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DESIGN OF SLAB USING SAFE
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SLAB DESIGN USING SAFE SOFTWARE
DATA FOR SLAB DESIGN
NO. OF SLAB PANELS (X- DIRECTION) = 2
NO. OF SLAB PANELS (Y- DIRECTION) = 3
X-DIRECTION SPACING = 24’
Y-DIRECTION SPACING = 18’
SLAB THICKNESSTAKEN = 6 INCH
fc’ (28 DAYS COMPRESSIVE STRENGTH) = 3000 psi
fy (YIELD STRENTH OF STEEL ) = 60,000 psi
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STEP 01 Grid Definition
File – New – Grid Definition .
No of Grid Lines (x-direction) = 3
No of Grid Lines (y-direction) = 4
Grid Spacing (x-direction) =24’
Grid Spacing (y-direction) =18’
For editing in Grid Spacing, use command Edit – Edit Grid .
Units = Kip-ft
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STEP 02 PROPERTIES DEFINITION
For defining the properties of different elements, use following Command,
Define – Slab Properties – Add new property – Set property name as Slab1In type click Slab, thickness = 0.5’ , give cover = 0.08’ ( 1 inch),Give fc’ and fy and Modulus of elasticity accordingly.
After this use following command & procedure
Define – Beam Properties – Add Rectangular Beam-Set Beam property name as Beam1.Give depth = 2’ & width = 1’ , give cover = 0.16’ ( 2 inch),Give fc’ and fy and Modulus of elasticity accordingly.
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STEP 02 PROPERTIES DEFINITION
Then use following command to define column properties
Define – Column Supports – Add New Property-Set property name as Col1.Give column dimensions = 1’ (X-dimension) , 1’ (Y-dimension) Column Height = 10’,Give fc’ and fy and Modulus of elasticity accordingly.
To draw beams in model useDraw – Line Objects.
To draw slab in model useDraw – Draw area objects.
To draw column in model useDraw – Draw point objects
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STEP 03 ASSIGNING PROPERTIES
After defining all properties, these are assigned to relative elements
slab, Beam & column as shown in next slides.
To assign slab properties in model use
Assign – Slab properties.
To assign beams in model use
Assign – Beam properties.
Assigning Slab.
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Assigning Beams.
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Assigning Column Supports
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Step 04 Load Application
Load cases are defined using following command
Define – Static Load Cases –
Load 1 – DL Selfwt multiplier =1 & Long term deflection factor =3
Load 2 – LL Selfwt multiplier =0 & Long term deflection factor =1
After selecting the slab, load is applied using following command
Select slab – Assign – Surface loads – DL – Load per area = 0.05 (ksf)
Select slab – Assign – Surface loads – LL – Load per area = 0.06 (ksf)
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Assigning Load
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Step 05 Defining Load Combination.
Load combinations are defined using command
Define – Load Combinations
Comb 1 - 1.2 DL + 1.6 LL
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To view the properties of element ,rendered view, or mesh of slab use following command
View – Set object options – Area object properties or show mesh.
To display the applied load
Display – Show Loads.
Auto Mesh of Slab.
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Step 06 Analysis of Model.
Analysis can be performed using command
Analyze – Run Analysis.
Step 07 Analysis Results .
Deformed shape can checked using command
Display – Show Deformed Shape. Max Deflections must be with in permissible limits .Max Deflection due to loads for this case is 0.23 inches.
Slab forces can be obtained using command
Display – Show Slab Forces.
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Step 07 Analysis Results .
To obtain the results of beams
Display – Show Beam Forces.
To obtain the results of slab strips
Display – Show Strip Forces.( Moments & Shears)
To obtain the results in tabulated form
Display – Show output tables.
Deformed Shape of Slab.
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Step 08 Design of Slab & Beams
To design the slab, use following command
Design – Select design combinations
Then Start Design
To check the results of reinforcement
Design – Display slab design info – Show rebar area.
Then click on X-strip reinforcement to check x-direction reinforcement.
Then click on Y-strip reinforcement to check Y-direction reinforcement.
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Step 08 Design of Slab & Beams
To check the results of punching shear
Design – Display punching shear ratios .(It must be less than 1.)