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Interaction With the Surface and AtmosphereII

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    Interaction of EMR with theSurface and Atmosphere II

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    Conservation of energy at the surface

    A + T + R = 1 - sum of the

    absorptance, reflectance and

    transmittance remains equal 1

    Absorptance A = a()/i(),

    Reflectance R = r()/i(),

    Transmittance T=

    t()/

    i()

    Absorption (a =A /l, m-1) is a loss of energy in a medium at specific

    frequency (wavelength). It occurs because of the excitation of atoms and

    molecules the energy is transformed to heat. Ex: absorption bychlorophyll in the process of photosynthesis.

    Transmission is a propagation of energy through a medium.

    i

    Ai

    Ti

    Ri

    l

    Reflection is the change in direction of a wave front at the boundary oftwo media so that the wave front returns into the medium from which it

    originated.

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    Conservation of energy in the

    volume

    z

    F0

    F

    - Incident flux

    - Absorbed flux

    - Scattered flux

    - Transmitted fluxt

    a

    s

    i

    a absorption

    coefficient, m-1

    Fdz

    dFa= dzF

    dFa=

    ])(exp[)()( 0 zFF a =

    - fraction of theincident power that is

    absorbed by the slab

    Very frequent form

    in optics])(exp[)()( 0 zII a =

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    Absorption, scattering and

    extinction coefficients

    a

    absorption coefficient, m-1

    s scattering coefficient, m-1

    e extinction coefficient, m-1

    Scattering is the deflection of electromagnetic radiation without absorption

    as a result of its interaction with particles.

    The sum of the absorption and scattering represents the loss of energy from

    the forward-propagating radiation and is called attenuation or extinction.

    )()()( saext +=

    ])(exp[)()( 0 zII ss =])(exp[)()( 0 zII aa =

    ])(exp[)()( 0 zII extext =

    zext

    )()(Optical thickness:

    (non-dimensional)

    = dzzz

    ext

    =

    0

    ),()( or

    Transmittance: ))(exp())(exp()(

    )()(

    0

    === z

    I

    IT ext

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    Absorption and scattering by

    particles

    Absorption cross-section, m2: Naa /)()( =

    If N is the number of particles in the volume, 1/m3

    or Naa =Scattering cross-section, m2: Nss /(( )=) or Nss =

    Extinction cross-section, m2:

    Nextsaext /)()()()( =+= or Nextext =

    ])(exp[)()(0

    zNIIa

    =

    FP a

    - Beer-Lambert law

    =Cross-section can be considered as the absorbed power P

    by the particle per the incident flux F, it can be compared

    with the geometrical cross-section of the particle

    zNz extext )()()(Optical thickness: === drrNrextext )()(

    If the scattering particles have size

    distribution, for each :

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    Absorption and scattering by

    particles

    These relationships are true for solid

    surfaces (soil, leaves) small penetration

    For water (absorption by water itself and

    organic components, scattering byphytoplankton and mineral particles)-deeper penetration (1-50 m)

    For atmosphere (absorption by gases andwater vapor, scattering by molecules andaerosols) dozens of km

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    Fluorescence, Raman scattering

    We have considered so far elastic scattering effects in which the wavelength ofthe radiation is unchanged by the scattering process. Fluorescence and Raman

    scattering belong to inelastic processes in which excitation wavelengths are

    different from the emitting wavelength.

    Typical example of

    fluorescence is the

    chlorophyll fluorescence

    which occurs as a result

    of illumination of leaves

    and phytoplankton inwater. Part of the light

    absorbed in the 400-700

    nm range is emitted as

    fluorescence signal inthe red near 685 nm

    Raman scattering is another trans-spectral process: as a result light

    emits at higher or lower frequency or at several frequency pairs.

    Inelastic effects are useful for tracing specific substances with

    known fluorescence or Raman signatures

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    Absorption of Gases in the

    AtmosphereMechanisms of molecular absorption:

    1. Promotion of electrons to higher energy level electronic transitions;

    absorption lines appear in UV and VIS

    2. Vibration energy levels absorption lines in the thermal infrared region

    3. Rotation energy levels absorption lines are in the microwave and far IR

    4. Combinations of mechanisms

    Line broadening: narrow absorption bands

    become broader due to the additional

    processes in the atmosphere

    Thermal motion (Doppler boadening):

    Pressure broadening (collision):

    2cMRT

    ff

    m

    =

    RTM

    pf

    m

    ~

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    Scattering by particles

    rx

    2=

    In the most simple case, atmospheric particles can be considered as

    small spheres.

    The rigorous solution for the scattering of a plane monochromatic

    wave by a spherical dielectric particle with an index of refraction n

    was derived by Mie.

    This solution establishes for given index of refraction n of particles

    relationship between scattering and extinction cross sections and the

    parameter

    where r is the radius

    of the sphere, so

    )(xfs = and )(xfext =

    Ratio r/ determines the type of scattering

    Function which defines probability of light scattering

    in various directions called phase function)(pp =

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    Comparison of Raleigh and Mie

    Scattering Regimes

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    Sky is blue

    Blue light is most efficiently scattered

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    Why are sunsets red ???

    Blue

    scattered

    away

    Long Path compared to noon

    Green

    scattered

    away

    Yellow

    scattered

    away

    Orangescattered

    away

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    Clouds in contrast to the blue sky

    appear white to achromatic gray.

    The water droplets that make up the cloud are much larger than the

    molecules of the air and the scattering from them is almost independent

    of wavelength in the visible range.

    Scattering from the clouds

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    Average Composition of the

    Atmosphere Below 25 kmCom p on en t Ch em ical Ab b r ev iat ion

    Vo lume %( d r y a ir )

    Nitrogen N2 78.08

    Oxygen O2 20.98

    Argon Ar 0.93

    Carbon dioxide CO2 0.035

    Neon Ne 0.0018

    Helium He 0.0005

    Hydrogen H2 0.00006

    Krypton

    Kr 0.0011

    Xenon Xe 0.00009

    Methane CH4 0.0017

    Ozone O3 0.00006

    This gaseous mixture remains remarkably uniform in composition, and is the result of

    efficient biogeochemical recycling processes and turbulent mixing in the atmosphere.

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    Water Vapor

    )(Tp

    pH

    sat

    water

    =

    There is also a significant but variable amount of water vapor (0.1-3%)specified by relative humidity H

    waterp

    H =0100%

    is the partial pressure of the water vapor product of the total

    atmospheric pressure with volume fraction of water vapor

    )(Tpsat is the saturated vapor pressure of water at temperature T

    For t =20C psat = 2.34 kPa, so if total atm pressure is 100 kPa and humidity is

    80% the volume fraction of water vapor is f = psat*H*100/ptot = 1.9%

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    Atmospheric Vertical Structure of

    Temperature and Pressure

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    Atmospheric Vertical Structure of

    Temperature and Pressure (cont.)

    RT

    pMm=

    Where is the gas density, kg/m3, p is the

    pressure, Newton/m2, T- temperature, K, R is

    the gas constant, R=8,314 J/K, Mm is the kmole

    mass in kg, for air 28.97kg

    dzzgzdp )()( =Expression basically states that the difference of

    pressure between levels z and z+dz is equal to

    the weight of the atmosphere between two

    levels

    Combining equationsdzRT

    Mg

    p

    dp m=

    mgM

    RTH =

    )/exp()0()( Hzpzp =

    Scale height

    If T=const pressure decreases exponentially

    with altitude. The same is true for density and

    number density N (molecules/m3

    )(0) = 1.21 kg/m3, p(0) =105Pa

    )/exp()0()( Hzz = )/exp()0()( HzNzN =

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    Atmospheric Vertical Structure of

    Temperature and Pressure (cont.)

    The above illustrations assumed an isothermal atmosphere. Usually this

    is not exactly true. The change of the atmospheric temperature can be

    derived for a simplified case assuming thermal equilibrium. It can be

    shown that rate of temperature change is 9.81 K/km.

    Actual change is lower and is about 6.5 K/km

    At higher altitudes the temperature profile is more complex.

    VIIRS, MODIS, FY-1C, AVHRR

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    , , ,

    H2O

    H2OH2O

    H2O

    O2

    CO2

    CO2

    H2O

    O2

    O3

    H2O

    O2

    Comparison of Solar and Thermal Radiation

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    Comparison of Solar and Thermal Radiation

    with Transmission Bands

    O ti l Thi k d

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    Optical Thickness and

    TransmittanceOptical thickness from different materials will add:

    total = 1 + 2 + 3 + .

    ...

    321321 ...)( ++

    == eeeIeII ooI = IoT1T2T3

    Optical thickness is additive, transmittance is multiplicative.

    = 1/cos

    B L b t L f th

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    Beer-Lambert Law for the

    atmosphereThe Beer-Lambert law for the atmosphere is usually written as

    where each x is the optical depth whose subscript identifies the source of

    the absorption or scattering it describes:

    a refers to aerosols (that absorb and scatter)

    g are uniformly mixed gases (mainly carbon dioxide (CO2) and

    molecular oxygen (O2) which only absorb) NO2 is nitrogen dioxide, mainly due to urban pollution (absorption

    only)

    w is water vapour absorption

    O3 is ozone (absorption only) r is Rayleigh scattering from molecular oxygen (O2) and nitrogen

    (N2) (responsible for the blue color of the sky).

    m is the optical mass or airmass factor, a term approximately equal (for

    small and moderate values of) to 1 / cos(), where is the observed

    object's zenith angle (the angle measured from the direction perpendicular

    to the Earth's surface at the observation site).

    ))(exp(32

    0 rOwNOgamII +++++=


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