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8/14/2019 KELANTAN-Answer Physics-Trial SPM 2008
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Answers to Paper 1
1 C2 D3 C4 B5 C6 A7 A8
A
9 B10 C11 C12 A13 C14 C15 C16 C17 D18 B19 C20 C21 B22 D
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23 D24 B25 A26 D27 D28 A29 B30 B31
C
32 B33 A34 C35 D36 D37 B38 D39 A40 A41 A42 B43 A44 B45 A
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46 C47 A48 D49 A50 B
MARKING SCHEME
Question
No.
Answer Marks
1 (a) P = Lifting Force
Q = Weight / Gravitational Force Attraction
1
1(b) P = Q 1
(c) Lifting Force / P 1
Total
2. (a) 300 s 1
(b) Pt = ml
100 x ( 1050 300) = 0.5 l
l = 150 000 J kg-1
m(with unit) 2
(c) Heat supplied is used to break up bonds between molecules
Heat is not used to increase kinetic energy
Total 5
3. (a) Parallel circuit 1
(b) Mk 1 all symbols correctMk 2 circuit is correct 2
(c) The brightness of lamp J = lamp K = lamp L = lamp M 1
(d) The voltage is the same 1(e) One bulb blow , other bulbs can still lights up 1
Total 6
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4. (a) The process where induced current / e.m.f in a conductor
when the conductor experiences a change in magnetic
flux.
1
(b) (i) Solenoid experiences a change in magnetic field. An
induced current / e.m.f induced in the solenoid
1
1
(ii) A : North pole - 1m
B : South pole - 1m
1
1
(c) (i) Increases 1
(ii) The magnitude of induced current increases // the rate of
change of the magnetic flux increases
1
Total 7
5. (a)Change of momentum/product of Force with time ofimpact
1
(b) (i) Force on the watermelon in Diagram 5.1 is larger than theforce on the watermelon in Diagram 5.2
1
(ii) Time of impact on surface A is shorter than time of impact
on surface B
1
(iii) A shorter time of impact will produce a larger force 1
(c) The change of momentum of the watermelon in Diagram
5.1 is equal to that of the watermelon in Diagram
1
(d) Sponge/carpet/towel/cloth/grass & other suitable materials 1
(e) 1. Body will be hold back by the seat belt when car stoppedsuddenly
2. The seat belt will lengthen slightly, the impulsive force
inflicted on the body will be less
1
1
Total 8
6. (a) The light which has one wavelength / one colour 1
(b) Wavelength of red light > Wavelength of blue light 1
(c)The distance between consecutive bright fringes for red
light is more than that of blue light./
The distance between consecutive bright fringes for thesame light are constant.
1
1
(d) The longer the wavelength, the longer the distance between
consecutive bright fringes1
(e) (i) The distance between two consecutive bright fringes will
decrease1
(ii) a is inversely proportional to x 1
(f) Diffraction // Interference 1
Total 8
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7. (a) (i) Temperature , resistance 1(ii) - Lines drawn on the graph.
-1.35 1
(b) (i) Output,R
01
1
1
1
(ii) OR 1
(iii) 1
(c) (i) To control the current flows into the base terminal. 1
(ii) At night, no light fall on the LDP, resistance, R of LDP .As R, the voltage, V across the LDP also .V across the base circuit > Vmin , this will switch on the
transistor and the collector circuit works.
1
1
1
(iii) The voltage 6 V in the collector circuit will not light up the
bulb.1
Total 10
8 (a) 2
(b) Real, diminished, inverted 1
(c) (i) 1/f = 1/u +1/vv = 15 cm
2
(ii) m = v/u m = 0.5 1
(d)(i) Objective lens = convex lens Y
Eyepiece = convex lens X2
(ii) Power of convex lens X > power of convex lens Y 1
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(iii)
3
Total 12
9 (a) (i) Angle between incident ray and normal line 1
(ii) Increase the angle of incidence,i, then angle ofrefraction,r will also increase
Keep on increasing the angle of incidence untilangle of refraction is 90
The angle of incidence is called critical angle
Increase the angle of of incidence more than thecritical angle
The ray will be reflected.
1
1
1
1
1
4/5
(b) Density diagram 9.2 < density diagram 9.3Refractive index 9.2 < Refractive index 9.3Angle of refraction in diagram 9.2 > angle of
refraction in diagram 9.3The higher the density the smaller the angle of
refraction
The higher the refractive index the smaller the angleof refraction.
1
1
1
1
1
(c)
Suggestion Explanation
Use refractive index of outerlayer is less than the
refractive index of outer
layer
So that total internalreflection can happen in the
fiber optic.
Use high flexibility material so that it can be bend
Use strong material do not break easily
Use thin material Lighter // can be use insmall area
Low density material Lighter
10
Total 20
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10(a) A resultant field due to the combination of the magneticfield due to the current in the conductor and external
magnetic field // Diagram
1
(b) M1 Number of turns in D10.2 is bigger
M2 angle of deflection of the ammeter indicator inD10.2 is bigger
M3 the reading of spring balance in D10.2 is smaller
M4 as current flows is bigger, force acting upwards isbigger
M5 the reading of spring balance is smaller as ,the force
upwards that act onthe coils is bigger
1
1
1
1
1
(c) (i) M1 Force acting on the cooper rod
M2 moved the cooper rod towards the magnet
1
1
(ii) M1 the cooper rod vibratesM2 as current change direction
11
(d) (i) M1 When the current flow into the coil, magnetic field
is produced.
And forces are producedM2 Catapult field is produced
M3 The forces are in the opposite direction
M4 These pair of forces produce the turning effect on
the coil.
1
1
1
1
(ii) M1 Increase the strength of magnet / add more magnetM2 increase the strength of magnetic field
M3 Increase the number of turns in the coils
M4 to increase the magnitude of forceM5 Increase the magnitude of current
M6 to increase the magnitude of force / increase the
strength of magnetic field
11
1
1
1
1
Total 20
11(a) (i) Weight is the gravitational force acts an object. 1
(ii) Upthrust = weight of the boat 1(iii) - Sea water is denser
- Boat displaced less sea water and gain the sameupthrust . Therefore boat sinks less in sea water
1
11
(b) (i) Upthrust = mass of sea water displaced= mg
= Vg= 250 X 1080 X 10 = 2.7 X 10
6N
1
1
1
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(ii) 2. 7 X 106
= V X 1000 X 10
V = 270 m3
1
1
(c) (i)
Specifications Reasons
Small stemand long.
Increase the sensitivity where the scaledivisions are far apart so that small
changes in density can be detected.
Glass wall Do not erode and small adhesive force.
Largediameter of
bulb.
High upthrust /displaces more liquid/tobe able to float easily.
Lead shots Hydrometer can stay upright.
8
(ii) - P is chosen- Small and long stem, glass wall, large diameter of
bulb and lead shots used.
1
1Total 20
12(a) (i) The time taken for half of nucleus radioactive material to
decay.
1
(ii) Fast moving electron / electron 1
(iii) Geiger-Muller tube 1
(b) - 800 ---------> 400 ---------> 200 ----------> 100
----------> 50 //
14 days 14 days 14 days14 days
No. of T 1/2 = 4
- 4 x 14 days / 64 days
1
1
(c) - The state of matter of radioisotope is solid.
- Easier to handled.
- Emits gamma-ray.
- Penetrating power is high.
- Long half-life.
- Last longer.
1
1
1
1
1
1
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- The most suitable radioisotope is Cobalt-60.
- Because the state of matter is solid, emits
gamma-ray and long half-life
1
1
(d) (i) The process of breaking up of on heavy nucleus into lighternucleus.
1
(ii) - Neutron bombarded a uranium nucleus //
Diagram
- Three neutrons produced // Diagram- The new neutron bombarded a new uranium
nucleus // Diagram
- For every reaction, the neutrons produced willgenerate a chain reaction // Diagram - 1m
1
1
1
1
(iii) E = mc2
2.9 x 10-11
= m x (3.0 x 108)
2
m = 3.22 x 10-28
kg1
1
Total 20
PAPER 3
Section A
1(a) (i) Angle of incidence. 1
(ii) Angle of refraction. 1
(iii) Glass block/refractive index of the glass block/density of the glass block. 11(b) (i)
i/0
r/0
20 13
30 19
40 25
50 30
60 36
2
Value of r5 values correct ----- (2)
4 or 3 values correct ------(1)
2 values and below -------(0)
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(ii)
i/0
r/0
sin i sin r
20 13 0.34 0.22
30 19 0.50 0.33
40 25 0.64 0.42
50 30 0.77 0.5060 36 0.87 0.59
1) All quantities i, r, sin i and sin r correct --2) Units for all quantities correct ---- 3) * All values of sin i correct -----
* 1 value of sin i incorrect ------* > 1 value of sin i incorrect ------ 0
4) * All values of sin r correct ----- * 1 value of sin r incorrect ------* > 1 value of sin r incorrect ------ 0
5) Consistency of decimal point for sin i --- 6) Consistency of decimal point for sin r ---
Score Mark
7 8 5
5 6 4
3 4 3
2 2
1 1
0 0
5
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1(c)On the graph paper.
1) Correct title on axes-----2) Units correct ------- 3)
Even scale -------4) * All points correctly plotted --------
1 point incorrectly plotted ------- > 1 point incorrectly plotted ------ 0
5) Best fit straight line -------- 6) > 50% graph paper --------
Score Mark
6 7 5
5 4 4
3 3
2 21 1
5
Total 16
1(d) Sin r is directly proportional to sin i . 1
2(a) (i)R increases linearly with
I
1..(1)
1
(ii)- Extrapolated line shown to intercept at
I
1axis---------(1)
- 0.2 A-1
------------------------------(1)
2
(iii) I
1= 0.4r
0.2 = 0.4r-----------------------(1)
r= 0.5 ---------------------------(1)
2
2(b)
(i)- Show a big on the graph to determine the gradient------------------(1)
- The correct12
12
xx
yy
from the drawn ------------------------(1)
- m = 0.4 A-1
-1------------------ Ans + unit --------------(1)
3
(ii)
m = E
1
,
0.4 =E
1, ----------------(1)
E = 2.5 V --------------------(1)
2
2(c) 1. The connection of the wires must be tight.2. The circuit is switched off whenever the readings were not taken from the
meters. This is to reduce energy loss from the cell.
1
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3 (a)
(b)
(c) (i)
(ii)
(iii)
(iv)
(v)
1 Menyatakan inferens dengan betul
Pressure depends on volume// Volume influences pressure
1 Menyatakan hipotesis dengan betul.
When the volume decrease , the pressure increase ,1 menyatakan tujuan dengan betul
To investigate the relationship between volume and pressure
1 menyatakan pembolehubah manipulasi dan bergerakbalas dengan betul
Manipulated : volume
Responding : pressure
1 menyatakan pembolehubahyang dimalarkan dengan betul
Fixed : mass of gas // temperature
1 menyatakan alat radas dan bahan
Syringe, clip , thick rubber tube, bourdon gauge .
1 menyatakan atau melukis gambar rajah susunan radas.
Menyatakan kaedah mengawal pembolehubah manipulasi
The piston of the 100 cm -3 syringe is adjusted until the volume of air in the
syringe at atmospheric pressure.The other end of the rubber tube is connected tobourdon gauge and the pressure of the air in the syringe is read on the gauge.
1 The piston of the syringe is pushed in until the enclosed volume
is 98 cm3 / V1.
1
1
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(vi)
(vii)
1 Menyatakan kaedah mengawal pembolehubah bergerakbalas.The pressure on the Bourdon gauge is recorded.
1 Menyatakan ulangan eksperimenThe steps is repeated for an enclosed volume of
96 cm3/V2, 94 cm3/V3, 92cm3/V4, 90 cm
3/V5
1 menyatakan kaedah menjadual data dengan betul
tajuk//symbol dengan unit yang betul
Tabulating data
Isipadu,V/cm3 Tekanan,P/ Nm-2 1/V , cm-3
98 /V1
96 /V2
94 /V3
92 /V4
90/V5
1 menyatakan kaedah menganalisa data dengan betul
P ( Nm-2
)
V (cm3) 10
4(a)
(b)
(c)(i)
(ii)
1 Menyatakan inferens dengan betul
Magnetic field strength depends on the number of turns
1 Menyatakan hipotesis dengan betul.
The magnetic field strength will increase when the number of turns
increase
1 menyatakan tujuan dengan betul
To investigate the relationship between magnetic field strength and
number of turn on the coil
1 menyatakan pembolehubah manipulasi dan begerakbalas dengan betul
1
1
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(iii)
(iv)
(v)
manipulated : number of turns
responding : magnetic field strength //number of small iron pin
1 menyatakan bembolehubahyang dimalarkan dengan betul
Fixed : size of current// type of core
1 menyatakan alat radas dan bahan
Retort stand, soft iron core, connector wire, PVC insulated copper wire,
small iron pin, ammeter, rheostat , battery/ power supply
1 menyatakan atau melukis gambar rajah susuan radas berlabel.
1 Menyatakan kaedah mengawal pembolehubah manipulasi
The soft iron core is wound with 20 turns of insulated copper wire and set
up as shown in diagram above.
1 Menyatakan kaedah mengawal pembolehubah bergerakbalas.
The switch is turned on and the rheostat adjusted until the ammeterReading is 1.0 A. The beaker containing small steel pin then
brought near the iron core.
Count and record the number of small iron pin attached to the softIron core.
1 Menyatakan ulangan eksperimen
Repeat the experiment by winding the soft iron core with, 30 turns,40 turns, 50 turns and 60 turns.
turns
retort stand
Soft iron core
small iron pins
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(vi)
(vii)
1 menyatakan kaedah menjadual data dengan betul
tajuk//symbol dengan unit yang betul
Numberof turns, n,
turns
Number of pins attached, n /pieces
20 / n1
30 / n2
40 / n3
50 / n4
60 / n5
(vii) 1 menyatakan kaedah menganalisa data dengan betul
number of pin
n / pieces
Number of turns/turns
JAWAPAN TAMAT
10