Date post: | 21-Dec-2015 |
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-8 +15
-120
-20
-4 +5
f
F Wearedone! Now we just ¢¢¢
(6) ¢(¡ 20) = ¡ 120F Two numbers whoseproduct is -120
and whosesum is +7
F Two numbers whoseproduct is -20
First one¯ts evenly into -8
Second one¯ts evenly into +15
(wait)
ExampleA 6x2+7x ¡ 20
Ready?
-8 +15
-120
-20
-4 +5
2 3
¢
F Solution is
(6) ¢(¡ 20) = ¡ 120
and +15 by +5
(2x+5) (3x ¡ 4)
F Divide ¡ 8 by ¡ 4
ExampleA 6x2+7x ¡ 20
(wait)
(10) ¢(¡ 3) = ¡ 30
-15
+2 -30
-3
-3 +1
F Two numbers whoseproduct is -30
F Two numbers whoseproduct is -3
First one¯ts evenly into -15f
and whosesum is ¡ 13
Second one¯ts evenly into +2
F Wearedone! Now we just ¢¢¢
(wait)
ExampleB 10x2 ¡ 13x ¡ 3
Ready?
(10) ¢(¡ 3) = ¡ 30
-15
+2 -30
-3
-3 +1
5 2
and +2by +1
¢(2x ¡ 3)
F Solution is
(5x+1)
(wait)
F Divide ¡ 15 by ¡ 3
ExampleB 10x2 ¡ 13x ¡ 3