Ge6161 Cp Record

HINDUSTHAN INSTITUTE OF TECHNOLOGY, Coimbatore-32

2014 – 2015/ I YEAR/ I SEMESTER/ GE6161 – COMPUTER PRACTICES 1

EX.NO : 1.a CREATING ADVERTISEMENT

DATE :

AIM:

To prepare an advertisement for a company with the following specifications.

Attractive page border.

Use at least one Clip Art.

Design name using Word Art.

Use bullets.

ALGORITHM:

Step 1: Open a new document by clicking Start → All Programs → Microsoft Office →

Microsoft Office Word 2007. Step 2: Go to Page LayoutPage BordersSelect Attractive Page BorderOk.

Step 3: Go to InsertClip ArtSelect Attractive Clip ArtOk.

Step 4: Type a name and selectgo to InsertWord ArtSelect a Word Art & click.

Step 5: Type a brief company details & Right ClickSelect the Bullets Ok.

Step 6: Save the document.



OUTPUT:

RESULT:



EX.NO : 1.b CURRICULUM VITAE

DATE :

AIM:

To create curriculum vitae (CV) of a B.E graduate with the specification.

Table to show qualifications with heading.

Left & Right margins

Page numbers in the footer on the right side.

Use Watermark.

ALGORITHM:


Microsoft Office Word 2007. Step 2: Type a Bio-data briefly then go to Insert Table Select number of rows &

columnsOk for qualifications.

Step 3: Go to Page LayoutMarginsAssignLeft and Right Margins

Step 4: Go to Insert Page NumbersSelect footer on the right sideOk.

Step 5: Go to Page LayoutWatermarkCustomize text as Bio-dataOk.

Step 6: Save the Document.



OUTPUT:

RESULT:



EXNO : 1.c SEARCHING & REPLACING DATA

DATE :

AIM

To search and replace the data using MS - Word.

ALGORITHM:

Step 1: Start the process.


Microsoft Office Word 2007.

Step 3: To open a document, click file menu in the menu bar and select new. A new page

will appear.

Step 4: Type a paragraph of text in the new opened document.

Step 5: To find a repeated words press Ctrl + F and type the word in the find what text box.

Step 6: Click Find next button to search the full document.

Step 7: To replace the word press Ctrl + H and enter the word to replace the data in replace

with text box.

Step 8: Click replace all button to replace the all word in the full document.

OUTPUT:

1. FIND



2. REPLACE

RESULT:



EX.NO : 1.d SCIENTIFIC NOTATIONS

DATE :

AIM:

To create a MS-WORD document for the following scientific notation

A= + + +

+

+ 7 4 + 6 o

ALGORITHM:


Microsoft Office Word 2007. Step 2: Go to InsertEquationSelect the specific format.

For eg, for , …………..

Step 3: Select for

Step 4: Select x/y for




OUTPUT:

RESULT:



EX.NO : 1.e CREATING TIME TABLE & CONVERT TO TEXT

DATE :

AIM:

To prepare a class timetable using Merge rows, Split row, Insert rows, columns and

convert the table into text format in spreadsheet.

ALGORITHM:



Step 2: Go to Insert Menu Table Select Number of rows & columnsOk.

Step 3: Select two cells from the table then, Right click Merge Cells.

Step 4: Select one cell from the table Right clickSplit Cell.

Step 5: To insert a row, select a cell and Right click Insert Insert One row above or

below.

Step 6: To insert a column, select a cell and Right click Insert Insert One column left or

right.

Step 7: Type a Class Timetable with Headings.

Step 8: Go to Layout Convert to text Select Tabs Ok.

Step 9: Save the document as Table and Text Format.



OUTPUT:

RESULT:



EX.NO : 1.f MAIL MERGE & LETTER PREPARATION

DATE :

AIM:

To create a WORD document to call letters for an interview using Mail Merge & send

to 10 candidates.

ALGORITHM:



Step 2: Go to Mailings Menu Start Mail merge Letters.

Step 3: Type an interview call letter with FROM address and leave some Space for TO

address.

Step 4: Go to Mailings MenuSelect recipients Type a new list Customize the

Columns Ok.

Step 5: Type a 10 address new some fieldsOkSave.

Step 6: Go to Mailings Menu Select recipients Use Existing list open a file Ok.

Step 7: Under the TO Address insert the Merge fields & preview the results.

Step 8: Go to Finish MergeEdit individual Documents All Ok.




OUTPUT:



OUTPUT:

RESULT:



EX.NO : 1.g DRAWING FLOW CHART

DATE :

AIM:

To create a flowchart in WORD to find the greatest among three numbers

ALGORITHM:


Microsoft Office Word 2007. Step 2: Construct a Flowchart for a given program.

Step 3: To draw the flowchart, click Insert → Shapes.

Step 4: Click on the required shape.

Step 5: Select the location to draw the shape and then click and drag.

Step 6: To add text within the shape place the cursor over the shape and Right click to add the

text.

Step 7: Use decision symbols for checking the conditions.

Step 8: Use the arrow symbols to represent the flow of control.

Step 9: Stop the process.



OUTPUT:

RESULT:



EX.NO :1.h SPREAD SHEET FORMULA EDITOR

DATE :

AIM:

To create a spreadsheet to calculate HRA , DA, TA, PF, LIC, Gross Salary , Net

Salary from the given data.

HRA=18% of basic Pay

LIC =7% of Basic Pay

Deduction= PF + LIC

PF =10% of Basic Pay

DA=15% of Basic Pay

TA=12% of Basic Pay

Gross Salary = Basic Pay + HRA + DA + TA

Net Salary = Gross Salary – Deduction

ALGORITHM:

Step 1: Open a new worksheet by clicking Start → All Programs → Microsoft Office →

Microsoft Office Excel 2007.

Step 2: Type the details about the employees and Basic Salary.

Step 3: For HRA, move to corresponding row & column and assign the Formula =18/100* BS

(row & column).

Step 4: For DA, move to corresponding row & column and assign Formula =15/100*BS (row

& column).

Step 5: For TA, move to corresponding row & column and assign the Formula=12/100* BS

(row & column).

Step 6: For PF, move to corresponding row & column. And assign the Formula =10/100* BS

(row & column).

Step 7: For LIC, move to corresponding row & column and assign the formula =7/100* BS,

Step 8: For GS, move to corresponding row & column and assign the

Formula = Basic Pay + HRA + DA + TA.

Step 9: To calculate the Deduction assign the formula = PF + LIC

Step 10: For calculating Net Salary assign the formula = Gross Salary – Deduction.

Step 11: Save the ExcelSheet.



OUTPUT:

RESULT:



EX.NO : 1.i PROTECT SPREAD SHEET

DATE :

AIM:

To create a spreadsheet for inserting a Picture, object and to apply the option of

protecting the document.

ALGORITHM:

Step 1: Open a new worksheet by clicking Start → All Programs → Microsoft Office →

Microsoft Office Excel 2007.

Step 2: Go to Insert Select the Picture Insert and type some Text.

Step 3: Go to Review Protect Sheet Set a Password & Re-enter the Password.

Step 4: For Unprotect again go to Review UnProtect Sheet Type Password.

Step 5: Modify the Worksheet and protect it.




OUTPUT:

RESULT:



EX.NO : 1.j SPREAD SHEET SORTING & IMPORT/ EXPORT FEATURES

DATE :

AIM:

To create a spreadsheet to sort the names and sort the numbers and convert the numbers

Decimal numbers: 243, 46, 173, 425, 625.

Binary numbers:-11011, 1110110101, 11001, 11111.

ALGORITHM:

Step 1: Open a Microsoft Excel Worksheet.

Step 2: Type some list of names in randomly.

Step 3: Select the names and Right click Sort Select the names and sort. In Ascending

Order (A to Z).

Step 4: Select the numbers and Right click Sort Select the numbers and sort. In

Ascending Order (Small to Large).

Step 5: For Conversion go to Formula Select More Functions Engineering Select

DEC2BIN, DEC2HEX, DEC2OCT and BIN2DEC, BIN2HEX, BIN2OCT etc.


Step 7: Open MSACCESS Create a database name Save Table design Insert record

save the table.

Step 8: Open a Microsoft Excel Worksheet From access Select Database name Select

the option in import data OK.

Step 9: Open the database Right-click and select EXPORT options Save file OK.



OUTPUT:



OUTPUT:

RESULT:



EX.NO : 2 PRESENTATION AND VISUALIZATION

DATE :

AIM:

To create graphs and charts with 2D and 3D effects in MS PowerPoint.

ALGORITHM:

GENERATING CHARTS WITH 2D AND 3D EFFECTS

Step 1: Start the Process.

Step 2: Open a document by clicking Start → All Programs → Microsoft Office →

Microsoft Office PowerPoint 2007.

Step 3: To open a new document, click file menu in the menu bar and select new. A new page

will appear.

Step 4: Go to Insert Chart.

Step 5: Choose a template from the displayed types.

Step 6: Enter the data in the corresponding Spreadsheet appeared.

Step 7: A new Chart (2D chart) will be appeared in the slide created.

Step 8: Choose the chart and Click Layout3D rotation from the menu bar for 3D effects.

Step 9: Give the values for x and y axis. Click Reset button.

Step 10: To save the corresponding slide click file and click save.

GENERATING GRAPHS WITH 2D AND 3D EFFECTS

Step 1: Start the Process.

Step 2: Open a document by clicking Start → All Programs → Microsoft Office →

Microsoft Office PowerPoint 2007.

Step 3: To open a new document, click file menu in the menu bar and select new. A new page

will appear.

Step 4: Go to Insert Chart.

Step 5: Select XY SCATTER from the types available.

Step 6: Enter the data in the corresponding Spreadsheet appeared.

Step 7: A new graph will be appeared in the slide created.

Step 8: Choose the chart and Click Layout3D rotation from the menu bar

Step 9: To save the corresponding slide click file and click save.



OUTPUT:



OUTPUT:



OUTPUT:

RESULT:



EX.NO : 3 PROBLEM FORMULATION, PROBLEM SOLVING, FLOWCHART

DATE :

AIM:

To construct the algorithm, Pseudocode and flowchart for the given program in MS

word.

ALGORITHM:

Step 1: Start the process.



Step 3: Construct Algorithm, Pseudocode and Flowchart for a given program.

Step 4: To draw the flowchart, click Insert → Shapes.

Step 5: Click on the required shape.

Step 6: Select the location to draw the shape and then click and drag.

Step 7: To add text within the shape place the cursor over the shape and Right click to add the

text.

Step 8: Use decision symbols for checking the conditions.

Step 9: Use the arrow symbols to represent the flow of control.

Step 10: Stop the process.

BIGGEST OF THREE NUMBERS

ALGORITHM:

Step 1: Start the program.

Step 2: Read the value of x, y, z.

Step 3: Check the condition whether ((x>y)&&(x>z))

Step 4: print x is the biggest numbers.

Step 5: Check the condition whether (y>z)

Step 6: Print y is the biggest number.

Step 7: Else print z is biggest number.

Step 8: Stop the Program.

PSEUDOCODE:

START

READ x, y, z as integer

IF x is greater than y and z THEN.

PRINT x

IF y is greater than z THEN

PRINT y

ELSE

PRINT z



FLOWCHART:

CALCULATE STUDENT DATABASE

ALGORITHM:


Step 2: Read the input values of roll no, name, marks.

Step 3: Calculate total and average.

Step 4: Print the values of roll no, name, average.

Step 5: Stop the program.



PSEUDOCODE:

START

READ roll no as integer

READ name as character

READ marks as integer

CALCULATE total = mark1 + mark2 + mark3

CALCULATE average = total / 3.

PRINT roll no

PRINT name

PRINT total

PRINT average

FLOWCHART:

RESULT:



EX.NO : 4.a AREA OF CIRCLE AND CIRCUMFERENCE

DATE :

AIM:

To write a C program to find an area and circumference of circle.

ALGORITHM:

Step 1: Start the Program.

Step 2: Input the radius of the Circle.

Step 3: Find the area and circumference of the circle using the formula

area =3.14*r*r

circum=2*3.14*r

Step 4: Print the area and circumference.


PROGRAM:

//AREA AND CIRCUMFERENCE OF CIRCLE

#include<stdio.h>

#include<conio.h>

void main()

{

float r,area,circum;

clrscr();

printf("\n Enter the radius of the Circle");

scanf("%f",&r);

area=3.14*r*r;

circum=2*3.14*r;

printf("\n Area=%f",area);

printf("\n Circumference=%f",circum);

getch();

}



OUTPUT:

RESULT:



EX.NO : 4.b CENTIGRADE AND FARHENHEIT VALUES

DATE :

AIM:

To write a program in C to find the centigrade and Fahrenheit values.

ALGORITHM:


Step 2: Read the centigrade value of c.

Step 3: Compute equivalent Fahrenheit value using formulae f= 1.8 * c+ 32.

Step 4: Print the value f.

Step 5: Read Fahrenheit value of fv.

Step 6: Compute the equivalent centigrade value using formulae cv= (fv – 32) / 1.8

Step 7: Print the value of cv.


PROGRAM:

// CENTIGRADE AND FARHENHEIT VALUES

#inlcude<stdio.h>

#include<conio.h>

void main()

{

float c, f, cv, fv;

clrscr();

printf(“\n Enter the temperature in Centigrade:”);

scanf(“%f”,&c);

f=1.8*c+32;

printf(“\n Fahrenheit Equivalent is:% .3f\n”,f);

printf(“\n Enter the temperature in Fahrenheit:”);

scanf(“%f”,&fv);

cv = (fv – 32)/1.8;

printf(“\n Centigrade equivalent is:%.3f\n”,cv);

getch();

}



OUTPUT:

RESULT:



EX.NO : 4.c LEAP YEAR

DATE :

AIM:

To write a C program to find the given year is a leap year or not.

ALGORITHM:


Step 2: Read the given year.

Step 3: Check the condition whether it is true or not.

Step 4: If the condition is true, print the year is leap.

Step 5: Else, Print the year is not a leap year.


PROGRAM:

//LEAP YEAR

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

int year;

clrscr();

printf(“\n Enter the year:”);

scanf(„%d”, &year);

if((year%4==0)&&(year%100!=0)||(year%400==0))

{

printf(“\n The year %d is a leap year”, year);

}

else

{

printf(“\n The year %d is not a leap year”, year);

}

getch();

}



OUTPUT:

RESULT:



EX.NO : 4.d QUADRATIC EQUATION

DATE :

AIM:

To a write a program in C is to find the roots of the quadratic equation and to evaluate the

expression.

ALGORITHM:

Step 1: Start the Program.

Step 2: Read the variables a, b, c, d, x1, x2.

Step 3: Compute the quadratic equation d = b * b – 4 * a * c.

Step 4: Check the condition whether d value is equal to zero.

Step 5: If the condition becomes true, print both roots are equal.

5.1 - Perform the operation x1 = - b / (2.0 * a).

5.2 - Swap the value of x1 to x2.

5.3 - Print the value of x1 and x2.

Step 6: If the condition becomes false, print both roots are real and difference.

6.1 - Perform the operation of x1 = (-b+sqrt(d))/(2*a);

x2 = (-b-sqrt(d))/(2*a);.

6.2 - Print the value of x1 and x2.

Step 7: If both the condition becomes false, print the roots are imaginary.


PROGRAM:

// QUADRATIC EQUATION

#include <stdio.h>

#include <conio.h>

#include<math.h>

void main()

{

int a,b,c,d;

float x1,x2;

clrscr();

printf("enter the value of a,b & c\n");

scanf("%d%d%d",&a,&b,&c);

d=b*b-4*a*c;

if(d==0)

{

printf("Both roots are equal\n");

x1=-b/(2.0*a);

x2=x1;

printf("First Root x1= %f\n",x1);

printf("Second Root x2= %f\n",x2);

}



else if(d>0)

{

printf("Both roots are real and diff-2\n");

x1=(-b+sqrt(d))/(2*a);

x2=(-b-sqrt(d))/(2*a);

printf("First Root x1= %f\n",x1);

printf("Second Root x2= %f\n",x2);

}

else

printf("Root are imaginary\n No Solution \n");

getch();

}

OUTPUT:

RESULT:



EX.NO : 4.e ARITHMETIC OPERATIONS

DATE :

AIM:

To a write a C program to evaluate the arithmetic operation.

ALGORITHM:


Step 2: Read the input value of a and b.

Step 3: Read the value for the variable n and check the given case value.

Step 4: If n==1 then, perform addition operation and print the value of c.

Step 5: If n==2 then, perform subtraction operation and print the value of c.

Step 6: If n==3 then, perform multiplication operation and print the value of c.

Step 7: If n==4 then, perform division operation and print the value of c.

Step 8: If n==0, exit the program.

Step 9: Default case is an invalid operation code statement.


PROGRAM:

//ARITHMETIC OPERATIONS

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b,c,n;

clrscr();

printf(„\n Arithmetic Operation”);

printf(„\n ~~~~~~”);

printf(“\n MENU”);

printf(“\n 1-Addition”);

printf(“\n 2-Subtraction”);

printf(“\n 3-Multiplication”);

printf(“\n 4-Division”);

printf(“\n 5-Exit(0)”);

printf("Enter First Number:");

scanf("%d", &a);

printf("Enter Second Number:");

scanf("%d", &b);

printf("choose the arithmetic option\n");

scanf("%d",&n);

switch(n)

{

case 1: c=a+b;



printf("The addition of two numbers %d\n",c);

break;

case 2: c=a-b;

printf("The subtraction of two numbers %d\n",c);

break;

case 3: c=a*b;

printf("The multiplication of two numbers %d\n",c);

break;

case 4: c=a/b;

printf("The division of two numbers %d\n",c);

break;

case 5: exit(0);

break;

default: printf(“\n Invalid Operation Code”);

}

getch();

}

OUTPUT:

RESULT:



EX.NO : 5.a PRIME NUMBERS

DATE :

AIM:

To write a c program to find the first 100 prime numbers.

ALGORITHM:


Step 2: Read the value of n.

Step 3: Initialize the value of i as 2.

Step 4: Check the if loop condition whether it‟s true or not.

Step 5: If condition is true, then print it is a prime number.

Step 6: If condition is false, then print it is not a prime number.

Step 7: Otherwise else part is executed, and then variable i is increased by 1 then goto Step1.

Step 8: Print the given is a prime number.


PROGRAM:

//PRIME NUMBERS

#include<stdio.h>

#include<conio.h>

void main()

{

int n=2, count=0;

int i, m;

clrscr();

printf("\n Enter the number upto which you want to find prime numbers : ");

scanf("%d",&m);

printf("\n Prime numbers are : ");

while(n<m)

{

for(i=2; i<n; i++)

{

if(n%i==0)

goto t;

}

printf("\t%d ", n);

count++;

t : n++;

}

printf("\n\n Number of prime numbers are %d", count);

getch();

}



OUTPUT:

RESULT:



EX.NO : 5.b FIBONACCI SERIES

DATE :

AIM:

To write a C program to generate the Fibonacci series.

ALGORITHM:


Step 2: Read the input value as a=0 and b=1.

Step 3: Determine the condition (i <= n) is true or not.

Step 4: If the condition is true, just add the two variables.

Step 5: Assign the value of b to a and the value of c to b.

Step 6: Every increment in the loop prints the value of c.

Step 7: After the execution of the loop stops the program.

PROGRAM:

#include<stdio.h>

#include<conio.h>

void main()

{

int a, b, c=0,i,n;

clrscr();

a=0;

b=1;

printf(“\n ENTER THE RANGE OF SERIES:”);

scanf(“%d”, &n);

printf(“\n The Fibonacci series are”);

for(i=1;i<=n;i++)

{

printf(“\n %d”, c);

a=b;

b=c;

c=a+b;

}

getch();

}



OUTPUT:

RESULT:



EX.NO : 5.c DIVISIBLE BY 2 AND NOT DIVISIBLE BY 3 AND 5

DATE :

AIM:

To write a C program to generate numbers between 1 and 100 which are divisible by 2

and not divisible by 3 and 5.

ALGORITHM:


Step 2: Declare and read the variable n.

Step 3: Determine the condition (n<= 100) is true or not.

Step 4: If the condition is true, further check the given number is divisible by 2 and not

divisible by 3 and 5.

Step 5: If true, print the numbers and increment the n value.

Step 6: If the condition is false, skip the if loop and increment the n value.

Step 6: If the for condition fails, skip the loop.


PROGRAM:

// NUMBERS DIVISIBLE BY TWO

#include<stdio.h>

#include<conio.h>

void main()

{

int n;

clrscr();

printf("\n Display numbers between 1 and 100");

printf("\n");

printf("\n The number divisble by 2 and not divisble by 3 and 5");

for(n=1;n<=100;n++)

{

if((n%2==0)&&(n%3!=0)&&(n%5!=0))

{

printf("\n %d",n);

}

}

getch();

}



OUTPUT:

RESULT:



EX.NO : 5.d BINARY CODE TO GRAY CODE CONVERSION

DATE :

AIM:

To write a C program to convert binary code to gray code conversion.

ALGORITHM:


Step 2: Read the variable bin and check the condition whether it is not equal to zero.

Step 3: The Most Significant Bit of the gray code will be exactly equal to the first bit of the given

binary number.

Step 4: The second bit of the code will be exclusive-or of the first and second bit of the given

binary number.

Step 5: The third bit of gray code will be equal to the exclusive-or of the second and third bit of the

given binary number.

Step 6: Display the gray code value.


PROGRAM:

// BINARY TO GRAY CODE CONVERSION

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

int bin,gray=0;

int a,b,i=0;

clrscr();

printf("Enter a binary number: ");

scanf("%d",&bin);

while(bin!=0)

{

a=bin%10;

bin=bin/10;

b=bin% 10;

if((a&&!b)||(!a&&b))

{

gray=gray+pow(10,i);

}

i++;

}

printf("The gray code is %d\n",gray);

getch();



}

OUTPUT:

RESULT:



EX.NO : 5.e GRAY CODE TO BINARY CODE CONVERSION

DATE :

AIM:

To write a C program to convert gray code to binary code conversion.

ALGORITHM:


Step 2: Read the variable n and check the condition whether it is not equal to zero.

Step 3: If the Number is not equal to zero then modulo the number with 10.

Step 4: Store the value in a[i] and using for loop check the condition.

Step 5: If a[i] =1 then check the condition using if loop.

Step 6: Display the result.


PROGRAM:

// GRAY TO BINARY CODE CONVERSION

#include<stdio.h>

#include<conio.h>

void main()

{

int a[10],i=0,c=0,n;

clrscr();

printf("\n Enter the gray code:\t");

scanf("%d",&n);

while(n!=0)

{

a[i]=n%10;

n/=10;

i++;

c++;

}

for(i=c-1;i>=0;i--)

{

if(a[i]==1)

{

if(a[i-1]==1)

a[i-1]=0;

else

a[i-1]=1;

}

}

printf("\n The binary code is \t");

for(i=c-1;i>=0;i--)

{

printf("%d",a[i]);

}



getch();

}

OUTPUT:

RESULT:



EX.NO : 5.f DECIMAL CODE TO OCTAL CODE CONVERSION

DATE :

AIM:

To write a C program to convert decimal code to octal code conversion.

ALGORITHM:


Step 2: Read the variable num and check the condition whether it is greater than zero.

Step 3: If the number is less than 8 the octal number is the same.

Step 4: If the num > 7 then divide the number with 8, mention the remainder value.

Step 5: Repeat the step 4 with the quotient till that quotient is less than 8.

Step 6: Display the remainder value in reverse order.


PROGRAM:

// DECIMAL TO OCTAL CODE CONVERSION

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

int num;

int rem[50],i=0,length=0;

clrscr();

printf("\n Enter the decimal number: ");

scanf("%d",&num);

while(num>0)

{

rem[i]=num%8;

num=num/8;

i++;

length++;

}

printf("\n Octal number : ");

for(i=length-1;i>=0;i--)

printf("%d",rem[i]);

getch();

}



OUTPUT:

RESULT:



EX.NO : 5.g SUM OF DIGITS, REVERSE AND PALINDROME

DATE :

AIM:

To write a C program to find the sum, reverse of digits and check it is Palindrome or

not.

ALGORITHM:


Step 2: Get the value of a, num. Initialize the value of sum as zero and rnum as zero

Step 3: Check the given condition is not equal to zero.

Remnum%10

SumSum+rem

Rnumrnum *10 +rem

Num num/10

Step 4: After the end of the loop print the sum and reverse no of the digit.

Step 5: Find whether the given reverse number is equal then is palindrome or not.


PROGRAM:

//SUM OF DIGITS, REVERSE, PALINDROME

#include<stdio.h>

#include<conio.h>

void main()

{

int a, num, sum=0, rnum=0, rem;

clrscr();

printf("\n Enter the Number:");

scanf("%d", &num);

a=num;

while(num!=0)

{

rem=num%10;

sum=sum+rem;

rnum=rnum*10+rem;

num=num/10;

}

printf("\n The Sum of Digits %d is = %d \n", a, sum);

printf("\n The Reverse %d is = %d \n", a, rnum);

if(a==rnum)

printf("\n The given number is a Palindrome");

else

printf("\n The given number is not a Palindrome");



getch();

}

OUTPUT:

RESULT:



.

EX.NO : 5.h ARMSTRONG NUMBER

DATE :

AIM:

To write a C program for finding an Armstrong Number.

ALGORITHM:


Step 2: Read the value of n and set a = n, sum = 0.

Step 3: Check whether a > 0 or not.

Step 4: If the condition is true then, compute

r = n%10,

sum = sum + r * r * r,

n = n/10.

Step 4: Continue the loop until the condition gets false.

Step 5: If the condition becomes false, check the value of a is equal to the value of c.

Step 6: If true, print the given value as an Armstrong Number.

Step 7: Else, print the given value as not an Armstrong Number.

Step 8: Stop the program

PROGRAM:

//ARMSTRONG NUMBER

#include<stdio.h>

#include<conio.h>

#include<math.h>

void main()

{

int a, b, c=0, d, e;

clrscr();

printf(“ \n enter the number: “);

scanf(“%d”, &a);

e = a;

while(e!=0)

{

b = e % 10;

c = c + b * b * b;

e = e / 10;

}

if(a==c)

printf(“\n %d is an Armstrong number”, a);

else

printf(“\n %d is not an Armstrong number”, a);



getch();

}

OUTPUT:

RESULT:



EX.NO : 5.i PASCAL TRIANGLE

DATE :

AIM:

To write a C program to print the Pascal triangle.

ALGORITHM:


Step 2: Read the value of num.

Step 3: Initialize the value of i = 1, j = 1 and x = 1.

Step 4: Check the condition i <= num.

Step 5: If true, check the condition j<=i.

Step 6: If the loop is true then, verify whether j =1.

Step 7: If j=1 then print the value of x as 1.

Step 8: Else, compute the given equation: x=(x*(i-j+1)/ (j-1)) and print the value of x.

Step 9: Continue the loop until the condition is true and also increment the value of i and j.


PROGRAM:

//PASCAL TRIANGLE

#include<stdio.h>

#include<conio.h>

void main()

{

int i,j,n,c,k,space;

clrscr();

printf("Enter the limit ");

scanf("%d",&n);

printf("\n\n");

space=n;

for(i=0;i<n;i++)

{

c=1;

for(k=space;k>=0;k--)

printf(" ");

space--;

for(j=0;j<=i;j++)

{

printf("%d ",c);

c=(c*(i-j)/(j+1));

}

printf("\n");

}



getch();

}

OUTPUT:

RESULT:



EX.NO : 6.a LARGEST AND SMALLEST NUMBER IN AN ARRAY

DATE :

AIM:

To write a C program to find the largest and smallest number in an array.

ALGORITHM:


Step 2: Read „n‟ number element of array.

Step 3: Save the numbers in ascending order using temp‟t‟.

Step 4: Print the first element (i.e) smallest end largest elements.


PROGRAM:

// LARGEST AND SMALLEST NUMBER IN AN ARRAY

#include<stdio.h>

#include<conio.h>

void main()

{

int n,i,j,a[15],t;

clrscr();

printf("\n enter the array size to find min and max values\n");

scanf("%d",&n);

printf(“\n enter the array values \n”);

for(i=1;i<=n;i++)

{

scanf("%d",&a[i]);

}

for(i=1;i<=n;i++)

{

for(j=i+1;j<=n;j++)

{

if(a[i]>a[j])

{

t=a[i];

a[i]=a[j];

a[j]=t;

}

}

}

printf("The minimum value is %d\n",a[1]);

printf("The maximum value is %d\n",a[n]);



getch();

}

OUTPUT:

RESULT:



EX.NO : 6.b TRANSPOSE OF A MATRIX

DATE :

AIM:

To write a C program to print transpose of matrix elements.

ALGORITHM:


Step 2: Read m rows and n columns of a matrix.

Step 3: Read the elements of A[i][j] matrix.

Step 4: Assign A[j][i] → B[i][j].

Step 5: Print the transpose matrix B[i][j].


PROGRAM:

//TRANSPOSE OF A MATRIX

#include<stdio.h>

#include<conio.h>

void main()

{

int a[10][10],b[10][10],i,j,m,n;

clrscr();

printf("Input row & column of matrix:\n");

scanf("%d%d",&n,&m);

printf("Enter the elements of matrix:\n");

for(i=0;i<n;i++)

for(j=0;j<m;j++)

scanf("%d",&a[i][j]);

for(i=0;i<m;++i)

for(j=0;j<n;++j)

b[i][j]=a[j][i];

printf("Transpose of the matrix is:\n");

for(i=0;i<m;++i)

{

prinf(“\n”);

for(j=0;j<n;++j)

printf("\t%3d",b[i][j]);

}

getch();

}



OUTPUT:

RESULT:



EX.NO : 6.c MATRIX MULTIPLICATION

DATE :

AIM:

To write a C program to perform Matrix Multiplication.

ALGORITHM:


Step 2: Enter the m rows and n columns of the A matrix.

Step 3: Enter the p rows and q columns of the B matrix.

Step 4: Enter the elements of the A matrix.

Step 5: Enter the elements of the B matrix.

Step 6: Print the elements of the A matrix in matrix form.

Step 7: Print the elements of the B matrix in matrix form.

Step 8: Multiply the A and B matrix and store the element in the C matrix.

Step 9: Print the resultant matrix.


PROGRAM:

//MATRIX MULTIPLICATION

#include<stdio.h>

#include<conio.h>

#include<process.h>

void main()

{

int a[10][10],b[10][10],c[10][10];

int i,j,m,n,p,q,s;

clrscr();

printf("Input row and column of matrix-A\n");

scanf("%d%d",&m,&n);

printf("Input row and column of matrix-B\n");

scanf("%d%d",&p,&q);

if(n!=p)

{

printf("Matrix cannot be multiplied\n");

getch();

exit(0);

}

printf("Input Matrix A\n");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)



{


}

}

printf("Input Matrix-B\n");

for(i=0;i<p;i++)

{

for(j=0;j<q;j++)

{

scanf("%d",&b[i][j]);

}

}

for(i=0;i<m;i++)

{

for(j=0;j<q;j++)

{

c[i][j]=0;

for(s=0;s<n;s++)

c[i][j]=c[i][j]+a[i][s]*b[s][j];

}

}

printf("\nProduct of matrix A and matrix B is:\n");

for(i=0;i<m;i++)

{

for(j=0;j<q;j++)

{

printf("\t%d",c[i][j]);

}

printf("\n");

}

getch();

}



OUTPUT:

RESULT:



EX.NO : 6.d SUM OF TWO MATRICES

DATE :

AIM:

To write a C program for sum of two matrices.

ALGORITHM:


Step 2: Read p rows and q columns of matrix A.

Step 3: Read m rows and n columns of matrix B.

Step 4: Check the values of p is equal to m and q is equal to n.

Step 5: Read the matrix A[i][j] and B[i][j].

Step 6: Compute the sum of matrix A[i][j] and B[i][j].

Step 7: Print the matrix C[i][j].


PROGRAM:

//SUM OF TWO MATRICES

#include <stdio.h>

#include <conio.h>

void main()

{

int a[10][10],b[10][10],c[10][10];

int i,j,m,n,p,q;

clrscr();

printf("enter the row and column of A matrix");

scanf("%d%d",&p,&q);

printf("enter the row and column of B matrix");

scanf("%d%d",&m,&n);

if((n==p)&&(m==q))

{

printf("matrices can be added");

printf("enter the element of A matrices:\n");

for(i=0;i<p;++i)

for(j=0;j<q;++j)


printf("enter the element of B matrices:\n");

for(i=0;i<n;++i)

for(j=0;j<m;++j)

scanf("%d",&b[i][j]);



for(i=0;i<n;++i)

for(j=0;j<m;++j)

c[i][j]=a[i][j]+b[i][j];

printf("sum of A and B matrix:\n");

for(i=0;i<n;++i)

{

for(j=0;j<m;++j)

{

printf("%5d",c[i][j]);

printf("\n");

}

}

getch();

}

else

printf("matrix cannot be added\n");

}



OUTPUT:

RESULT:



EX.NO : 7.a STRING CONCATENATION

DATE :

AIM:

To write a program to perform the string Concatenation using C.

ALGORITHM:


Step 2: Declare the variables and read the input of str1 and str2 as strings.

Step 3: Concatenate the two strings using for loop.

Step 4: Print the string.


PROGRAM:

// STRING CONCATENATION

#include<stdio.h>

#include<conio.h>

void main()

{

int i,j,k;

char str[10],str1[10],str2[20];

clrscr();

printf("\n Enter the String1:");

gets(str1);


gets(str2);

for(i=0,j=0;str1[i]!='\0';i++,j++)

str[j]=str1[i];

for(i=0,k=j;str2[i]!='\0';i++,k++)

str[k]=str2[i];

str[k]='\0';

printf("\n The Concatenated String is %s",str);

getch();

}



OUTPUT:

RESULT:



EX.NO : 7.b STRING COMPARISON

DATE :

AIM:

To write a program to perform the string Comparison using C.

ALGORITHM:


Step 2: Declare the variables and assign a string to str1 and str2.

Step 3: Compare the two strings using for loop.

Step 4: If the given strings are equal then, print “Strings are equal”.

Step 5: If the given strings are not equal then, print “Strings are not equal”.


PROGRAM:

//STRING COMPARISON

#include<stdio.h>

#include<conio.h>

void main()

{

char str1[10],str2[10],i;

clrscr();


gets(str1);


gets(str2);

for(i=0;str1[i]!='\0'||str2[i]!='\0';i++)

if(str1[i]!=str2[i])

{

printf("\n Strings are not equal");

break;

}

else

{

printf("\n Strings are equal");

break;

}

getch();

}



OUTPUT:

RESULT:



EX.NO : 7.c STRING COPY

DATE :

AIM: To write a program to perform the string Copy using C.

ALGORITHM:


Step 2: Declare the variables.

Step 3: Read input string 1.

Step 4: Copy the strings using for loop.

Step 5: Store the string into string 2.

Step 6: Print the String.


PROGRAM:

//STRING COPY

#include<stdio.h>

void main()

{

char str1[10],str2[10],i;

clrscr();

printf(" Enter string 1");

gets(str1);

for(i=0;str1[i]!='\0';i++)

str2[i] = str1[i];

str2[i] = '\0';

printf("\n The Input string is %s",str1);

printf("\n The Copied string 2 is %s",str2);

getch();

}



OUTPUT:

RESULT:



.

EX.NO : 7.d STRING LENGTH

DATE :

AIM:

To write a program to calculate the string length using C.

ALGORITHM:


Step 2: Declare the variables.

Step 3: Read input str.

Step 4: Count the string length using for loop.

Step 5: Print the String length.


PROGRAM:

//STRING LENGTH

#include<stdio.h>

#include<conio.h>

void main()

{

int i,sum=0;

char str[20];

clrscr();

printf("\n Enter the String:");

gets(str);

for(i=0;str[i]!='\0';i++)

sum+=i;

printf("\n The number of characters in the string is %d", i);

getch();

}



OUTPUT:

RESULT:



EX.NO : 7.e PROGRAM TO COUNT VOWELS IN STRING

DATE :

AIM:

To develop a program to count vowels in the given string.

ALGORITHM:


Step 2: Read input string.

Step 3: Initialize count=0.

Step 4: If input character is equal to vowel, increment the count value.

Step 5: Move to next character. Go to Step 4.

Step 6: If count = 0 is true, Print there is no vowels in the string.

Step 7: If count = 0 is false, Print the count vowels in the string.


PROGRAM:

//TO COUNT VOWELS IN STRING

#include<stdio.h>

#include<conio.h>

#include<ctype.h>

void main()

{

char str[20],c;

int i,count=0;

clrscr();

printf("\nEnter a string");

gets(str);

for(i=0;str[i]!='\0';i++)

{

c=toupper(str[i]);

if(c=='A'||c=='E'||c=='I'|| c=='O'|| c=='U')

count+=1;

}

if(count==0)

printf("\nThere are no vowels in %s",str);

else

printf("\nThere are %d vowels in %s",count,str);

getch();

}



OUTPUT:

RESULT:



EX.NO : 7.f ARRANGE NAMES IN ALPHABETICAL ORDER

DATE :

AIM:

To write a C program to arrange names in alphabetical order.

ALGORITHM:


Step 2: Read the input n.

Step 3: Get the names using for loop and initialize i to 0, j→i+1.

Step 4: Compare the names by using strcmp function.

Step 5: Print the names in alphabetical order.

Step 6: Stop the execution.

PROGRAM:

//ARRANGE NAMES IN ALPHABETIC ORDER

#include<stdio.h>

#include<conio.h>

#include<string.h>

void main()

{

char names[50][20],temp[20];

int n,i,j;

clrscr();

printf("\n how many names?");

scanf("%d", &n);

printf("\n Enter the %d names one by one \n ",n);

for(i=0;i<n;i++)

scanf("%s",names[i]);

for(i=0;i<n-1;i++)

{

for(j=i+1;j<n;j++)

{

if(strcmp(names[i],names[j])>0)

{

strcpy(temp,names[i]);

strcpy(names[i],names[j]);

strcpy(names[j],temp);

}

}

}

printf("\n Names in Alphabetical Order");

for(i=0;i<n;i++)



printf("\n%s",names[i]);

getch();

}

OUTPUT:

RESULT:



EX.NO : 8.a SWAPPING OF TWO NUMBERS USING CALL BY VALUE

DATE :

AIM:

To develop a program to swap two numbers using call by value.

ALGORITHM:

MAIN PROGRAM


Step 2: Read the two numbers.

Step 3: Call the function by value to swap two numbers.

Step 4: Print the swapped numbers.


SUBROUTINE

Step 1: Start the sub-routine with two parameters.

Step 2: temp = number1.

Step 3: number1 = number2.

Step 4: number2 = temp.

Step 5: Return from sub-routine.

PROGRAM:

// SWAPPING OF TWO NUMBERS USING CALL BY VALUE

#include<stdio.h>

#include<conio.h>

void swap(int , int);

void main( )

{

int a = 10, b = 20 ;

swap(a,b);

printf ( "\n Berfore swapping a = %d b = %d", a, b ) ;

getch();

}

void swap( int x, int y )

{

int t;

t=x;

x=y;

y=t;

printf ( "\nAfter swapping x = %d y = %d", x, y ) ;



}

OUTPUT:

RESULT:



EX.NO : 8.b SWAPPING OF TWO NUMBERS USING CALL BY REFERENCE

DATE :

AIM:

To develop a program to swap two numbers using call by reference.

ALGORITHM:

MAIN PROGRAM


Step 2: Read the value of the variables a and b.

Step 3: Call the function by reference (by address) to swap two numbers.

Step 4: Print the swapped numbers.


SUBROUTINE

Step 1: Start the sub-routine with two parameters (addresses of the two numbers).

Step 2: Declare the variable temp.

Step 3: Swap the variables by assigning the number1 value → temp variable.

Step 4: Assign the value of number2 →number1.

Step 5: Assign the value of temp →number2.

Step 6: Return from sub-routine.

PROGRAM:

//SWAPPING OF TWO NUMBERS USING CALL BY REFERENCE

#include <stdio.h>

void swap(int*, int*);

int main()

{

int x, y;

clrscr();

printf("Enter the value of x and y\n");

scanf("%d%d",&x,&y);

printf("Before Swapping\nx = %d\ny = %d\n", x, y);

swap(&x, &y);

printf("After Swapping\nx = %d\ny = %d\n", x, y);

return 0;

}

void swap(int *a, int *b)

{

int temp;

temp = *b;

*b = *a;



*a = temp;

}

OUTPUT:

RESULT:



EX.NO : 8.c CALCULATION OF MEAN, VARIANCE &

STANDARD DEVIATION

DATE :

AIM:

To write a C program to calculate the mean, variance and standard deviation using

functions.

ALGORITHM:


Step 2: Enter the array size.

Step 3: Enter the elements of the array.

Step 4: Print the Entered elements.

Step 5: Call the function to calculate mean.

Step 6: Call the function to calculate variance.

Step 7: Call the function to calculate standard deviation.

Step 8: Call the average function from the standard deviation function.


PROGRAM:

//COMPUTE STANDARD DEVIATION USING FUNCTION

#include<stdio.h>

#include<math.h>

#include<conio.h>

main()

{

int i, num;

float dev, list[100];

float standev();

clrscr();

printf("\n Enter the size of the list");

scanf("%d",&num);

printf("\n Enter the elements of the list");

for(i=0;i<num;i++)

scanf("%f",&list[i]);

printf("\n Entered elements are");

for(i=0;i<num;i++)

printf("\n%f",list[i]);

dev= standev(list,num);

printf("\n Standard Deviation of the list is %10.5f\n",dev);

getch();

}



float standev(float list[100],int no)

{

int i;

float mean,dev,sum=0.0;

float avg();

mean=avg(list,no);

printf("\n Mean of %3d elements is %10.2f\n",no,mean);

for(i=0;i<no;i++)

sum=sum+(mean-list[i])*(mean-list[i]);

dev=sqrt(sum/(float)no);

return(dev);

}

float avg(float v[100],int n)

{

int i;

float sum=0.0;

for(i=0;i<n;i++)

sum=sum+v[i];

return(sum/(float)n);

}

OUTPUT:

RESULT:



EX.NO : 9 FACTORIAL NUMBER USING RECURSIVE FUNCTION

DATE :

AIM:

To write a c program to generate the Factorial number using Recursive Function.

ALGORITHM:

MODULE A (MAIN FUNCTION):


Step 2: Read the value of n.

Step 3: Pass the integer value of n to module B.

Step 4: Print the value returned by module B as the required factorial.

MODULE B (USER DEFINED FUNCTION)

Step 1: Accept the value from calling module.

Step 2: Check the integer n is equal to 1, if yes return 1 to main function.

Step 3: Else, perform the expression n*fact(n-1) and return the value to main function.

PROGRAM

// FACTORIAL NUMBER USING RECURSIVE FUNCTION

#include<stdio.h>

#include<conio.h>

int fact(int n);

void main()

{

int n;

clrscr();

printf("\nEnter an integer:");

scanf("%d",&n);

printf("\nThe factorial of % is = %d",n,fact(n));

getch();

}

int fact(int n)

{

if(n==1)

return 1;

else

return(n*fact(n-1));

}



OUTPUT:

RESULT:

.



EX.NO : 10.a MARKSHEET OF STUDENTS USING STRUCTURES

DATE :

AIM:

To write a C program to print the mark sheet of n students using structures.

ALGORITHM:


Step 2: Assign Structure with tag name std.

Step 3: Declare the variables rno, marks as integer, and name[10] as character.

Step 3: Read total number of students n.

Step 4: Read s[i].rno, s[i].name, s[i].marks.

Step 5: Print s[i].rno, s[i].name, s[i].marks.


PROGRAM:

// MARKSHEET OF STUDENTS USING STRUCTURES

#include<stdio.h>

#include<conio.h>

typedef struct std

{

int rno;

char name[10];

int marks;

}student;

student s[10];

void main()

{

int i,n;

clrscr();

printf("Enter total no.of students:");

scanf("%d",&n);

printf("Enter student details:\n");

printf("Enter the RollNo,Name and Mark:\n");

for(i=1;i<=n;i++)

scanf("%d%s%d",&s[i].rno,s[i].name,&s[i].marks);

printf("\n");

printf("student details are \n\n");

printf("Rollno \t Name\t\tMarks\n");

for(i=1;i<=n;i++)

printf("%d\t\t%s\t\t%d\n",s[i].rno,s[i].name,s[i].marks);

getch();



}

OUTPUT:

RESULT:



EX.NO : 10.b EMPLOYEE DETAILS USING NESTED STRUCTURE

DATE :

AIM:

To write a C program to print the given employee details using nested structure.

ALGORITHM:


Step 2: Assign Structure with a tag name date.

Step 3: Declare the variables day, year as an integer and month as a character.

Step 4: Assign Structure with a tag name employee.

Step 5: Declare the variables code as an integer, name as a character and salary as a float.

Step 6: Nest the structure date within a structure employee.

Step 7: Read the employee details such as emp.code, emp.name, emp.salary.

Step 8: Read the employee joining date using nested structure such as

emp.joining.day, emp.joining.month, emp.joining.year.

Step 9: Print the employee details.


PROGRAM:

//EMPLOYEE PERSONAL DETAILS

#include<stdio.h>

#include<conio.h>

void main()

{

struct date

{

int day;

char month[20];

int year;

};

struct employee

{

int code;

char name[30];

float salary;

struct date joining;

};

struct employee emp;

printf("\n\n");

printf("\n Enter the employee code:");



scanf("%d",&emp.code);

printf("\n Enter the employee name:");

scanf("%s",emp.name);

printf("\n Enter the employee salary:");

scanf("%f",&emp.salary);

printf("\n Enter the employee date of joining:");

scanf("%d %s %d", &emp.joining.day, emp.joining.month, &emp.joining.year);

printf("\n\n");

printf("Display the Employee Details:");

printf("\n Employee code: %d",emp.code);

printf("\n Employee name: %s",emp.name);

printf("\n Employee salary: %d",emp.salary);

printf(“Employee date of joining: %d %s %d”,emp.joining.day, emp.joining.month,

emp.joining.year);

getch();

}

OUTPUT:

RESULT:



EX.NO : 10.c STUDENTS RECORD USING UNIONS

DATE :

AIM:

To write a C program to print the record of n students using unions.

ALGORITHM:


Step 2: Assign union to student1 student2.

Step 3: Read student1.name, student1.subject, student1.percentage.

Step 4: Read student2.name, student2.subject, student2.percentage.

Step 5: Print student1, student2 records.


PROGRAM:

// STUDENTS RECORD USING UNIONS

#include <stdio.h>

#include <string.h>

union student

{

char name[20];

char subject[20];

float percentage;

};

int main()

{

union student record1;

union student record2;

clrscr();

// assigning values to record1 union variable

printf("Union record1 values example\n");

strcpy(record1.name, "Raju");

printf(" Name : %s \n", record1.name);

strcpy(record1.subject, "Maths");

printf(" Subject : %s \n", record1.subject);

record1.percentage = 86.50;

printf(" Percentage : %f \n\n", record1.percentage);

// assigning values to record2 union variable

printf("Union record2 values example\n");

strcpy(record2.name, "Mani");



printf(" Name : %s \n", record2.name);

strcpy(record2.subject, "Physics");

printf(" Subject : %s \n", record2.subject);

record2.percentage = 99.50;

printf(" Percentage : %f \n", record2.percentage);

getch();

}

OUTPUT:

RESULT:

Date post:	18-Jul-2016
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