Honors Chemistry

2011 – 2012

Summer Assignments

May 25, 2011

Dear ’11 -‘12 Honors Chemistry Students, I have put together the enclosed summer syllabus and materials to accomplish an introduction to Honors Chemistry. It is comprised of six reading and problem solving sets covering the first two chapters of the course text. I estimate that a thoughtful effort would require about 10 hours. These assignments serve the purpose of introducing preliminary topics that will allow us more time to cover the College Board’s SAT II Chemistry examination syllabus. However, please understand that our short school year makes covering the entire SAT II curriculum untenable. Therefore, students interested in taking the Chemistry SAT II should purchase a commercial test-prep book (e.g. Princeton Review, Barron’s, etc.) and develop a plan to bridge the gap in a gradual and disciplined manner. These summer assignments are required. The deadline for mailing me your completed work is August 20. You may send it by regular mail or e-mail scanned copies. Please keep the two text chapters – do not send them. These introductory topics represent important foundational material. If you learn them well (particularly the Chapter 2 material) you will likely fair much better on early assessments. I thank you in advance for your efforts in this regard.

Best wishes, Mr. Kemer

P.S. pdf versions of all the materials will be available in our FirstClass conference and the Library Website. Please let me know if you are not subscribed to this conference by mid-June

Honors Chemistry 2011-2012

Summer Syllabus Chapter 1. Introduction

Assign. Reading Exercises

1. Chapter 1 1: 1 through 9

Chapter 2. Atoms, Molecules, and Ions 2 Sec. 2.1 2: 1 through 8 3. Sec. 2.2, 2.3 2: 9 through 15 4. Sec. 2.4 2: 16, 17, 18, 19, 20, 21, 24, 27, 28, 33, 34 5. Sec. 2.5- 2.7 2: 36, 39, 40, 41, 43, 44, 47, 49, 50, 51 6. Sec. 2.8 2: 61 through 70

1-1

Chapter 1. Introduction to Chemistry 1.1. The Study of Chemistry

Chemistry's primary goals are to describe the macroscopic properties and transformations of matter and then explain these in terms of submicroscopic models based on the interactions between atoms. Chemists have discovered that the incredible variety of matter in the physical world arises from only 92 naturally occurring elements whose smallest unit is an atom (see periodic table provided). Different atoms link in innumerable ways to form molecules, the smallest unit of compounds. Millions of different molecules, and therefore unique compounds can be formed from the 92 atoms. Molecules may be represented using colored spheres to represent each element. Several molecules of are shown in Figure 1.1. In these examples the red spheres represent oxygen atoms, the black spheres carbon atoms and the white spheres hydrogen atoms.

First, note that the element oxygen exists as a diatomic molecule and is represented symbolically as

€

O2 . There are several elements that exist naturally as diatomic atoms. These include hydrogen (

€

H2), nitrogen (

€

N2 ), fluorine (

€

F2), chlorine (

€

Cl2), bromine (

€

Br2), and Iodine (

€

I2). Second, note that ethanol molecules contain two atoms of carbon (black), six atoms of hydrogen (white), and one atom of oxygen (red). Ethanol is the type of alcohol found in beverages such as beer and wine. Note that the addition of just one oxygen atom to an ethanol molecule converts it to ethylene glycol, which is the thick toxic liquid used in automobile antifreeze. The important lesson to learn here is that minor and subtle changes in the composition and atomic arrangements of atoms in molecules can cause profound changes in macroscopic properties.

Molecules are not the only basic unit of elements and compounds. Most metal elements exist as simple atoms aligned in a 3-dimensional ordered lattice as shown in the figure below. Most compounds formed from the chemical combinations of metals and nonmetals, such as sodium chloride (common salt) exist in a 3-dimensional ordered lattice of alternating metal and nonmetal atoms. We will have much more to say about these different types of structures later in the course.

Metal atoms packed in acrystal lattice

Sodium atoms (purple) and chlorine atoms (s)

packed in a crystal lattice

1-2

1.2 Classifications of Matter

Perhaps the most straightforward way to begin our study of chemistry is to establish a way of classifying matter according to its properties. In general, classification schemes serve to organize objects and processes in terms of their similarities and differences. Classification schemes allow us to discern patterns of behavior that may point to underlying principles or laws. Biologists use this approach in the study of living creatures which are classified in terms kingdom, phylum, class, order, family, genus, and species. The simplest way of classifying matter is according to its physical state, or phase. The Physical States of Matter

Matter generally exists in one of three states (or phases) depending on the temperature and external pressure. These are the familiar sold, liquid, and gas phases. The physical behaviors associated with each phase are listed below along with the simple kinetic-molecular model scientists use to explain them. The figure at the bottom of the page illustrates some features of the model.

Solid

Macroscopic Properties: Definite shape (rigid, resists deformation), definite volume (little compressibility or thermal expansion)

Submicroscopic Theory: Atoms/molecules are closely and tightly bound in an ordered lattice. They vibrate about fixed position.

freeze ↑↓ melt

Liquid

Macroscopic Properties: Indefinite shape (flows under its own weight or shear stresses), definite volume (little compressibility or thermal expansion)

Submicroscopic Theory: Atoms/molecules are close together but not so tightly bound; they can slide and jiggle past each other.

condense ↑↓ vaporize

Gas

Macroscopic Properties: Indefinite shape (fills all available volume), indefinite volume (highly compressible), expands by significant fractions with temperature

Submicroscopic Theory: Atoms/molecules are not bound to each other; they fly about randomly and independently.

The figures above are limited in the sense that they are they are static and two-dimensional. You will have to imagine the random motions and 3rd dimension” showing (1) molecules in the solid phase vibrating, (2) molecules in the liquid phase jiggling, rotating, and sliding past each other, and (3) molecules in the gas phase rotating, vibrating and translating at high speeds through the empty space between them (and colliding when they run into each other).

1-3

Most compounds can exist in each of the three states if brought to the right conditions of temperature and pressure. A common example of a single compound that exhibits all three of its phases at temperatures that humans exist in is water.

At 1 atm of pressure: Water: solid ice

€

melt→

0  C

freeze←

liquid water

€

boil→

100  C

condense←

gaseous steam

Note that it is possible for a solid to transform directly into gas and vise-versa. These processes are called sublimation and deposition respectively. Classifying Matter by Analysis. Throughout human history people have interacted with their material world, driven both by the requirements of survival and by their curiosity. Simple observations revealed that many natural substances were combinations of simpler materials. These simpler materials seemed to be “pure” in the sense that they were uniform in all of their properties (such as color, density, hardness, etc.) and seemed to be impervious to further separation. This experience suggested the concept of elements, the most basic or fundamental components of matter. A major goal of early chemists was to identify the elements. This involved dogged efforts to utilize fire and other materials (such as acids) to separate naturally occurring materials into their fundamental components. The separation and identification of the components of materials is called chemical analysis. Over time, the early chemists became quite sophisticated in their analytical methods. Among the greatest accomplishments was the discovery that many materials could be broken down by the aggressive application of heat or electricity. Substances that were successfully broken down by these techniques were called compounds. Substances that could not be broken down further were taken as elements. These early chemists found that when elements combined to form compounds they did so in definite mass proportions (or ratios). For example, common salt (NaCl), always contains 39.3% sodium and 60.7% chlorine. Water contains 12.5% hydrogen and 87.5% oxygen. By the 19th century, the long road of analysis led chemists to an established classification scheme that went beyond the simple physical state (solid, liquid, or gas). This scheme was simple and practical. It was based on characteristic properties and separation methods that took advantage of differences in characterisitc properties. Before outlining the classification scheme, we must clearly define what is meant by characteristic properties and then discuss some separation methods based on them. • Characteristic properties are those that can be used to distinguish one material from another. There are

two categories of characteristic properties

1. Physical properties can be observed or measured without altering the material's composition by chemical reaction.

color luster specific heat density ductility viscosity solubility boiling point odor magnetism hardness melting point electrical conductivity thermal conductivity

1-4

2. Chemical properties are those that relate how a material changes in composition upon interacting with another material. In other words, they relate to chemical reactions and lead to dramatic changes in physical properties

Reacts with oxygen Reacts with acids Decomposes upon heating Decomposes with electricity

The chief indicators of a chemical change are changes in color, the generation of significant amounts of thermal energy, and/or the generation of a gas.

In addition to characteristic properties are state properties. State properties cannot be used to distinguish one type of material from another because any substance may share them. State properties include

temperature pressure mass volume concentration

A secondary descriptor used for properties is extensive or intensive. Extensive properties are those for which it makes sense to add or accumulate. Mass and volume are the most common examples. Intensive properties are those that can vary from point to point within a sample of matter. Examples of intensive properties include temperature, pressure, and all characteristic properties. Note that some intensive properties are defined by dividing one extensive property by another. Density is an example of this. Separation Methods can be classified as either physical or chemical separation.

1. Physical separation methods exploit differences in the physical properties of materials to achieve the separation.

Physical separation method Physical property(s) difference utilized Picking apart Color, size

Selective floatation/sedimentation Density relative to a liquid Distillation (selective vaporization) Boiling point

Magnetic separation Attraction to a magnet Filtering Size, solubility

Chromatography Solubility

2. Chemical separation methods involve chemical decomposition reactions

Chemical Separation Method Chemical Property Utilized

Electrolysis Decomposes with electricity Thermal Decomposition Thermal stability Selective precipitation Reacts to form an insoluble species

So, we can imagine a program of research undertaken by the early chemists to uncover the simplest forms of matter. Armed with the concepts of physical and chemical properties, and a wide assortment of separation methods based on these, they “attacked” samples of naturally occurring material, which in most occasions was obviously not fundamental (e.g. dirt has many different colored components in it) but became more challenging the further along they got. Ultimately they arrived at the following classification scheme

I. Substances are defined as material samples that are uniform in all their characteristic properties (below the microscopic level) and cannot be separated into two or more simpler forms by physical separation methods.

1-5

Substances are further classified according to whether they may still be separated by chemical means.

1. Elements are substances that cannot be broken down into simpler substances chemical means.

Elements are the simplest substances from which all matter is composed.

Note: The modern explanation of elements is that each element is made up of one type of atom. Elements cannot be broken down by chemical means because the atom is the basic chemical building block.

2. Compounds are substances that can be separated into two or more elements by chemical means and have fixed elemental compositions.

Note: The modern explanation for compounds is that a compound is made up of two or more types of atoms strongly bonded together in fixed number ratios. The interatomic bonds are too strong to be broken by physical means but can be broken by the more forceful chemical reactions into more basic elements.

The molecular basis of compounds explains the Law of Definite Mass Proportions, which states that a particular compound always has a definite mass ratio of elements. The definite mass ratio arises from the definite number ratio of atoms that make up its molecules. For example water is a compound made from the elements hydrogen and oxygen. The properties of water are distinctly different from either hydrogen or oxygen. The chemical composition of water is 11.11% hydrogen and 88.89 % oxygen by mass. Modern theory explains this fixed mass ratio by stating that (i) water is made up of molecules comprised of a single atom of oxygen bonded to two atoms of hydrogen, and (ii) oxygen atoms are 16 times heavier than hydrogen atoms (oxygen atoms weigh 16 atomic mass units on a scale that defines the mass of hydrogen to be 1 atomic mass unit) . Example: Carbon dioxide is a compound of carbon and oxygen. It when decomposed it is found to be 27.29% carbon and 71.71% oxygen by mass. If a molecule of carbon dioxide is made up on 1 atom of carbon and 2 atoms of oxygen (CO2) and if carbon atom weighs 12 atomic mass units, what is the mass of an oxygen atom? Answer: We can set up a ratio to solve this problem with

€

MO and

€

MC representing the atomic masses of oxygen and carbon and

€

NO and

€

NC representing the number of oxygen and carbon atoms per molecule

€

mass % Omass % C

=NO ⋅MONC ⋅MC

⇒ 71.2927.29

=2 ⋅MO1 ⋅12

⇒ MO = 16

II. Mixtures are combinations of two or more substances that can be separated by physical means.

They can also exist in a range of mass proportions and, and retain the properties of each component substance.

1. Homogeneous mixtures (or solutions) are mixtures that appear completely uniform in their

properties and composition (below the microscopic level). In this regard, solutions look like pure substances. The difference is that solutions can be separated by physical means while substances cannot. Solutions can also exist in a wide range of component proportions while compounds are made of elements in fixed or definite proportions.

2. Heterogeneous mixtures are mixtures whose characteristic properties and composition vary from point to point. These can be identified by the variations in color, texture, or any other physical property within the material, even if the variations occur on a microscopic scale. For instance, a mixture of fine white powdered sugar and fine white powdered salt is heterogeneous even though it may appear uniform in color and texture.

1-6

Most materials encountered in nature are heterogeneous mixtures because it is impossible to completely remove all impurities from any sample of matter. The purest manufactured material is silicon used in electronic chips. It is 99.9999% pure. However, still represents billions of billions of impurity atoms per cubic centimeter. In a more common example, “clear” saltwater will invariably have microscopic dust particles in it. The ideas of a pure substances and homogeneous solutions is an idealization.

Example: A material sample appears to the naked eye as a gray powder. When it is stirred into water and filtered through a fine mesh paper into a beaker about half of the original solid sample is trapped by the filter and appears black. The remainder of the sample is recovered by letting the water evaporate from the beaker. It appears white. Classify the original sample.

Answer: The original sample was a heterogeneous mixture. It was a mixture because it was separated by physical means (filtration). It was heterogeneous because black and white powders were not mixed on a molecular scale. The black particles were larger than the holes in the filter.

The recovered white powder is placed inside an evacuated chamber and heated. When the temperature reaches 700˚C the powder began to give off a green gas and turned an orange. Classify this component?

Answer: This component was most likely a compound since there is good evidence of chemical decomposition. The fact that it was heated in a vacuum is important to this conclusion. If the reaction occurred in air we could not be sure that the chemical change was a chemical decomposition. The powder might have been an element reacting with a component of the air.

The definitions for substances and mixtures are examples of operational definitions. This is because they are based on definite practical operations (procedures). These are outlined schematically represented in the flowchart on the next page that could serve chemists as a “roadmap” for analysis.

Can it be separatedby physical means?

compound elementhomogeneous

mixtureheterogeneous

mixture

Sample material

yes no

Mixture Substance

In it uniform throughout (down to the molecular scale)?

yes noyes no

Can it be separatedby chemical means?

Flowchart for the classification of matter incorporating the operational definitions of homogeneous and heterogeneous mixtures and compound and elemental substances.

The alternative to an operational definition, at least in chemistry, is a theoretical definition. Theoretical definitions are based on concepts that are based on analogies or models rather than direct or measurable procedures. For example, the theoretical definition of an element is a sample of matter made up of one type of atom.

1-7

Our theoretical understanding of the difference between substances (elements and compounds) and mixtures of substances is based on the notion of chemical bonding. Elements are pure substances that cannot be separated into simpler components because they are made up of a single type of atom that cannot be broken apart further1. Compounds are pure substances because they are made up of molecular units, specific groupings of atoms that are held together by strong forces (chemical bonds) that cannot be disrupted the relatively gentle forces associated with physical separation methods, but can be separated by the more aggressive forces associated with chemical separation methods. To separate the chemically bonded atoms or molecules takes considerable energy. On the other hand, mixtures are simply separate substances that lie side-by-side and are not bonded together by particularly strong forces. Each component substance making up a mixture retains its own identity and can be separated from the other components without much energy expenditure. This is why they can also have a range of compositions. Physical separation methods do not involve as much energy.

1 Atoms can be broken apart in nuclear reactions in which their nuclei break apart (radioactive decay or nuclear fission). But we generally do not consider nuclear reactions in chemistry.

Honors Chemistry- Summer Assignment 1 Refer to Chapter 1 Reading 1.1. Estimate the temperature reading from the dial-type thermometer shown below. Express your estimate with a reasonable “± absolute error” range. Be as precise as can be reasonably justified (this can be better than ±5˚C)

1.2. What macroscopic physical characteristics do solids and liquids share? Explain these similarities in terms of the molecular model. 1.3. What are the differences between the macroscopic physical characteristics of liquids and gases. Explain these differences in terms of the molecular model. 1.4. Consider a solution of sugar and water. (a) Why is this combination defined as a mixture? (b) Why is this combination defined as a homogeneous mixture? (c) Describe how one might separate the sugar from the water. (d) What physical property does your method in part (c) exploit? 1.5. A yellow granular material turns black and emits a colorless gas when heated in air. Eventually it disappears. Why would it be wrong to conclude from this process that the original material is a compound that had decomposed? 1.6. Answer the following True/False questions. (a) A state property can be used to distinguish one substance from another. (b) An intensive property of a sample substance is proportional to the mass of the sample. (c) The components of a mixture must differ in at least one physical property in order to separate them. 1.7. Which of the following measurements is the most appropriate one to report for the temperature indicated in the thermometer illustrated in the figure below? Remember that it is possible to interpolate between scale marks to the nearest one tength of the scale unit.

(a) 7 ˚C (b) 7.2 ˚C (c) 7.24 ˚C

8

7

6

Figure for Problem 1.7. 1.8. A student partially fills a graduated cylinder of an unknown liquid to a volume of 2.32±0.02 ml. She then places the cylinder on an electronic balance and determines its mass (glass cylinder plus the liquid it contains) to be 73.41±0.01 grams. Next, she adds more of the same liquid to a volume of 6.73±0.02 mL and then determines the new combined mass to be 77.89±0.01 grams. (a) Show that the density of the liquid is best reported as 1.02 ± 0.02 g/mL (or 1.016 ± 0.014 g/mL) (c) If the student failed to notice that a bubble of air was trapped under the liquid surface during the second addition of liquid, how would her measured density be in error? Would her value be too great or too small? 1.9. A 32.65-g sample of a solid is placed in a flask. Liquid toluene, in which the solid is insoluble, is added to the flask so that the total volume of solid and liquid together is 50.00 ml. The solid and toluene together weigh 58.58 g. The density of toluene at the temperature of the experiment is 0.864 g/ml. Calculate the density of the solid. Since absolute errors are not given, report your result with the appropriate number of significant figures (in this case there will be 4 significant figures in the final calculation).

2-1

Chapter 2. Atoms, Molecules, and Ions

2.1 The Atomic Theory of Matter: The Early History

As stated in Chapter 1, chemistry's primary goal is to explain the macroscopic behavior of matter in terms of the atomic scale structures and interactions. This chapter provides brief historical sketch of the major steps that led our modern atomic theory that accomplishes this goal.

Ancient Theories

The ancient Greek philosopher Leucippus and his pupil Democritus (470-380 BC.) were the first to speculate that matter is made of indivisible particles called atomos (a = "not" + tomos = "to cut"). Their theory was not widely accepted in their time. Most Greek philosophers, including Aristotle (384-322 BC.), believed that matter was infinitely divisible (i.e., continuous). Aristotle further speculated that all material derived their properties from the various proportions of just four elements: earth, air, fire, and water. Their view prevailed for 2000 years.

While the Greeks can be given credit for trying to provide rational explanations for the physical world, they never adopted the modern scientific approach of using experiments to "test" scientific models or theories. Their ideas did not amount to scientific theories in the modern sense. Rather, they were mere speculations aimed at fitting observations to preconceived notions about how the world should be.

From pre-historic times curiosity and practical needs have led enterprising and curious humans to manipulate their material environment, beginning with bone and stone tools, fire, and native metals. The Medieval alchemists (500 AD-1500 AD) combined such practical interests with mystical strivings to search for a "philosopher's stone," a substance that could transform base metals (copper, iron, zinc, etc.) into gold. Alchemical "theories" of transmutation seem strange by today's standards. Ultimately, none of their ideas could be supported by experiment. Although the Alchemists' primary goal was never Alchemists doing strange experiments. achieved, their work resulted in many practical techniques and knowledge that supported the development of modern chemistry later on.

The Dawn of the Modern Atomic Theory

In 1661, Robert Boyle defined an element as a substance that cannot be broken down into simpler substances by chemical operations (e.g., heating). This represented the modern and eminently practical idea of an operational definition. It was based on practical procedures and facts and not on preconceived notions or mystical beliefs about the ultimate nature of matter.

In 1789, Antoine Lavoisier published the first chemistry textbook that listed 33 elements. While a few of these elements were later found to be compounds, the notion of fundamental substances with unique and definite properties was firmly established.

Portrait of Antoine Laurent and Marie- Anne Lavoisier, his wife and collaborator

2-2

Lavoisier’s experiments utilized very sensitive balances to measure and compare the mass of reactants and products in chemical reactions suggested the idea that matter is neither created nor destroyed. That is, he promoted the Law of Conservation of Mass:

Matter is neither created nor destroyed in any physical or chemical process. The total mass of the reacting substances equals the mass of the products

Lavoisier’s use of the mass balance placed chemistry on a firm quantitative footing and led to other important chemical laws. In 1799, Joseph Louis Proust discovered that copper carbonate, whether obtained from natural sources or synthesized in the labortory, always contained copper, oxygen, and carbon in the same proportions by mass, (i.e., 5.3 parts Copper to 4.0 parts Oxygen to 1.0 parts Carbon). Similar results with other substances led to the formulation of the Law of Definite Proportions:

Compounds always contain elements in certain definite proportions by mass.

Dalton's Atomic Theory In 1803, John Dalton published the first modern atomic theory to explain the unique identity of elements, what happens in a chemical reaction, the Law of Conservation of Mass, the Law of Definite Proportions, and the Law of Multiple Proportions.

Dalton's Atomic Theory consisted of five postulates. These postulates along with the explanations their provided are:

1. All elements are made up of tiny, indivisible particles called atoms.

Atoms can neither be created nor destroyed during chemical reactions.

This postulate explains the conservation of mass. Dalton imagining atoms.

2. All atoms of a given element are identical, but the atoms of one element differ from the atoms of another.

Along with the first postulate, this explains why elements cannot be broken down into simpler substances.

3. Atoms of different elements form compounds by joining in fixed, small, whole number ratios to form molecules.

This postulate explains the law of definite proportions. If compounds are made of molecules with fixed number ratios of atoms then they must also have fixed mass ratios of elements.

4. A chemical reaction involves a change not in the atoms

themselves, but in the way the atoms are combined to form compounds.

This postulate explains chemical reactions and emphasizes the fundamental nature of atoms.

Dalton proposed that the atoms of each element are distinguished by their mass. He assigned the hypothetical hydrogen atom, the lightest, a relative mass of 1. He and others developed a table of atomic weights of the other elements from experimentally measured mass proportions of compounds and guessing the number ratio of atoms in the compound (i.e., the compound’s formula) Dalton’s molecular models

2-3

Example: The mass ratio of oxygen to hydrogen in water is 8:1. The mass ratio of carbon to oxygen in carbon dioxide is 3:8. Determine the atomic masses of oxygen and carbon relative to hydrogen (which is arbitrarily assigned the value of 1 atomic mass unit) given that the formula of water is

!

H2O (2 atoms H to 1 atom O) and the formula of carbon dioxide is

!

CO2 (1 atom C to 2 atoms O).

You can probably figure out the required atomic masses in (please try!). Oxygen would have an atomic mass of 16 and carbon would then be 12. However, the following mathematical model can help you quickly and confidently calculate them is very useful for more complicated cases.

Let

!

mAmB

be the measured definite mass ratio of element A to element B in a compound of A and B.

Let

!

NANB

be the hypothetical (guessed) number ratio of A atoms to B atoms in a molecule of the

compound. Let

!

MA and

!

MB be the atomic masses of atoms of elements A and B relative to hydrogen, which is arbitrarily assigned the value 1 atomic mass unit. Then, Dalton’s Atomic Theory explains the Law of Definite through the expression

!

mAmB

=NAMANBMB

where the left side expresses the empirical measurements that go into the Law of Definition Proportions and the right side expresses the theoretical justification. Applying this expression to oxygen and hydrogen in water, assuming the atom number ratio of hydrogen to water is

!

NH NO = 2 /1 leads to

!

mOmH

=NOMONHMH

" MO =NHNO

#mOmH

#MH =21$

% & '

( ) #

81$

% & '

( ) # 1( ) = 16

And applying this formula for carbon in carbon dioxide given that

!

MO = 16 gives

!

mCmO

=NCMCNOMO

" MC =NONC

#mCmO

#MO =21$

% & '

( ) #

38$

% & '

( ) # 16( ) = 12

Although Dalton's theory successfully explained many chemical laws, it did not prove that atoms existed. Atoms were considered hypothetical particles. Strong evidence for the actual existence of atoms was not available until the early 1900's.

The Law of Multiple Proportions

Soon after proposing his atomic theory John Dalton announced the Law of Multiple Proportions and was able to employ his theory to provide a convincing explanation.

When two elements form more than one compound, the ratio of the mass ratio of first element to the second element in one compound to the mass ratio of first element to the second in the other compound is a simple whole number ratio.

Example: Nitrogen and oxygen form three compounds that show the law of multiple proportions

Compound number

Compound

name

!

mass Omass N

!

mass Omass N"

# $

%

& ' imass Omass N"

# $

%

& ' 1

1 Nitrous oxide 0.571 1 2 Nitric oxide 1.142 2 3 Nitrogen dioxide 2.284 4

2-4

The Law of Multiple Proportions and its explanation by Dalton’s atomic theory can be mathematically modeled by simply extending the simple Definite Proportions model outlined above. The expression for the Law is given on the left side and the following expression and the theory on the right side.

!

mass Amass B"

# $

%

& ' cmpd 1

mass Amass B"

# $

%

& ' cmpd 2

=

NA (MANB (MB

"

# $

%

& ' cmpd 1

NA (MANB (MA

"

# $

%

& ' cmpd 2

=

NANB

"

# $

%

& ' cmpd 1

NANB

"

# $

%

& ' cmpd 2

All of the symbols have the same meaning as before. That the ratio of mass ratios turns out (empirically) to be a ratio of simple integers (the Law of Multiple Proportions) follows directly from a model of compounds having as their smallest unit molecules that have simple integer number ratios of atoms. Example: If nitrous oxide molecules (see table above) have the formula

!

N2O (each molecule contains two atoms of nitrogen and one atom of oxygen) then what must be the formula of nitric oxide?

Applying the above expression leads to:

!

mass Omass N"

# $

%

& ' cmpd 1

mass Omass N"

# $

%

& ' cmpd 2

=

NONN

"

# $

%

& ' cmpd 1

NONN

"

# $

%

& ' cmpd 2

( 0.5711.142

=

12"

# $ %

& '

NONN

"

# $

%

& ' cmpd 2

( NONN

"

# $

%

& ' cmpd 2

= 1

Therefore, the simplest possible formula is NO. But it also may be true that the actual molecules are

!

N2O2 or

!

N2O2 , we cannot tel.

Problems with Dalton's Theory By the early 20th century experimental evidence had arisen that showed that Dalton's Theory was incomplete and only approximate. For example

1. Nonstochiometric compounds having a range of mass ratios of elements were found.

2. Not all of the atoms of a given element had precisely the same mass. These were called isotopes.

3. Atoms are not indestructible and have a subatomic structure. The discovery of the “radioactive decay” of some elements led to the development of nuclear fission and fusion.

These "chinks" in the armor of Dalton's Theory led to the development of the modern theory of the atom during the late 19th century and early 20th century. Some of the major steps of this development will be given here, with the rest taken up in Chapter 6.

Still, great progress in chemistry followed Dalton’s program. Dozens of elements were discovered by the mid 19th century and the relative atomic masses were “weighed” by relating the relative masses of elements in compounds to the hypothetical number ratio of atoms in the compound.

2.2. The Discovery of Atomic Structure

In 1879, William Crookes discovered cathode rays. These were beams of particles that were emitted from a highly charged negative metal electrodes embedded inside a partially evacuated tube. As the cathode rays passed through the gas they made it glow. When the rays struck a phosphorescent screen, they would cause it to glow also. They could not, however, pass through the glass walls of the tube.

2-5

In 1895 Wilhelm Roentgen discovered X-rays. These were later determined to be high-energy light emitted when cathode rays struck a metal target. X-rays traveled many meters through air outside the tube. Their ability to pass through flesh, but not as well bone, led to X-ray photography In 1896 Antoine Bequeral, Madame Curie, and Pierre Curie observed that uranium spontaneously emitted X-rays without cathode ray bombardment. They call it the process radioactivity. Their discovery suggested that "something" was coming out of the atom. In other words, atoms have "insides" or parts. In 1897 J. J. Thomson demonstrated that cathode rays are negatively charged particles by repelling them with a strong negative charge and by deflecting them sideways with a magnet1. He names them electrons. Thomson also measures the charge to mass ratio of the electron (q/m). Thomson concluded that electrons are subatomic particles and a common building block of all matter. The following experimental results supported this conclusion.

1. All electrons are identical no matter what metal the cathode material. 2. Since electrons have negative charge the other parts of the atom must

be positively charged. 3. The cathode does not lose mass. If cathode rays were whole atoms

the cathode would eventually show a loss of mass.

In 1904 J. J. Thomson developed his "plum pudding" model of atom. It depicted electrons imbedded like raisins in a continuous positively charged pudding-like mass. Thomson's model was more sophisticated than this sounds. He worked out the precise positions the electrons must occupy within the positive charge to be stable. In 1909 Robert Millikan determined the charge on an electron by performing a Newton’s Second law analysis of the terminal velocities of tiny charged oils drops falling between electrically charged plates2. This charge was hypothesized to be the elementary (or smallest) unit of charge (

!

1.6x10"19Coloumb). They don’t get smaller! Millikan’s determination of the electron charge allowed the mass of the electron to be calculated from Thomson’s q/m ratio. That is:

1 A negatively charged particle moving across a flat-face of the north pole of a magnet will be deflected sideways. This important effect led to the modern means of measuring atomic masses, as we shall soon see. 2 We will see precisely how this experiment works in Experiment 14. It utilizes several concepts that we learned in Honors Physics.

2-6

!

me =e

e /m=

"1.6x10"19Coloumb"1.76x108Coloumb /gram

= 9.11x10"28g

The mass of the electron was 1/1827 the mass of a hydrogen atom, which supported Thomson’s theory that the electron is a subatomic particle. In 1907 Ernest Rutherford identified three subatomic particles emitted from radioactive elements. He named them alpha, beta, and gamma particles after the first three letters of the Greek alphabet. These particles were later shown to the positive nucleus of a helium atom, electrons, and gamma light rays, respectively3. This was further evidence that atoms have parts; there exists a subatomic structure.

Particle Name Symbol Mass (amu) Charge Later Identified as alpha

!

" 4 +2 Helium nucleus beta

!

" 1/837 -1 electron gamma

!

" 0 0 High energy light

In 1911 Rutherford and Marsden performed an experiment in which they bombarded a very thin gold foil with positively charged alpha particles emitted from radioactive uranium (see Figure at top of next page). While Thomson's “plum pudding” model predicted that the particles would fly straight through without slowing down, they found that a very small percentage were deflected through very large angles. The rare deflections suggested that the vast majority of an atom's mass was concentrated in a very tiny positively charged nucleus. Most positive alpha-particles pass straight through because they miss any nucleus by wide margins. Only a few pass close enough to a nuclei to suffer a large deflection. A statistical analysis of the scattering allowed Rutherford to deduce the nuclear diameter to be about 1/10,000 the diameter of the atom! Atoms were mostly empty space. This evidence suggested a planetary model of the atom in which negatively charged electrons orbited the tiny, but massive, positively charged nucleus, held in orbit by the attractive electrical forces. To make the atom neutral, the number of orbiting electrons must equal the nuclear charge.

3 The beta particle is therefore identical to a cathode ray. They are both electrons. The distinction is the source. Cathode rays are produced by strong electric fields that “pull” them from the outer “orbit” of atoms. Beta particles originate from inside the atomic nucleus during a radioactive decay process.

2-7

2.3. A Preview of the "Modern" View of Atomic Structure

While Rutherford's planetary model still lingers in the minds of nonscientists, it actually came under immediate attack because it contradicted the well-established theory of electromagnetic radiation. This theory predicted that an orbiting electron would continuously convert its kinetic energy into light energy. As a result it should spiral into the nucleus. Still, there was no doubt that an atom was comprised of a very small, massive, positive nucleus and electrons that were held close to it by electrical attractions.

Neil's Bohr, a Danish physicist and student of Rutherford, was the first to propose an alternate model. His model was supported by the discoveries and theories of Albert Einstein and others in the early 20th century. The major threads of Bohr's contribution to atomic theory, as well its subsequent development into the most modern form of atomic theory, called quantum mechanics, will be studied up in Chapter 6.

For now it is worth describing just a few of the features of modern atomic theory. Remember, however, that a more complete picture will be needed to explain the chemical properties and transformations of matter, which, after all, is the ultimate goal of Chemistry.

Subatomic Particles: Electrons, Protons, and Neutrons

Atoms are not indivisible as Dalton hypothesized. They are made up protons, neutrons, and electrons which have the properties given in the table below

Particle Name

Symbol Charge (e)

Approx mass (amu)

Precise Mass (g)

Size (m)

electron e- -1 1/1837

!

9.10953x10"28 “point” proton p+ +1 1

!

1.67265x10"24

!

< 1x10"15 neutron n 0 1

!

1.67495x10"24

!

< 1x10"15

!

1 amu = 1.6606x10"24 g

!

1 e = 1.6x10"19C

The Structure and Size of the Atoms

The protons and neutrons of an atom are located in a very tiny region called the nucleus. The diameter of atomic nuclei is on the order of

!

10"15m . The electrons "swarm" around the nucleus in regions called orbitals. The electrons determine the overall size of atoms that are on the order of

!

10"10m . That is, atomic size is determined by this region occupied by the electrons. To give an idea of this scale difference between the nucleus and the whole atom, if an atom was magnified to the size of a baseball stadium, the nucleus would be the size of a marble. In the late 1980’s the invention of tunneling electron microscopes allowed images of atoms and dramatically confirm these scales. Mr. Kemer took the micrograph below during his sabbatical appointment as a Visiting Scholar at Amherst College in 2000. It shows neatly aligned molecules of docosyl-ether and docosyl-sulfide lying on a flat surface of graphite. The smallest white dots are hydrogen atoms. The brightest dots are sulfur atoms. The figure to the right shows models of these same molecules (the yellow center atom represents sulfur and the red center represents oxygen). The blurriness of the images arises in part to the motions of the molecules during the scan that produced the image. The image is about 10 nanometers (10 billionths of a meter) across.

2-8

Atomic Number and Mass Number

All atoms of a particular element have the same number of protons in their nuclei. This number is called its atomic number (Z). For instance Hydrogen has 1 proton in its nucleus and therefore has the atomic number 1. It is the atomic number that identifies the element.

The mass number (A) is defined as the total number of protons and neutrons in the nucleus.

Mass number = atomic number + neutron number (A = Z + A)

A neutral atom has equal numbers of electrons and protons.

Example: Fill in the blanks of the following table. Use a periodic table or other source for the symbols.

Atomic Number

Mass Number

Number of Protons

Number of Neutrons

Number of Electrons*

Element Symbol

Element name

7 7 nitrogen 9 10 39 19 59 27

2.4. Atomic Weights

Measuring The Masses of Atoms

The mass of atoms and molecules is accomplished using a mass spectrometer. The basis of mass spectroscopy is the law of magnetic force on a moving charged particle. This law, called the Lorentz Force law, states that a charged particle will be deflected sideways into a circular path when is moves across the face of a magnet having its north pole pointing perpendicular to the particles velocity. The magnitude of the force is proportional to the particle charge and speed and the strength of the magnetic field.

N+

!

F = ma

!

ac = v2 R!

FB = qvB

!

qvB = mv2 R

!

m =qBRv

A detailed diagram of a mass spectrometer is shown below. Note that the atoms are stripped of an electron to give them a single positive elementary charge. This loss of mass must be added in to give the correct mass of the atom. Note that the north pole of the magnet points down.

2-9

Isotopes

Two atoms of the same element must have the same number of protons. However, they may have different numbers of neutrons and therefore different mass numbers and masses. Atoms of a given element with different mass numbers are called isotopes (“same position”). Although isotopes of the same element differ in mass, they generally have very similar chemical properties. The symbol system used to designate an isotope is

!

ZAX

where X is the element symbol, Z is the atomic number, and A is the mass number. Often the atomic number is not written since it is implied by the element symbol.

Isotopes are also expressed with the element name followed by a hyphen and the mass number.

Example: Two isotopes of chlorine:

!

1735Cl (chlorine-35) and

!

1737Cl (chlorine-37)

Example: Two isotopes of Carbon:

!

612C (carbon-12) and

!

614C (carbon-14)

Example: Hydrogen has three isotopes. They are the only isotopes given specific names.

!

11H (Protium)

!

12H (Deuterium)

!

13H (Tritium)

Example: Complete the following table using the definitions of atomic number, mass number.

isotope symbol Atomic number Mass number No. of protons No. neutrons

Carbon-12

!

612C

!

3883Sr

92 146 29 61

The Atomic Weight Scale and the Mole

The mass spectrometer allows the masses of atoms (minus an electron) to be measured in gram units. For instance, the

!

1H isotope has a mass of

!

1.6735x10"24 g and the

!

16O isotope has a mass of

!

2.6560x10"23g . Because it would be cumbersome to continually express such small masses in grams, we instead use a unit called the atomic mass unit, or amu. The amu is defined in as 1/12 the mass of the

!

12C isotope.

!

1 amu = 1.66054 x10"24 g .

A proton has a mass of 1.0073 amu, a neutron 1.0087 amu, and an electron 5.486 x 10-4 amu.

The mole is the number defined as the number of

!

12C atoms in exactly 12.0 grams of

!

12C . This is also the number of amu units in 1.0 gram

!

1 mole = 6.022x1023

The clever thing about this definition of a mole is that the mass of 1 mole of an element (or compound) is the number of grams numerically equal to its mass in amu. This will be made more clear in Chapter 3. Average Atomic Masses of the Elements The atomic weight of an element is a weighted average mass of its isotopes that reflects the relative abundances of each isotope as they occur naturally.

2-10

Example: A sample of chlorine contains 75.78% of

!

1735Cl and 24.22% of

!

1737Cl by mass. Calculate the

atomic weight of chlorine given that the atomic mass of

!

1735Cl is 34.969 amu and

!

1737Cl is 36.966 amu.

(0.7578)(34.969 amu) + (0.2423)(36.966 amu) = 35.45 amu

Example: A naturally occurring sample of Chlorine, which contains of

!

1735Cl and

!

1737Cl , has an average

atomic weight of 35.45 amu. What is the relative abundance of each isotope?

Let x be the fractional relative abundance of

!

1735Cl . Approximate the atomic mass of these two isotopes

to be 35 and 37. (x)(35 amu) + (1 - x)(37 amu) = 35.45 amu

Solving for x leads to x = 0.76. Therefore,

%

!

1735Cl = (100%) x = 76%, %

!

1737Cl = (100%)(1-x) = 24%

The relative abundances of isotopes are determined by mass spectroscopy. On a mass spectrograph the relative heights of the peaks is directly related to the mass percentages of each isotope.

Example: The mass spectrograph for chlorine on the top right figure of page 2-9 shows the two peaks for the isotopes of chlorine. The relative heights of the peaks give the relative mass % abundances. In this case the relative heights of the 35Cl and 37Cl peaks are 5.0 and 1.6, respectively. Therefore, naturally occurring chlorine contains 5/(5+1.6) = 76% 35Cl and 1.6/(5+1.6) = 24% 37Cl by mass.

2.5. The Periodic Table

In 1814, J. J. Berzelius invented modern element symbols. Today we know that each element is made up of a unique type of atom. 89 elements (atoms) occur naturally on the earth. 20 elements have been synthesized since 1937 by smashing smaller atoms (nuclei) together at nearly the speed of light in particle accelerators. Most synthesized atoms radioactively decay into stable elements in very short times

Abundant and Rare Elements The matter of the known universe is 93% H, 7% He, and < 0.1% all else. The solar system is 85% H, 15% He, and < 0.1% all else. Strangely, more than 60% of the mass of the Universe is of unknown composition; it is simply called “dark matter.”

Periodic Table of the Elements

In 1869 Dimitri Mendeleev, a Russian Chemist, organized the known elements into a table in order of increasing atomic weights. He chose to start new horizontal rows (or periods) of the table in such a way that elements with similar chemical and physical properties lined up in vertical columns (or groups).

2-11

Mendeleev's ordering scheme resulted in some "empty" places that he took for undiscovered elements. Indeed, on this basis he predicted the existence of scandium (Sc), gallium (Ga) and germanium (Ge), all of which were discovered shortly afterward. Modern atomic theory has determined that the true basis for the ordering the elements in the periodic table is increasing atomic number and that the vertical groups are were comprised of elements whose atoms have similar arrangements on electrons in the atoms. In other words, modern atomic theory relates chemical properties to the electronic structure of atoms.

Elements are commonly classified as follows: Type Physical properties . Metals Solid at room temperature (except Hg), good conductors of heat and electricity, shiny,

ductile, have a wide range of hardness.

Nonmetals May be solid, liquid, and gas at room temperature, are poor conductors of heat and electricity, nonmetal solids have dull surfaces and are brittle.

Metalloids have properties are intermediate to metals and nonmetals. Some have unique electrical properties (semiconductors)

Diatomic These exist naturally as diatomic molecules. They include :

!

H2,

!

N2 , and

!

O2 plus Elements the halogens:

!

F2,

!

Cl2,

!

Br2, and

!

I2

Noble: These do not ordinarily form compounds with other elements. They are all Gases monatomic gases at room temperature. They include He, Ne, Ar, Kr, Xe, Rn

The group designations include:

• The Group IA metals are called the Alkali metals

• The Group IIA metals are called the Alkaline Earth metals

• The Group 1B-8B metals (center portion of the periodic table) are called the Transition Metals

• The Group VIIA nonmetals are called the Halogens

• The section of elements 57-70 and 89-102 are called the Inner Transition Metals

• The other Groups are simply referred to by their Group number or by the element at the top.

2-12

Modern periodic tables include a wealth of physical and chemical information for each element including the average atomic weight. It is important to review three things about the atomic weight listed in periodic tables

1. It represents the weighted average of all the naturally occurring isotopes of that element.

2. If interpreted as amu units, it gives the average mass of a single atom.

3. If interpreted as gram units, it gives the mass of 1 mole of atoms of that element.

2.6. Molecules and Molecular Compounds

The atom is the smallest representative sample of an element. However, only the noble gas elements (He, Ne, Ar, Rn) are normally found in nature as isolated atoms. Most matter is composed of molecules or ions, both of which are formed from atoms. We examine molecules here and ions in the next section.

A molecule is an assembly of two or more atoms tightly bound together. The resultant "package" of atoms behaves in many ways as a single, distinct object. We will discuss the forces that hold the atoms together (the chemical bonds) in Chapters 8 and 9. Molecules and Chemical Formulas

Many elements are found in nature in molecular form; that is, two or more of the same type of atom are bound together. For example, the oxygen normally found in air consists of molecules that contain two oxygen atoms. We represent this molecular form of oxygen by the chemical formula O2 (read "oh two"). The subscript in the formula tells us that two oxygen atoms are present in each molecule. Any molecule that is made up of two atoms is said to be a diatomic molecule. The other diatomic elements include hydrogen (H2), nitrogen (N2), fluorine (F2), chlorine (Cl2), bromine (Br2), and iodine (I2)

Oxygen also exists in another molecular form known as ozone. Molecules of ozone consist of three oxygen atoms, so its chemical formula is O3. Even though "normal" oxygen (O2) and ozone are both composed only of oxygen atoms, they exhibit very different chemical and physical properties. For example, O2 is essential for life, but O3 is toxic; O2 is odorless, whereas O3 has a sharp, pungent smell. Elements that exist in more than one form are called allotropes.

Substances that are composed of molecules made up or two or more types of atoms are called molecular compounds. For example, water is a molecular compound comprised of molecules made of two hydrogen atoms and one oxygen atom. It is represented by the chemical formula H2O. Lack of a subscript on the O indicates one atom of O per water molecule. Another molecular compound composed of these same elements is hydrogen peroxide, H2O2. The properties of these two compounds are very different. Several molecules of other molecular compounds are shown in Figure 2.16. Notice how the composition of each compound is given by its chemical formula. Notice also that these substances are composed only of nonmetallic elements. Molecular substances contain only nonmetals.

Figure 2.16. Molecular models of some simple molecules.

2-13

Molecular and Empirical Formulas

Chemical formulas that indicate the actual numbers and types of atoms in a molecule are called molecular formulas (the formulas in Figure 2.16 are molecular formulas). Chemical formulas that give only the relative number of atoms of each type in a molecule are called empirical formulas. The subscripts in an empirical formula always give the smallest whole-number ratios of the atoms. Example: The molecular formula for hydrogen peroxide is H2O2; its empirical formula is HO. Example: The molecular formula for ethylene is C2H4; its empirical formula is CH2. For many substances, the molecular formula and the empirical formula are identical, as in the case of water, H2O. Whenever we know the molecular formula of a compound, we can determine its empirical formula. However, the converse is not true; if we know the empirical formula of a substance, we can't determine its molecular formula unless we know more information. So why do chemists concern themselves with empirical formulas? As we will see in Chapter 3, common methods of analyzing substances lead to the empirical formula only. Once the empirical formula is known, additional experiments can give the information needed to convert the empirical formula to the molecular one. In addition, there are substances such ionic compounds that do not exist as molecules. For these substances only empirical formulas are meaningful. Example: Write the empirical formulas for the following molecules: (a) glucose (a.k.a. blood sugar or dextrose) whose molecular formula is C6H12O6 : CH2O (b) nitrous oxide (a.k.a laughing gas) whose molecular formula is N2O: Same as empirical formula

Picturing Molecules

The molecular formula of a substance summarizes its composition but does not show how its atoms join together. For many molecules it is possible to draw structural formulas that show the connectivity of the atoms. For example the structural formulas of water, hydrogen peroxide, and methane (CH4) are:

Usually a structural formula does not depict the actual geometry of the molecule. That is, it cannot show the actual angles at which atoms are joined together in three-dimensions. A structural formula can be written, however, as a perspective drawing to give some sense of three-dimensional shape, as shown in Figure 2.17.

2-14

Scientists also rely on various other types of models to help them visualize molecules. Ball-and-stick models show atoms as spheres and the bonds as sticks, and they give a good sense of the angles at which the atoms are attached to one another within the molecule. Often, all atoms are represented by balls of the same size. In other cases, however, the relative sizes of the balls reflect the relative sizes of the atoms. Sometimes the chemical symbols of the elements are superimposed on the balls, but often the atoms are identified simply by color. Space-filling models give a semi-accurate depiction of what the molecule would look like if it were scaled up in size. These models show the relative sizes of the atoms, but the angles between atoms, which help define their molecular geometry, are often more difficult to see than in ball-and-stick models. As in ball-and-stick models, the identities of the atoms are indicated by their colors, but they may also be labeled with the element's symbol. You might wonder how chemists determine all of the details of these structures. This is a fascinating question that we will address later in the course. If you do not care to wait, try doing a little research yourself. Google is a convenient place to start.

2.7. Ions and Ionic Compounds

The nucleus of an atom is unchanged by ordinary chemical processes, but atoms can readily gain or lose electrons. If electrons are removed or added to a neutral atom, a charged particle called an ion is formed. An ion with a positive charge is called a cation (pronounced CAT-ion); a negatively charged ion is called an anion (AN-ion). For example, the neutral sodium atom, which has 11 protons and 11 electrons, easily loses one electron. The resulting cation has 11 protons and 10 electrons, and hence has a net charge of 1+. The net charge on an ion is represented by a superscript; +, 2+, and 3+ mean a net charge resulting from the loss of one, two, or three electrons, respectively. The superscripts -, 2-, and 3- represent net charges resulting from the gain of one, two, or three electrons, respectively. The formation of the Na+ ion from a Na atom is shown schematically below:

Chlorine, with 17 protons and 17 electrons, gains an electron in chemical reactions, producing the Cl- ion:

<

(In general, metal atoms tend to lose electrons; nonmetal atoms tend to gain electrons)

In addition to simple ions such as Na+ and Cl-, there are polyatomic ions such as

!

NO3" (nitrate ion) and

!

SO42" (sulfate ion). These ions consist of atoms joined as in a molecule, but they have a net positive or

negative charge. We will consider further examples of polyatomic ions in Section 2.8. The chemical properties of ions are greatly different from those of the atoms from which they are derived.

2-15

Determining Ionic Charges Many atoms gain or lose electrons so as to end up with the same number of electrons as the noble gas closest to them in the periodic table. The members of the noble gas family are chemically very non-reactive and form very few compounds. We might deduce that this is because their electron arrangements are somehow complete and, therefore, energetically stable. The other elements can obtain these same stable electron arrangements by losing or gaining electrons. For example, the loss of one electron from an atom of sodium leaves it with the same number of electrons as the neutral neon atom (atomic number 10). Similarly, when a chlorine atom gains an electron, it ends up with 18, the same as argon (atomic number 18). We will use this simple rule to predict the formation of ions. Example: Predict the charges expected for the most stable ions of barium (Ba) and oxygen (O). From the periodic table, barium has atomic number 56. The nearest noble gas is xenon, atomic number 54. Barium can most readily obtain the stable arrangement of 54 electrons by losing two of its electrons, forming the

!

Ba2+ cation. Oxygen has atomic number 8. The nearest noble gas is neon, atomic number 10. Oxygen can most readily obtain this stable electron arrangement by gaining two electrons, thereby forming an anion of 2- charge,

!

O2" . In general, metals tend to lose electrons to form positive cations and nonmetals tend to gain electrons to form negative anions. The periodic table can be used to determine the charges of ions. The table below shows how the charges of these ions relate in a simple way to their positions in the table. On the left side of the table, we see that the group 1A elements (the alkali metals) form 1+ ions, and the group 2A elements (the alkaline earths) form 2+ ions. On the other side of the table, the group 7A elements (the halogens) form 1- ions, and the group 6A elements form 2- ions. The transition metals do not lend themselves to such simple rules and many can form more than one charge.

Ionic Compounds

A great deal of chemical activity involves the transfer of electrons between substances. Ions form when one or more electrons transfer from one neutral atom to another. In Figure 2.19 below we see that when elemental sodium is allowed to react with elemental chlorine, an electron transfers from a neutral sodium atom to a neutral chlorine atom. We are left with a Na+ ion and a Cl- ion. But that is not the end of the matter. Because objects of opposite charge attract, the Na+ and Cl- ions bind together to form NaCl, an ionic compound. An ionic compound is a compound that contains positively charged ions and negatively charged ions. We can often tell whether a compound is ionic or molecular (consisting of molecules) from its composition. Ionic compounds are generally combinations of metals and nonmetals, as in NaCl. In contrast, molecular compounds are generally composed of nonmetals only, as in

!

H2O ,

!

C6H12O6, and

!

NO2 .

2-16

Ionic compounds are also identified by the fact that they do not conduct electricity in solid form, but do conduct electricity when molten (liquid) or dissolved in water. This behavior is good evidence that ionic compounds are made of charged ions. When in the molten state or dissolved in water, the charged ions are mobile and free to respond to an external electric field; in other words, conduct electricity. For this reason ionic compounds are called electrolytes.

Example: Which of the following compounds would you expect to be ionic:

!

Na2O ,

!

CaCl2 ,

!

SF4 ?

Answer:

!

Na2O and

!

CaCl2 are ionic compounds since they are made of a metal and non-metal.

!

SF4 is a molecular compound since S and F are both non-metals.

The ions in an ionic compound are arranged in an extended three-dimensional structure called a lattice. The arrangement of Na+ and Cl- ions in NaCl is shown in Figure 2.19. Note how each positive ion is surrounded by negative ion nearest neighbors and vise versa. This extended, well-ordered, three-dimensional structure distinguishes ionic compounds from molecular compounds. The basic unit of a molecular compound is a molecule - a self-contained neutral group of atoms linked together in a particular order (see Figure 2-16). Ionic crystals do not have smallest units per se. They are built up from these extended three-dimensional arrangements of ions held together by electrostatic forces. How many positive and negative ions must get together before you can say there is a piece of an ionic solid? That’s hard to say. It is certainly many times more than a few of each ion. The tiniest crystal just visible under a microscope would have trillions. On the hand, a single molecule constitutes a piece of a molecular compound. Because we cannot identify ionic compounds with molecules, the formulas we use to represent them communicate only the relative numbers of positive and negative ions. For example, when we represent magnesium chloride by the formula

!

MgCl2 we are NOT referring to a molecule containing one Mg and

2 Cl atoms. This formula means that the ration of

!

Mg2+ ions to

!

Cl" ions 1:2. In other words, formulas for ionic compounds are empirical formulas. It is a simple matter to write the empirical formula for an ionic compound if we know the charges of the ions of which it is composed. Chemical compounds are always electrically neutral. Consequently, the ions in an ionic compound always occur in such a ratio that the total positive charge is equal to the total negative charge. Thus, there is one Na+ to one Cl- giving NaCl, one Ba2+ to two Cl- giving BaCl2, and so forth. As you consider these and other examples, you will see that if the charges on the cation and anion are equal, the subscript on each ion will be 1 (and left unwritten). If the charges are not equal, the charge on one ion (without its sign) will become the subscript on the other ion:

2-17

Example: What are the empirical formulas of the compounds formed by (a)

!

Al3+ and

!

Cl" ions; (b)

!

Al3+ and

!

O2" ions; (c)

!

Mg2+ and

!

NO3" ions?

SOLUTION (a)

!

AlCl3 (b)

!

Al2O3 (c)

!

Mg NO3( )2 . Note that in this last case, the formula for the

!

NO3" must be enclosed in parentheses so that it is clear that the subscript 2 applies to all the atoms of

that ion. Otherwise it might look like there were 32 oxygen atoms! (

!

MgNO32)

2.8. Naming Inorganic Compounds (Chemical Nomenclature)

The astronomical number of compounds that exist makes it essential that a system of chemical nomenclature be used. The International Union of Pure and Applied Chemistry (IUPAC) has developed such a system for assigning names and formulas to compounds. In this section you will learn this system as it applies to inorganic compounds.

A. Naming Methods for Monatomic Ions

1. Cations of representative metal elements having just one charge (or oxidation) state:

element name ion Example:

!

Mg2+ is named the "magnesium ion."

2. Anions of representative non metal elements having just one charge state:

element root- ide ion Example:

!

Cl" is named the "chloride ion."

!

P3" is named the "phosphide" ion

3. Cations with more than one possible charge states:

Several transition metals can form cations of different charge. Examples include copper (

!

Cu+ and

!

Cu2+ ) and iron (

!

Fe2+ and

!

Fe3+ ). There are two methods for naming ions that exist in more than one charge state:

• The Stock System: A Roman numeral is put in parentheses after the element name to indicate

the particular value of the cation charge.

Examples:

!

Cu+ = copper (I) ion (read "copper one ion")

!

Cu2+ = copper (II) ion (read "copper two ion")

!

Fe2+ = iron (II) ion (read "iron two ion")

!

Fe3+= iron (III) ion (read "iron three ion")

• Classical system: The suffixes -ous and -ic are added to the element root name. The -ous is used for the lower possible charge state while the -ic is used for the higher charge.

Examples:

!

Cu+= cuprous ion;

!

Cu2+ = cupric ion

!

Fe2+ = ferrous ion;

!

Fe3+ = ferric ion

In this course we will stick to the modern Stock system, that is, we will use the Roman numerals.

2-18

B. Naming Polyatomic Ions

Polyatomic ions are tightly bound groups of atoms that behave as a unit and carry a charge. They are "charged molecules." Common examples include the nitrate ion (

!

NO3" ), the sulfate ion (

!

SO42" ), and

the phosphate ion ion (

!

PO43"). The only common polyatomic cation is the ammonium ion (

!

NH4+ ).

The names of common polyatomic anions are given Table 2.5 at the end of the chapter.

C. Names and Formulas of Binary Ionic Compounds

A binary ionic compound is made up of a monatomic cation and a monatomic anion. 1. Writing Formulas of Binary Ionic Compounds

Consider the ionic compound formed between Mg and Cl.

• Mg atoms lose two electrons to become cations with a +2 charge. This is written as

!

Mg2+ • Cl atoms gain 1 electron each to become anions with a -1 charge. This is written as

!

Cl" • Because ionic compounds are electrically neutral, there must be two

!

Cl" for each

!

Mg2+ in the compound. • Therefore the formula for this compound is

!

MgCl2 .

In general, the ionic compound formed from the metal ion

!

M x+and a nonmetal ion

!

A"y is given by

!

MyAx Example: Sodium oxide: The ions are

!

Na+ ,

!

O2"

!

" Na2O

Example: Iron (III) oxide: The ions are

!

Fe3+and

!

O2"

!

" Fe2O3 Example: Magnesium nitride: The ions are

!

Mg2+ and

!

N 3"

!

" Mg3N2

2. Naming Binary Ionic Compounds

Binary ionic compounds are named by writing the cation name followed by the anion name (-ide ending).

Example: NaCl , sodium chloride

!

AlN , aluminum nitride

!

Na3P , sodium phosphide

When a cation has more than one possible charge state the particular cation charge that it exists in must be indicated by a Roman numeral in parentheses or by the proper cation suffix (-ous or -ic)

Example: CuO, copper (II) oxide or cupric oxide

!

Cu2O , copper (I) oxide or cuprous oxide

The anion charge along with the condition of electrical neutrality determines the cation charge.

Example:

!

SnO2 , must be tin (IV) oxide since the oxygen anion always has a -2 charge.

Roman numerals are used on an "as needed" basis only. That is, tehy are only used when the cation is one that can have more than one charge.

2-19

D. Names and Formulas of Ionic Compounds Containing Polyatomic Ions

1. Formulas of Ionic Compounds with Polyatomic Ions

The procedure for writing the formulas of ionic compounds having polyatomic ions is similar to that used for binary ionic compounds.

Example: Calcium nitrate:

!

Ca2+ ,

!

NO3"1

!

" Ca NO3( )2

Example: Ammonium phosphate:

!

NH4+ , PO4

3" # NH4+( )3

PO4

Note that parentheses must be placed around the polyatomic ion when there is more than one of them in the formula. This is necessary to make the subscripts clear. Parentheses are never placed around monatomic ions.

2. Naming Ionic Compounds Having Polyatomic Ions

Simply name the ions, cation first and anion second.

Example:

!

NaC2H3O2, sodium acetate

Example:

!

Cu C2H3O2( )2, copper (II) acetate Note the necessity of using Roman numeral after any cation that is one of those that can have more than one charge.

E. Binary Molecular Compounds

Binary molecular compounds are composed of two nonmetallic elements. Prefixes are used to describe the number of each atom in molecules.

1. Naming Binary Molecular Compounds

Since molecular compounds have nothing to do with ionic charges, the formulas cannot be predicted and prefixes are needed to show how many atoms of a given element are in a given molecule.

Prefix Number Prefix Number Prefix Number mono- 1 penta- 5 nona- 9 di- 2 hexa- 6 deca- 10 tri- 3 hepta- 7 tetra- 4 octa- 8

To name a binary molecular compound

1. Recognize the compound as being binary molecular. It must contain no metal atoms

2. Add prefixes to each element to indicate the number of atoms of each element.

3. The second element is written with an -ide ending

4. The "o" at the end of the prefix mono- is dropped when the element name begins with a vowel.

5. The mono- prefix is omitted entirely when there is a single atom of the first element.

2-20

Examples:

!

N2O : dinitrogen monoxide (note that the "o" is dropped from mono- before "oxide."

!

PCl3

!

: phosphorous trichloride

!

AlCl3 aluminum chloride (WATCH OUT, this is an ionic compound so prefixes are not used!)

!

CO2: carbon dioxide CO: carbon monoxide (Note: drop the “o” on mono when the element name starts with a

vowel. You don’t want to write monoxide)

Two important facts should be kept in mind when dealing with molecular compounds

• They are not made of ions so ionic charges cannot be used in determine or imply the formula. • Nonmetallic elements can often combine in more than one way. For example, there are many

molecules that have C and H each having different numbers of each element. That is why prefixes are needed

2. Writing Formulas of Binary Molecular Compounds.

The prefixes give the numbers of atoms and therefore the subscripts to use.

Write the element symbols with the numbers of atoms of each as subscripts (1 is understood) Examples: Carbon disulfide:

!

CS2 Dichlorine pentoxide:

!

Cl2O5

F. Nomenclature of Acids

Acids are molecular compounds that contain a hydrogen atom that breaks away from the rest of its molecule when it dissolves in water. When not dissolved in water they are neutral molecules. When dissolved, they break up into an

!

H+ ion and a negative anion. For this reason, when dissolved in water, acids can be thought of as ionic compounds with a hydrogen ion H+ playing the role of the metal cation.

Examples: In its pure gaseous state, hydrogen chloride is a molecular compound and is symbolically represented as HCl(g). When it dissolved in water hydrogen chloride dissociates into

!

H+ (aq) and

!

Cl"(aq) ions. In this dissolved state HCl(aq) is called hydrochloric acid. In its pure gaseous state

!

H2S (g) is called hydrogen sulfide. When dissolved in water

!

H2S (aq) is called hydrosulfuric acid

Note that to indicate that a compound is dissolved in water the symbol (aq) is placed after the compound symbol. This stands for aqueous solution (dissolved in water).

2-21

1. Naming Acids

The general formula for an acid is:

!

HaAb (aq)

where H is hydrogen, A is an anion, and the symbol (aq) indicates that it is dissolved in water.

The following are the rules for naming acids.

1. When the anion is derived from a single atom, write: hydro-anion stem-ic acid

Examples: HBr (aq):

!

Br"= bromide ion

!

" hydrobromic acid HI (aq):

!

I"= iodide ion

!

" hydroiodic acid

!

H2S (aq) :

!

S2"= sulfide ion

!

" hydrosulfic acid 2. When the anion name ends in -ite , write: anion stem-ous acid

Examples:

!

H2SO3(aq) :

!

SO32"= sulfite ion

!

" sulfurous acid

!

HClO(aq) :

!

ClO"= hypochlorite ion

!

" hypochlorous acid

3. When the anion ends in -ate, write anion stem-ic acid

Examples:

!

HNO3(aq):

!

NO3"= nitrate ion

!

" nitric acid

!

H3PO4 (aq) :

!

PO43"= phosphate ion

!

" phosphoric acid

2. Writing Acid Formulas: Use the above rules in reverse

2-22

G. Nomenclature of Hydrates

Many ionic compounds incorporate a specific number of water molecules per formula unit into their crystal structures. These water molecules form part of the crystal and do not make the salt appear “wet.” Ionic compounds that contain water in this manner are called hydrates and the water that is incorporated into the crystal is called water of hydration. The water of hydration can usually be removed by heating at temperatures near 100

!

˚C . An ionic compound that has had its water of hydration removed is called an anhydrous salt.

The formula of a hydrate consists of the formula of the ionic compound followed by ". x

!

H2O " where x is the number of water molecules attached to each formula unit of ionic compound.

The name of the hydrate is given by the ionic compound name followed by prefix-hydrate where the prefix is that corresponding to the x.

Examples: Copper (II) sulfate pentahydrate:

!

CuSO4 "5H2O

The images above show the hydrate copper (II) sulfate on the left. In the center is the anhydrous copper (II) sulfate attained after gentle heating. The right photograph shows a drop of water added to the anhydrous copper (II) sulfate which results in the return to the hydrated form. The “dehyradtion” of copper (II) sulfate pentahydrate may be written as a chemical equation:

!

CuSO4 " 5H2O(s) #heat

CuSO4 (s) + 5H2O(l) (hydrate) (anhydrous salt) (water)

Another example of a hydrated salt is barium chloride dihydrate,

!

BaCl2. "2H2O .

2-23

Table of Common Ions

Cations Anions Name Symbol Hydrated

color Name Symbol Hydrated

Color Aluminum

!

Al3+ - Acetate

!

CH3COO" -

Ammonium

!

NH4+ - Arsenide

!

As3" -

Barium

!

Ba2+ - Bromide

!

Br" - Cadmium

!

Cd 2+ yellow Bromate

!

BrO3" -

Calcium

!

Ca2+ - Carbide

!

C 4" - Chromium (II)

!

Cr2+ varies Carbonate

!

CO32" -

Chromium (III)

!

Cr3+ blue Hydrogen carbonate

!

HCO3" -

Cobalt (II)

!

Co2+ light red Chloride†

!

Cl" - Cobalt (III)

!

Co3+ - Chlorate†

!

ClO3" -

Copper (I)

!

Cu+ - Chlorite†

!

ClO2" -

Copper (II)

!

Cu2+ pale blue Hypochlorite†

!

ClO" - Hydrogen

!

H+ - Perchlorate†

!

ClO4" -

Iron (II)

!

Fe2+ pale green Chromate

!

CrO42" yellow

Iron (III)

!

Fe3+ brown Dichromate

!

Cr2O72" orange

Lead (II)

!

Pb2+ - Cyanide

!

CN" - Lead (IV)

!

Pb4+ - Thiocyanate

!

SCN" - Lithium

!

Li+ - Fluoride

!

F" - Magnesium

!

Mg2+ - Hydride

!

H" -

Manganese (II)

!

Mn2+ light pink Hydroxide

!

OH" - Manganese (III)

!

Mn3+ - Nitride

!

N 3" - Mercury (I)

!

Hg22+ - Nitrate

!

NO3" -

Mercury (II)

!

Hg2+ - Nitrite

!

NO2" -

Nickel (II)

!

Ni2+ green Oxalate

!

C2O42" -

Nickel (III)

!

Ni3+ Oxide

!

O2" - Potassium

!

K+ - Permanganate

!

MnO4" purple

Sodium

!

Na+ - Peroxide

!

O22" -

Tin (II)

!

Sn2+ - Phosphide

!

P3" - Tin (IV)

!

Sn4+ - Phosphate

!

PO43" -

Strontium

!

Sr2+ - Phosphite

!

PO33" -

Silver

!

Ag+ - Selenide

!

Se2" -

Zinc

!

Zn2+ - Sulfide

!

S2" - Sulfate

!

SO42" -

Hydrogen sulfate

!

HSO4" -

Sulfite

!

SO32" -

Hydrogen sulfite

!

HSO3" -

† Ions with bromine and iodine in place of chlorine are named similarly

Thiosulfate

!

S2O32" -

Chapter 2. Homework Section 2-1. 2.1. What is the main goal of chemistry? 2.2. Why are the chemical theories of both the ancient Greeks and the medieval alchemists not considered scientific today? 2.3. (a) What is the general meaning of the term operational definition? (b) In what sense was Boyle’s definition of an element an “operational definition.” 2.4. What basic laws of matter did Dalton’s Theory provide explanations for? 2.5. If we assume that nitrous oxide molecules are comprised of 2 atoms of nitrogen (N) and 1 atom of oxygen (O), use the Law of Multiple Proportions to determine the number ratio of nitrogen to oxygen atoms in nitric oxide and nitrogen dioxide. 2.6. The mass ratio of nitrogen to hydrogen in ammonia is 4.67. Taking the atomic mass of hydrogen to be 1 atomic mass unit (amu), determine the atomic mass of nitrogen if the formula of ammonia is assumed to be (a) NH (1 atom N: 1 atom H), (b) NH2

(1 atoms N: 2 atoms H), (c) NH3 (1 atom N to 3 atoms H). Use the general expression found in the reading relating bulk mass ratio to atomic mass ratio to derive your results. 2.7. The mass ratio of carbon to oxygen in carbon dioxide (

!

CO2) is 3:8. Predict the mass ratios would be for the compounds (a) CO, (b)

!

CO3 and (c)

!

C2O . 2.8. Use Google to find an example of a nonstoichiometric compound. Section 2-2. 2.9. State two differences in the behavior of cathode rays (electrons) and X-rays (high energy light), both of which were generated in a Crooke’s tube. 2.10. What experimental evidence supported Thomson’s hypothesis that electrons are subatomic particles (i.e., universal parts or building blocks of atoms) 2.11. What piece of data did J.J. Thomson need in order to calculate the mass of the electron from the charge to mass ratio that he calculated? Who provided this information?

2.12. What is similar between a cathode ray and a beta particle? What is the difference? 2.13. Imagine that you begin dropping pennies into a deep circular well having a diameter of 1-meter, You release each penny from random locations about the opening. For each of the first 78 drops you note that the pennies make no sound until they “plunk” in the water 3.0 seconds after release. Then, on the 79th penny, you hear a distinct metallic “clink” 2.0 seconds after release. After 10,000 additional random drops you find that the randomly dropped pennies produce the metallic “clink” once every 100 drops, on average. It would be easy to conclude from this experiment that there is an obstruction part way down the well. (a) Estimate the obstruction’s cross sectional area from the data described. (b) Calculate in meters the depth of the well and the depth of the obstruction. Section 2-3. 2.14. The ratio of the diameter of a typical atomic nucleus to the diameter of a typical atom is 1/10,000. (a) What is the approximate ratio of the volume of the nucleus to the volume of the atom? (b) If the diameter of the nucleus were 1 inch, what would be the diameter of the atom in feet? 2.15. Complete the table at the end of Section 2-3 (Reproduce it on your own worksheet to hand in) Section 2-4. 2-16. Is there an error in the direction that the positive Cl ion’s deflection as shown in the detailed diagram of the mass-spectrometer in the text? (Hint: Compare the mass spectrometer diagram with the preceding diagram showing the path of + and – charged particles across the face of a north pole of a magnet (pointing out of the page). 2-17. Complete the isotope table in Section 12-4 (Reproduce it on your answer sheet to hand in).

(Reproduce this table on your answer sheets)

(Hint: This requires taking a weighted average)

2.34. How many peaks will be found in a mass

spectrograph of water molecules assuming that there are detectable amounts of all three isotopes of hydrogen and detectable amounts of two isotopes of oxygen. Hint: There are more than you may at first think! Write out each possibility

in the form

!

1H"1O"1H and make sure you don’t duplicate.

Section 2-5 and 2-6

Section 2-7 2.47. Fill in the gaps of the following table

Symbol

!

59Co3+ protons 34 76 80 neutrons 46 116 120 electrons 36 78 Ion charge 2+ (Reproduce this table on your answer sheets)

(Note: In each case the positive charge on the metal is determined by the group (or column) number (e.g. Na = +1, Al = +3, Cl = 7 - 8 = -1)

Section 2-8 Questions Note: Take the time needed to get them right the first time! Refer explicitly to the nomenclature rules in the text. Be particularly alert to those cations that require a roman numeral in the naming of the compounds they form, such as iron (III) oxide and nickel (II) chloride. You will find these in the table of ions at the end of Chapter 2. ON YOUR PAPER WRITE OUT YOUR ANSWERS IN THE SAME ARRANGEMENT (COLUMN AND ROWS) AS THE QUESTIONS. THINK ABOUT AND INCLUDE THE ONES FOR WHICH THE ANSWERS ARE GIVEN. 2-61. State differences in the types of elements that combine to form ionic vs. molecular compounds. 2-62. Would you expect the following compounds to be ionic or molecular? (Think about metals and non metals)

(a)

!

CO (b)

!

KBr (c)

!

Mn3 PO4( )2 (d)

!

C3H8 2-63. Using only the periodic table, write the formula of the ions formed from these representative elements. Include

the charge as a superscript.

(a) lithium (

!

Li+ ) (b) fluorine (

!

F") (c) oxygen (d) potassium (e) barium (f) nitrogen (

!

N 3") (g) beryllium (h) magnesium (i) aluminum (

!

Al3+ ) (j) chlorine (k) calcium (

!

Ca2+ ) (l) sulfur 2-64. Write the formulas for compounds formed from these pairs of ions.

(a)

!

Sr2+ ,

!

Se2"

!

SrSe( ) (b)

!

K+ ,

!

O2" (c)

!

Ca2+ ,

!

N 3" (d)

!

Co3+ ,

!

I"

2-65. Write formulas for these compounds (Note the names that need Roman numerals. Why is that?) (a) tin (IV) bromide (b) ammonium dichromate (c) lithium hydrogen sulfate

(d) sodium hydrogen sulfate (e) sodium bicarbonate (f) copper (II) carbonate 2-66. Name the following binary molecular compounds

(a)

!

OF2 (b)

!

Cl2O8 (c)

!

SO3 (d

!

P4O10 (e)

!

CCl4 2-67. Write formulas for the following binary molecular compounds (a) dinitrogen tetroxide (b) phosphorous pentachloride (c) nitrogen trifluoride (d) disulfur dichloride

2-68. Name each of the following acids (Be sure you understand the restricted use of “hydro-“ in naming an

acid.) (a)

!

H2C2O4 (aq) (b) HF (aq) (c)

!

H2SO4 (aq) (d)

!

HClO2 (aq) (e)

!

H2CO3(aq) (f) HCl (aq) (g)

!

HNO3(aq) (h)

!

HC2H3O2 (aq)

2-69. Name each of the following substances. Be careful to distinguish molecular compounds, ionic compounds, and acids.

Acids are indicated by (aq). (a) CaO (b)

!

CuC2H3O2 (c)

!

Ba3 PO4( )2 (d)

!

HClO4 (aq) (e)

!

I2 (f)

!

Cl2O (g)

!

BaSO4 (h)

!

HgF2 (i)

!

Mg OH( )2 (j)

!

NH4( )2C2O4 (k)

!

NO2 (l)

!

Ni3 PO4( )2 (m)

!

Li2HPO4 (n)

!

FeCO3 (o)

!

H2CrO4 (aq) (p)

!

H2O2 (q)

!

SnCl4 (r) HgS (s)

!

N2O5 (t)

!

CS2

2-70. Write the chemical formula for each of the following substances. Keep in mind that these include both ionic, molecular compounds, and acids. Be alert to those metal ions that can form ions of two different positive charges and require roman numerals to name (example: copper (I) and copper (II)). Finally, remember to that (aq) must be places after the formula to designate an acid.

(a) calcium carbonate (b) nitrogen gas (c) sodium bromide

(d) barium hydroxide (e) iron (III) sulfate (f) hydrobromic acid

(g) magnesium sulfide (h) sulfuric acid (i) potassium permanganate (j) sulfite ion (k) sulfur trioxide (l) ammonium perchlorate

(m) phosphorous pentabromide (n) copper (II) iodide (o) phosphoric acid