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Graphical solutions
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Fig. 5.18
4
5
Assuming operation in the saturation region
For small signal case is negligible
The gate current for FET is negligible
Where,
Small signal equivalent circuit
gm = transconductance
Where
Small signal equivalent circuits
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μn- surface mobility of electronCox- capacitance of gate per unit area
We know that
and
K
IVV
DQtoGSQ
But from (5.3)
Therefore
Dependence of gm on Q-point and device parameters
More complex equivalent circuits
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• At higher frequencies small capacitance have to be added between device terminals
• Also in the saturation region iD versus VDS is considered to be constant. This is not actually the case. The drain current, iD increases slightly as VDS increases. In order to take care of that we must add a drain resistance rd in the small signal model.
Example
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Determine the values of gm and rd the MOSFET characteristics shown below.
From equation 5.34, we have, obtain iD = 6.7 mA at VDS = 4 V and iD = 8 mA at VDS = 14 V.
Thus, the reciprocal of rd is calculated as:
S
V
mA
v
i
r DS
D
d
31013.0414
7.681
Thus, rd = 7.7 KΩ
Common source amplifier
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C1, C2 – Coupling capacitors short circuit for AC signals and open circuit for DC bias calculation
CS – bypass capacitor small impedance for AC
Voltage Gain
Ldd
L
RRr
R111
1'
'0 )( Lgsm Rvgv
gsin vv
'0Lm
inv Rgv
vA
(5.38)
(5.39)
(5.40)
(5.41)
Common source amplifier contd..
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= 0 implies 1/rd = 0 or rd =
Input resistance
Output resistance
Example 5.6 (Modified)
Find the midband voltage gain, input resistance, and output resistance of the amp.
dd Rr
R11
10
21 RRRi
vR G
in
inin (5.42)
(5.43)
mW
mL
VV
VV
VAKP
t
DD
450
15
0
1
20
/40
0
2
VRR
RVV DDG 4
105
10206
6
21
2
Bias circuit
Thevenin Equivalent
Circuit
Common source amplifier contd..
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or
kRrR
rRR
MRRR
RgV
VA
rrask
RRr
R
mSIL
WKPg
VVmAIVVVV
KP
L
WK
KR
KVRKVRKVRV
Ddd
dD
in
Lmin
V
dd
Ldd
L
DQm
DSQDQGSQGSQ
s
tsGstsGSQ
411
5
4
4.5107
20109.1
]01
,,[;7
20
10101
1041
1111
1
3.1108.115
450104022
76.12,44.1,2.2,55.2
106.02
1040
15
450
2)(
2
14)12(
0
21
33'0
33
'
36
21
36
00
The Source Follower
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Section 5.6
Recall the similarity with Emitter Follower
Drain is grounded
Source is not grounded
R1 Gate to ground (drain)
R2 Gate to ground (drain)
RS Source to ground (drain)
gmvgs & rd drain to source
To draw the small-signal ac equivalent circuit, we have to first draw the following circuit like remembering that:
Thus,
Small-signal ac equivalent circuit
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The Source Follower contd…
How to calculate the output resistance ?
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Current gain:
The current gain Ai = Av Rin/RL , like before.
Fig. 5.33
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Example contd….