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Interaction of EMR with theSurface and Atmosphere II
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Conservation of energy at the surface
A + T + R = 1 - sum of the
absorptance, reflectance and
transmittance remains equal 1
Absorptance A = a()/i(),
Reflectance R = r()/i(),
Transmittance T=
t()/
i()
Absorption (a =A /l, m-1) is a loss of energy in a medium at specific
frequency (wavelength). It occurs because of the excitation of atoms and
molecules the energy is transformed to heat. Ex: absorption bychlorophyll in the process of photosynthesis.
Transmission is a propagation of energy through a medium.
i
Ai
Ti
Ri
l
Reflection is the change in direction of a wave front at the boundary oftwo media so that the wave front returns into the medium from which it
originated.
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Conservation of energy in the
volume
z
F0
F
- Incident flux
- Absorbed flux
- Scattered flux
- Transmitted fluxt
a
s
i
a absorption
coefficient, m-1
Fdz
dFa= dzF
dFa=
])(exp[)()( 0 zFF a =
- fraction of theincident power that is
absorbed by the slab
Very frequent form
in optics])(exp[)()( 0 zII a =
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Absorption, scattering and
extinction coefficients
a
absorption coefficient, m-1
s scattering coefficient, m-1
e extinction coefficient, m-1
Scattering is the deflection of electromagnetic radiation without absorption
as a result of its interaction with particles.
The sum of the absorption and scattering represents the loss of energy from
the forward-propagating radiation and is called attenuation or extinction.
)()()( saext +=
])(exp[)()( 0 zII ss =])(exp[)()( 0 zII aa =
])(exp[)()( 0 zII extext =
zext
)()(Optical thickness:
(non-dimensional)
= dzzz
ext
=
0
),()( or
Transmittance: ))(exp())(exp()(
)()(
0
=== z
I
IT ext
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Absorption and scattering by
particles
Absorption cross-section, m2: Naa /)()( =
If N is the number of particles in the volume, 1/m3
or Naa =Scattering cross-section, m2: Nss /(( )=) or Nss =
Extinction cross-section, m2:
Nextsaext /)()()()( =+= or Nextext =
])(exp[)()(0
zNIIa
=
FP a
- Beer-Lambert law
=Cross-section can be considered as the absorbed power P
by the particle per the incident flux F, it can be compared
with the geometrical cross-section of the particle
zNz extext )()()(Optical thickness: === drrNrextext )()(
If the scattering particles have size
distribution, for each :
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Absorption and scattering by
particles
These relationships are true for solid
surfaces (soil, leaves) small penetration
For water (absorption by water itself and
organic components, scattering byphytoplankton and mineral particles)-deeper penetration (1-50 m)
For atmosphere (absorption by gases andwater vapor, scattering by molecules andaerosols) dozens of km
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Fluorescence, Raman scattering
We have considered so far elastic scattering effects in which the wavelength ofthe radiation is unchanged by the scattering process. Fluorescence and Raman
scattering belong to inelastic processes in which excitation wavelengths are
different from the emitting wavelength.
Typical example of
fluorescence is the
chlorophyll fluorescence
which occurs as a result
of illumination of leaves
and phytoplankton inwater. Part of the light
absorbed in the 400-700
nm range is emitted as
fluorescence signal inthe red near 685 nm
Raman scattering is another trans-spectral process: as a result light
emits at higher or lower frequency or at several frequency pairs.
Inelastic effects are useful for tracing specific substances with
known fluorescence or Raman signatures
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Absorption of Gases in the
AtmosphereMechanisms of molecular absorption:
1. Promotion of electrons to higher energy level electronic transitions;
absorption lines appear in UV and VIS
2. Vibration energy levels absorption lines in the thermal infrared region
3. Rotation energy levels absorption lines are in the microwave and far IR
4. Combinations of mechanisms
Line broadening: narrow absorption bands
become broader due to the additional
processes in the atmosphere
Thermal motion (Doppler boadening):
Pressure broadening (collision):
2cMRT
ff
m
=
RTM
pf
m
~
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Scattering by particles
rx
2=
In the most simple case, atmospheric particles can be considered as
small spheres.
The rigorous solution for the scattering of a plane monochromatic
wave by a spherical dielectric particle with an index of refraction n
was derived by Mie.
This solution establishes for given index of refraction n of particles
relationship between scattering and extinction cross sections and the
parameter
where r is the radius
of the sphere, so
)(xfs = and )(xfext =
Ratio r/ determines the type of scattering
Function which defines probability of light scattering
in various directions called phase function)(pp =
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Comparison of Raleigh and Mie
Scattering Regimes
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Sky is blue
Blue light is most efficiently scattered
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Why are sunsets red ???
Blue
scattered
away
Long Path compared to noon
Green
scattered
away
Yellow
scattered
away
Orangescattered
away
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Clouds in contrast to the blue sky
appear white to achromatic gray.
The water droplets that make up the cloud are much larger than the
molecules of the air and the scattering from them is almost independent
of wavelength in the visible range.
Scattering from the clouds
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Average Composition of the
Atmosphere Below 25 kmCom p on en t Ch em ical Ab b r ev iat ion
Vo lume %( d r y a ir )
Nitrogen N2 78.08
Oxygen O2 20.98
Argon Ar 0.93
Carbon dioxide CO2 0.035
Neon Ne 0.0018
Helium He 0.0005
Hydrogen H2 0.00006
Krypton
Kr 0.0011
Xenon Xe 0.00009
Methane CH4 0.0017
Ozone O3 0.00006
This gaseous mixture remains remarkably uniform in composition, and is the result of
efficient biogeochemical recycling processes and turbulent mixing in the atmosphere.
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Water Vapor
)(Tp
pH
sat
water
=
There is also a significant but variable amount of water vapor (0.1-3%)specified by relative humidity H
waterp
H =0100%
is the partial pressure of the water vapor product of the total
atmospheric pressure with volume fraction of water vapor
)(Tpsat is the saturated vapor pressure of water at temperature T
For t =20C psat = 2.34 kPa, so if total atm pressure is 100 kPa and humidity is
80% the volume fraction of water vapor is f = psat*H*100/ptot = 1.9%
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Atmospheric Vertical Structure of
Temperature and Pressure
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Atmospheric Vertical Structure of
Temperature and Pressure (cont.)
RT
pMm=
Where is the gas density, kg/m3, p is the
pressure, Newton/m2, T- temperature, K, R is
the gas constant, R=8,314 J/K, Mm is the kmole
mass in kg, for air 28.97kg
dzzgzdp )()( =Expression basically states that the difference of
pressure between levels z and z+dz is equal to
the weight of the atmosphere between two
levels
Combining equationsdzRT
Mg
p
dp m=
mgM
RTH =
)/exp()0()( Hzpzp =
Scale height
If T=const pressure decreases exponentially
with altitude. The same is true for density and
number density N (molecules/m3
)(0) = 1.21 kg/m3, p(0) =105Pa
)/exp()0()( Hzz = )/exp()0()( HzNzN =
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Atmospheric Vertical Structure of
Temperature and Pressure (cont.)
The above illustrations assumed an isothermal atmosphere. Usually this
is not exactly true. The change of the atmospheric temperature can be
derived for a simplified case assuming thermal equilibrium. It can be
shown that rate of temperature change is 9.81 K/km.
Actual change is lower and is about 6.5 K/km
At higher altitudes the temperature profile is more complex.
VIIRS, MODIS, FY-1C, AVHRR
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, , ,
H2O
H2OH2O
H2O
O2
CO2
CO2
H2O
O2
O3
H2O
O2
Comparison of Solar and Thermal Radiation
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Comparison of Solar and Thermal Radiation
with Transmission Bands
O ti l Thi k d
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Optical Thickness and
TransmittanceOptical thickness from different materials will add:
total = 1 + 2 + 3 + .
...
321321 ...)( ++
== eeeIeII ooI = IoT1T2T3
Optical thickness is additive, transmittance is multiplicative.
= 1/cos
B L b t L f th
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Beer-Lambert Law for the
atmosphereThe Beer-Lambert law for the atmosphere is usually written as
where each x is the optical depth whose subscript identifies the source of
the absorption or scattering it describes:
a refers to aerosols (that absorb and scatter)
g are uniformly mixed gases (mainly carbon dioxide (CO2) and
molecular oxygen (O2) which only absorb) NO2 is nitrogen dioxide, mainly due to urban pollution (absorption
only)
w is water vapour absorption
O3 is ozone (absorption only) r is Rayleigh scattering from molecular oxygen (O2) and nitrogen
(N2) (responsible for the blue color of the sky).
m is the optical mass or airmass factor, a term approximately equal (for
small and moderate values of) to 1 / cos(), where is the observed
object's zenith angle (the angle measured from the direction perpendicular
to the Earth's surface at the observation site).
))(exp(32
0 rOwNOgamII +++++=