| Date post: | 18-Apr-2015 |
| Category: |
Documents |
| Upload: | sachin-sadadekar |
| View: | 200 times |
| Download: | 20 times |
Workshop on “IP Addressing & Subnetting” Page 1 of 33 RAJASEKAR (IT)
SUR COLLEGE OF APPLIED SCIENCES DEPARTMENT OF INFORMATION TECHNOLOGY
WORKSHOP ON IP ADDRESSING & SUBNETTINGWORKSHOP ON IP ADDRESSING & SUBNETTINGWORKSHOP ON IP ADDRESSING & SUBNETTINGWORKSHOP ON IP ADDRESSING & SUBNETTING
Conducted by
V.R. RAJASEKAR Lecturer – IT
On
04/04/2011 Student Id:_________ Name :______________________________________________
Workshop on “IP Addressing & Subnetting” Page 2 of 33 RAJASEKAR (IT)
ContentContentContentContent
1.1.1.1. IP addressing basicsIP addressing basicsIP addressing basicsIP addressing basics
2.2.2.2. BBBBinary to decimal conversioninary to decimal conversioninary to decimal conversioninary to decimal conversion
3.3.3.3. Decimal to binary conversionDecimal to binary conversionDecimal to binary conversionDecimal to binary conversion
4.4.4.4. Decimal to hexadecimal conversionDecimal to hexadecimal conversionDecimal to hexadecimal conversionDecimal to hexadecimal conversion
5.5.5.5. Address class identificationAddress class identificationAddress class identificationAddress class identification
6.6.6.6. Network & host identificationNetwork & host identificationNetwork & host identificationNetwork & host identification
7.7.7.7. Default subnet mask identificationDefault subnet mask identificationDefault subnet mask identificationDefault subnet mask identification
8.8.8.8. Network id identificatNetwork id identificatNetwork id identificatNetwork id identificationionionion
9.9.9.9. First and last host id identificationFirst and last host id identificationFirst and last host id identificationFirst and last host id identification
10.10.10.10. Subnet directed broadcast IP address identificationSubnet directed broadcast IP address identificationSubnet directed broadcast IP address identificationSubnet directed broadcast IP address identification
11.11.11.11. Apply your knowledgeApply your knowledgeApply your knowledgeApply your knowledge
12.12.12.12. SubnettingSubnettingSubnettingSubnetting
13.13.13.13. VLSM : Variable Length Subnet MaskVLSM : Variable Length Subnet MaskVLSM : Variable Length Subnet MaskVLSM : Variable Length Subnet Mask
14.14.14.14. Apply your knowledgeApply your knowledgeApply your knowledgeApply your knowledge
Workshop on “IP Addressing & Subnetting” Page 3 of 33 RAJASEKAR (IT)
1)1)1)1) IP ADDRESSING BASICS:IP ADDRESSING BASICS:IP ADDRESSING BASICS:IP ADDRESSING BASICS: • Define IP Address: ______________________________________________________________________________________________________________________________________________________________________ • Find the IP Address of your computer and write it. ______________________________________________________________________________________________________________________________________________________________________ Other facts: • ________________________ Addressing. • 2 Versions: 1) ____________________ 2) ____________________.
• IP Version used in our college: __________________________. • IP Addresses are used to identify _________________ in networks. • Assigned by __________________________________. • Length of IPv4 address: ____________________. • Length of IPv6 Address: ____________________. • IPv4 Address of broken into ___________________ octets (8 Bits). • General format of IPv4 is ___________________________. • Uses _______________________________format. • Example IP Address: ________________________. • Range of value per octet: __________________________. • Two types of IPv4 Address: 1) _____________________________ 2) _______________________.
Work
shop
on “
IP A
ddre
ssing
& S
ubne
tting
”
Pag
e 4 o
f 33
R
AJAS
EKAR
(IT)
CLASS
Ran
ge
(1st
Octet)
Highe
r Order
Bit (1
st
Octet)
# of
Network
Bits
# of
Host
Bits
Defau
lt
Subn
et M
ask
CID
R
Value
Total # of
Networks
Total # of
Host p
er
Network
Priva
te IP Add
ress
0.0.0.0 : _______
____
____
____
____
____
____
____
___
127.0.0.0 – 12
7.255.255.255 : _
______
____
____
____
____
____
______
____
_ 25
5.25
5.25
5.25
5 : ______
____
____
____
____
____
____
____
____
Workshop on “IP Addressing & Subnetting” Page 5 of 33 RAJASEKAR (IT)
2) 2) 2) 2) BBBBinary To Decimal Conversion:inary To Decimal Conversion:inary To Decimal Conversion:inary To Decimal Conversion: a) 10010010 b) 01110111 c) 11111111 d) 11000101 e) 00011011 f) 10101010 g) 01101111 h) 11111000 i) 00100000 j) 01010101 k) 00111110 l) 00000011 m) 11101101 n) 11000000 o) 00011100 p) 10101010
128 64 32 16 8 4 2 1 Answer Scratch Area a) b) c) d) e) f) g) h) i) j) k) l) m) n) o) p)
Workshop on “IP Addressing & Subnetting” Page 6 of 33 RAJASEKAR (IT)
3) 3) 3) 3) Decimal To Binary Conversion:Decimal To Binary Conversion:Decimal To Binary Conversion:Decimal To Binary Conversion: a) 238 b) 34 c) 123 d) 50 e) 255 f) 200 g) 10 h) 138 i) 1 j) 13 k) 250 l) 98 m) 15 n) 79
128 64 32 16 8 4 2 1 Answer Scratch Area a)
b)
c)
d)
e)
f)
g)
h)
i)
j)
k)
l)
m)
n)
o)
Workshop on “IP Addressing & Subnetting” Page 7 of 33 RAJASEKAR (IT)
4) Decimal to Hexadecimal Conversion4) Decimal to Hexadecimal Conversion4) Decimal to Hexadecimal Conversion4) Decimal to Hexadecimal Conversion::::
a) 197 b) 220 c) 79 d) 129 e) 148 f) 119 g) 97
h) 168 i) 172 j) 201
Decimal àààà Binary àààà Hexadecimal
128 64 32 16 8 4 2 1 Binary Value Hexadecimal a)
b)
c)
d)
e)
f)
g)
h)
i)
j)
Decimal Binary Hexadecimal 0 0000 0 1 0001 1 2 0010 2 3 0011 3 4 0100 4 5 0101 5 6 0110 6 7 0111 7
8 1000 8 9 1001 9 10 1010 A 11 1011 B 12 1100 C 13 1101 D 14 1110 E 15 1111 F
Workshop on “IP Addressing & Subnetting” Page 8 of 33 RAJASEKAR (IT)
5) 5) 5) 5) Address Class Identification:Address Class Identification:Address Class Identification:Address Class Identification: Identify the Class of the following IP Addresses.
Address Class a) 10.250.1.1 _____ b) 150.10.15.0 _____ c) 192.14.2.0 _____ d) 148.17.9.1 _____ e) 193.42.1.1 _____ f) 126.8.156.0 _____ g) 220.200.23.1 _____ h) 230.230.45.58 _____ i) 177.100.18.4 _____ j) 119.18.45.0 _____ k) 249.240.80.78 _____ l) 199.155.77.56 _____ m) 117.89.56.45 _____ o) 215.45.45.0 _____ p) 199.200.15.0 _____ q) 95.0.21.90 _____ r) 33.0.0.0 _____ s) 158.98.80.0 _____ t) 219.21.56.0 _____
Class Range A B C D E
Workshop on “IP Addressing & Subnetting” Page 9 of 33 RAJASEKAR (IT)
6) 6) 6) 6) NETWORK & HOST IDENTIFICATION:NETWORK & HOST IDENTIFICATION:NETWORK & HOST IDENTIFICATION:NETWORK & HOST IDENTIFICATION: 6.1 Circle the Network portion of these addresses: a) 177. 100. 18. 4 b) 119. 18. 45. 0 c) 209. 240. 80. 78 d) 199. 155. 77. 56 e) 117. 89. 56. 45 f) 215. 45. 45. 0 g) 192. 200. 15. 0 h) 95. 0. 21. 90 i) 33. 0. 0. 0 j) 158. 98. 80. 0 k) 217. 21. 56. 0 l) 10. 250. 1. 1 m) 150. 10. 15. 0 n) 192. 14. 2. 0 o) 148. 17. 9. 1 p) 193. 42. 1. 1 q) 126. 8. 156. 0 r) 220. 200. 23. 1
Class SNM A 255.0.0.0 B 255.255.0.0 C 255.255.255.0
Workshop on “IP Addressing & Subnetting” Page 10 of 33 RAJASEKAR (IT)
6.2 Circle the host portion of these addresses: a) 10. 15. 123. 50
b) 171. 2. 199. 31
c) 198. 125. 87. 177
d) 223. 250. 200. 222
e) 17. 45. 222. 45
f) 126. 201. 54. 231
g) 191. 41. 35. 112
h) 155. 25. 169. 227
i) 192. 15. 155. 2
j) 123. 102. 45. 254
k) 148. 17. 9. 155
l) 100. 25. 1. 1 m) 195. 0. 21. 98
n) 25. 250. 135. 46
o) 171. 102. 77. 77
p) 55. 250. 5. 5
q) 218. 155. 230. 14
r) 10. 250. 1. 1
Class SNM A 255.0.0.0 B 255.255.0.0 C 255.255.255.0
Workshop on “IP Addressing & Subnetting” Page 11 of 33 RAJASEKAR (IT)
7) Default Subnet Mask Identification:7) Default Subnet Mask Identification:7) Default Subnet Mask Identification:7) Default Subnet Mask Identification: Write the correct Default Subnet Mask & CIDR Value for each of the following addresses: IP Address Subnet Mask CIDR Value a) 177.100.18.4 _____________________________ __________ b) 119.18.45.0 _____________________________ __________ c) 191.249.234.191 _____________________________ __________ d) 223.23.223.109 _____________________________ __________ e) 10.10.250.1 _____________________________ __________ f) 126.123.23.1 _____________________________ __________ g) 223.69.230.250 _____________________________ __________ h) 192.12.35.105 _____________________________ __________ i) 77.251.200.51 _____________________________ __________ j) 189.210.50.1 _____________________________ __________ k) 88.45.65.35 _____________________________ __________ l) 128.212.250.254 _____________________________ ___________ m) 193.100.77.83 _____________________________ ___________ n) 125.125.250.1 _____________________________ ___________ o) 1.1.10.50 _____________________________ __________ p) 220.90.130.45 _____________________________ ___________ q) 134.125.34.9 _____________________________ __________ r) 95.250.91.99 _____________________________ __________
Workshop on “IP Addressing & Subnetting” Page 12 of 33 RAJASEKAR (IT)
8) network id Identification:) network id Identification:) network id Identification:) network id Identification: Identify the Network Id of the following IP Addresses. IP Address Network ID a) 177.100.18.4 _____________________________
b) 119.18.45.0 _____________________________
c) 191.249.234.191 _____________________________
d) 223.23.223.109 _____________________________
e) 10.10.250.1 _____________________________
f) 126.123.23.1 _____________________________
g) 223.69.230.250 _____________________________
h) 192.12.35.105 _____________________________
i) 77.251.200.51 _____________________________
j) 189.210.50.1 _____________________________
k) 88.45.65.35 _____________________________
l) 128.212.250.254 _____________________________
m) 193.100.77.83 _____________________________
n) 125.125.250.1 _____________________________
o) 1.1.10.50 _____________________________
p) 220.90.130.45 _____________________________
q) 134.125.34.9 _____________________________
r) 95.250.91.99 _____________________________
Workshop on “IP Addressing & Subnetting” Page 13 of 33 RAJASEKAR (IT)
9) ) ) ) first and last host id first and last host id first and last host id first and last host id Identification:Identification:Identification:Identification: Identify the First Host Id and Last Host Id of the following IP Addresses. IP Address Network ID First Host Id Last Host Id a) 177.100.18.4 _________________ _____________ ________________ b) 119.18.45.0 _________________ _____________ ________________ c) 191.249.234.191 _________________ _____________ ________________ d) 223.23.223.109 _________________ _____________ ________________ e) 10.10.250.1 _________________ _____________ ________________ f) 126.123.23.1 _________________ _____________ ________________ g) 223.69.230.250 _________________ _____________ ________________ h) 192.12.35.105 _________________ _____________ ________________ i) 77.251.200.51 _________________ _____________ ________________ j) 189.210.50.1 _________________ _____________ ________________ k) 88.45.65.35 _________________ _____________ ________________ l) 128.212.250.254 _________________ _____________ ________________ m) 193.100.77.83 _________________ _____________ ________________ n) 125.125.250.1 _________________ _____________ ________________ o) 1.1.10.50 _________________ _____________ ________________ p) 220.90.130.45 _________________ _____________ ________________ q) 134.125.34.9 _________________ _____________ ________________ r) 95.250.91.99 _________________ _____________ ________________
Workshop on “IP Addressing & Subnetting” Page 14 of 33 RAJASEKAR (IT)
10101010) ) ) ) SUBNET DIRECTED BROADCAST IP ADDRESS SUBNET DIRECTED BROADCAST IP ADDRESS SUBNET DIRECTED BROADCAST IP ADDRESS SUBNET DIRECTED BROADCAST IP ADDRESS IDENTIFICATION:IDENTIFICATION:IDENTIFICATION:IDENTIFICATION:
Find the Subnet Directed Broadcast IP address of the following Networks. IP Address Network ID a) 177.100.18.4 _____________________________
b) 119.18.45.0 _____________________________
c) 191.249.234.191 _____________________________
d) 223.23.223.109 _____________________________
e) 10.10.250.1 _____________________________
f) 126.123.23.1 _____________________________
g) 223.69.230.250 _____________________________
h) 192.12.35.105 _____________________________
i) 77.251.200.51 _____________________________
j) 189.210.50.1 _____________________________
k) 88.45.65.35 _____________________________
l) 128.212.250.254 _____________________________
m) 193.100.77.83 _____________________________
n) 125.125.250.1 _____________________________
o) 1.1.10.50 _____________________________
p) 220.90.130.45 _____________________________
q) 134.125.34.9 _____________________________
r) 95.250.91.99 _____________________________
Workshop on “IP Addressing & Subnetting” Page 15 of 33 RAJASEKAR (IT)
11111111) Apply your knowledge:) Apply your knowledge:) Apply your knowledge:) Apply your knowledge: Solve the following problems. 1) Give Network ID : 138.169.0.0 Class: ________________________________ SNM: ____________________________________ First HID: ____________________________ Last HID:_________________________________ Broadcast IP:__________________________ No of hosts: _______________________________ 2) Give Network ID : 206.207.0.0 Class: ________________________________ SNM: ____________________________________ First HID: ____________________________ Last HID:_________________________________ Broadcast IP:__________________________ No of hosts: _______________________________ 3) Give Network ID : 189.0.0.0 Class: ________________________________ SNM: ____________________________________ First HID: ____________________________ Last HID:_________________________________ Broadcast IP:__________________________ No of hosts: _______________________________ 4) Give Network ID : 203.0.0.0 Class: ________________________________ SNM: ____________________________________ First HID: ____________________________ Last HID:_________________________________ Broadcast IP:__________________________ No of hosts: _______________________________ 5) Give Network ID : 208.255.0.0 Class: ________________________________ SNM: ____________________________________ First HID: ____________________________ Last HID:_________________________________ Broadcast IP:__________________________ No of hosts: _______________________________
Workshop on “IP Addressing & Subnetting” Page 16 of 33 RAJASEKAR (IT)
12) SUBNETTING12) SUBNETTING12) SUBNETTING12) SUBNETTING
• Subnetting is a procedure to support the subnetting or division of a single Class A, B, or C network number into smaller pieces.
• Instead of the Classful two-level hierarchy, subnetting supports a three-level hierarchy.
• Below Figure, illustrates the basic idea of subnetting, which is to divide the standard classful
host number field into two parts-the subnet number and the host number on that subnet.
Problem 1 : Network Address : 192.10.10.0 Number of needed subnets : 14 Complete the following: Address class :________________________________________ Default subnet mask : ________________________________________
Number of bits borrowed : ________________________________________
Custom / New Sub NetMask : ________________________________________
CIDR Value : ________________________________________
Workshop on “IP Addressing & Subnetting” Page 17 of 33 RAJASEKAR (IT)
Problem 2: Network Address : 130.150.0.0 Number of needed subnets : 62 Complete the following: Address class :________________________________________ Default subnet mask : ________________________________________
Number of bits borrowed : ________________________________________
Custom / New Sub NetMask : ________________________________________
CIDR Value : ________________________________________
Problem 3: Network Address : 35.0.0.0 Number of needed subnets : 30 Complete the following: Address class :________________________________________ Default subnet mask : ________________________________________
Number of bits borrowed : ________________________________________
Custom / New Sub NetMask : ________________________________________
CIDR Value : ________________________________________
Workshop on “IP Addressing & Subnetting” Page 18 of 33 RAJASEKAR (IT)
Problem 4: Network Address : 22.0.0.0 Number of needed subnets : 6 Complete the following: Address class :________________________________________ Default subnet mask : ________________________________________
Number of bits borrowed : ________________________________________
Custom / New Sub NetMask : ________________________________________
CIDR Value : ________________________________________
Subnet Id (Subnet 1) : ________________________________________
Subnet Id (Subnet 2) : ________________________________________
Subnet Id (Subnet 3) : ________________________________________
Subnet Id (Subnet 4) : ________________________________________
Subnet Id (Subnet 5) : ________________________________________
Subnet Id (Subnet 6) : ________________________________________ Show your work in the space below.
Workshop on “IP Addressing & Subnetting” Page 19 of 33 RAJASEKAR (IT)
Problem 5: Network Address : 140.10.0.0 Number of needed subnets : 8 Complete the following: Address class :________________________________________ Default subnet mask : ________________________________________
Number of bits borrowed : ________________________________________
Custom / New Sub NetMask : ________________________________________
CIDR Value : ________________________________________
Subnet Id (Subnet 1) : ________________________________________
Subnet Id (Subnet 2) : ________________________________________
Subnet Id (Subnet 3) : ________________________________________
Subnet Id (Subnet 4) : ________________________________________
Subnet Id (Subnet 5) : ________________________________________
Subnet Id (Subnet 6) : ________________________________________
Subnet Id (Subnet 7) : ________________________________________
Subnet Id (Subnet 8) : ________________________________________ Show your work in the space below.
Workshop on “IP Addressing & Subnetting” Page 20 of 33 RAJASEKAR (IT)
Problem 6: Network Address : 200.100.100.0 Number of needed subnets : 6 Complete the following: Address class :________________________________________ Default subnet mask : ________________________________________
Number of bits borrowed : ________________________________________
Custom / New Sub NetMask : ________________________________________
CIDR Value : ________________________________________
Subnet Id (Subnet 1) : ________________________________________
Subnet Id (Subnet 2) : ________________________________________
Subnet Id (Subnet 3) : ________________________________________
Subnet Id (Subnet 4) : ________________________________________
Subnet Id (Subnet 5) : ________________________________________
Subnet Id (Subnet 6) : ________________________________________ Show your work in the space below.
Workshop on “IP Addressing & Subnetting” Page 21 of 33 RAJASEKAR (IT)
Problem 7: Network Address : 12.0.0.0 Number of needed subnets : 2 Complete the following: Address class :________________________________________ Default subnet mask : ________________________________________
Number of bits borrowed : ________________________________________
Custom / New Sub NetMask : ________________________________________
CIDR Value : ________________________________________
Subnet Id (Subnet 1) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 2) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________ Show your work in the space below.
Workshop on “IP Addressing & Subnetting” Page 22 of 33 RAJASEKAR (IT)
Problem 8: Network Address : 135.20.0.0 Number of needed subnets : 6 Complete the following: Address class :________________________________________ Default subnet mask : ________________________________________
Number of bits borrowed : ________________________________________
Custom / New Sub NetMask : ________________________________________
CIDR Value : ________________________________________
Subnet Id (Subnet 1) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 2) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 3) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 4) : ________________________________________
First Host ID : ________________________________________
Workshop on “IP Addressing & Subnetting” Page 23 of 33 RAJASEKAR (IT)
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 5) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 6) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________ Show your work in the space below.
Workshop on “IP Addressing & Subnetting” Page 24 of 33 RAJASEKAR (IT)
Problem 9: Network Address : 192.168.1.0 Number of needed subnets : 14 Complete the following: Address class :________________________________________ Default subnet mask : ________________________________________
Number of bits borrowed : ________________________________________
Custom / New Sub NetMask : ________________________________________
CIDR Value : ________________________________________
Subnet Id (Subnet 1) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 2) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 3) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 4) : ________________________________________
First Host ID : ________________________________________
Workshop on “IP Addressing & Subnetting” Page 25 of 33 RAJASEKAR (IT)
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 5) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 6) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 7) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 8) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 9) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Workshop on “IP Addressing & Subnetting” Page 26 of 33 RAJASEKAR (IT)
Subnet Id (Subnet 10) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 11) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 12) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 13) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
Subnet Id (Subnet 14) : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________ Show your work in the space below.
Workshop on “IP Addressing & Subnetting” Page 27 of 33 RAJASEKAR (IT)
Problem 10: Given IP Address: 172.185.128.0 Subnet Required: 10 Find the Subnet Id, First Host Id, Last Host Id, Broadcast IP of 1st, 2nd, 13th and 14th Subnets. Find the New Subnet Mask.
Workshop on “IP Addressing & Subnetting” Page 28 of 33 RAJASEKAR (IT)
Problem 11: Given IP Address: 192.168.1.7 Subnets Required: 10 Find the Subnet Id, First Host Id, Last Host Id, Broadcast IP of 1st, 2nd & 10th Subnets. Find the new subnet mask.
Workshop on “IP Addressing & Subnetting” Page 29 of 33 RAJASEKAR (IT)
13) 13) 13) 13) VLSM : Variable Length Subnet MaskVLSM : Variable Length Subnet MaskVLSM : Variable Length Subnet MaskVLSM : Variable Length Subnet Mask Problem 1: Your organization has been assigned the network number 220.25.25.0/16, the topology diagram is also given below. Apply VLSM with a minimal wastage of IP addresses. IP Address Given :________________________________________ Address class :________________________________________ Default subnet mask : ________________________________________
Topology Diagram :
Number of Subnets Needed : _______________________________________
Subnet Id (Subnet 1) : ________________________________________
Number of Host needed : ________________________________________
Number of Bits borrowed : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
New Subnet Mask (CIDR) : ________________________________________
Subnet Id (Subnet 2) : ________________________________________
Workshop on “IP Addressing & Subnetting” Page 30 of 33 RAJASEKAR (IT)
Number of Host needed : ________________________________________
Number of Bits borrowed : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
New Subnet Mask (CIDR) : ________________________________________
Subnet Id (Subnet 3) : ________________________________________
Number of Host needed : ________________________________________
Number of Bits borrowed : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
New Subnet Mask (CIDR) : ________________________________________
Subnet Id (Subnet 4) : ________________________________________
Number of Host needed : ________________________________________
Number of Bits borrowed : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________ New Subnet Mask (CIDR) : ________________________________________
Workshop on “IP Addressing & Subnetting” Page 31 of 33 RAJASEKAR (IT)
Problem 2: Your organization has been assigned the network number 140.25.0.0/16, the topology diagram is also given below. Apply VLSM with a minimal wastage of IP addresses. IP Address Given :________________________________________ Address class :________________________________________ Default subnet mask : ________________________________________
Topology Diagram :
Number of Subnets Needed : _______________________________________
Subnet Id (Subnet 1) : ________________________________________
Number of Host needed : ________________________________________
Number of Bits borrowed : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
New Subnet Mask (CIDR) : ________________________________________
Workshop on “IP Addressing & Subnetting” Page 32 of 33 RAJASEKAR (IT)
Subnet Id (Subnet 2) : ________________________________________
Number of Host needed : ________________________________________
Number of Bits borrowed : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
New Subnet Mask (CIDR) : ________________________________________
Subnet Id (Subnet 3) : ________________________________________
Number of Host needed : ________________________________________
Number of Bits borrowed : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
New Subnet Mask (CIDR) : ________________________________________
Subnet Id (Subnet 4) : ________________________________________
Number of Host needed : ________________________________________
Number of Bits borrowed : ________________________________________
First Host ID : ________________________________________
Last Host ID : ________________________________________
Broadcast IP : ________________________________________
New Subnet Mask (CIDR) : ________________________________________
Workshop on “IP Addressing & Subnetting” Page 33 of 33 RAJASEKAR (IT)
14) 14) 14) 14) APPLY YOUR KNOWLEDGE:APPLY YOUR KNOWLEDGE:APPLY YOUR KNOWLEDGE:APPLY YOUR KNOWLEDGE:
1) On the network 131.1.123.0/27, what is the last IP Address that can be assigned to a host? a) 131.1.123.30 b) 131.1.123.31 c) 131.1.123.32 d) 131.1.123.33
2) For the network 192.0.2.0/23, which option is a valid IP address that can be assigned to a host? a) 192.0.2.0 b) 192.0.2.255 c) 192.0.3.255 d) 192.0.4.0
3) Which two addresses can be assigned to a host with a subnet mask of 255.255.254.0? (Choose two)
a) 113.10.4.0 b) 186.54.3.0 c) 175.33.3.255 d) 26.35.2.255 e) 17.35.36.0
4) Given a subnet mask of 255.255.255.224, which of the following addresses can be assigned to network hosts? (Choose three)
a) 15.234.118.63 b) 92.11.178.93 c) 134.178.18.56 d) 192.168.16.87 e) 201.45.116.159 f) 217.63.12.192
5) Given the address 192.168.20.19/28, which of the following are valid host addresses on this subnet? (Choose two)
a) 192.168.20.29 b) 192.168.20.16 c) 192.168.20.17 d) 192.168.20.31 e) 192.168.20.0
