+ All Categories
Home > Documents > Intermediate Quantum 491: Homework 1 Solutions g

Intermediate Quantum 491: Homework 1 Solutions g

Date post: 12-Feb-2022
Category:
Upload: others
View: 5 times
Download: 0 times
Share this document with a friend
8
Intermediate Quantum 491: Homework 1 Solutions 1-1 Consider the sets of test grades g i = 75.71 71.43 41.43 64.29 77.14 65.71 58.57 68.57 24.29 54.29 48.57 68.57 78.57 61.43 58.57 Then we get the mean = 61.1, STD = 14.6. Figure 1: Histogram of data with 10 bins from 0 to 100: hxi = 60.x = 14.1 Let bin centers be x[i] and number in each bin n[i] with n[i]= N the total number of grades. Then mean hxi = n[i]x[i] N and variance x) 2 = n[i](x[i] -hxi) 2 N - 1 Where we divide by N-1 because we used the data to calculate the mean. The probability to have a grade in the i th bin is estimated from this data as p[i]= n[i]/N .
Transcript
Page 1: Intermediate Quantum 491: Homework 1 Solutions g

Intermediate Quantum 491: Homework 1 Solutions

1-1

Consider the sets of test grades gi = 75.71 71.43 41.43 64.29 77.14 65.7158.57 68.57 24.29 54.29 48.57 68.57 78.57 61.43 58.57

Then we get the mean = 61.1, STD = 14.6.

Figure 1: Histogram of data with 10 bins from 0 to 100: 〈x〉 = 60.3 ∆x = 14.1

Let bin centers be x[i] and number in each bin n[i] with∑

n[i] = Nthe total number of grades.

Then mean

〈x〉 =

∑n[i]x[i]

N

and variance

(∆x)2 =

∑n[i](x[i]− 〈x〉)2

N − 1

Where we divide by N-1 because we used the data to calculate themean.

The probability to have a grade in the ith bin is estimated from thisdata as p[i] = n[i]/N .

Michael Gold
Michael Gold
Page 2: Intermediate Quantum 491: Homework 1 Solutions g
Page 3: Intermediate Quantum 491: Homework 1 Solutions g
Michael Gold
(1.4)
Page 4: Intermediate Quantum 491: Homework 1 Solutions g
Michael Gold
(1.6)
Page 5: Intermediate Quantum 491: Homework 1 Solutions g
Michael Gold
This P is for inside the range. Outside is 1-P = 1/4
Michael Gold
(1.8)
Page 6: Intermediate Quantum 491: Homework 1 Solutions g
Michael Gold
+
Michael Gold
P has is dimensionless probability, so J has dimensions of inverse time.
Michael Gold
(1.9)
Page 7: Intermediate Quantum 491: Homework 1 Solutions g
Michael Gold
= -(1/𝛕) P
Michael Gold
I check dimensions as c𝞽 = ħc/(2𝝘) = (energy*distance)/(energy)
Michael Gold
(1.10)
Michael Gold
P(t) = exp(-t/𝞽)
Michael Gold
then,
Page 8: Intermediate Quantum 491: Homework 1 Solutions g
Michael Gold
(8) (1.12)

Recommended