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Geometry Section 10-3 1112

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Arcs and Chords
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Section 10-3 Arcs and Chords Monday, May 14, 2012
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Page 1: Geometry Section 10-3 1112

Section 10-3Arcs and Chords

Monday, May 14, 2012

Page 2: Geometry Section 10-3 1112

Essential Questions

• How do you recognize and use relationships between arcs and chords?

• How do you recognize and use relationships between arcs, chords, and diameters?

Monday, May 14, 2012

Page 3: Geometry Section 10-3 1112

Theorems10.2 - Congruent Minor Arcs:

10.3 - Perpendicularity:

10.4 - Perpendicularity:

10.5 - Congruent Chords:

Monday, May 14, 2012

Page 4: Geometry Section 10-3 1112

Theorems10.2 - Congruent Minor Arcs: In the same or congruent

circles, two minor arcs are congruent IFF their corresponding chords are congruent

10.3 - Perpendicularity:

10.4 - Perpendicularity:

10.5 - Congruent Chords:

Monday, May 14, 2012

Page 5: Geometry Section 10-3 1112

Theorems10.2 - Congruent Minor Arcs: In the same or congruent

circles, two minor arcs are congruent IFF their corresponding chords are congruent

10.3 - Perpendicularity: If a diameter or radius of a circle is perpendicular to a chord, then it bisects the chord and its arc

10.4 - Perpendicularity:

10.5 - Congruent Chords:

Monday, May 14, 2012

Page 6: Geometry Section 10-3 1112

Theorems10.2 - Congruent Minor Arcs: In the same or congruent

circles, two minor arcs are congruent IFF their corresponding chords are congruent

10.3 - Perpendicularity: If a diameter or radius of a circle is perpendicular to a chord, then it bisects the chord and its arc

10.4 - Perpendicularity: The perpendicular bisector of a chord is a diameter or radius of the circle

10.5 - Congruent Chords:

Monday, May 14, 2012

Page 7: Geometry Section 10-3 1112

Theorems10.2 - Congruent Minor Arcs: In the same or congruent

circles, two minor arcs are congruent IFF their corresponding chords are congruent

10.3 - Perpendicularity: If a diameter or radius of a circle is perpendicular to a chord, then it bisects the chord and its arc

10.4 - Perpendicularity: The perpendicular bisector of a chord is a diameter or radius of the circle

10.5 - Congruent Chords: In the same or congruent circles, two chords are congruent IFF they are equidistant from the center

Monday, May 14, 2012

Page 8: Geometry Section 10-3 1112

Example 1 In X , AB ≅ CD and mCD = 90°. Find mAB .

Monday, May 14, 2012

Page 9: Geometry Section 10-3 1112

Example 1 In X , AB ≅ CD and mCD = 90°. Find mAB .

mAB = 90°

Monday, May 14, 2012

Page 10: Geometry Section 10-3 1112

Example 2 In the figure, A ≅ B and WX ≅ YZ . Find WX .

Monday, May 14, 2012

Page 11: Geometry Section 10-3 1112

Example 2 In the figure, A ≅ B and WX ≅ YZ . Find WX .

7x − 2 = 5x + 6

Monday, May 14, 2012

Page 12: Geometry Section 10-3 1112

Example 2 In the figure, A ≅ B and WX ≅ YZ . Find WX .

7x − 2 = 5x + 6

2x = 8

Monday, May 14, 2012

Page 13: Geometry Section 10-3 1112

Example 2 In the figure, A ≅ B and WX ≅ YZ . Find WX .

7x − 2 = 5x + 6

2x = 8

x = 4

Monday, May 14, 2012

Page 14: Geometry Section 10-3 1112

Example 2 In the figure, A ≅ B and WX ≅ YZ . Find WX .

7x − 2 = 5x + 6

2x = 8

x = 4

WX = 7(4) − 2

Monday, May 14, 2012

Page 15: Geometry Section 10-3 1112

Example 2 In the figure, A ≅ B and WX ≅ YZ . Find WX .

7x − 2 = 5x + 6

2x = 8

x = 4

WX = 7(4) − 2

WX = 28 − 2

Monday, May 14, 2012

Page 16: Geometry Section 10-3 1112

Example 2 In the figure, A ≅ B and WX ≅ YZ . Find WX .

7x − 2 = 5x + 6

2x = 8

x = 4

WX = 7(4) − 2

WX = 28 − 2

WX = 26Monday, May 14, 2012

Page 17: Geometry Section 10-3 1112

Example 3 In G, mDEF =150°. Find mDE.

Monday, May 14, 2012

Page 18: Geometry Section 10-3 1112

Example 3 In G, mDEF =150°. Find mDE.

mDE =

12

mDEF

Monday, May 14, 2012

Page 19: Geometry Section 10-3 1112

Example 3 In G, mDEF =150°. Find mDE.

mDE =

12

mDEF

mDE =

12

(150)

Monday, May 14, 2012

Page 20: Geometry Section 10-3 1112

Example 3 In G, mDEF =150°. Find mDE.

mDE =

12

mDEF

mDE =

12

(150)

mDE = 75°

Monday, May 14, 2012

Page 21: Geometry Section 10-3 1112

Example 4 In C , AB =18 inches and EF = 8 inches. Find CD.

Monday, May 14, 2012

Page 22: Geometry Section 10-3 1112

Example 4 In C , AB =18 inches and EF = 8 inches. Find CD.

CF is a radius.

Monday, May 14, 2012

Page 23: Geometry Section 10-3 1112

Example 4 In C , AB =18 inches and EF = 8 inches. Find CD.

CF is a radius.

a2 + b2 = c2

Monday, May 14, 2012

Page 24: Geometry Section 10-3 1112

Example 4 In C , AB =18 inches and EF = 8 inches. Find CD.

CF is a radius.

a2 + b2 = c2

42 + b2 = 92

Monday, May 14, 2012

Page 25: Geometry Section 10-3 1112

Example 4 In C , AB =18 inches and EF = 8 inches. Find CD.

CF is a radius.

a2 + b2 = c2

42 + b2 = 92

16 + b2 = 81

Monday, May 14, 2012

Page 26: Geometry Section 10-3 1112

Example 4 In C , AB =18 inches and EF = 8 inches. Find CD.

CF is a radius.

a2 + b2 = c2

42 + b2 = 92

16 + b2 = 81

b2 = 65

Monday, May 14, 2012

Page 27: Geometry Section 10-3 1112

Example 4 In C , AB =18 inches and EF = 8 inches. Find CD.

CF is a radius.

a2 + b2 = c2

42 + b2 = 92

16 + b2 = 81

b2 = 65

b = 65

Monday, May 14, 2012

Page 28: Geometry Section 10-3 1112

Example 4 In C , AB =18 inches and EF = 8 inches. Find CD.

CF is a radius.

a2 + b2 = c2

42 + b2 = 92

16 + b2 = 81

b2 = 65

b = 65 inches or ≈ 8.06 inches

Monday, May 14, 2012

Page 29: Geometry Section 10-3 1112

Example 5 In P , EF = GH = 24, PQ = 4x − 3, and PR = 2x + 3. Find PQ.

Monday, May 14, 2012

Page 30: Geometry Section 10-3 1112

Example 5 In P , EF = GH = 24, PQ = 4x − 3, and PR = 2x + 3. Find PQ.

4x − 3 = 2x + 3

Monday, May 14, 2012

Page 31: Geometry Section 10-3 1112

Example 5 In P , EF = GH = 24, PQ = 4x − 3, and PR = 2x + 3. Find PQ.

4x − 3 = 2x + 3

2x = 6

Monday, May 14, 2012

Page 32: Geometry Section 10-3 1112

Example 5 In P , EF = GH = 24, PQ = 4x − 3, and PR = 2x + 3. Find PQ.

4x − 3 = 2x + 3

2x = 6

x = 3

Monday, May 14, 2012

Page 33: Geometry Section 10-3 1112

Example 5 In P , EF = GH = 24, PQ = 4x − 3, and PR = 2x + 3. Find PQ.

4x − 3 = 2x + 3

2x = 6

x = 3

PQ = 4(3) − 3

Monday, May 14, 2012

Page 34: Geometry Section 10-3 1112

Example 5 In P , EF = GH = 24, PQ = 4x − 3, and PR = 2x + 3. Find PQ.

4x − 3 = 2x + 3

2x = 6

x = 3

PQ = 4(3) − 3

PQ = 12 − 3

Monday, May 14, 2012

Page 35: Geometry Section 10-3 1112

Example 5 In P , EF = GH = 24, PQ = 4x − 3, and PR = 2x + 3. Find PQ.

4x − 3 = 2x + 3

2x = 6

x = 3

PQ = 4(3) − 3

PQ = 12 − 3

PQ = 9

Monday, May 14, 2012

Page 36: Geometry Section 10-3 1112

Check Your Understanding

p. 704 #1 - 6

Monday, May 14, 2012

Page 37: Geometry Section 10-3 1112

Problem Set

Monday, May 14, 2012

Page 38: Geometry Section 10-3 1112

Problem Set

p. 705 #7-33 odd, 45, 49, 51

"I may not have gone where I intended to go, but I think I have ended up where I needed to be." - Douglas Adams

Monday, May 14, 2012


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