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Harvard Physics Circle · 2020. 10. 4. · Sabina Dragoi Harvard Physics Circle §3Harder problems...

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Harvard Physics Circle Momentum Sabina Dragoi §1 Theory (Momentum conservation law/generalized Newton’s 2nd law.) For the net momentum p = i m i v i of a system of point masses m i upon which a total exterior force F acts, we have: d p dt = F This implies that the net momentum is conserved if F . Center of mass For a system of point masses m i , each at coordinate r i , we have that the coordinate of the center of mass is: r c = i m i r i i m i Corollaries: If external forces cancel out on some direction i, then the center of mass will be stationary on the coordinate i. For a non-homogeneous body of density ρ(x, y, z ), we have the integral form that defines its center of mass: r c = r i dm dm Newton’s third law If two bodies have interacted, then the changes of momenta of the two bodies are equal and opposite. §2 Warm-up problems §2.1 F=ma, 2018 1
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Page 1: Harvard Physics Circle · 2020. 10. 4. · Sabina Dragoi Harvard Physics Circle §3Harder problems §3.1Estonian-Finnish Olympiad, 2012 §3.2Estonian-Finnish Olympiad, 2012 ...

Harvard Physics CircleMomentum

Sabina Dragoi

§1 Theory(Momentum conservation law/generalized Newton’s 2nd law.) For the netmomentum ~p = ∑

imi~vi of a system of point masses mi upon which a total exterior force~F acts, we have:

d~p

dt= ~F

This implies that the net momentum is conserved if ~F .

Center of mass For a system of point masses mi, each at coordinate ~ri, we have thatthe coordinate of the center of mass is:

~rc =∑

imi~ri∑imi

Corollaries:• If external forces cancel out on some direction i, then the center of mass will be

stationary on the coordinate i.

• For a non-homogeneous body of density ρ(x, y, z), we have the integral form thatdefines its center of mass:

~rc =∫~ridm∫dm

• Newton’s third law If two bodies have interacted, then the changes of momentaof the two bodies are equal and opposite.

§2 Warm-up problems§2.1 F=ma, 2018

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Sabina Dragoi () Harvard Physics Circle

§2.2 F=ma, 2015

§2.3 F=ma, 2017

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Sabina Dragoi () Harvard Physics Circle

§2.4 F=ma, 2016

§2.5 F=ma, 2019

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Page 4: Harvard Physics Circle · 2020. 10. 4. · Sabina Dragoi Harvard Physics Circle §3Harder problems §3.1Estonian-Finnish Olympiad, 2012 §3.2Estonian-Finnish Olympiad, 2012 ...

Sabina Dragoi () Harvard Physics Circle

§3 Harder problems§3.1 Estonian-Finnish Olympiad, 2012

§3.2 Estonian-Finnish Olympiad, 2012Three little cylinders are connected with weightless rods, where there is a hinge near themiddle cylinder, so that the angle between the rods can change freely. Initially this angleis a right angle. Two of the cylinders have mass m, another one at the side has the mass4m. Find the acceleration of the heavier cylinder immediately after the motion begins.Ignore friction.

§3.3 Estonian-Finnish Olympiad, 2014

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Page 5: Harvard Physics Circle · 2020. 10. 4. · Sabina Dragoi Harvard Physics Circle §3Harder problems §3.1Estonian-Finnish Olympiad, 2012 §3.2Estonian-Finnish Olympiad, 2012 ...

Sabina Dragoi () Harvard Physics Circle

§4 Homework/Additional problemsMost problems that involve momentum also involve its angular equivalent, the angularmomentum which we will discuss in some future meeting. I would suggest trying todo the problems regarding momentum in Morin’s book (Morin, David J. Problems andSolutions in Introductory Mechanics) and also check out Kalda’s book (first referencebelow).

§5 References1. https://www.ioc.ee/ kalda/ipho/meh_ENG2.pdf

2. https://www.aapt.org/physicsteam/2020/pastexams.cfm

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