Slide 1

Kinematics

Slide 2

What is gravity? Where does it come from? What kinds of things have gravity? I have two masses. One is a basketball. The other is a 5lb bag of potatoes. If I hold them at the same height and drop them at the same time, which one hits the ground first? Do they have a constant velocity? Do they have the same gravitational force acting on them?

Slide 3

What if I use a piece of paper and a book? What happens now? Why? First http://www.youtube.com/watch?v=oBdalzRJR5g Second http://www.youtube.com/watch?v=_mCC-68LyZM

Slide 4

Equations!!! Equations in IB look different. Fill in the following chart based on the given equations. ConceptVariableUnit

Slide 5

2.1.1 Define displacement, velocity, speed and acceleration. Distance a scalar quantity of position changed Displacement - a vector quantity of a change in the position of an object. Speed is the rate of change of distance with respect to time. (scalar) Velocity is the rate of change of displacement with respect to time. (vector quantity) Acceleration is the rate of change of velocity with respect to time. (vector quantity)

Slide 6

2.1.1 Define displacement, velocity, speed and acceleration. A mass initially at 0m moves 10m to the right and then 2m to the left. What is the final displacement? What is the final distance traveled? A mass initially at 0m, first moves 5m to the right and then 12m to the left. What is the total distance covered by the mass and what is the change in displacement?

Slide 7

Distance and Displacement Distance = 12m, Displacement = 8m Distance = 17m, Displacement = -7m

Slide 8

2.1.1 Define displacement, velocity, speed and acceleration. Speed is normally given in m/s or km/h. OR ms -1 or kmh -1 What the difference between speed and Velocity Speed is a scalar, velocity is a vector.

Slide 9

2.1.1 Define displacement, velocity, speed and acceleration. A car of length 4.2m travelling in a straight line takes 0.56s to go past a mark on the road. What is the speed of the car? A car starts out from the 100km mark in a straight line and moves a distance of 20km towards the right, and then returns to its starting position 1h later. What is the average speed and the average velocity for this trip?

Slide 10

V = 7.5 m/s Avg speed = 40km/h, avg velocity = 0km/h Starting point is irrelevant.

Slide 11

2.1.2 Explain the difference between instantaneous and average values of speed, velocity and acceleration. A car travels 16 km and takes about 4 hours. What is the cars velocity? Really? Are you sure? Are you saying that the car traveled at a speed of 4km/h the entire time?

Slide 12

2.1.2 Explain the difference between instantaneous and average values of speed, velocity and acceleration. 4km/h is the average velocity. At any given moment that car could have been moving at 0km/h or even 100km/h. If we look at the velocity at any given moment in time we would be looking at the INSTANTANEOUS VELOCITY. Double check your equations. Avg Velocity = Displacement / time Instantaneous velocity = velocity at given moment. ex. Initial velocity, final velocity.

Slide 13

Equations

Slide 14

2.1.1 Define displacement, velocity, speed and acceleration. We mostly look at constant acceleration situations. In this case the instantaneous acceleration and average acceleration are the same thing. Acceleration due to gravity is 9.8m/s 2 or 10m/s 2 or 9.81m/s 2. Dont forget about the ball thrown upward. Dont forget about the variable table!

Slide 15

Acceleration An object starting with an initial velocity of 2 m/s undergoes constant acceleration. After 5s its velocity is found to be 12m/s. What is the acceleration? A ball is thrown downward from a 70m tower with an initial velocity of 3m/s. How fast would it be going after 2 seconds? What would its position be after 2seconds?

Slide 16

Acceleration 2m/s 2 22.6m/s, 44.4m high

Slide 17

2.1.1 Define displacement, velocity, speed and acceleration. A mass has an initial velocity of 10m/s. It moves with acceleration -2m/s 2. When will it have a zero velocity? What is the displacement after 10s of a mass whose initial velocity is 2m/s and moves with acceleration of 4m/s 2 ? A car has an initial velocity of 5m/s. When its displacement increases by 20m, its velocity becomes 7m/s. What is the acceleration? A body has initial velocity of 4m/s and a velocity of 12m/s after 6s. What is the displacement?

Slide 18

t = 5s s = 220m a =.6m/s 2 s = 48m

Slide 19

Ready for a challenge! Two balls start out moving to the right with constant velocities of 5m/s and 4m/s. The slow ball stars first and the other 4s later. How far from the starting position are they when they meet? A mass is thrown upwards with an initial velocity of 30m/s. A second mass is dropped from directly above, a height of 60m from the first mass, 0.5s later. When do the masses meet and how high is the point where they meet?

Slide 20

t=20s so s = 80m t=2.35s so s is 42.9m

Slide 21

Exercises (Hamper, Ch2) 1)Convert the following speeds into m/s. a) A car travelling at 100 km/h b) A runner running at 20 km/h 3)Calculate the final velocity of a body that starts from rest and accelerates at 5m/s for a distance of 100m. 4)A body starts with a velocity of 20m/s and accelerates for 200m with an acceleration of 5m/s. What is the final velocity of the body? 5)A body accelerates at 10m s -2 reaching a final velocity of 20m s -1 in 5s. What was the initial velocity of the body? 6) A ball is thrown upwards with a velocity of 30m/s. What is the displacement of the ball after 2s? 7) A ball is dropped. What will its velocity be after falling 65cm? 8) A ball is thrown upwards with a velocity of 20m/s. After how many seconds will the ball return to its starting point?

Slide 22

Graphing

Slide 23

Cheat Sheet

Slide 24

The slope of d-t graph gives the value of the v-t graph The slope of v-t graph gives the value of the a-t graph Area under a-t graph gives the change in velocity Area under v-t graph gives the change in displacement.

Slide 25

Example

Slide 26

Bell Ringer Sept 4/5 Consider the following graph

Slide 27

Bell Ringer Sept 4/5 What is the initial displacement? What is the velocity for the first 10s? Second 5s? When is the object at the origin? What is s? What is the total distance traveled? What is the avg velocity?

Slide 28

Initial displacement is -10m 2m/s, -2m/s 5s and 15s s = 10m, total distance = 30m Avg speed = 2m/s, avg velocity =.66m/s

Slide 29

Interpreting graphs A mass starts out from zero with velocity 10m/s and continues moving at this velocity for 5s. The velocity is then abruptly reversed to -5m/s and the object moves at this velocity for 10s. For this event find: a) The graph b) The change in displacement c) The total distance travelled d) The average speed e) The average velocity

Slide 30

Slide 31

a) See previous slide b) 10 x 5m = 50m, -5 x 10 = -50m, s = 0 The object moved toward the right, stopped and returned to its starting position. c) 50m to the right, 50m to the left, 100m total d) Avg velocity =0 e) Avg speed= 100m/15s = 6.7m/s

Slide 32

Use the graph and your understanding of slope calculations to determine the acceleration of the rocket during the listed time intervals. t = 0 - 1 s, t = 1 - 4 s, t = 4 - 12 s

Slide 33

a = 40 m s -2 b = 20 m s -2 c = - 20 m s -2

Slide 34

Describe the motion depicted by the following velocity-time graphs. In your descriptions, make reference to the direction of motion (+ or - direction), the velocity and acceleration and any changes in speed (speeding up or slowing down) during the various time intervals (e.g., intervals A, B, and C).

Slide 35

The object moves in the + direction at a constant speed - zero acceleration (interval A). The object then continues in the + direction while slowing down with a negative acceleration (interval B). Finally, the object moves at a constant speed in the + direction, slower than before (interval C). The object moves in the + direction while slowing down; this involves a negative acceleration (interval A). It then remains at rest (interval B). The object then moves in the - direction while speeding up; this also involves a negative acceleration (interval C). The object moves in the + direction with a constant velocity and zero acceleration (interval A). The object then slows down while moving in the + direction (i.e., it has a negative acceleration) until it finally reaches a 0 velocity (stops) (interval B). Then the object moves in the - direction while speeding up; this corresponds to a - acceleration (interval C)

Slide 36

Consider the velocity-time graph below. Determine the acceleration (i.e., slope) of the object as portrayed by the graph.

Slide 37

The acceleration (i.e., slope) is 4 m/s/s. If you think the slope is 5 m/s/s, then you're making a common mistake. You are picking one point (probably 5 s, 25 m/s) and dividing y/x. Instead you must pick two points (as in the discussed in this part of the lesson) and divide the change in y by the change in x.

Slide 38

Determine the displacement of the object during the time interval denoted by the shaded area.

Slide 39

a = 90m b = 45m c = 40m

Slide 40

Relative velocities

Slide 41

http://regentsprep.org/Regents/physics/phys01/velocit y/relative.htm http://regentsprep.org/Regents/physics/phys01/velocit y/relative.htm

Slide 42

A car (A) moves to the left with speed 40km/h (with respect to the road). Another car (B) moves to the right with speed 60km/h(also with respect to the road). Find the relative velocity of B with respect to A.

Slide 43

Do pg 46 #4,5, 6, 8, 9, 11, 12

Slide 44

FORCES!!!

Slide 45

Types of forces Gravitational between objects as a result of their masses. (also called weight) Normal reaction between two surfaces that are touching Frictional- force that opposes the relative motion of two surfaces. (Includes Air resistance/drag) Applied force of an outside object pushing or pulling Tension- when a string/spring is stretched, it is equal and opposite the force acting on it. Compression opposite of tension (applies to solid objects) Upthrust the upward force that acts on objects when it is submerged in a fluid. Causes objects to float. Lift caused when air flows over an aircrafts wing. Causes an upward force.

Slide 46

Free Body Diagram Five Steps. 1) Is there gravitational force? (F g ) 2) Is it sitting on a surface? (F n ) 3) Is there some thing pushing or pulling? (F app ) 4) Is there friction? (F f ) 5) Is it accelerating? a = ? http://www.youtube.com/watch?v=BuPfDI7TyL0

Slide 47

Forces are vectors Magnitude and direction Many times the direction is the x or y This means they can be resolved into components. This also means they can be added and subtracted. http://www.youtube.com/watch?v=IrY-FlJ0c7Y

Slide 48

Practice/Application 1. A person is trying to lift a heavy concrete block without success. The upward force exerted on the block by the person is P, the contact force on the block by the floor is C, the weight of the block is W. Which one of the following is true about the magnitudes of the forces on the block while the person is trying to lift it? a) P + C =W b) P + C < W c) P+ C > W d) P = C = W

Slide 49

Practice/Application 2. Consider the vector with a magnitude of 7N acting at an angle of 140 to the horizontal. What will the horizontal and vertical components of this vector be? 3. An object O is acted upon by three forces as shown in the diagram. What is the magnitude of the resultant force acting on O?

Slide 50

Answers 1) Since the person is not succeeding to lift the box, the weight of the box must be equal to the sum of the upward force and the floor contact force. Answer: A 2) y= 5.4 x = -4.5 3) The 6N and 3N forces are acting against each other. This results in a 3N force to the left. This resulting 3N force left and the 4N upward force can be resolved using Pythagoras. Answer = 5N

Slide 51

Practice/Application 4) A block of wood of mass 4kg rests on a slope, inclined at an angle of 25 to the horizontal as shown. Calculate: a) The weight of the block b) The normal reaction force of the plane acting on the block. c) The resultant accelerating force down the slope d) The acceleration of the block down the slope

Slide 52

Answers 4) There are several a) F g = mg => F g = 40N b) F N = F g cos => F N = 36.6N c) F R = F g sin => F R = 16.9N d) F g = mg => a = 4.2m/s 2 5) d

Slide 53

Pg 73 # 1, 2, 4, 6, 7

Slide 54

Equilibrium Occurs when the net force on an object is zero. An object can move and still be at equilibrium. Neutral equilibrium(translational) an object is at equilibrium, it is then moved and then it is still at equilibrium. A displacement results in another equilibrium position. The net force acting on an object is zero.

Slide 55

Newtons Three Laws First Law - Inertia An object will remain at its state of rest or of constant velocity unless acted upon by a force

Slide 56

Practice 1) For an object to be in translational equilibrium a) It must be at rest b) it must be moving with constant acceleration c) No external force must be acting on it d) The net force acting on it must be zero

Slide 57

2) A rain drop falling through air reaches a terminal velocity before hitting the ground. At terminal velocity, the frictional force on the raindrop is a) Zero b) Less than the weight of the raindrop c) Greater than the weight of the rain drop d) Equal to the weight of the raindrop

Slide 58

A car is travelling along a level highway at a constant velocity in a straight line. Air resistance is not negligible. Draw the free-body diagram for this car.

Slide 59

Newtons Second Law The rate of acceleration of an object is directly proportional to the applied force and inversely proportional to its mass. OR. F=ma

Slide 60

Practice 4) A car mass 1100kg accelerates from 10m/s to 30m/s in 5.5s calculate the cars engine force. 5) A boy on a bicycle, travelling at 12m/s applies the brakes and comes to rest in a distance of 16m. If the combined mass of the boy and bicycle is 70kg, calculate the braking force.

Slide 61

6) An elevator of mass 800kg is supported by a thick metal rope capable of withstanding a tension of 1200N. Calculate the tension in the rope when the elevator is: a) Not moving, between floors b) Moving at constant velocity, of 2m/s upward c) Moving at constant velocity, of 2m/s downwards d) Accelerating upwards at a rate of 3m/s e) Accelerating downwards at a rate of 3m/s

Slide 62

Newtons Third Law http://www.youtube.com/watch?v=8bTdMmNZm2M&f eature=edu&list=PL772556F1EFC4D01C When two bodies A and B interact, the force that A exerts on B is equal to the force that B exerts on A but acts in the opposite direction.

Slide 63

7) A man pushes a car along a road. He exerts a force F on the car. In this situation, what is the equal and opposite force to F as referred to in Newtons third law? 8) Newtons third law identifies pairs of forces that are equal in magnitude. One of the forces acting on a bird in flight is the gravitational force W downward. What is the re-action force?