction air friction

normal force extension net force free-body

diagram lubricant equilibrium ball bearing dimension spring Hooke’s law

compression spring

constant deformation restoring force coefficient of

friction engineering design cycle subscript prototype coefficient of

static friction

Page 5: Forces

6.1 Mass, Weight, and Gravity

Mass is a measure of matter.

Mass is constant. Weight is a force. Weight is not

constant.

Page 6: Forces

6.1 Mass, Weight, and Gravity

The weight of an object depends on the strength of gravity wherever the object is.

The mass always stays the same.

Page 7: Forces

6.1 Weight

Fw = mg

Gravity (9.8 m/sec2)

Mass (kg)

Weight force (N)

Page 8: Forces

6.1 Free fall and weightlessness An elevator is accelerating downward at 9.8

m/sec2. The scale feels no force because it is falling away

from your feet at the same rate you are falling. As a result, you are weightless.

Page 9: Forces

6.1 Calculate weight

How much would a person who weighs 490 N (110 lbs) on Earth weigh on Jupiter?

The value of g at the top of Jupiter’s atmosphere is 23 N/kg.

(Since Jupiter may not actually have a surface, “on” means at the top of the atmosphere.)

Page 10: Forces

6.1 Calculate force

A 10-kilogram ball is supported at the end of a rope. How much force (tension) is in the rope?

Page 11: Forces

6.1 Mass, Weight, and Gravity

Key Question:

What is speed and how is it measured?

*Students read Section 6.1 BEFORE Investigation 6.1

Page 12: Forces

6.2 Friction Friction results from relative

motion between objects. Frictional forces are forces that

resist or oppose motion.

Page 13: Forces

6.2 Types of Friction

Static friction

Sliding friction

Rolling friction

Page 14: Forces

6.2 Types of Friction

Air friction

Viscous friction

Page 15: Forces

6.2 Friction

Ff = Fn

Normal force (N)

Coefficient of friction

Friction force (N)

Page 16: Forces

6.2 Calculate force of friction

A 10 N force pushes down on a box that weighs 100 N. As the box is pushed horizontally, the coefficient of

sliding friction is 0.25. Determine the force of friction resisting the motion.

Page 17: Forces

6.2 Sliding Friction

Ff = sFn

Normal force (N)

Coefficient of sliding friction

Friction force (N)

Page 18: Forces

Table of friction coefficients

Page 19: Forces

6.2 Calculate using friction

A steel pot with a weight of 50 N sits on a steel countertop.

How much force does it take to start the pot sliding?

Page 20: Forces

6.2 Calculate using friction

The engine applies a forward force of 1,000 newtons to a 500-kg car.

Find the acceleration of the car if the coefficient of rolling friction is 0.07.

Page 21: Forces

6.2 Friction

Key Question:

How can we describe and model friction?

*Students read Section 6.2 AFTER Investigation 6.2

Page 22: Forces

6.3 Equilibrium and Hooke's Law

When the net force acting on an object is zero, the forces on the object are balanced.

We call this condition equilibrium.

Page 23: Forces

6.3 Equilibrium and Hooke's Law

Newton’s second law simply requires that for an object to be in equilibrium, the net force, or the sum of the forces, has to be zero.

Page 24: Forces

6.3 Equilibrium and Hooke's Law

Many problems have more than one force applied to an object in more than one place.

Page 25: Forces
Page 26: Forces

6.3 Calculate net force

Four people are pulling on the same 200 kg box with the forces shown.

Calculate the acceleration of the box.

Page 27: Forces

6.3 Calculate force using equilibrium

Two chains are used to lift a small boat. One of the chains has a force of 600 newtons.

Find the force in the other chain if the mass of the boat is 150 kilograms.

Page 28: Forces

6.3 Equilibrium and Hooke's Law

The most common type of spring is a coil of metal or plastic that creates a force when it is extended (stretched) or compressed (squeezed).

Page 29: Forces

6.3 Equilibrium and Hooke's Law The force from a

spring has two important characteristics:— The force always acts in a

direction that tries to return the spring to its unstretched shape.

— The strength of the force is proportional to the amount of extension or compression in the spring.

Page 30: Forces
Page 31: Forces

6.3 Hooke's Law

F = - k x

Spring constant N/m

Force (N)Deformation (m)

Page 32: Forces

6.3 Calculate force

A spring with k = 250 N/m is extended by one centimeter.

How much force does the spring exert?

Page 33: Forces

6.3 Equilibrium and Hooke's Law

The restoring force from a wall is always exactly equal and opposite to the force you apply, because it is caused by the deformation resulting from the force you apply.

Page 34: Forces

6.3 Calculate using equilibrium

The spring constant for a piece of solid wood is 1×108 N/m.

Use Hooke’s law to calculate the deformation when a force of 500 N (112 lbs) is applied.

Page 35: Forces

6.3 Equilibrium of Forces and Hooke's Law

Key Question:

How do you predict the force on a spring?

*Students read Section 6.3 AFTER Investigation 6.3

Page 36: Forces

Application: The design of structures


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