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Latyra Thomas Inss 300 WB2 Grdae 23.5/35=24/35 Acces s Relationship shows 1 to Many; justification why it is 1:many?; grade=-.5 Course Primary Key is Course id Function Key is Price; there is no foreign key in this table since it is not referencing any table where price is Pk; grade=-1
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Page 1: home.ubalt.eduhome.ubalt.edu/ntsbagga/web/300_sp_2012/assignment 2... · Web viewLatyra Thomas Inss 300 WB2 Grdae 23.5/35=24/35 Acces s Relationship shows 1 to Many; justification

Latyra Thomas

Inss 300 WB2

Grdae 23.5/35=24/35

Acces s Relationship shows 1 to Many;

justification why it is 1:many?; grade=-.5

Course

Primary Key is Course id

Function Key is Price;

there is no foreign key in this table since it is not referencing any table where price is Pk;

grade=-1

Trainee

Page 2: home.ubalt.eduhome.ubalt.edu/ntsbagga/web/300_sp_2012/assignment 2... · Web viewLatyra Thomas Inss 300 WB2 Grdae 23.5/35=24/35 Acces s Relationship shows 1 to Many; justification

PK is Trainee Id and Course_id , however your ACCESS table does not show that, you have a new field ID as PK

FK is Trainee Name

FK is course_ID, there is NO Trainee_ID in COURSE table; grade=-1.5

Q1, 5 ok

Q6 need a count; grade=-1

Q 7 need a count, need to group by name and then count; grade=-1

Q8 no need to take sum of course_ID and there can not be any constraint realted to Shirley dent on course-ID only trainee name; Grade=-1.5

Q 9, need to group by to avoid duplication; grade=-1

Q10 not attempted; grade=-4

Courses

Trainee

Page 3: home.ubalt.eduhome.ubalt.edu/ntsbagga/web/300_sp_2012/assignment 2... · Web viewLatyra Thomas Inss 300 WB2 Grdae 23.5/35=24/35 Acces s Relationship shows 1 to Many; justification

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