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The Biquaternions
Renee RussellKim Kesting
Caitlin Hult
SPWM 2011
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Sir William Rowan Hamilton(1805-1865)
Physicist, Astronomer and Mathematician
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This young man, I do not say
will be, but is, the first
mathematician of his age
Bishop Dr. John Brinkley
Optics
Classical and Quantum
Mechanics
Electromagnetism
Algebra:
Discovered
Quaternions &
Biquaternions!
Contributions to Science and
Mathematics:
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Review of Quaternions, H
A quaternion is a number of the form of:
Q = a + bi + cj + dk
where a, b, c, dR,
and i2
= j2
= k2
= ijk = -1.
So what is a biquaternion?
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CONFUSING:
(a+bi) + (c+di)i + (w+xi)j + (y+zi)k
Biquaternions
We can avoid this confusion by renaming i, j,and k:
B = (a +bi) + (c+di)e1 +(w+xi)e2 +(y+zi)e3
e12 = e22 = e32 =e1e2e3 = -1.
* Notice this i is different from the i component of the
basis, {1, i, j, k} for a (bi)quaternion! *
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B can also be written as the complex combination
of two quaternions:
B = Q + iQ where i =-1, and Q,QH.
B = (a+bi) + (c+di)e1 + (w+xi)e2 + (y+zi)e3
=(a + ce1 + we2 +ye3) +i(b + de3 + xe2 +ze3)
where a, b, c, d, w, x, y, zR
Biquaternions
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Properties of the Biquarternions
ADDITION: We define addition component-wise:
B = a + be1 + ce2 + de3 where a, b, c, d C
B = w + xe1 + ye2 + ze3 where w, x, y, zC
B +B =(a+w) + (b+x)e1 +(c+y)e2 +(d+z)e3
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Properties of the Biquarternions
SCALAR MULTIPLICATION:
hB =ha + hbe2 +hce3 +hde3 where h C orR
The Biquaternions form a vectorspace overC and R!!
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Biquaternions
are an algebra
overC!biquaterions
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Properties of the Biquarternions
So far, the biquaterions overC have all the same
properties as the quaternions overR.
DIVISION?
In other words, does every non-zero element have a
multiplicative inverse?
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Properties of the Biquarternions
Recall for a quaternion, Q H,
Q-1 = abe1ce2de3 where a, b, c, dRa2 + b2 + c2 + d2
Does this work for biquaternions?
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Biquaternions are NOT a division algebra
overC!
Quaternions
(over R)
Biquaternions
(over C)
Vector Space?
Algebra?
DivisionAlgebra?
Normed
Division
Algebra?
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Biquaternions are
isomorphic to M2x2
(C)
Define a map f: BQM2x2(C)by the following:
f(w + xe1 + ye2 + ze2) = w+xi y+zi
-y+zi w-xi
where w, x, y, z
C.
We can show that fis one-to-one, onto, and is a linear
transformation. Therefore,BQis isomorphic toM2x2(C).
[ ]
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Applications of Biquarternions
Special Relativity Physics
Linear Algebra
Electromagnetism