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1Prof. Sergio B. MendesSummer 2018
Chapter 8 of Essential University Physics, Richard Wolfson, 3rd Edition
Gravitation
2Prof. Sergio B. MendesSummer 2018
• Newton's law of universal gravitation
• About motion in circular and other orbits
• How to calculate gravitational potential energy
• How to describe orbital types in terms of total mechanical energy
• The concept of escape speed
• The concept of gravitational field
What you are about to learn:
3Prof. Sergio B. MendesSummer 2018
Kepler’s Observational Laws(1609 – 1619)
1. The orbit of a planet is an ellipse with the Sun at one of the two foci.
2. A line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time.
3. The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit.
4Prof. Sergio B. MendesSummer 2018
• This law strictly holds only for point masses. However Newton showed that it applies to spherically symmetric masses. Also, it is a good approximation for any objects that are small compared with their separation.
𝐹𝐹 = 𝐹𝐹1 = 𝐹𝐹2 = 𝐺𝐺𝑚𝑚1 𝑚𝑚2
𝑟𝑟2
Universal Law of Gravitation
• Newton's law of universal gravitation states that any two point particles attract each other with a force that is proportional to the product of their masses and inversely proportional to the square of their separation.
• G is the constant of universal gravitation.
(1686)
5Prof. Sergio B. MendesSummer 2018
Cavendish’s Experiment
G = 6.67408(31) × 10–11 N·m2/kg2
(1797–1798)
current value:
6Prof. Sergio B. MendesSummer 2018
𝐹𝐹 = 𝐺𝐺𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 𝑚𝑚𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸2
= 𝑚𝑚 𝑔𝑔
𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 =𝑔𝑔 𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸2
𝐺𝐺
𝜌𝜌𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 =3 𝑔𝑔
4 𝜋𝜋 𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 𝐺𝐺
Earth’s mass
Earth’s density
Once G is known, then:
= (5.9722 ± 0.0006) × 1024 kg
= 5.5153 g/cm3
𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 = 6.3781 × 106 m
Earth’s radius
close to Earth’s surface
7Prof. Sergio B. MendesSummer 2018
Example 8.1𝑔𝑔 =
𝐺𝐺 𝑀𝑀𝑟𝑟2
𝑟𝑟 = 𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝑔𝑔𝐸𝐸 =
𝐺𝐺𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸
𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸2
𝑟𝑟 = 𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 + ℎℎ = 380 𝑘𝑘𝑚𝑚
𝑔𝑔𝐸 =𝐺𝐺𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸
𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 + ℎ 2
𝑀𝑀 = 𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸
𝑀𝑀 = 𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸
𝑟𝑟 = 𝑅𝑅𝑀𝑀𝐸𝐸𝐸𝐸𝑀𝑀𝑀𝑀 = 𝑀𝑀𝑀𝑀𝐸𝐸𝐸𝐸𝑀𝑀 𝑔𝑔𝑀𝑀 =
𝐺𝐺 𝑀𝑀𝑀𝑀𝐸𝐸𝐸𝐸𝑀𝑀
𝑅𝑅𝑀𝑀𝐸𝐸𝐸𝐸𝑀𝑀2
𝐺𝐺 = 6.67 × 10–11 N·m2/kg2
= 9.81 𝑚𝑚/𝑠𝑠2
= 8.74 𝑚𝑚/𝑠𝑠2
= 3.75 𝑚𝑚/𝑠𝑠2
8Prof. Sergio B. MendesSummer 2018
The Dependence on the Center-to-Center Distance of
Spherical Objects
10Prof. Sergio B. MendesSummer 2018
PhET
11Prof. Sergio B. MendesSummer 2018
𝐹𝐹 = 𝐺𝐺𝑀𝑀 𝑚𝑚𝑟𝑟2
The Circular Orbit
= 𝑚𝑚𝑣𝑣2
𝑟𝑟
𝑣𝑣 =𝐺𝐺 𝑀𝑀𝑟𝑟
𝑇𝑇2 =4 𝜋𝜋2𝑟𝑟3
𝐺𝐺 𝑀𝑀
𝑣𝑣 =2 𝜋𝜋 𝑟𝑟𝑇𝑇
K3: The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit.
when the ellipse becomes a circle
12Prof. Sergio B. MendesSummer 2018
Example 8.2
𝑣𝑣 =𝐺𝐺 𝑀𝑀𝑟𝑟
=𝐺𝐺 𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸
𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 + ℎ= 7.68 𝑘𝑘𝑚𝑚/𝑠𝑠
𝑇𝑇 =4 𝜋𝜋2 𝑟𝑟3
𝐺𝐺 𝑀𝑀=
4 𝜋𝜋2 𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 + ℎ 3
𝐺𝐺 𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸= 5.52 × 103 𝑠𝑠
= 90 𝑚𝑚𝑚𝑚𝑚𝑚
ℎ = 380 𝑘𝑘𝑚𝑚
14Prof. Sergio B. MendesSummer 2018
Example: Period of the Moon
𝑇𝑇 =4 𝜋𝜋2 𝑟𝑟3
𝐺𝐺 𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸
𝑟𝑟 = 384,402 km
= 27.3 days
16Prof. Sergio B. MendesSummer 2018
Example 8.3
𝑟𝑟 =𝐺𝐺 𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 𝑇𝑇2
4 𝜋𝜋2
1/3
𝑇𝑇2 =4 𝜋𝜋2𝑟𝑟3
𝐺𝐺 𝑀𝑀
= 4.22 × 107 𝑚𝑚
= 42.2 × 103 𝑘𝑘𝑚𝑚
ℎ = 𝑟𝑟 − 𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 = 36.0 × 103 𝑘𝑘𝑚𝑚
𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 = 6.4 × 103 km
Geostationary Orbit: 𝑇𝑇 = 24 ℎ
Geostationary Operational Environmental Satellite
17Prof. Sergio B. MendesSummer 2018
Gravitational Potential Energy
𝑊𝑊𝑔𝑔𝐸𝐸𝐸𝐸𝑔𝑔 = �𝐸𝐸1
𝐸𝐸2𝑭𝑭𝑔𝑔𝐸𝐸𝐸𝐸𝑔𝑔 𝒓𝒓 .𝑑𝑑𝒓𝒓 = − 𝑈𝑈𝐸𝐸2 − 𝑈𝑈𝐸𝐸1
𝐹𝐹𝑔𝑔𝐸𝐸𝐸𝐸𝑔𝑔 = 𝐺𝐺𝑀𝑀 𝑚𝑚𝑟𝑟2
𝑈𝑈𝐸𝐸2 − 𝑈𝑈𝐸𝐸1 = − 𝐺𝐺𝑀𝑀𝑚𝑚1𝑟𝑟2−
1𝑟𝑟1
𝑭𝑭𝑔𝑔𝐸𝐸𝐸𝐸𝑔𝑔 𝒓𝒓 .𝑑𝑑𝒓𝒓 = −𝐹𝐹𝑔𝑔𝐸𝐸𝐸𝐸𝑔𝑔 𝑑𝑑𝑟𝑟
19Prof. Sergio B. MendesSummer 2018
Example 8.4
−𝑊𝑊𝑔𝑔𝐸𝐸𝐸𝐸𝑔𝑔 = 𝑈𝑈𝐸𝐸2 − 𝑈𝑈𝐸𝐸1
𝑟𝑟1 = 𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 = 6.4 × 103 km 𝑟𝑟2 = 𝑟𝑟𝑔𝑔𝑔𝑔𝑔𝑔𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸 = 42.2 × 103 𝑘𝑘𝑚𝑚
𝑊𝑊𝑔𝑔𝑒𝑒𝐸𝐸 = −𝑊𝑊𝑔𝑔𝐸𝐸𝐸𝐸𝑔𝑔 = 𝑈𝑈𝐸𝐸3 − 𝑈𝑈𝐸𝐸2 = − 𝐺𝐺 𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 𝑚𝑚1𝑟𝑟3−
1𝑟𝑟2
𝑟𝑟2 = 𝑟𝑟𝑔𝑔𝑔𝑔𝑔𝑔𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸 = 42.2 × 103 𝑘𝑘𝑚𝑚 𝑟𝑟3 = 𝑟𝑟𝑚𝑚𝑔𝑔𝑔𝑔𝑚𝑚 = 384.4 × 103 𝑘𝑘𝑚𝑚
𝑚𝑚 = 11 × 103 𝑘𝑘𝑔𝑔
= 5.842 × 1011 𝐽𝐽
= 0.925 × 1011 𝐽𝐽
𝑊𝑊𝑔𝑔𝑒𝑒𝐸𝐸 = = − 𝐺𝐺 𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸 𝑚𝑚1𝑟𝑟2−
1𝑟𝑟1
20Prof. Sergio B. MendesSummer 2018
𝑟𝑟1 = ∞
𝑈𝑈𝐸𝐸1 = 0
𝑈𝑈𝐸𝐸 = −𝐺𝐺𝑀𝑀 𝑚𝑚𝑟𝑟
𝑈𝑈𝐸𝐸2 − 𝑈𝑈𝐸𝐸1 = − 𝐺𝐺𝑀𝑀𝑚𝑚1𝑟𝑟2−
1𝑟𝑟1
𝑈𝑈𝐸𝐸1 = −𝐺𝐺𝑀𝑀 𝑚𝑚𝑟𝑟1
A Simplifying and Meaningful Reference Point
𝑟𝑟2 → 𝑟𝑟
21Prof. Sergio B. MendesSummer 2018
Mechanical Energy (Kinetic + Potential Energies)
𝐸𝐸 = 𝐾𝐾 + 𝑈𝑈 =12𝑚𝑚 𝑣𝑣2 −
𝐺𝐺𝑀𝑀 𝑚𝑚𝑟𝑟
22Prof. Sergio B. MendesSummer 2018
Example 8.5𝑣𝑣𝑔𝑔 = 3.1 𝑘𝑘𝑚𝑚/𝑠𝑠
ℎ = ? ? 𝑟𝑟 = ℎ + 𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸
𝐸𝐸 = 𝐾𝐾 + 𝑈𝑈 =12𝑚𝑚 𝑣𝑣2 −
𝐺𝐺𝑀𝑀 𝑚𝑚𝑟𝑟
12𝑚𝑚 𝑣𝑣𝑔𝑔2 −
𝐺𝐺𝑀𝑀 𝑚𝑚𝑟𝑟𝑔𝑔
=12𝑚𝑚 𝑣𝑣2 −
𝐺𝐺𝑀𝑀 𝑚𝑚𝑟𝑟
𝑟𝑟𝑔𝑔 = 𝑅𝑅𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸
𝑣𝑣 = 01𝑟𝑟
=1𝑟𝑟𝑔𝑔−
𝑣𝑣𝑔𝑔2
2 𝐺𝐺 𝑀𝑀
𝑀𝑀 = 𝑀𝑀𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸𝐸
𝑚𝑚: unknown
24Prof. Sergio B. MendesSummer 2018
Escape Velocity
𝐸𝐸 = 𝐾𝐾 + 𝑈𝑈 =12𝑚𝑚 𝑣𝑣2 −
𝐺𝐺𝑀𝑀 𝑚𝑚𝑟𝑟
≥ 0
𝑣𝑣 ≥2 𝐺𝐺 𝑀𝑀𝑟𝑟
𝐸𝐸 ≥ 0