Ising model in the Ising model in the zeroth approximationzeroth approximation

Done by Done by Ghassan M. Masa’dehGhassan M. Masa’deh

Introduction:In principle the Ising model is not a very good approximation for any temperature range. However it has the advantage of starting directly from the energy levels

and skipping all the steps that lead to

them from the Hamiltonian, in other methods .

This convenient short cut makes it possible to concentrate on the details of the statistical

mechanics .

Therefore, the ising model is very widely used in a variety of other problems, more than in ferromagnetism for which it was originally developed .

The Ising model

In 1928 Gorsky attempted a statistical study of order - disorder transitions in binary alloys on the basis of the assumption that the work expended in transferring an atom from an order position to a disordered one is directly proportional to the degree of order prevailing in the system

This idea was further developed by Bragg and Williams, who, for the first time introduced the concept of long range order

The basic assumption in the Bragg-Williams approximation is " the energy of an individual atom in the given system is determined by the average degree of order prevailing in the entire system rather than by the fluctuating

configurations of the neighboring atoms. ".

Define: along range parameter 'L' is given by:

= N+ - N-/N …….(1) -1<L<1

Where: σi = +1 for an up spin - = 1 for adown spin

N+ = total number of up spins N- = total number of down spins

L

iNL /1

Where N = N+ + N-

Substitute in (1) we get

L = (2N+/N) -1

So, N+=N/2(1+L)

And

N-= N/2 (1-L)

The magnetization M is given by :

M = (N+- N-)µ =µ NL ; -Nµ<M<Nµ

For Ising model we can write the Hamiltonian by:

H{σi} = -J ∑σI σ j - µB∑σi ………………(2)

Where : - µB is the potential energy - Jσi σj is the kinetic energy

H{σi} = -J (1/2 q σ) ∑σi - µB∑σi ……………(3)

We can find the total configurational energy of the system is given by

E= -1/2 (qJL) NL –( µB) NL ……….(4)

And

<E< = U = -1/2 qJNL - µBNL………..(5)2

Define: ∆ɛ is the difference between the over all configurational energy of an up spin and the over all configurational energy of down spin , the energy expended in changing any up spin into a down one is

given by :

∆ɛ = -J(qσ) ∆σ - µB∆σ ……………..(6)

= 2µ (qJσ/(µ+B) ) ; ∆σ= -2……….(7)

The relative values of the equilibrium numbers N+ and N- then follow from the Boltzmann

principle: N-/N+ = exp (-∆ɛ/KT)

= exp (-2µ(B'+B)/KT) ………(8)

Where B' the internal molecular field and given by:

B' = qJM/Nµ2

)1-L)/(1+L = (exp [-2 (qJL+B)/KT] ……..(11)

)qJL+B /(KT =1/2 ln [(1+L)/(1-L)]

= tanh L ………(12)

L= tanh [(qJL+B)/KT ] ………………(13)

Let B =0 =< L0 = tanh [(qJL0)/KT] ……..(14)

This is called the possibility of spontaneous magnetization

-1

We obtain a Tc below which the system can acquire a non zero spontaneous

magnetization and above which it can not. We can identify the Tc with the Curi temperature. The temperature that marks a transition from the ferromagnetic to the paramagnetic behavior of the system or

vice verse .

From equation (14) :

L0(T) {3(1-T/Tc)} ;(T T≃ ≲ c,B→0)…(15)

At T→0 =< L0 → 1

L0(T) 1-2 exp(-2T≃ c/T) ; (T/Tc 1)….(16)≪

1/2

The configrational energy of the system is given by:

U0(T) = -1/2 qJNL0 ……………(17)

And the specific heat is

C0(T) = -qJNL0 dL0/dT) = NKL0)] / (T/Tc)/(1- L0) - (T/Tc)... [(18(

At T<Tc =< U0(T) = C0(T) = 0`

2

2 2 2

The specific heat at the transition temperature Tc is:

C0(T) = lim {(NK* 3x)/[[(1-x)/(1-3x)] – (1-x)]} = 3/2 NK ……(19) And at T→ 0

C0(T) 4NK (T≃ c/T) exp(-2Tc/T) (20)

2

2

Note that the vanishing of the configurational energy and the specific heat of the system at temperature above Tc is directly related to the configurational order prevailing in the system at lower temperatures is completely wiped out

as T→ Tc.

We note that all the microstate are equally likely to occur is related to the fact that for T ≥ Tc there is no configurational order in the system

Define : X is the magnetic susceptibility of the system

and given by: X(B,T) = (dM/dT)T = Nµ(dL/dB)T

)= Nµ /K)](1-L(B,T)]/(T-Tc{1-L(B,T)} [[ For L 1 we obtain the Curi – weiss law≪ X0(T) (Nµ /K)/ (T-T≃ c) (T T≳ c ,B→ 0 )

2 2 2

2

For T <Tc we get.

X0(T) (Nµ /2K)/ (T≃ c-T) (T T≲ c , B→ 0 )

Experimentally the Curi – Weiss law is satisfied with considerable accuracy except that the empirical value of Tc thus obtained is always some what larger than the true transition temperature of the material.

2

As T → 0 the law field susceptibility vanishes in accordance with the formula

X0(T) (4 Nµ /KT) exp (-2T≃ c/T)

Finally , the relation ship between L and B at T=Tc and use tanh x x + x /3 we have≃:

L (3 µB/KT) (T =T≃ c ,B→ 0 )

2

-1 3

1/3

Thank you