Date post: | 27-Dec-2015 |
Category: |
Documents |
Upload: | noel-summers |
View: | 218 times |
Download: | 1 times |
I. Current I is _________________________________________
Units: 1 coulomb/second = 1 _______________
1 C/s = 1 ____
So the answer can be written I = ________
Ex. 22 C of charge pass a point in 4.0 seconds. Find I.
I =
Ex. How much charge passes a point if the currentat the point is __________ ampere for ________seconds?
Amperes are ______________________ units. (m___sk)
Coulombs are ______________________ units
What is a coulomb written in terms of fundamental units?
1 C =
Ex. How many electrons pass a point in 2.5 seconds if
the current at that point is 0.50 A?
Don't forget that the amount of charge q passing a
point can be written with units of __________________
or __________________________________ . The conversion
from one unit to the other is found on pg 1 of PhysRT:
1 C = _______________________ e
or 1 e = ________________________ C
To have current, you need _________________ 2 things:
1.___________________________ (aka ___________ source)
a/ a ______:
wire wire
two _________________
The amount of ____________ depends on the metals used.
b/ a battery = _______________cell:
_________side or _______ potential
c/ a ______________ :
more cells _________________
_________side or _______ potential
A voltage source V supplies ____________ to a circuit by setting up ___________________________ within the circuit.
_______ pot. _______ pot.
V flow of___________charge
flow of________( )
Electrons flow out of the ________________ side of V.This is equivalent to flow of ___ charge out of ___ side of V.The e-'s collide with _____________ of wire. This absorbs electrical __________________ and ______________ the wire.The speed of e-'s ______________ collisions is ____________, but the drift (________________) velocity of e- is __________ .
magnified wire cross section
.
Batteries supply a constant V _____________ current _______
I
I
t
Generators supply a varying V ________________ current ______
charge moves in ___________________
charge moves in _________________
t
charge moves in __________________
In Regents Physics, we will mostly study _____ ,
but the basic ideas are also valid for ______.
2. A ________________ circuit
Can you have voltage without current?
Can you have current without voltage?
Ex:
Switch up ___________ circuit ________ current
Close the switch ____________ circuit _____________ __________ flows ______________
Using circuit symbols:
+ -
Current I is measured with an _________________, which
is often part of a DMM (______________________________ ).
Its symbol is:
In an electrical circuit, ammeters are connected __________________ . This means the circuit must be ________________ and the _______________ must be _____________ into it:
circuitpart 2
circuitpart 3
circuitpart 2
circuitpart 3
Circuit _______ ammeter:
circuitpart 1
circuitpart 1
Circuit _________ ammeter:
Voltage V is measured with an _________________, which
is often part of a _________. Its symbol is:
In an electrical circuit, voltmeters are connected __________________ . This means the circuit is _______opened up , but the _______________ must be connected _____________ two points in the circuit:
Circuit:
circuitpart 3
circuitpart 2
circuitpart 1
circuitpart 1
circuitpart 2
circuitpart 3
Ammeters measure the current that passes _________ a part of the circuit, in other words, the amount of ___________ each second that passes ____________ it.
Voltmeters measure the ________________________ from one side of a part of the circuit to the other side. This is called the voltage _____________ the circuit part. It represents the ____________ or _____________ needed to force each ________________ of charge through.
Ideally, neither ammeter nor voltmeters ______________________________________________ , but in reality they do.
In symbols:
II. Resistance R - ___________________________________________________________________________________________________________________________________________
2. R is a __________________ . It has _________________ .
units of R: ___________________
It is a ______________________ unit.
1. Resistance occurs as a result of ________________
colliding with ___________________ and with the
__________________________ , resulting in ____________ .
This converts __________________energy to ___________.
3. Any factor that makes it more _________________for
_______________ to move will through a material will
__________________________________ of the material:
R
L
R
A
A. __________________
B. __________________
For _____________, there are four factors that affecthow much resistance it has:
temperature:R
T
Higher T atoms of the metal _________________
________________________ for e-'s
to move through the metal
more ____________________
D. ______________________ : Different metals have different numbers of ____________________ .
______ electrons ______ current _______ resistance
R
# of free electrons
These 4 factors are summed up in:
(rho) is called the _________________ of a material. depends on the ___________________ of a metal
and is different for different _____________ .
units of :
_________________
_________________
Lowest = _______________Highest = _______________Metals that have more free_____________ will have a_________ and _________ R.
Ex. Calculate the resistance of 100 meters of copper wire that has a cross-sectional area of 3.44 x 10-6 m2.
R =
=
=
A _________________is a device that is designed to
have a definite amount of _________________.
Resistors are used to
1. control _____________ flow; and
2. provide a _____________________
of a certain amount.
Symbols:
1. resistor:
2. variable resistor:
Semiconductors (like ___________ and ______________ )
have ____________ resistance at higher temperatures.
Here’s why:
___________ silicon (Si) is
an _______________________ .
It _____________ its outer e-’s
with 4 other silicon atoms in
a ___________________ bond,
so that its own electrons
_______________________
electricity.
Two materials that do not follow these rules for metals
are _____________________ and ______________________ .
= a ________ of shared e-s
= Si atom
Phosphorus P and arsenic Ashave __________ outer e- than Si.
Boron B and gallium Ga have __________ outer e- than Si.
If you add _________________ of P, As, B or Ga to pure Si, it creates extra charge carriers. This is called _____________ . Higher temps “free up” more of these extra charges and allows for more __________ and so less _____ . And because of the extra charge carriers, semiconductors have _________________ resistancesthat can be ______________ . They are now used in making almost all _______________________________ .
outer
e-’s3 4 5
a
t
o
m
C N
Al Si
Ge
Superconductors:
The resistance R of superconductors is _________
as long as the material is _____________________________.
Because they have no _____ , electrons can travel through
them __________ , and so they can carry ________ currents
for _________________ without producing large amounts
of ___________ . This in useful in the ___________________
___________ and _________________________________________
Originally (around 1911), only certain ____________
were found to be superconducting. But they had to be
cooled to near ___________________ using liquid helium
(boiling point about _______ ) for this to happen.
This is very expensive.
Materialmetal=mceramic=
c
critical temp.
(K)
absolute zero 0
Zinc 0.88
Aluminum 1.19
Tin 3.72
Mercury 4.15
liquid nitrogen
YBa2Cu3O7 90
TlBaCaCuO 125
room temp. 293
In _______, a new type of superconductor was discovered whose makeup is similar to ________________ . These become superconductors at higher temperatures. This makes them much more ____________________.
much ___________to use liquid N
Using R = L/A, R can be found using the ____________________________of a metal wire.
In a circuit, R is defined for any device as the ratio of __________________ the device to the________________________the device:
A simple circuit:
III. Ohm's Law
Ex. If the potential difference across a resistor is _______
and the current through it is __________, find R.
units: [ ] = [ ]/[ ]
=
=
R = V / I Solve this for
To remember all 3 equations, use:
V = ?
I = ?
units: [V] = [I][R] =
[I] = [V]/[R] =
Ex: What is the potential difference across a 25- resistor when it carries a current of 3.0 A?
Ex: What is the potential difference across a wire that has no resistance?
Ex: How much energy is required to make each coulombof charge pass through the above resistor?
3. I = charge flowing _______________________________ . The charge going __________ any circuit element must_________ the charge __________ that element. Assume ____ charge flows out of the ____ side of the source.
4. V = potential difference __________________ = ____________________________ available to do work = energy converted to _______________________ by R = energy is __________________ by passing through R = _________________________ across R = _______ if there is no resistance, e.g. in a __________
1. Assume the connecting wires have _________________ resistance. (They usually have ________________ R than the circuit elements.)
2. For simple devices such as _______________________ ,we often replace the device with the symbol for__________________ : and assume that it has all of the ______________________.
distance around the circuit
V
Vsource
R
Ex: A simple circuit has 1 _______.All of the __________________ is dropped across the ___________, because it is the only element in the circuit that requires ____________ (voltage).
Graph the voltage drops as you follow ____________ charge from the _________ potential side of source, throughthe _____________ , back to the _______ side of the source.
no V dropped in wireb/c V = IR = ________
Other ____________________ways to hook up the meters:
ammeter – measures current passing ____________ R - Ideally, it has no ____, so no ________ across it
voltmeter – measures potential difference _________ R - Ideally, it does not allow any ____ to enter it
R
A simple circuit with ____________:
The voltmeter must be connected across _______________ sides of Rto measure potential _____________.
Ohm’s Law: For __________________ conductors at _______________ temp., I is ___________ prop. to V.
V
I
V
I
Case A: a device obeys Ohm’s Law _____________
Case B: ________________ devices
slope = ΔV/ΔI = constantso the ratio V/I = ____ is ___________
slope = V/I = R is ________________
Remember:V ____________ I So changing V _______________ I.
(Traditionally, V is plotted on the ____ axis)
In the case shown, R _______________
Ex. If R is _____________ , then I is _____________ .
V
Ex. If R is ___________ , then I is _____________ .
= V
As R ____, I ____ . This is an ___________ circuit.
= V R =
V R =
This situation can be _______________________________ .Body resistance can be lowered by getting __________ .
As R ____, I ____ . This is a ___________ circuit.
Currents and the harm they can cause:
"It's _______________ that jolts, (shocks you)
But it's ___________ (milliamps of current) that kills."
AC tends to send heart nerves into _______________, which can be harder to fix than simply ________________________.
A__________, short for 'fusible link', is a type of
overcurrent protection device. Its essential
component is a
__________________________________________________
____________________ . Fuses usually are rated in
_______________ . If the current exceeds the rating, the
metal strip melts, and it _________ the circuit. This
protects the circuit from __________________ which may
damage other circuit parts or ________________ .
A _______________________ is an automatically-
operated electrical ______________ . Like a fuse, it is
designed to protect an electrical circuit from damage
caused by excess_________. Unlike a fuse, which
operates once and then must be replaced, a circuit
breaker ________________ once the problem that caused
the excess current is fixed.
A downed power linecan set up a _________through the ground.
Since the cables have _______ R, most voltage will be dropped along_________________ .
If the distance between thedowned line and the sourceis _________, there can be large _________ between2 nearby points along theground between your feet.___________ or ____________!
IV. Series circuits - _______________________________________________________________________________________
Assume:
1. _____________________________________________________
2. _____________________________________________________
3. _____________________________________________________
4. _____________________________________________________
circuitelement ___
voltage source circuit
element ___
circuitelement ___
wire________potential
________potential
wire
wirewire
_______________ Conservation: V =
_______________ Conservation: I =
_______________ (Total) Resistance: Req =
__________ Law applies to the total: V = and to each individual element: V1 =
V2 =
For a circuitwith 2 resistors:
Ex. Find all the voltages and currents in the circuit below:
20. V 40
120
V1 = I1 = R1 =
V2 = I2 = R2 =
V = I = Req =
V = 20. V
40
120
•V “divides up” ______________________________ as the R’s•This is because ___________ R requires _________ energy.•Series circuits are _______________________________.
Form the __________ of each resistance to Req = ________ ,
and then multiply by the ___________ voltage V.
R1
Req
R2
Req
Plot V vs. “distance around circuit.”
20
15
V dropped across the ______ resistor
0
back to ____side of thebattery
________ drop across wires because we assume ________
distance around circuit
potentialdifference
(V)
____ side ofbattery
V dropped across the ______ R at the ___
side of thebattery
Important:
“I is ______________ everywhere in ___________ circuit” does
NOT mean that I is ___________ in _________________ circuit!
10. V R1=
R2 =
I =
I1 =
I2 =
10. V R2=
R3=
I =
I1 =
I2 =
I3 =
I is still the _______________ in all parts of the second circuit, but it is a ________________ I than the first one!
R1=
Equivalent resistance: _________________________________
________________________________________________________
The total I =
20. V40
120
Replacing this part of thecircuit with a single_______________ resistor:
Req = R1 + R2 =
=
…gives you this circuit:
20. V
This is the ____________ as before.
V = 20 V
V = 12 V
All _______________ circuits can be ___________________ in this way.
This can be done even if the ______________________ is not shown.
Req =
_____ V = 20 V
V = 12 V
Req results in the _____________ as the _________________ circuit.
A.
B.
C.
D.
Req =
_____
Req =
_____
Req =
_____
Series Circuits__________ Hookups:
V R1
R2
Original circuit:
To measure I1, the current through R1, _________________ the circuit and ____________ an ________________ next to R1.
V R1
R2
V R1
R2
Other possibilities: V R1
R2
V R1
R2
___ is the same everywhere, so _________________________
To measure V1, the voltage across R1, __________disconnect the circuit. Simply connect the ______________ across R1
Other possibilities:
V R1
R2
V R1
R2
Original circuit:
V R1
R2
V R1
R2
Similarly, to measure the _________ voltage V or V2:
V R1
R2
V R1
R2
V. Parallel circuits - ___________________________________ ___________________________________________
Assume:
1. _____________________________________________________
2. _____________________________________________________
3. _____________________________________________________
4. _____________________________________________________
voltage source
wire________potential
________potential
wirewire
wire
circuitelement ___
circuitelement ___
circuitelement ___
circuitelement ___
wire
_______________ Conservation: V =
_______________ Conservation: I =
_______________ (Total) R: 1/Req =
__________ Law applies to the total: V = and to each individual element: V1 =
V2 =
For a circuitwith 2 resistors:
V1 = I1 = R1 =
V2 = I2 = R2 =
V = I = Req =
Ex. Find all the voltages and currents in the circuit below:
To find Req without using V and I:
1 Req
= 1 R1
+ 1 R2
=
=
=
=
NOTE: In a ________________ circuit,
Req is __________________ either R1 or R2.
•I “divides up” ______________________________ to the R’s
•R1 has ______ the current b/c it has __________resistance.
•Parallel circuits are _______________________________.
Compare the _________ of the resistances R1/R2 to the __________ of the currents: I1/I2.
I1
I2
R1
R2
But…
20. V 50 100
Notice what happens if one branch is __________________ :
I1= V1/R1
I2= V2/R2
20. V 50 100
These are ____________________ answers as before.
Each branch is_______________________of the others.
This is why __________________ circuits are used.
Plot V vs. “distance around circuit.”
20
____ resistor
0
back to ____side of thebattery
______ drop across wires because we assume _________
distance around circuit
potentialdifference
(V)
____ side ofbattery
_____ resistor at the ___side of thebattery
Important:
“V is ______________ everywhere in ___________ circuit” does
NOT mean that V is ___________ in ______________ circuit!
10. V R2=R1 =V=
V1=
V2=
20. V R2=
V =
V1 =
V2 =
V is the _______________ across all parts of the second circuit, but it is a ________________ V than the first one!
R1 =
Equivalent resistance: _________________________________
________________________________________________________
The total I =
Replacing this part of thecircuit with a single_______________ resistor:
Req = 1/(1/R1 + 1/R2)
= = =
…gives you this circuit:
20. V
This is the ____________ as before.
V = 3.0 V
All _______________ circuits can be ___________________ in this way.
This can be done even if the ______________________ is not shown.
Req = ____
V = 3.0 V
Req results in the _____________ as the _________________ circuit.
A.
B.
C.
Req =
_____
Req =
_____
Alternative ways to draw parallel circuits:
V R1 R2
The circuitat left can also be drawn:
or:
NOTE: The diagram below is _________________________
because there is ________________
__________ for the current.
V
or:
V V
V
Ex 1. Draw two 10- resistors in parallel between points A and B.
What is the equivalent resistance between points Aand B in each of the examples above? (Hint: For identicalparallel resistors, divide 1 R by the ___________ of resistors.)
A B
Ex 2. Draw three 60- resistors in parallel between points A and B.
A
B
Ex 1: Divide _______ by ____ Req = __________
Ex 2: Divide _______ by ____ Req = __________
Parallel Circuit__________ Hookups:
Original circuit:
V R1 R2
A. To measure, V1, the voltage across R1, connect the ______________ across R1.
V R2
To measure I1, the current through R1, _________________ the circuit and _____________ an ________________ next to R1
____ = where the ammeter could also be placed.
B. To measure the voltage _____________ and the current __________ resistor R2:
V R1
C. To measure the _________ voltage and current :
R1 R2
___ = optional ammeter position
___ = optional ammeter position
In an ideal parallel circuit, all of the ______________
are equal, so placing the ________________ across any
element gives ___________________________ .
V R1R2
In reality, each voltage will _______________________ .
This is because the wires have a small amount of ______ ,
and so by Ohm's law: __________ , there is a small amount
of _________________ dropped along each wire.
VI. Electrical Power P is the _________ at which electrical _____________________________ light, heat, mechanical, etc, energy or vice versa.
P
P is a _____________
The units of P are watts, W ( _____________ )
Electrical work: W =
1 watt = 1 W =
=
=
Since W = , you can write:
Ex. At what rate is electrical energy converted to heatand light in a 75 W bulb?
Ex: A 55-W toaster oven is used for 25 seconds. How much electrical energy is converted to heat?
Ex. A 12- resistor carries a current of 3.0 A for 5.0 s. a/ At what rate does the resistor convert energy?
b/ How much energy does the resistor convert in the 5.0 s?
Ex: How much power is developed in the circuit at right?
Ex. What quantity does P “·” represent?
Given:
At what rate is energy converted to heat?
How much energy is converted in one minute?
VR2
R1
Ex.
R1 R2V
Power of resistor R1: P1 =
or sum up the powers: P =
Power of resistor R2: P2 =
All of these equations work ___________________________ .
Total power: P =
Ex: Find the power in each resistor and the total power.
V1 = I1 = R1 = P1 =
V2 = I2= R2 = P2 =
V = I= R = P =
Ex: Find the power in each resistor and the total power.
V1 = I1 = R1 = P1 =
V2 = I2= R2 = P2 =V = I= R = P =
Which resistor develops more power in the series circuit?
Notice both circuits above have ____________ V, R1 and R2.
Which of the two circuits would drain a battery faster?
Which develops more power in the parallel circuit?
___ b/c both have same ___ but it has more ____________
The ____________ circuit has a ______________ Req.
This means it will have ____________ I. Because
P = ______ and both circuits have the _____ , the
_____________ circuit will develop more power.
___ b/c both have same ___ but it has more ____________
__________________ passed ___________ through a wire that was submerged in __________ and found that the amountof ________ produced was proportional to ____ and _____.This is called_________ or _____ heating. Less ___ means ______________ electrical energy is converted to _______.Because P = ____ , the current can be reduced if ____ is increased. For this reason, power is transmitted at high_____________ .
Power plant:~_____
At your house:_________
The power istransmitted at_____________
A substation cutsthe V to __________