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Inverter Topology and Control Strategies

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    Basic Three Phase Voltage Source

    Inverter Topology

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    Two Simultaneous Switch Gating

    Scheme

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    Two Switch Gating Scheme-Phase Voltag

    M MM1,M6 M1,M2 M3,M2 M3,M4 M5,M4 M5,M6 M1,M6 M1,M2 M3,M2 M3,M4 M5,M4 M5,M6

    R1

    R2

    R3

    100V

    M1,M6

    R1

    R2

    R3

    M1,M2

    100V

    R1

    R2

    R3

    M3,M2

    100V

    R1

    R2

    R3

    M3,M4

    100V

    R1

    R2

    R3

    M5,M4

    100V

    R1

    R2

    R3

    M5,M6

    100V

    M1 D1

    M4D4

    M3 D3 M5D5

    M6 M2D2

    R1 R2 R3

    R Y B

    N

    100V

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    Two Switch Gating Scheme-Phase Voltage

    Spectra

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    Two Switch Gating Scheme-Line Voltage

    MM1,M6 M1,M2 M3,M2 M3,M4 M5,M4 M5,M6 M1,M6 M1,M2 M3,M2 M3,M4 M5,M4 M5,M6

    R1

    R2

    R3

    100V

    M1,M6

    R1

    R2

    R3

    M1,M2

    100V

    R1

    R2

    R3

    M3,M2

    100V

    R1

    R2

    R3

    M5,M4

    100V

    R1

    R2

    R3

    M5,M6

    100V

    R1

    R2

    R3

    M3,M4

    100V

    M1 D1

    M4D4

    M3D3

    M5D5

    M6 M2D2

    R1 R2 R3

    R Y B

    N

    100V

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    Two Switch Gating Scheme-Line Voltage

    Spectra

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    Three Switch Gating Scheme

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    Three switch gating scheme- Phase voltage

    MM1,M6,M5 M1,M6,M2 M1,M3,M2 M4,M3,M2 M4,M3,M5 M4,M6,M5 M1,M6,M5 M1,M6,M2 M1,M3,M2 M4,M3,M2 M4,M3,M5 M4,M6,M5

    R1

    R2

    R3

    100V

    M1,M6,M5

    R1

    R2

    R3

    M1,M6,M2

    100V

    R1

    R2

    R3

    M1,M3,M2

    100V

    R1

    R2

    R3

    M4,M3,M2

    100V

    R1

    R2

    R3

    M4,M3,M5

    100V

    R1

    R2

    R3

    M4,M6,M5

    100V

    M1 D1

    M4D4

    M3 D3 M5D5

    M6 M2D2

    R1 R2 R3

    R Y B

    N

    100V

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    Three switch gating scheme- Line voltage

    MM1,M6,M5 M1,M6,M2 M1,M3,M2 M4,M3,M2 M4,M3,M5 M4,M6,M5 M1,M6,M5 M1,M6,M2 M1,M3,M2 M4,M3,M2 M4,M3,M5 M4,M6,M5

    R1

    R2

    R3

    100V

    M1,M6,M5

    R1

    R2

    R3

    M1,M6,M2

    100V

    R1

    R2

    R3

    M1,M3,M2

    100V

    R1

    R2

    R3

    M4,M3,M2

    100V

    R1

    R2

    R3

    M4,M3,M5

    100V

    R1

    R2

    R3

    M4,M6,M5

    100V

    M1 D1

    M4D4

    M3D3

    M5D5

    M6 M2D2

    R1 R2 R3

    R Y B

    N

    100V

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    Comparison of the two schemes2 Switch Scheme

    Six step L-L voltage Fourier Series:

    ...13,11,7,5,1

    sin3

    n

    d

    n

    tnV

    Quasi-square phase voltage Fourier Series:

    ...13,11,7,5,1

    3

    sin

    3n

    d

    n

    tn

    V

    3 Switch Scheme

    Quasi-Square L-L voltage Fourier Series:

    ...13,11,7,5,1

    sin32

    n

    dn

    tnV

    Six step phase voltage Fourier Series:

    ...13,11,7,5,1

    3sin

    2

    n

    d

    n

    tn

    V

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    Comparison of the two schemes(2)

    2 SWITCH OR 1200

    SCHEME

    SIX STEP L-L VOLTAGE

    3 SWITCH OR 1800

    SCHEME

    SQUARE L-L VOLTAGE

    PHASE VOLTAGES

    (BALANCED LOAD)

    QUASI-SQUARE SIX-STEP

    L-L RMS VALUEdV

    2

    1= 71 % of dV dV

    3

    2= 82% of dV

    L-L FUNDAMENTAL

    AMPLITUDE dV

    3

    = 95% of dV dV32

    =110% of dV

    RATIO OF mt

    HARMONIC

    AMPLITUDE TO

    FUNDAMENTAL

    m

    1

    m

    1

    dV = dc bus voltage. m (other than fundamental) = 6* any positive integer1.

    Conclusion: The 3 switch scheme gives higher fundamental component of line-line

    voltage. Thus it is preferred for 3 phase motor drives. However with the two switch

    scheme the chances of a shoot-through fault is largely eliminated.

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    Equivalent circuit of induction motors fed

    from inverters

    Harmonic supply voltage,1 = 1 .Harmonic synchronous speed, 1 = 1.(Please refer to section 9.2 of the textbook).(The negative sign because of reverse rotating magnetic field).

    Harmonic slip, =11 =

    11

    111 =

    1 1.

    Examples: = 5, 5 = 515 = 1.2 ; = 7, 7 =71

    7= 0.86; = 11, 11 = 11111 = 1.091; =

    13, 13 = 13113 = 0.923.

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    Equivalent circuit of induction motors

    fed from inverters(2)

    The magnitude of harmonic magnetizing current is negligible as nt harmonic current though it is1

    2 of the fundamental current . Therefore, the magnetizing branch can be open circuited. As themagnitude of1 and2

    are much larger than 1 and 2 the resistors can be neglected and the

    equivalent circuit reduces to the one shown above.

    Now1 = 1;2 = 2.

    The harmonic stator current is given by

    1 =1

    (1+2 )=

    121+2

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    Example using the two switch

    conduction scheme

    A 3 phase, 3 hp, 208 V, 1740 rpm, 60 Hz, 4 pole, Y connected, induction motor is supplied froma constant 300 V dc bus 3 phase inverter in the six pulse mode (2 switches conducting

    simultaneously). The motors equivalent circuit parameters are 1 =2 = 0.5 ,1=2 = 1 , =35 . Find the 1st, 5th, and 7th harmonic line current, output power, torque of the motorwhen it runs at 1740 rpm.

    Solution:

    For the 2 switch scheme, the Fourier series of the phase voltage is given by:

    = 3 sin

    3

    =1,5,7.11.13 .

    Thus the RMS value of the fundamental phase voltage is given by

    1 ( ) = 32 = 32 300 = 117 V

    5 ( ) =1( )

    5=

    117

    5= 23.4 V

    7 ( ) =1( )

    7=

    117

    7= 16.7 V

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    Problem continued

    V1 =117

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    Problem continued(2)1 = 32 22

    1 = 3 7.29

    2 14.5 = 2312

    1 = 01

    =2312

    2

    1740

    60

    = 12.69Nm.

    For 5th

    harmonic and 7th

    harmonic frequencies the equivalent circuit gets modified.

    Slip corresponding to 5th

    harmonic

    5 = 55 =518001740

    51800 = 1.2

    Slip corresponding to 7th harmonic

    7 = 77 =718001740

    71800= 0.86

    Solving the harmonic equivalent circuit,

    5 = 121+2 = 11725(2) = 2.34; 5 = 35 22 155 = 3 2.342 0.5 11.21.2 = 1.37 W;

    5 = 1.3721740

    60

    = 0.071 Nm.

    7 =1

    21+2 =

    117

    49(2)= 1.194; 7 = 37 22

    177

    = 3 1.1942 0.5 10.850.85

    =

    0.377 ; 7 =0.377

    2174060 = 2.07 103

    Nm.

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    Inverter Topologies For Induction Motor

    Drives

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    Limitations of the Two Switch or Three

    Switch Gating Schemes

    With two switch or three switch gating schemes only frequency variation is possible

    through the inverter.

    Voltage variation has to be achieved through controlled rectifiers or choppers which

    supplies the dc bus powering the inverter.

    When fundamental frequency is low these switching schemes will introduce harmonics that

    will cause considerable torque and speed ripple. For example iff1 is 10 Hz,f5 is 50 Hz,

    f7 is 70 Hz etc. All these 50 Hz, 70Hz, 110Hz, 130 Hz components can cause considerable

    current in a 50 Hz or 60 Hz machine and hence torque and speed ripple.

    To overcome this (separate voltage and frequency control and increase of lower order

    harmonics at lower fundamental frequency ) v/f control through the inverter gating

    alone can be achieved through various sinusoidal pulse width modulation

    (SPWM) techniques. Some of them are discussed next.

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    Sinusoidal PWM Inverters

    The inverter topology is same as that of the six-step inverter (see figure, top left). However the

    gating pattern is different.

    For each phase, two synchronized sine and triangle (zero crossing of sine coincides with the zero

    crossing or the peak of triangle) waveforms are compared (see figure, top right) to generate the

    PWM output. This is called natural sampling.The sine is called the modulating wave and the

    triangle is called the carrier wave. Free running sine and triangle waveforms give rise to sub

    harmonics. However, the sine and the triangle can be free running only with low frequency of the

    sine (about < 5 Hz) and high frequency of the triangle. As in the case of the utility supply, the

    sine-waves of each phase are phase shifted by 1200

    from one another as well.

    If is the peak of the sine and the peak of the triangle, then the modulation index (M)=

    defined as

    . Usually is varied and is kept fixed. Also 0 1.

    M1 D1

    M4D4

    M3D3

    M5D5

    M6 M2

    D2

    R1 R2 R3

    A B C

    N

    Vd/2

    Vd/2

    O

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    Sinusoidal PWM Inverters(2)If is the frequency of the sine and the frequency of the carrier, =

    is called the carrier

    ratio or the frequency ratio. For a three-phase sine-PWM inverter, = 9,15,21,27,3, =odd. This eliminates the even harmonics from the inverter voltage. Usually q is varied with

    such that is within a certain band. Normally is around 4-5 kHz. This frequency is a good

    compromise between stress level of motor insulation and THD of the motor current. The figure

    below shows a typical versus relationship.

    fc

    fm

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    Three-phase PWM waveforms and

    harmonic spectrum

    E i t l li lt ( i k) d li t (bl k) f 2 kW 4

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    Experimental line voltage (pink) and line current (black) for a 2 kW, 4

    pole, 60 Hz induction motor running at 1330 rpm in a closed-loop

    slip controlled drive using a PWM inverter

    Top : No Load . Bottom: Full Load

    Experimental line voltage (pink) and line current (black) waveform for a

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    Experimental line voltage (pink) and line current (black) waveform for a

    2 kW, 4 pole, 60 Hz induction motor running at 1770 rpm in a closed-

    loop slip controlled drive using a PWM inverter

    Top : No Load . Bottom: Full Load

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    Sinusoidal PWM Inverters(3)

    If the peak of the sine wave and the frequency of the sine wave are changed simultaneously such

    that their ratio is maintained constant, the inverter output voltage/frequency ratio is also kept

    constant as they change. Thus a single control signal that controls the amplitude and frequency o

    the sine wave is sufficient to obtain v/f control of the induction motor.

    The RMS line-line fundamental voltage 1 =3

    2 , =

    3

    22 = 0.612 .

    0 1. For RMS line-line voltages of other line harmonic components, the plot and thetable as shown in the next two slides, has to be used as the relationship is not linear as the

    fundamental.

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    Plot of the normalized fundamental

    and some higher harmonic components versus

    modulation index (M)

    qk=2q 1

    3q

    G li d h i f li li f

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    Generalized harmonics of line-line for a

    large q that is a multiple of 3

    0.2 0.4 0.6 0.8 1.0

    1 0.122 0.245 0.367 0.490 0.612

    2 0.010 0.037 0.080 0.135 0.195

    4 0.005 0.011

    2 1 0.116 0.200 0.227 0.192 0.111

    2 5 0.008 0.020

    3 2 0.027 0.085 0.124 0.108 0.038

    3 4 0.007 0.029 0.064 0.096

    4 1 0.100 0.096 0.005 0.064 0.042

    4 5 0.021 0.051 0.073

    4 7 0.010 0.030

    Example of PWM controlled induction motor drive

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    Example of PWM controlled induction motor driveIn a three-phase sine-PWM converter, = 300 V, = 0.2, = 39,1 = 12 Hz. a) Calculate

    the RMS values of the fundamental-frequency voltage and some dominant harmonics in the line-

    line voltages and the THD. b) Calculate next the harmonics in the phase current of an induction

    motor connected in delta and the THD for a slip frequency of 2 Hz. The motors equivalent

    circuit parameters are 1 =2 = 0.5 , 1=2

    = 1 , =35 at 60 Hz.

    Harmonic Line-line voltage (V) Harmonic Frequency (Hz)

    1 300*0.122=36.6 12 2 = 37 300*0.010=3 12*39= 444

    + 2 = 41 300*0.010=3 12*41= 492

    2 1 = 77 300*0.116=34.8 12*77=924

    2 + 1 = 79 300*0.116=34.8 12*79=948

    3 2 = 115 300*0.027=8.1 12*115=1380

    3 + 2 = 119 300*0.027=8.1 12*119=1428

    4 1 = 155 300*0.1=30 12*155=1860

    4 + 1 = 157 300*0.1=30 12*157=1884

    a) From the earlier table the line-line voltages at fundamental and other higher frequencies can

    be computed as follows using the values in the highlighted column corresponding to M=0.2

    from the table in the previous slide.

    Total Harmonic Distortion voltage =2 32 + 2 34.82 + 2 8.12 + 2 302

    36.6

    = 66.1236.6

    = 1.81 or 181%

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    b) = 212

    =1

    6

    With this value of slip and inverter frequency of 12 Hz the motor equivalent circuit can be

    redrawn as:

    V1 =36.6

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    Example of PWM controlled induction motor drive (3)

    Using the harmonic equivalent circuit as shown above the harmonic currents can be computed as

    37 =3

    2 0.2 37= 0.2 A

    39 =3

    2 0.2 39= 0.18 A

    77 =34.8

    2 0.2 77= 1.13 A

    79 =34.8

    2 0.2 79= 1.10 A

    115 =8.1

    2 0.2 115= 0.176 A

    117 =8.1

    2 0.2 117= 0.170 A

    155 =30

    2 0.2 155= 0.484 A

    157 =30

    2 0.2 157= 0.478 A

    Total Harmonic Distortion current

    =0.22 + 0.182 + 1.132 + 1.12 + 0.1762 + 0.172 + 0.4842 + 0.4782

    11.3

    =1.756

    11.3= 0.1554 or 15.54%

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    Overmodulation (M>1)Vd

    Normalized RMS value of the

    Fundamental line-line voltage

    (with respect to Vd , the dc bus

    voltage), versus modulation

    index M.

    Overmodulation: M =1.55. Pulse dropping due to

    overmodulation.

    For values of M > 1, the relationship between M and the fundamental value of the RMS voltagebecomes nonlinear (Figure above, left). This is caused as Vm , the sine peak becomes higher

    than Vc , the triangle peak (Figure above, middle). This also causes progressively narrowing

    pulses and notches with increasing M. Eventually because of dead time requirement of the

    switches they are eliminated by the control circuit (Figure above, right). Overmodulation finally

    leads to a quasi-square line-line voltage (like the three switch scheme earlier) once M= 3.24.

    Sinusoidal Modulation With Regular Sampling

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    Sinusoidal Modulation With Regular Sampling

    In this scheme a sampled version of the original sinusoidal reference in used. If the sampling is

    done only at the positive peaks of the triangle it is called symmetrical sampling (Fig. a above).

    If the sampling is done at both positive and negative peaks of the triangle it is called

    asymmetrical sampling (Fig. b above). The PWM pattern can then be stored for different

    values of modulating index M in a non-volatile memory. This scheme requires much

    less memory compared to naturally sampled PWM scheme when implemented using amicrocontroller. It also solves arameter drift, dc offset etc. associated with analo electronics.

    Optimal Pulse width Modulation

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    Optimal Pulse-width Modulation

    (Programmed Harmonic Elimination)Pre-determined notches are introduced in the switching patterns to eliminate certain harmonics

    like 5,7,11,13 etc. in the inverter output voltage. The notches are introduced in such a way that the

    quarter-wave symmetry is preserved. Because of the quarter-wave symmetry all cosine terms in

    the Fourier series will be absent.

    For example, if we want to eliminate the 5t

    and the 7t

    harmonic and keep the fundamental at a

    certain value , then from the definition of Fourier series

    =4

    sin

    2

    0.

    One needs to introduce three notches in the quarter cycle to write the following three equations:

    = 1 =4

    sin 1

    0

    4

    sin +21

    4

    sin

    4

    sin3

    3

    32

    =

    4

    cos1 + 1 cos1 + cos2 cos3 + cos2 cos3=

    4

    1 2cos1 + 2 cos2 2cos3

    0 = 5 =4

    51 2cos 51 + 2 cos 52 2cos 53

    0 = 7 =4

    71 2cos 71 + 2 cos 72 2cos 73

    Solving the three equations will yield 1,2,3.

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    Programmed Harmonic Elimination (2)

    M1 D1

    M4D4

    M3D3

    M5D5

    M6 M2

    D2

    R1 R2 R3

    A B C

    N

    Vd/2

    Vd/2

    O

    If such a gating signal is applied to the inverter in the figure above (left)the normalize voltage

    with respect to

    2

    will look like the figure above (right)

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    Programmed Harmonic Elimination (3)

    1,2,3 can be pre-computed as a function of percentage of the maximum fundamental voltage

    and stored in the memory as a look-up table. The figure above shows a plot using the data from

    the table.


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