+ All Categories
Home > Documents > Introduction to Cryptography

Introduction to Cryptography

Date post: 30-Dec-2015
Category:
Upload: andeana-munoz
View: 115 times
Download: 7 times
Share this document with a friend
Description:
Introduction to Cryptography. Lecture 2. x1. f. f(x1). x2. f(x3). f(x2). x3. Domain. Range. Functions. f. x1. f. x1. f(x1). x2. f(x1). x2. f(x2). f(x2). x3. Range. Range. Domain. Domain. Functions. - PowerPoint PPT Presentation
Popular Tags:
22
Introduction to Cryptography Lecture 2
Transcript

Introduction to Cryptography

Lecture 2

Functions

f(x1)

x3

x2

x1

f(x3)

f(x2)

f

Domain Range

Functions

Definition: A function is a relation, such that each element of a set (the domain) is associated with a unique element of another (possibly the same) set (the range)

f(x1)

x3

x2

x1

f(x2)

f

Domain Range

f(x1)

x2

x1

f(x2)

f

Domain Range

Function Not a function

Definition: A function is called one to one if each element of domain is associated with precisely one element of the range.

Definition: A function is called onto if each element of range is associated with at least one element of the domain.

Functions

Functions

f(x1)

x3

x2

x1

f(x2)

f

Domain Range

f(x1)

x3

x2

x1

f(x2)

f

Domain Range

Not one to one One to one

Onto Not onto

f(x1)

y

Functions

f

A one to one and onto function always has an inverse function

Definition: Given a function an inverse function is computed by rule: if .

Example: If , then .

1f xyf )(1

yxf )(

xyf log)(1 xexf )(

Functions and Cryptography

Cipher can be represented as a function

Example 1:

f(Secret message)= YpbzobqjbZqqyec

Example 2:

f(son) = girl (girl) = son

f(girl) = son (son) = girl

1f1f

For each key, an encryption method defines a one-to-one and onto function; and the corresponding decryption method is the inverse of this function.

Functions and Cryptography

Permutations

Definition: A permutation of n ordered objects is a way of reordering them.

It is a mathematical function It is one-to-one and onto An inverse of permutation is a permutation

Permutations

Example: x 1 2 3 4 5

p(x) 3 1 5 4 2

x 1 2 3 4 5

q(x) 2 5 1 4 3

Prime Numbers

Definition: A prime number is an integer number that has only two divisors: one and itself.

Example: 1, 2,17, 31. Prime numbers distributed irregularly

among the integers There are infinitely many prime numbers

Factoring

The Fundamental Theorem of Arithmetic tells us that every positive integer can be written as a product of powers of primes in essentially one way.

Example: 23176647 2

53290 2

Factoring

Problem of factoring a number is very hard The decision if n is a prime or composite

number is much easier Fermat’s factoring method sometimes can

be used to find any large factors of a number fair quickly (pg.251)

Greatest Common Divisors - GCD

Definition: Let x and y be two integers. The greatest common divisor of x and y is number d such that d divides x and d divides y.

Definition: x and y are relatively prime if gcd(x,y)=1.

Example: gcd(3,16) = 1

gcd(-28,8) = 4 One way to find gcd is by finding

factorization of both numbers Euclidean Algorithm is usually used in

order to find gcd

Greatest Common Divisors - GCD

Let m be a positive integer and let b be any integer. Then there is exactly one pair of integers q (quotient) and r (remainder) such that b = qm +r.

Division Principle

Euclidean Algorithm

Input x and y x0 = x, y0 = y For I >= 0 do xi+1 = yi, yi+1 = xi mod yi

If yi =0, stop Output gcd(x,y) = xi

Euclidean Algorithm

Example: Let x = 4200 and y = 1485

i xi yi qi ri

0 4200 1485 2 1230

1 1485 1230 1 255

2 1230 255 4 210

3 255 210 1 45

4 210 45 4 30

5 45 30 1 15

6 30 15 2 0

7 15 0    

For every x and y there are integers s and t such that sx + ty = gcd(x,y)

We can find s and t using Euclidean Algorithm

Extended Euclidean Algorithm

Extended Euclidean Algorithm

Input x and y x0 = x, y0 = y, s0 = t-1 = 0, t0 = s-1 = 1 For I >= 0 do

xi+1 = yi, yi+1 = xi mod yi,

si+1 = si-1 – qisi, ti+1 = ti-1 - qiti

If yi =0, stop Output gcd(x,y) = xi, si-1,ti-1

Extended Euclidean Algorithm

Example: Let x = 4200 and y = 1485

i xi yi qi ri si ti

0 4200 1485 2 1230 0 1

1 1485 1230 1 255 1 -2

2 1230 255 4 210 -1 3

3 255 210 1 45 5 -14

4 210 45 4 30 -6 17

5 45 30 1 15 29 -82

6 30 15 2 0 -35 99

7 15 0        

Homework

Read Section 1.2. Exercises: 4, 5 on pg.46-47. Read Section 4.1. Exercises: 6(a,c), 11(b,d), on pg.260-262

Those questions will be a part of your collected homework.


Recommended