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IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark]...

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8.10.2018 1a. [1 mark] Markscheme f (14) = 4 A1 N1 [1 mark] 1b. [2 marks] Markscheme attempt to substitute (M1) eg g (4), 3 × 4 − 7 5 A1 N2 [2 marks] 1c. [3 marks] Markscheme interchanging x and y (seen anywhere) (M1) eg x = 3y − 7 evidence of correct manipulation (A1) eg x + 7 = 3y A1 N3 [3 marks] 1
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Page 1: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

8.10.2018

1a. [1 mark]

Markscheme

f (14) = 4     A1 N1

[1 mark]

1b. [2 marks]

Markscheme

attempt to substitute     (M1)

eg   g (4), 3 × 4 − 7

5     A1 N2

[2 marks]

1c. [3 marks]

Markscheme

interchanging x and y (seen anywhere)     (M1)

eg   x = 3y − 7

evidence of correct manipulation     (A1)

eg   x + 7 = 3y

     A1 N3

[3 marks]

 

 

2a. [1 mark]

Markscheme

1

Page 2: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

     A1 N1

[1 mark]

2b. [1 mark]

Markscheme

f −1 (1) = 2     A1 N1

[1 mark]

2c. [1 mark]

Markscheme

−2 ≤ y ≤ 2, y [−2, 2]∈   (accept −2 ≤ x ≤ 2)     A1 N1

[1 mark]

2d. [4 marks]

Markscheme

2

Page 3: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

A1A1A1A1  N4

Note: Award A1 for evidence of approximately correct reflection in y = x with correct curvature.

(y = x does not need to be explicitly seen)

Only if this mark is awarded, award marks as follows:

A1 for both correct invariant points in circles,

A1 for the three other points in circles,

A1 for correct domain.

3

Page 4: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

[4 marks]

3a. [2 marks]

Markscheme

recognize that  is the gradient of the tangent at      (M1)

eg   

  (accept m = 3)     A1 N2

[2 marks]

3b. [2 marks]

Markscheme

recognize that       (M1)

eg 

     A1 N2

[2 marks]

3c. [5 marks]

Markscheme

recognize that the gradient of the graph of g is        (M1)

choosing chain rule to find       (M1)

eg  

     A2

     A1

     AG N0

[5 marks]

4

Page 5: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

 

 

3d. [7 marks]

Markscheme

 at Q, L1 = L2 (seen anywhere)      (M1)

recognize that the gradient of L2 is g'(1)  (seen anywhere)     (M1)

eg  m = 6

finding g (1)  (seen anywhere)      (A1)

eg   

attempt to substitute gradient and/or coordinates into equation of a straight line      M1

eg   

correct equation for L2 

eg         A1

correct working to find Q       (A1)

eg   same y-intercept, 

     A1 N2

[7 marks]

 

4a. [2 marks]

Markscheme

5

Page 6: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

A2 N2

[2 marks]

4b. [4 marks]

Markscheme

recognizing horizontal shift/translation of 1 unit      (M1)

eg  b = 1, moved 1 right

recognizing vertical stretch/dilation with scale factor 2      (M1)

eg   a = 2,  y ×(−2)

a = −2,  b = −1     A1A1 N2N2

[4 marks]

5a. [1 mark]

Markscheme

(1,5) (exact)      A1 N1

6

Page 7: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

[1 mark]

5b. [3 marks]

Markscheme

      A1A1A1   N3

Note: The shape must be a concave-down parabola.

Only if the shape is correct, award the following for points in circles:

A1 for vertex,

A1 for correct intersection points,

A1 for correct endpoints.

7

Page 8: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

[3 marks]

5c. [3 marks]

Markscheme

integrating and subtracting functions (in any order)      (M1)

eg   

correct substitution of limits or functions (accept missing dx, but do not accept any errors, including

extra bits)     (A1)

eg 

area = 9  (exact)      A1 N2

[3 marks]

6a. [1 mark]

Markscheme

correct range (do not accept )     A1     N1

eg

[1 mark]

6b. [1 mark]

Markscheme

    A1     N1

[1 mark]

6c. [1 mark]

Markscheme

    A1     N1

[1 mark]

6d. [3 marks]

8

Page 9: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

Markscheme

     A1A1A1    

N3

 

Notes:     Award A1 for both end points within circles,

A1 for images of and within circles,

A1 for approximately correct reflection in , concave up then concave down shape (do not accept

line segments).

9

Page 10: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

 

[3 marks]

7a. [2 marks]

Markscheme

attempt to form composite     (M1)

eg

correct function     A1     N2

eg

[2 marks]

7b. [4 marks]

Markscheme

evidence of     (M1)

eg , graph with horizontal asymptote when

 

Note:     Award M0 if candidate clearly has incorrect limit, such as .

 

evidence that (seen anywhere)     (A1)

eg , graph of or

with asymptote , graph of composite function with asymptote

correct working     (A1)

eg

    A1     N2

[4 marks]

10

Page 11: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

8a. [2 marks]

Markscheme

valid approach     (M1)

eg

0.816496

(exact), 0.816     A1     N2

[2 marks]

8b. [2 marks]

Markscheme

    A1A1     N2

[2 marks]

8c. [3 marks]

Markscheme

11

Page 12: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

     A1A1A1    

N3

 

Notes:     Award A1 for correct domain and endpoints at and in circles,

A1 for maximum in square,

A1 for approximately correct shape that passes through their -intercept in circle and has changed

from concave down to concave up between 2.29 and 7.

 

[3 marks]

9a. [2 marks]

12

Page 13: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

Markscheme

interchanging and     (M1)

eg

    A1     N2

[2 marks]

9b. [3 marks]

Markscheme

METHOD 1

attempt to substitute 7 into or     (M1)

eg

    (A1)

    A1     N2

 

METHOD 2

attempt to form composite function (in any order)     (M1)

eg

correct substitution     (A1)

eg

    A1     N2

[3 marks]

10a. [2 marks]

Markscheme

13

Page 14: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

correct interval     A2     N2

eg , from 0 to 6

[2 marks]

10b. [2 marks]

Markscheme

     M1A1     N2

 

Note:     Award M1 for a horizontal shift of the whole shape, 5 units to the left or right and A1 for the

correct graph.

 

[2 marks]

10c. [2 marks]

Markscheme

correct interval     A2     N2

14

Page 15: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

eg , from to 3

[2 marks]

11a. [2 marks]

Markscheme

attempt to form composite in either order     (M1)

eg

    A1

    AG     N0

[2 marks]

11b. [3 marks]

Markscheme

15

Page 16: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

   A1

A1A1     N3

 

Note:     Award A1 for approximately correct shape which changes from concave down to concave up.

Only if this A1 is awarded, award the following:

A1 for left hand endpoint in circle and right hand endpoint in oval,

A1 for minimum in oval.

 

16

Page 17: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

[3 marks]

11c. [3 marks]

Markscheme

evidence of identifying max/min as relevant points     (M1)

eg

correct interval (inclusion/exclusion of endpoints must be correct)     A2     N3

eg

[3 marks]

12a. [2 marks]

Markscheme

attempt to substitute      (M1)

eg

   A1     N2

[2 marks]

12b. [2 marks]

Markscheme

attempt to form composition (in any order)     (M1)

eg

     A1     N2

[2 marks]

12c. [3 marks]

Markscheme

valid approach     (M1)

17

Page 18: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

eg     , 

     A1A1     N3

[3 marks]

13a. [2 marks]

Markscheme

     A1A1     N2

[2 marks]

13b. [5 marks]

Markscheme

18

Page 19: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

(i) (ii)          A1

A1A1A1     N4

A1     N1

 

Notes: (i) Award A1 for correct cubic shape with correct curvature.

Only if this A1 is awarded, award the following:

A1 for passing through their point A and the origin,

A1 for endpoints,

A1 for maximum.

(ii) Award A1 for horizontal line through their A.

 

[5 marks]

19

Page 20: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

14a. [3 marks]

Markscheme

valid attempt to find the intersection     (M1)

eg , sketch, one correct answer

     A1A1     N3

[3 marks]

14b. [3 marks]

Markscheme

attempt to set up an integral involving subtraction (in any order)     (M1)

eg

0.537667

     A2     N3

[3 marks]

15a. [1 mark]

Markscheme

   A1     N1

[1 mark]

15b. [2 marks]

Markscheme

attempt to form composite (in any order)     (M1)

eg

    A1     N2

20

Page 21: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

[2 marks]

15c. [2 marks]

Markscheme

interchanging and (may be seen at any time)     (M1)

eg

     A1     N2

[2 marks]

16a. [3 marks]

Markscheme

(i)     3     A1     N1

(ii)     valid attempt to find the period     (M1)

eg

period      A1     N2

[3 marks]

16b. [4 marks]

Markscheme

21

Page 22: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

     A1A1A1A1     N4

[4 marks]

17a. [2 marks]

Markscheme

attempt to form composite     (M1)

e.g.

     A1     N2

[2 marks]

17b. [3 marks]

Markscheme

interchanging x and y     (M1)

22

Page 23: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

evidence of correct manipulation     (A1)

e.g. ,

     A1       N3

[3 marks]

18a. [5 marks]

Markscheme

(i)      (A1)

     A1        N2

(ii) METHOD 1

substituting answer from (i)     (M1)

e.g.

correct substitution      (A1)

     A1       N3

METHOD 2

attempt to find      (M1)

e.g.

correct expression for      (A1)

e.g.

     A1       N3

[5 marks]

18b. [3 marks]

Markscheme

23

Page 24: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

interchanging x and y (seen anywhere)     (M1)

e.g.

attempt to solve     (M1)

e.g.

     A1       N3

[3 marks]

19a. [3 marks]

Markscheme

METHOD 1

recognizing that      (M1)

e.g.

recognizing that       (A1)

e.g.

     A1       N2

METHOD 2

attempt to find the inverse of      (M1)

e.g. ,

substituting 1 and 8     (M1)

e.g. , 

       A1       N2

[3 marks]

24

Page 25: IB Questionbank Test · Web viewx + 7 = 3 y A1 N3 [3 marks] 2a. [1 mark] Markscheme A1 N1 [1 mark] 2b. [1 mark] Markscheme f −1 (1) = 2 ... attempt to substitute gradient and/or

19b. [4 marks]

Markscheme

METHOD 1

recognizing that      (M1)

e.g.

     (A1)

(accept )     A2       N3

METHOD 2

attempt to find inverse of      (M1)

e.g. interchanging x and y , substituting into

correct inverse     (A1)

e.g. ,

     A2     N3

[4 marks]

Printed for International School of Monza

© International Baccalaureate Organization 2018

International Baccalaureate® - Baccalauréat International® - Bachillerato Internacional®

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