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Kemahiran Asas Matematik

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KEMAHIRAN ASAS MATEMATIK

Basic Mathematics 1

148 + 39 3 =14 5 1

- =

6 227200 1.765

220 % of 150 =15Volume of a cube with sides of 5cm =28500 X 2. 5 =

30.64 + 284.7 =16Area of a right-angled triangle with 8cm height and 6cm length=29 1

2 - = 5

4100 X 0.35 =17 8 hrs 28 min + 6 hrs 52 min 300.35 kg + 1250g = kg

5 3 2

+ =

4 318 7 1

- =

9 631450 sen= RM

61hr 25min = min

19Area of a square with sides of 10 cm=32 1 3

m + m = cm 4 5

70.85 km = m20Price of 4 units = RM 20.80

Price of 1 unit=33If 100% = 40 orang.

20 % =

84.5kg + 250 g = kg21 1 1

1 - =

4 234Cost price = RM 8.00

If profit 40 %, how much is the selling price?

915 % of RM 80=22Volume of a cuboid with the sides 4cm,10cm dan 6cm=35If the area of a square is 64cm2, find its perimeter?

102125 hrs in 12 hrs system23Departure time = 1520 hrsJourney = 4 hrs 15min

Arrival time=36 1 2

kg + kg = g 2 5

11 3 1

+ =

8 424 1 1

hrs + hrs = min 4 637Arrival time = 0020 hrsJourney = 5 hrs 10min

Departure time =

123540 ml = liter2515,24,20 dan 13.

Average=38 2 1

4 +1 =

5 2

13456 cm + 0.75 m =260.64 + 2.3 +305 =391km 455 m = m

Basic Mathematics 21850+ 24 8 =14 3 3 - =

4 52720 0.275

210 % of 1800 =15Volume of a cube with sides of 10cm =28500 X 0.5 =

30.36 + 45.3 =16Area of a right-angled triangle with 10cm height and 5cm base =29 3 1 - = 5

410 X 5.45 =17 3hrs 48 min + 5 hrs 55 min300.6 kg + 1450g = kg

5 2 2

+ =

5 318 3 1

- =

4 6312000 sen= RM

62hrs 15min = min

19Area of a square with sides of 12 cm=32 3 4m + m = cm 4 5

70.05 km = m20Price of 5 units = RM 15.00

Price of 1 unit=33If 100% = 1000 orang.

50 % =

82.4kg + 60 g = kg21 1 1

1 - =

6 234Cost price = RM 10.00

If profit 10 %, how much is the selling price?

925 % of RM 160=22Volume of a cuboid with the sides 3cm, 8cm dan 5cm=35If the area of a square is 36cm2, find its perimeter?

100025 hrs in 12 hrs system 23Departure time = 0325 hrs

Journey = 4 hrs 15min

Arrival time=36 7 3 kg + kg = g 10 4

11 5 3 + =

8 424 3 5jam + jam = min 4 637Arrival time = 1400 hrs

Journey = 4 hrs 20min

Departure time =

122050 ml = liter2510 ,30 ,20 dan 60.

Average=38 3 52 +3 =

5 6

13350 cm + 0.5 m = m260.75 + 10.2+ 4.07 =390.5km 55 m = m

Kemahiran Asas Matematik 3 Nama: ______________________ Tarikh: _________________1246 + 560 8 =14 3 1

- =

4 527100 50.045

210 % dpd 500 =15Isipadu kubus yang sisinya 3 cm =280.5 X 30=

30.48 + 200 =16Luas segitiga bersudut tegak yang tingginya 10cm dan tapaknya 6cm=29 4 10 - = 5

410 X 2. 5 =17 2jam 18min +10jam 52 min 302.052 kg + 150g = kg

5 1 7 + =

4 818 5 1 - =

9 231285 sen= RM

62 jam 5min = min

19Luas segiempat sama yang sisinya 12 cm=32 2 3m + m = cm 5 10

71.5km = m20Harga 6 unit = RM 24

Harga 3 unit=33Jika 100% = 18 orang.

50 % =

80.65kg + 550 g = kg21 1 21 - =

5 334Jika harga beli = RM 20.00

Untung 10 %,berapa harga jualnya?

930 % dpd RM 25.00=22Isipadu kuboid yang berukuran 20cm,10cm dan 8cm=35Jika luas segiempatsama ialah 100 cmpersegi ,berapakah perimeternya?

10Jam 0825 = pukul23Masa berlepas = jam 2220

Perjalanan = 4jam 15min

Masa tiba=36 4 3kg + kg = g 5 10

11 5 1

+ =

6 324 3 7jam + jam = min 4 1037Masa tiba = jam 0120

Perjalanan = 3jam 10min

Masa bertolak =

12540 ml = liter258, 12, 16 dan 14.

Puratanya=38 3 2

4 +1 =

4 3

1340 cm + 1.75 m =260.04 + 3.06 +2.175 =391.5km 55 m = m

Kemahiran Asas Matematik 4122 + 36 9 =14 5 1 - =

8 62710 5.045

225 % dpd 80 =15Isipadu kubus yang sisinya 6 cm =280.2 X 88 =

310.45 + 4. 5 =16Luas segitiga bersudut tegak yang tingginya 12cm dan tapaknya

15 cm=29 3

1 - = 8

4100 X 0.15 =17 6 jam 36min+ 12 jam 28 min 304. 352 kg + 878g = kg

5 7 2 + =

9 318 4 1 - =

5 2313005 sen= RM

61 jam 30 min = min

19Luas segiempat sama yang sisinya 20 cm=32 4 7 m + m = cm 5 10

70.8km = m20Harga 4 unit = RM 12Harga 10 unit=33Jika 100% = 360 biji.

5 % =

80.8 kg + 1260 g = g21 1 51 - =

3 634Jika harga beli = RM 45 .00

Untung 20 %,berapa harga jualnya?

940 % dpd RM 50.00=22Isipadu kuboid yang berukuran 10cm, 10cm dan 12 cm=35Jika luas segiempatsama ialah 81

cm persegi ,berapakah perimeternya?

10Jam 2340 = pukul23Masa berlepas = jam 1845Perjalanan = 6jam 45 min

Masa tiba=36 1 3

kg + kg = g 2 4

11 3 4 + =

4 524 1 7jam + jam = min 4 1237Masa tiba = jam 0200

Perjalanan = 4 jam 30min

Masa bertolak =

121240 ml = liter2560, 54, 48 dan 36.

Puratanya=38 2 2

3 +1 =

5 3

13112 cm + 0.88 m =260.36 + 4.6 + 0.248 =392 km 645 m = m

Nama: ______________________ Tarikh:______________124 + 5x 8 =14 1 1 - =

2 5271 0.063=

280 % dpd 200 =15Isipadu kubus yang sisinya

5 cm =281.5 X 30=

39.25 + 7.06 0.684 =16Luas segitiga bersudut tegak yang tingginya 18 cm dan tapaknya

8 cm=29 9 20 - = 10

4100 X 5. 25 =17 6 jam 15min + 1 jam 5 min 302.05 kg + 1150g = kg

5 2 1 + =

5 318 4 1 - =

5 2311260 sen= RM

61 jam 45min = min

19Luas segiempat sama yang sisinya 8 cm=32 1 3 m + m = cm 2 10

71. 05 km = m20Harga 10 unit = RM 2..50Harga 4 unit=33Jika 100% = 24 orang.

25 % =

80.35kg + 850 g = kg21 1 31 - =

3 434Jika harga asal = RM 20.00

diskaun 10 %,berapa harga jualnya?

940 % dpd RM 80 =22Isipadu kuboid yang berukuran

15 cm,10cm dan 4 cm=35Jika luas segiempatsama ialah 64 cm persegi ,berapakah perimeternya?

10Jam 0025 = pukul23Masa berlepas = jam 18 20

Perjalanan = 6jam 45 min

Masa tiba=36 8 35 kg + kg = g 10 100

11 7 1 + =

8 224 5 1jam + jam = min 6 237Masa tiba = jam 08 20

Perjalanan = 4 jam 50min

Masa bertolak =

121040 ml = liter2515, 18, 12 dan 25.

Puratanya=38 1 44 + 1 =

2 5

13120 cm + 0.75 m =262.5 + 0.06 +10.135 =390.75km 25 m = m

Kemahiran Asas Matematik 5 Nama: _____________________ Tarikh: Kemahiran Asas Matematik 61125 + 250 5 =14 1 4

1 - =

4 52710 3.025 =

225 % dpd 144 =15Isipadu kubus yang sisinya

4 cm =280.25 x 480 =

315. 55 + 4 x 5 =16Luas segitiga bersudut tegak yang tingginya 9 cm dan tapaknya

6cm =29 5 10 - = 8

41000X 1.25 =17 4jam 48min

+ 10jam 52 min 302.05 kg - 550g = kg g

5 2 11 + =

3 1218 3 2 - =

4 3312540 sen= RM

63 jam 55 min = min

19Luas segiempat sama yang sisinya 15 cm=32 4 7m + m = cm 5 10

72.45 m = cm20Harga 8 unit = RM 24

Harga 5 unit=33Jika 100% = 48 orang.

25 % =

80.25kg + 85g = g21 1 31 - =

6 434Jika harga asalnya RM 20.00

Diskaun 10 %, berapa harga jualnya?

975 % dpd RM 100 =22Isipadu kuboid yang berukuran 20cm,10cm dan 8cm=35Jika luas segiempatsama ialah

400 cm persegi ,berapakah perimeternya?

10Jam 2025 = pukul23Masa berlepas = jam 14 30

Perjalanan = 10jam 15min

Masa tiba=36 3 9 kg + kg = g 4 10

11 5 3 + =

6 824 1

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