Mohammad Tanvir Shahriar ID. 16024

Tashmeem Farhana Iftekhar ID. 16061

Tahniyat sultana Prova ID. 16017

Tanvir Ahmed ID. 16009

Md.Farhadul Islam ID. 16066

Dhaka Bank Limited is a private-owned commercial bank in Bangladesh.

It has Authorized Capital of Tk. 1,000 million and Paid-up Capital of Tk. 100 million.

It has 54 Branches, 4 SME Service Centers, 5 CMS Units & 2 offshore Banking Units

It offers the full range of real-time online banking services through its all Branches, ATMs and Internet Banking Channels.

We used

Dependent Variable

Total Asset

Independent Variable

Deposit

Investment

Fixed Asset

Mean Std.Deviation Variance

Total Asset 68816.40 16733.06 2.80000000

Investment 55186.40 10262.46 105300000

Fixed Asset 7138.40 1456.61 2121716.30

Deposit 459.20 300.63 90380.20

MULTIPLE REGRATION EQUATION

Formula of Multiple Regression Equation:

Formula of Multiple Regression Equation:

Ŷ=a+b₁x₁+b₂x₂+b₃x₃

Here,a= constantX₁=DepositX₂=InvestmentX₃=Fixed asset

Ŷ=a+b₁x₁+b₂x₂+b₃x₃

Here,a= constantX₁=DepositX₂=InvestmentX₃=Fixed asset

Ŷ= -14357.25+1.28x1+1.29x2+6.82x3Total Asset= -

14357.25+1.28Deposit+1.29Investment+6.82Fixed Asset

Ŷ= -14357.25+1.28x1+1.29x2+6.82x3Total Asset= -

14357.25+1.28Deposit+1.29Investment+6.82Fixed Asset

Predictor Coef SE coef T

Constant -14257.245 3135.83 4.578

Deposit 1.284 .176 7.282

Investment 1.286 .909 1.415

Fixed Assets 6.817 2.652 2.570

It is symbolized by a capital R squared.

It can range from 0 to 1 It cannot assume negative values. It is easy to interpret

R² = = 1

R²adj = 1- ÷ = .99

Here R² is 1and Adjusted R² is .99, which is less than R²

R² is 1 so it means association between dependent and independent variables are strong

Only 1% of the variation if the estimation can not be explained through the adjustment of degrees of freedom

Global Test: ANOVA

• We can test the ability of the independent variables x1 ,x2, x3…xk to explain the behavior of the dependent variable Y.

• Basically, it investigates whether it is a possible all the independent variables have zero regression equation.

ANOVA TestStep 1 : State the null and alternate hypothesis:

The null hypothesis is:The independent variables have less significant effect on dependent variableHo: β1=β2=β3=0

 The alternative hypothesis is:

The independent variables have significant effect on dependent variable.H1: β1 ≠ β2 ≠ β3≠ 0

Continued…Continued…

Step 2: Select the level of significance:We will use .05 significance level

Step 3: Determine the test statistics:The test statistics follows the F distribution

F=

Step 2: Select the level of significance:We will use .05 significance level

Step 3: Determine the test statistics:The test statistics follows the F distribution

F=

Step 4: Formulate the decision rule:

The decision rule is reject Ho >216The critical value of F is found in Appendix B.4.It is 216.The degrees of freedom for numerator is 3;The degrees of freedom for denominator is 1, found by

n-(k+1); 5-(3+1).

Step 5: Perform calculations and make a decision: The value of F is :

F=

=

=968.70

Particulars Calculated Value

Null Hypothesis

Comment

F test 968.70 > 216 Rejected Independent variables have significant effect on dependent variable

ANOVAb

Model Sum of Squares df Mean Square F Sig.

1 Regression1.120E9 3 3.732E8 968.699 .024a

Residual385257.551 1 385257.551

Total1.120E9 4

Total AssetDepositInvestmentFixed Asset

Independent Variables

year Total asset Deposit Investment Fixed asset

2006 47594.00 41554.00 5378.00 217.00

2007 57443.00 48731.00 5972.00 291.00

2008 71137.00 56986.00 7239.00 387.00

2009 77767.00 60918.00 8660.00 424.00

2010 90141.00 67743.00 8443.00 977.00

Model Unstandardized coefficients

Standardized

coefficients

t sig

B Std.Error

Beta

(Constant)

Deposit

Investment

Fixed asset

-14357.2

45

1.284

1.286

6.817

3135.832

.176

.909

2.652

.788

.112

.122

-4.578

7.282

1.415

2.570

.137

.087

.392

.236

The null hypothesis for three independent variables is:

Ho: β1=0; β2=0; β3 =0The alternative hypothesis is:

H1: β1 ≠0; β2 ≠0; β3≠0

We will use .05 level of significance

The decision rule is reject Ho >12.706

The value of t is found from the following equation:

ti=bi - 0/sbi

Critical Value is:t=12.706

Calculated values are:t1(Deposit)=7.20>12.706=Null hypothesis acceptedt2(Investment)=1.40<12.706=Null hypothesis accepted

t3(Fixed asset)=2.57>12.706=Null hypothesis accepted

Variables Calculated value

Null hypothesis

Conclusion

Deposit 7.20>2.120 Accepted Less Significant

effect on Total deposit

Investment 1.40<2.120 Accepted Less Significant

effect on Total deposit

Fixed asset 2.57>2.120 Accepted Less Significant

effect on Total deposit